I was (unsuccessfully) trying to figure out how to create a list of compound letters using loops. I am a beginner programmer, have been learning python for a few months. Fortunately, I later found a solution to this problem - Genearte a list of strings compound of letters from other list in Python - see the first answer.
So I took that code and added a little to it for my needs. I randomized the list, turned the list into a comma separated file. This is the code:
from string import ascii_lowercase as al
from itertools import product
import random
list = ["".join(p) for i in xrange(1,6) for p in product(al, repeat = i)]
random.shuffle(list)
joined = ",".join(list)
f = open("double_letter_generator_output.txt", 'w')
print >> f, joined
f.close()
What I need to do now is split that massive file "double_letter_generator_output.txt" into smaller files. Each file needs to consist of 200 'words'. So it will need to split into many files. The files of course do not exist yet and will need to be created by the program also. How can I do that?
Here's how I would do it, but I'm not sure why you're splitting this into smaller files. I would normally do it all at once, but I'm assuming the file is too big to be stored in working memory, so I'm traversing one character at a time.
Let bigfile.txt contain
1,2,3,4,5,6,7,8,9,10,11,12,13,14
MAX_NUM_ELEMS = 2 #you'll want this to be 200
nameCounter = 1
numElemsCounter = 0
with open('bigfile.txt', 'r') as bigfile:
outputFile = open('output' + str(nameCounter) + '.txt', 'a')
for letter in bigfile.read():
if letter == ',':
numElemsCounter += 1
if numElemsCounter == MAX_NUM_ELEMS:
numElemsCounter = 0
outputFile.close()
nameCounter += 1
outputFile = open('output' + str(nameCounter) + '.txt', 'a')
else:
outputFile.write(letter);
outputFile.close()
now output1.txt is 1,2, output2.txt is 3,4, output3.txt is 5,6, etc.
$ cat output7.txt
13,14
This is a little sloppy, you should write a nice function to do it and format it the way you like!
FYI, if you want to write to a bunch of different files, there's no reason to write to one big file first. Write to the little files right off the bat.
This way, the last file might have fewer than MAX_NUM_ELEMS elements.
Related
Background
I have a list of "bad words" in a file called bad_words.conf, which reads as follows
(I've changed it so that it's clean for the sake of this post but in real-life they are expletives);
wrote (some )?rubbish
swore
I have a user input field which is cleaned and striped of dangerous characters before being passed as data to the following script, score.py
(for the sake of this example I've just typed in the value for data)
import re
data = 'I wrote some rubbish and swore too'
# Get list of bad words
bad_words = open("bad_words.conf", 'r')
lines = bad_words.read().split('\n')
combine = "(" + ")|(".join(lines) + ")"
#set score incase no results
score = 0
#search for bad words
if re.search(combine, data):
#add one for a hit
score += 1
#show me the score
print(str(score))
bad_words.close()
Now this finds a result and adds a score of 1, as expected, without a loop.
Question
I need to adapt this script so that I can add 1 to the score every time a line of "bad_words.conf" is found within text.
So in the instance above, data = 'I wrote some rubbish and swore too' I would like to actually score a total of 2.
1 for "wrote some rubbish" and +1 for "swore".
Thanks for the help!
Changing combine to just:
combine = "|".join(lines)
And using re.findall():
In [33]: re.findall(combine,data)
Out[33]: ['rubbish', 'swore']
The problem with having the multiple capturing groups as you originally were doing is that re.findall() will return each additional one of those as an empty string when one of the words is matched.
I have just started doing my first research project, and I have just begun programming (approximately 2 weeks ago). Excuse me if my questions are naive. I might be using python very inefficiently. I am eager to improve here.
I have experimental data that I want to analyse. My goal is to create a python script that takes the data as input, and that for output gives me graphs, where certain parameters contained in text files (within the experimental data folders) are plotted and fitted to certain equations. This script should be as generalizable as possible so that I can use it for other experiments.
I'm using the Anaconda, Python 2.7, package, which means I have access to various libraries/modules related to science and mathematics.
I am stuck at trying to use For and While loops (for the first time).
The data files are structured like this (I am using regex brackets here):
.../data/B_foo[1-7]/[1-6]/D_foo/E_foo/text.txt
What I want to do is to cycle through all the 7 top directories and each of their 6 subdirectories (named 1,2,3...6). Furthermore, within these 6 subdirectories, a text file can be found (always with the same filename, text.txt), which contain the data I want to access.
