I am working validation in gwt. I am having textbox which allows only whole numbers and decimalvalues. I used regex pattern like ^[0-9.]+$.It works fine. But when i entered single dot like . it accepts. How can i restrict single dot on above regex pattern?
^[0-9]+([.][0-9]+)?$
So a series of digits, optionally followed by a period and a series of digits.
For our GWT project we are using Hibernate validator and annotations like
#DecimalMax(value = "9999999.99")
#DecimalMin(value = "0.01")
private BigDecimal amount;
instead of regular expressions.
How about:
^\d+(?:\.\d+)?$
It will match integers or decimal numbers.
Explanation:
The regular expression:
(?-imsx:^\d+(?:\.\d+)?$)
matches as follows:
NODE EXPLANATION
----------------------------------------------------------------------
(?-imsx: group, but do not capture (case-sensitive)
(with ^ and $ matching normally) (with . not
matching \n) (matching whitespace and #
normally):
----------------------------------------------------------------------
^ the beginning of the string
----------------------------------------------------------------------
\d+ digits (0-9) (1 or more times (matching
the most amount possible))
----------------------------------------------------------------------
(?: group, but do not capture (optional
(matching the most amount possible)):
----------------------------------------------------------------------
\. '.'
----------------------------------------------------------------------
\d+ digits (0-9) (1 or more times (matching
the most amount possible))
----------------------------------------------------------------------
)? end of grouping
----------------------------------------------------------------------
$ before an optional \n, and the end of the
string
----------------------------------------------------------------------
) end of grouping
----------------------------------------------------------------------
Related
I have a URL that contains multiple sequences of numbers I want to capture them all in groups suppose I have the following
https://www.example.com//first/part/54323?key=value
or
https://www.example.com/first/12345/second/part/part2/5432?key=value
I tried to use something like that but it only matches one sequence of numbers
(.*\/)([0-9]{4,})(\/.*|$|)
I want to have multiple groups represent different sections if numbers sequence is included
1st group will be "example.com/first"
2nd group "12345"
3rd group "second/part"
4th group "5432"
5th group "?key=value"
The initial .* is Greedy, meaning it tries to match as much as possible. It matched everything up to the last slash "https://www.example.com/first/12345/second/part". You can modify this behavior by replacing the initial .* with .*?, but that will stop after the first slash, which is also not what you want "https:/" because there are no digits after those slashes.
But really we need to back up and ask some questions about your pattern. Apparently, you have a preamble you are not interested in, an indefinite number of sequences of 'character string, followed by slash, followed by number string' and then there is the "everything after there are no more slash digit patterns".
The key question is whether the number of char/char/digits combos are indefinite or limited to a definite number like the two pairs in your example. To get the regex parser to return an unbounded number of string-number pairs, you are going to want to turn on the /g (Global) switch so regex will return all matches. That is a problem with the part of your URL at the beginning and end which does not fit your pattern.
I recommend first using a regular expression to divide your URL into three parts, preamble, path, remaining data. Then you can pass the path string to a second regular expression to parse the pairs - it will be much simpler.
If you do it that way your first expression could be:
^[a-z+.-]+?:\/\/(:www\.)?([^?#]+?)(.*)$
The first part skips over everything through the optional www. and does not capture it because you are not interested in that part. The second part captures everything up to any query or fragment (delimited by ? and #, respectively) and places it in the first capture group. The last part captures the rest of the URL into the the second capture group. In your example that is ?key=value.
Now take your first capture group, which contains the host and the path, and pass it to a second regex with the global flag set (so it processes all pairs repeatedly). This second regex will be:
(.*?)\/([0-9]{4,})\/?
For each match of this string, the parsed values and numbers will be in capture groups 1 & 2.
It sounds very straight-forward:
https?:\/\/(?:www\.)?(.*?)\/(\d+)\/(.*?)\/(\d+)(?:\?(.*))?
See regex proof.
