In Clojure I could use something like this solution: Compact Clojure code for regular expression matches and their position in string, i.e., creating a re-matcher and extracted the information from that, but re-matcher doesn't appear to be implemented in ClojureScript. What would be a good way to accomplish the same thing in ClojureScript?
Edit:
I ended up writing a supplementary function in order to preserve the modifiers of the regex as it is absorbed into re-pos:
(defn regex-modifiers
"Returns the modifiers of a regex, concatenated as a string."
[re]
(str (if (.-multiline re) "m")
(if (.-ignoreCase re) "i")))
(defn re-pos
"Returns a vector of vectors, each subvector containing in order:
the position of the match, the matched string, and any groups
extracted from the match."
[re s]
(let [re (js/RegExp. (.-source re) (str "g" (regex-modifiers re)))]
(loop [res []]
(if-let [m (.exec re s)]
(recur (conj res (vec (cons (.-index m) m))))
res))))
You can use the .exec method of JS RegExp object. The returned match object contains an index property that corresponds to the index of the match in the string.
Currently clojurescript doesn't support constructing regex literals with the g mode flag (see CLJS-150), so you need to use the RegExp constructor. Here is a clojurescript implementation of the re-pos function from the linked page:
(defn re-pos [re s]
(let [re (js/RegExp. (.-source re) "g")]
(loop [res {}]
(if-let [m (.exec re s)]
(recur (assoc res (.-index m) (first m)))
res))))
cljs.user> (re-pos "\\w+" "The quick brown fox")
{0 "The", 4 "quick", 10 "brown", 16 "fox"}
cljs.user> (re-pos "[0-9]+" "3a1b2c1d")
{0 "3", 2 "1", 4 "2", 6 "1"}
Related
If I have this set
(def my-set #{"foo.clj" "bar.clj" "baz.clj"})
How can I turn it to this pattern string:
"foo\.clj|bar\.clj|baz\.clj"
My attempt :
(defn set->pattern-str [coll]
(-> (clojure.string/join "|" coll)
(clojure.string/replace #"\." "\\\\.")))
(set->pattern-str my-set)
=> "foo\\.clj|baz\\.clj|bar\\.clj" ;I get the double backslash
Better ideas?
In case your set of strings might have other metacharacters than just . in them, a more general approach is to ask the underlying java.util.regex.Pattern implementation to escape everything for us:
(import 'java.util.regex.Pattern)
(defn set->pattern-str [coll]
(->> coll
(map #(Pattern/quote %))
(clojure.string/join \|)
re-pattern))
IDEone link here. Remember, IDEone is not a REPL, and you have to tell it to put values on stdout with e.g. println before you can see them.
You were close to the final solution. Double backslash is displayed because it is shown escaped. When you turn it into a seq you will see individual characters:
(seq "foo\\.clj")
;;=> (\f \o \o \\ \. \c \l \j)
And working solution:
(def my-set #{"foo.clj" "bar.clj" "baz.clj"})
(def my-set-pattern
(-> (clojure.string/join "|" my-set)
(clojure.string/replace "." "\\.")
(re-pattern)))
(re-matches my-set-pattern "foo.clj")
;;=> "foo.clj"
(re-matches my-set-pattern "bar.clj")
;;=> "bar.clj"
(re-matches my-set-pattern "baz.clj")
;;=> "baz.clj"
(re-matches my-set-pattern "foo-clj")
;;=> nil
Edit: OK, this one does in fact work. Probably want to break it apart a bit more if it's meant to be long lived code, but this is the simplest way I could find to do it with minimal string munging.
(defn is-matching-file-name [target-string]
(re-matches
(re-pattern (clojure.string/escape (String/join "|" my-set) {\. "\\."}))
target-string))
The clojure.string/escape here takes two arguments: the string to escape, and a mapping of the characters to escape to the replacement strings. The key in this map is the literal \. and the value needs two backslashes since we want to include one backslash preceding any . in the final string to be used as the argument for the re-pattern function.
Can anybody explain what the type below is in the code below which I seen in the clojure docs for string/replace?
(clojure.string/replace "The color is red" #"red" "blue")
I am talking specifically about the #"red" "blue"
Also, if I have an array-map like this:
{"red" "blue"}
How could I transform this array-map into this unknown type?
{"red" "blue"} ;=> #"red" "blue"???
If you have a map {"red" "blue"} and you'd like to use that to drive the replacement, you could do:
;; Generic form of your question - uses re-pattern to create a regex
(defn replace-with [s find replacement]
(clojure.string/replace s (re-pattern find) replacement))
;; Walk through every [find replace] pair in replacements map
;; and repeatedly apply it to string
(defn replace-with-all [s replacements]
(reduce (fn [s [f r]] (replace-with s f r))
s
replacements))
(replace-with-all "foo bar baz" {"foo" "blue" "baz" "red"})
;; "blue bar red"
In Clojure, #"....." is a Regular Expression definition. So you are replacing red with blue.
(replace s match replacement)
Replaces all instance of match with replacement in s.
match/replacement can be:
string / string
char / char
pattern / (string or function of match).
But I didn't understand what do you mean by 'transform this array-map into this unknown type'.