The 'text.txt' files is structured something like this:
1 91.146 4.571 0.064 1.393 939.134 14.765
2 88.171 5.760 0.454 0.029 25227.999 137.883
3 88.231 4.919 0.232 0.026 34994.013 247.058
4 ... ... ... ... ... ...
The table continues down. Every other row is empty. I want to extract information from 13 rows starting from the 8th line, and I'm only interested in the 2nd, 3rd and 5th columns. I want to put them into lists 'parameter_a' and 'parameter_b' and 'parameter_c', respectively. I want to do this from each of these 'text.txt' files (of which there is a total of 7*6 = 42), and append them to three large lists (each with a total of 7*6*13 = 546 items when everything is done).
This is my attempt:
First, I made a list, 'list_B_foo', containing the seven different 'B_foo' directories (this part of the script is not shown). Then I made this:
parameter_a = []
parameter_b = []
parameter_c = []
j = 7 # The script starts reading 'text.txt' after the j:th line.
k = 35 # The script stops reading 'text.txt' after the k:th line.
x = 0
while x < 7:
for i in range(1, 7):
path = str(list_B_foo[x]) + '/%s/D_foo/E_foo/text.txt' % i
m = open(path, 'r')
line = m.readlines()
while j < k:
line = line[j]
info = line.split()
print 'info:', info
parameter_a.append(float(info[1]))
parameter_b.append(float(info[2]))
parameter_c.append(float(info[5]))
j = j + 2
x = x + 1
parameter_a_vect = np.array(parameter_a)
parameter_b_vect = np.array(parameter_b)
parameter_c_vect = np.array(parameter_c)
print 'a_vect:', parameter_a_vect
print 'b_vect:', parameter_b_vect
print 'c_vect:', parameter_c_vect
I have tried to fiddle around with indentation without getting it to work (receiving either syntax error or indentation errors). Currently, I get this output:
info: ['1', '90.647', '4.349', '0.252', '0.033', '93067.188', '196.142']
info: ['.']
Traceback (most recent call last):
File "script.py", line 104, in <module>
parameter_a.append(float(info[1]))
IndexError: list index out of range
I don't understand why I get the "list index out of range" message. If anyone knows why this is the case, I would be happy to hear you out.
How do I solve this problem? Is my approach completely wrong?
EDIT: I went for a pure while-loop solution, taking RebelWithoutAPulse and CamJohnson26's suggestions into account. This is how I solved it:
parameter_a=[]
parameter_b=[]
parameter_c=[]
k=35 # The script stops reading 'text.txt' after the k:th line.
x=0
while x < 7:
y=1
while y < 7:
j=7
path1 = str(list_B_foo[x]) + '/%s/pdata/999/dcon2dpeaks.txt' % (y)
m = open(path, 'r')
lines = m.readlines()
while j < k:
line = lines[j]
info = line.split()
parameter_a.append(float(info[1]))
parameter_b.append(float(info[2]))
parameter_c.append(float(info[5]))
j = j+2
y = y+1
x = x+1
Meta: I am not sure If I should give the answer to the person who answered the quickest and who helped me finish my task. Or the person with the answer which I learned most from. I am sure this is a common issue that I can find an answer to by reading the rules or going to Stackexchange Meta. Until I've read up on the recomendations, I will hold off on marking the question as answered by any of you two.
Welcome to stack overflow!
The error is due to name collision that you inadvertenly have created. Note the output before the exception occurs:
info: ['1', '90.647', '4.349', '0.252', '0.033', '93067.188', '196.142']
info: ['.']
Traceback (most recent call last):
...
The line[1] cannot compute - there is no "1"-st element in the list, containing only '.' - in python the lists start with 0 position.
This happens in your nested loop,
while j < k
where you redefine the very line you read previously created:
line = m.readlines()
while j < k:
line = line[j]
info = line.split()
...
So what happens is on first run of the loop, your read the lines of the files into line list, then you take one line from the list, assign it to line again, and continue with the loop. At this point line contains a string.
On the next run reading from line via specified index reads the character from the string on the j-th position and the code malfunctions.
You could fix this with different naming.
P.S. I would suggest using with ... as ... syntax while working with files, it is briefly described here - this is called a context manager and it takes care of opening and closing the files for you.