EXPLANATION
--------------------------------------------------------------------------------
http 'http'
--------------------------------------------------------------------------------
s? 's' (optional (matching the most amount
possible))
--------------------------------------------------------------------------------
: ':'
--------------------------------------------------------------------------------
\/ '/'
--------------------------------------------------------------------------------
\/ '/'
--------------------------------------------------------------------------------
(?: group, but do not capture (optional
(matching the most amount possible)):
--------------------------------------------------------------------------------
www 'www'
--------------------------------------------------------------------------------
\. '.'
--------------------------------------------------------------------------------
)? end of grouping
--------------------------------------------------------------------------------
( group and capture to \1:
--------------------------------------------------------------------------------
.*? any character except \n (0 or more times
(matching the least amount possible))
--------------------------------------------------------------------------------
) end of \1
--------------------------------------------------------------------------------
\/ '/'
--------------------------------------------------------------------------------
( group and capture to \2:
--------------------------------------------------------------------------------
\d+ digits (0-9) (1 or more times (matching
the most amount possible))
--------------------------------------------------------------------------------
) end of \2
--------------------------------------------------------------------------------
\/ '/'
--------------------------------------------------------------------------------
( group and capture to \3:
--------------------------------------------------------------------------------
.*? any character except \n (0 or more times
(matching the least amount possible))
--------------------------------------------------------------------------------
) end of \3
--------------------------------------------------------------------------------
\/ '/'
--------------------------------------------------------------------------------
( group and capture to \4:
--------------------------------------------------------------------------------
\d+ digits (0-9) (1 or more times (matching
the most amount possible))
--------------------------------------------------------------------------------
) end of \4
--------------------------------------------------------------------------------
(?: group, but do not capture (optional
(matching the most amount possible)):
--------------------------------------------------------------------------------
\? '?'
--------------------------------------------------------------------------------
( group and capture to \5:
--------------------------------------------------------------------------------
.* any character except \n (0 or more
times (matching the most amount
possible))
--------------------------------------------------------------------------------
) end of \5
--------------------------------------------------------------------------------
)? end of grouping
I would like to match a specific pattern with regex but I am running into catastrophic backtracking. I wonder if there's a way it would be possible to match what I would like and not get an error.
I start with a simple assumption; I want my string to contain only one specific number e.g. 7 and only that specific number:
^\D*7\D*$
Only if I find this pattern do I want to look for another word in the same text such as "Coffee"; I put my condition into a group (^\D*7\D*$) and reference the group in my conditional and the then part will contain "Coffee":
(?(1)Coffee|)
Is there another phrasing that would avoid the the catastrophic backtracking?
You can use a negative lookahead to assert that the word Coffee is at the right.
^(?=.*\bCoffee\b)\D*7\D*$
The pattern matches:
^ Start of string
(?= Positive lookahead, assert that on the right is
.*\bCoffee\b Match Coffee between word boundaries \b to prevent a partial match
) Close lookahead
\D*7\D* Match number 7 between optional non digit characters.
$ End of string
Regex demo
Note that \D also matches a newline. If you don't want to cross newline boundaries, you can use [^\r\n\d] instead.
Left to right checking is more traditional:
^(?=.*Coffee)[^\d7]*7\D*$
See regex proof.
EXPLANATION
--------------------------------------------------------------------------------
^ the beginning of the string
--------------------------------------------------------------------------------
(?= look ahead to see if there is:
--------------------------------------------------------------------------------
.* any character except \n (0 or more times
(matching the most amount possible))
--------------------------------------------------------------------------------
Coffee 'Coffee'
--------------------------------------------------------------------------------
) end of look-ahead
--------------------------------------------------------------------------------
[^\d7]* any character except: digits (0-9), '7' (0
or more times (matching the most amount possible))
--------------------------------------------------------------------------------
7 '7'
--------------------------------------------------------------------------------
\D* non-digits (all but 0-9) (0 or more times
(matching the most amount possible))
--------------------------------------------------------------------------------
$ before an optional \n, and the end of the string
Right to left checking is only possible with engines like latest JavaScript, .NET or PyPi regex in Python:
^[^\d7]*7\D*$(?<=Coffee.*)
See proof.