I'm trying to convert a hyphenated string to CamelCase string. I followed this post: Convert hyphens to camel case (camelCase)
(defn hyphenated-name-to-camel-case-name [^String method-name]
(clojure.string/replace method-name #"-(\w)"
#(clojure.string/upper-case (first %1))))
(hyphenated-name-to-camel-case-name "do-get-or-post")
==> do-Get-Or-Post
Why I'm still getting the dash the output string?
You should replace first with second:
(defn hyphenated-name-to-camel-case-name [^String method-name]
(clojure.string/replace method-name #"-(\w)"
#(clojure.string/upper-case (second %1))))
You can check what argument clojure.string/upper-case gets by inserting println to the code:
(defn hyphenated-name-to-camel-case-name [^String method-name]
(clojure.string/replace method-name #"-(\w)"
#(clojure.string/upper-case
(do
(println %1)
(first %1)))))
When you run the above code, the result is:
[-g g]
[-o o]
[-p p]
The first element of the vector is the matched string, and the second is the captured string,
which means you should use second, not first.
In case your goal is just to to convert between cases, I really like the camel-snake-kebab library. ->CamelCase is the function-name in question.
inspired by this thread, you could also do
(use 'clojure.string)
(defn camelize [input-string]
(let [words (split input-string #"[\s_-]+")]
(join "" (cons (lower-case (first words)) (map capitalize (rest words))))))
I'm new to Clojure and I'm doing some basic stuff from labrepl, now I want to write a function that will replace certain letters with other letters, for example: elosska → elößkä.
I wrote this:
(ns student.dialect (:require [clojure.string :as str]))
(defn germanize
[sentence]
(def german-letters {"a" "ä" "u" "ü" "o" "ö" "ss" "ß"})
(doseq [[original-letter new-letter] german-letters]
(str/replace sentence original-letter new-letter)))
but it doesn't work as I expect. Could you help me, please?
Here is my take,
(def german-letters {"a" "ä" "u" "ü" "o" "ö" "ss" "ß"})
(defn germanize [s]
(reduce (fn[sentence [match replacement]]
(str/replace sentence match replacement)) s german-letters))
(germanize "elosska")
There are 2 problems here:
doseq doesn't preserve head of list that created by its evaluation, so you won't get any results
str/replace works on separate copies of text, producing 4 different results - you can check this by replacing doseq with for and you'll get list with 4 entries.
You code could be rewritten following way:
(def german-letters {"a" "ä" "u" "ü" "o" "ö" "ss" "ß"})
(defn germanize [sentence]
(loop [text sentence
letters german-letters]
(if (empty? letters)
text
(let [[original-letter new-letter] (first letters)]
(recur (str/replace text original-letter new-letter)
(rest letters))))))
In this case, intermediate results are collected, so all replacements are applied to same string, producing correct string:
user> (germanize "elosska")
"elößkä"
P.S. it's also not recommended to use def in the function - it's better to use it for top-level forms
Alex has of course already correctly answered the question with respect to the original issue using doseq... but I found the question interesting and wanted to see what a more "functional" solution would look like. And by that I mean without using a loop.
I came up with this:
(ns student.dialect (:require [clojure.string :as str]))
(defn germanize [sentence]
(let [letters {"a" "ä" "u" "ü" "o" "ö" "ss" "ß"}
regex (re-pattern (apply str (interpose \| (keys letters))))]
(str/replace sentence regex letters)))
Which yields the same result:
student.dialect=> (germanize "elosska")
"elößkä"
The regex (re-pattern... line simply evaluates to #"ss|a|o|u", which would have been cleaner, and simpler to read, if entered as an explicit string, but I thought it best to have only one definition of the german letters.
I'm looking to create a list of characters using a string as my source. I did a bit of googling and came up with nothing so then I wrote a function that did what I wanted:
(defn list-from-string [char-string]
(loop [source char-string result ()]
(def result-char (string/take 1 source))
(cond
(empty? source) result
:else (recur (string/drop 1 source) (conj result result-char)))))
But looking at this makes me feel like I must be missing a trick.
Is there a core or contrib function that does this for me? Surely I'm just being dumb right?
If not is there a way to improve this code?
Would the same thing work for numbers too?
You can just use seq function to do this:
user=> (seq "aaa")
(\a \a \a)
for numbers you can use "dumb" solution, something like:
user=> (map (fn [^Character c] (Character/digit c 10)) (str 12345))
(1 2 3 4 5)
P.S. strings in clojure are 'seq'able, so you can use them as source for any sequence processing functions - map, for, ...
if you know the input will be letters, just use
user=> (seq "abc")
(\a \b \c)
for numbers, try this
user=> (map #(Character/getNumericValue %) "123")
(1 2 3)
Edit: Oops, thought you wanted a list of different characters. For that, use the core function "frequencies".
clojure.core/frequencies
([coll])
Returns a map from distinct items in coll to the number of times they appear.
Example:
user=> (frequencies "lazybrownfox")
{\a 1, \b 1, \f 1, \l 1, \n 1, \o 2, \r 1, \w 1, \x 1, \y 1, \z 1}
Then all you have to do is get the keys and turn them into a string (or not).
user=> (apply str (keys (frequencies "lazybrownfox")))
"abflnorwxyz"
(apply str (set "lazybrownfox")) => "abflnorwxyz"