EXPLANATION
--------------------------------------------------------------------------------
^ the beginning of the string
--------------------------------------------------------------------------------
[^\d7]* any character except: digits (0-9), '7' (0
or more times (matching the most amount
possible))
--------------------------------------------------------------------------------
7 '7'
--------------------------------------------------------------------------------
\D* non-digits (all but 0-9) (0 or more times
(matching the most amount possible))
--------------------------------------------------------------------------------
$ before an optional \n, and the end of the
string
--------------------------------------------------------------------------------
(?<= look behind to see if there is:
--------------------------------------------------------------------------------
Coffee 'Coffee'
--------------------------------------------------------------------------------
.* any character except \n (0 or more times
(matching the most amount possible))
--------------------------------------------------------------------------------
) end of look-behind
I have some strings in Oracle where there is a minus sign (not at the beginning but inside the string), followed by a number (int or decimal with dot or comma).
I would like to find these in PLSQL. I have this already, and it's almost perfect:
REGEXP_LIKE(string, '-\d+(,|\.)*\d*')
I was hoping that it's finding strictly strings like somestring-11,1 but the problem is, it finds also strings like somestring-11a1,1 so where there is eventually a non numeric (or word) character between the minus and the numbers. I was trying to use negative lookahead, but unfortunately it's not working:
REGEXP_LIKE(string, '-\d+!(\w)(,|\.)*\d*')
because somestring-1s won't be found either anymore. Could you please point me to the right direction? Thank you.
Could you please try following, written and tested based on your shown samples. Simple explanation would be: using lazy match to match till - then match digits(1 or more occurrences) followed by , and followed by 1 or more occurrences of digits.
.*?-\d+,\d+
Online regex demo for above regex
Use
(^|\D)-(\d+([,.]*\d+)?)($|\W)
See proof.
EXPLANATION
--------------------------------------------------------------------------------
( group and capture to \1:
--------------------------------------------------------------------------------
^ the beginning of the string
--------------------------------------------------------------------------------
| OR
--------------------------------------------------------------------------------
\D non-digits (all but 0-9)
--------------------------------------------------------------------------------
) end of \1
--------------------------------------------------------------------------------
- '-'
--------------------------------------------------------------------------------
( group and capture to \2:
--------------------------------------------------------------------------------
\d+ digits (0-9) (1 or more times (matching
the most amount possible))
--------------------------------------------------------------------------------
( group and capture to \3 (optional
(matching the most amount possible)):
--------------------------------------------------------------------------------
[,.]* any character of: ',', '.' (0 or more
times (matching the most amount
possible))
--------------------------------------------------------------------------------
\d+ digits (0-9) (1 or more times
(matching the most amount possible))
--------------------------------------------------------------------------------
)? end of \3 (NOTE: because you are using a
quantifier on this capture, only the
LAST repetition of the captured pattern
will be stored in \3)
--------------------------------------------------------------------------------
) end of \2
--------------------------------------------------------------------------------
( group and capture to \4:
--------------------------------------------------------------------------------
$ before an optional \n, and the end of
the string
--------------------------------------------------------------------------------
| OR
--------------------------------------------------------------------------------
\W non-word characters (all but a-z, A-Z, 0-
9, _)
--------------------------------------------------------------------------------
) end of \4
I want to use regex validation formula on Text Field. Here is pure regex:
^(?!(?:\D*\d){7})\d+(\.\d{1,2})?$
When I test this expression in regex online tools (eg: https://regex101.com/) everything works fine.
But when I try to use this as validator in Orbeon like this:
matches(string(.), '^(?!(?:\D*\d){7})\d+(\.\d{1,2})?$') or xxf:is-blank(string(.))
I get error 'Incorrect XPath expression'.
When I removed from regex lookahead part, I was able to use it.
matches(string(.), '^\d+(\.\d{1,2})?$') or xxf:is-blank(string(.))
Is Orbeon Forms supports regex lookahead?
Regex lookahead:
https://www.regular-expressions.info/lookaround.html
Re-write the expression without lookahead. It matches strings with no more than 6 digits.
Use
^(\d{1,4}(\.\d{1,2})?|\d{5}(\.\d)?|\d{6})$
See proof
EXPLANATION
NODE EXPLANATION
--------------------------------------------------------------------------------
^ the beginning of the string
--------------------------------------------------------------------------------
( group and capture to \1:
--------------------------------------------------------------------------------
\d{1,4} digits (0-9) (between 1 and 4 times
(matching the most amount possible))
--------------------------------------------------------------------------------
( group and capture to \2 (optional
(matching the most amount possible)):
--------------------------------------------------------------------------------
\. '.'
--------------------------------------------------------------------------------
\d{1,2} digits (0-9) (between 1 and 2 times
(matching the most amount possible))
--------------------------------------------------------------------------------
)? end of \2 (NOTE: because you are using a
quantifier on this capture, only the
LAST repetition of the captured pattern
will be stored in \2)
--------------------------------------------------------------------------------
| OR
--------------------------------------------------------------------------------
\d{5} digits (0-9) (5 times)
--------------------------------------------------------------------------------
( group and capture to \3 (optional
(matching the most amount possible)):
--------------------------------------------------------------------------------
\. '.'
--------------------------------------------------------------------------------
\d digits (0-9)
--------------------------------------------------------------------------------
)? end of \3 (NOTE: because you are using a
quantifier on this capture, only the
LAST repetition of the captured pattern
will be stored in \3)
--------------------------------------------------------------------------------
| OR
--------------------------------------------------------------------------------
\d{6} digits (0-9) (6 times)
--------------------------------------------------------------------------------
) end of \1
--------------------------------------------------------------------------------
$ before an optional \n, and the end of the
string
I need to validate the date format, that can be either 11/11/11 or 11/22/2013, i.e. the year block can be in YY or YYYY and the complete format will either MM/DD/YY or MM/DD/YYYY
I've this code
^(\d{1,2})\/(\d{1,2})\/(\d{4})$
and I've tried
^(\d{1,2})\/(\d{1,2})\/(\d{2}{4})$ // doesn't works, does nothing
and
^(\d{1,2})\/(\d{1,2})\/(\d{2|4})$ // and it returns null every time
PS: I'm applying it with Javascript/jQuery
^(\d{1,2})\/(\d{1,2})\/(\d{2}|\d{4})$
Both \d{2}{4} and \d{2|4} are not correct regex expression. You have to do two digits and for digits separately and combine then using or: (\d{2}|\d{4})
You could use:
^\d\d?/\d\d?/\d\d(?:\d\d)?$
explanation:
The regular expression:
(?-imsx:^\d\d?/\d\d?/\d\d(?:\d\d)?$)
matches as follows:
NODE EXPLANATION
----------------------------------------------------------------------
(?-imsx: group, but do not capture (case-sensitive)
(with ^ and $ matching normally) (with . not
matching \n) (matching whitespace and #
normally):
----------------------------------------------------------------------
^ the beginning of the string
----------------------------------------------------------------------
\d digits (0-9)
----------------------------------------------------------------------
\d? digits (0-9) (optional (matching the most
amount possible))
----------------------------------------------------------------------
/ '/'
----------------------------------------------------------------------
\d digits (0-9)
----------------------------------------------------------------------
\d? digits (0-9) (optional (matching the most
amount possible))
----------------------------------------------------------------------
/ '/'
----------------------------------------------------------------------
\d digits (0-9)
----------------------------------------------------------------------
\d digits (0-9)
----------------------------------------------------------------------
(?: group, but do not capture (optional
(matching the most amount possible)):
----------------------------------------------------------------------
\d digits (0-9)
----------------------------------------------------------------------
\d digits (0-9)
----------------------------------------------------------------------
)? end of grouping
----------------------------------------------------------------------
$ before an optional \n, and the end of the
string
----------------------------------------------------------------------
) end of grouping
----------------------------------------------------------------------