P.P.S. I would also suggest reading the naming conventions
Looks like you are overwriting the line array with the first line of the file. You call line = m.readlines(), which sets line equal to an array of lines. You then set line = line[j], so now the line variable is no longer an array, it's a string equal to
1 91.146 4.571 0.064 1.393 939.134 14.765
This loop works fine, but the next loop will treat line as an array of chars and take the 4th element, which is just a period, and set it equal to itself. That explains why the info variable only has one element on the second pass through the loop.
To solve this, just use 2 line variables instead of one. Call one lines and the other line.
lines = m.readlines()
while j < k:
line = lines[j]
info = line.split()
May be other errors too but that should get you started.
I am trying to run the following code:
fname = raw_input ('Enter file name:')
fh = open (fname)
count = 0
for line in fh:
if not line.startswith ('X-DSPAM-Confidence:') : continue
else:
count = count + 1
new = fh #this new = fh is supposed to be fh stripped of the non- x-dspam lines
for line in new: # this seperates the lines in new and allows `finding the floats on each line`
numpos = new.find ('0')
endpos = new.find ('5', numpos)
num = new[numpos:endpos + 1]
float (num)
# should now have a list of floats
print num
The intention of this code is to prompt the user for a file name, open the file, read through the file, compile all the lines that start with X-DSPAM, and extract the float number on these lines. I am fairly new to coding so I realise I may have committed a number of errors, but currently when I try to run it, after putting in the file name I get the return:
I looked around and I have seen that mode 'r' refers to different file modes in python in relation to how the end of the line is handled. However the code I am trying to run is similar to other code I have formulated and it does not have any non-text files inside, the file being opened is a .txt file. Is it something to do with converting a list of strings line by line to a list of float numbers?
Any ideas on what I am doing wrong would be appreciated.
The default mode of handling a file is 'r' - which means 'read', which is what you want. It means the program is going to read the file (as opposed to 'w' - write, or 'a' - append, for example - which would allow you to overwrite the file or append to it, which you don't want in this case).
There are some bugs in your code, which I've tried to indicate in the edited code below.
You don't need to assign new = fh - you're not grabbing lines and passing them to a new file. Rather, you're checking each line against the 'XDSPAM' criteria and if it's a match, you can proceed to parse out the desired numbers. If not, you ignore it and go to the next line.
With that in mind, you can move all of the code from the for line in new to be part of the original if not ... else block.
How you find the end of the number is also a bit off. You set endpos by searching for an occurence of the number 5 - but what I think you want is to find a position 5 characters from the start position (numpos + 5).
(There are other ways to parse the line and pull the number, but I'm going to stick with your logic as indicated by your code, so nothing fancy here.)
You can convert to float in the same statement where you slice the number from the line (as below). It's acceptable to do:
num = line[numpos:endpos+1]
float_num = float(num)
but not necessary. In any event, you want to assign the conversion (float(num)) to a variable - just having float(num) doesn't allow you to pass the converted value to another statement (including print).
You say that you should have 'a list of floats' - the code as corrected below - will give you a display of all the floats, but if you want an actual Python list, there are other steps involved. I don't think you wanted a Python list, but just in case:
numlist = [] # at the beginning, declare a new, empty list
...
# after converting to float, append number to list
XDSPAM.append(num)
print XDSPAMs # at end of program, to print full list
In any event, this edited code works for me with an appropriate file of test data, and outputs the desired float numbers:
fname = raw_input ('Enter file name:')
fh = open (fname)
count = 0
for line in fh:
if not line.startswith ('X-DSPAM-Confidence:') : continue
else:
# there's no need to create the 'new' variable
# any lines that meet the criteria can be processed for numbers
count = count + 1
numpos = line.find ('0')
# i think what you want here is to set an endpoint 5 positions to the right
# but your code was looking for the position of a '5' in the line
endpos = numpos + 5
# you can convert to float and slice in the same statement
num = float(line[numpos:endpos+1])
print num
I've looked at the other questions posted on the site about index error, but I'm still not understanding how to fix my own code. Im a beginner when it comes to Python. Based on the users input, I want to check if that input lies in the fourth position of each line in the list of lists.
Here's the code:
#create a list of lists from the missionPlan.txt
from __future__ import with_statement
listoflists = []
with open("missionPlan.txt", "r") as f:
results = [elem for elem in f.read().split('\n') if elem]
for result in results:
listoflists.append(result.split())
#print(listoflists)
#print(listoflists[2][3])
choice = int(input('Which command would you like to alter: '))
i = 0
for rows in listoflists:
while i < len(listoflists):
if listoflists[i][3]==choice:
print (listoflists[i][0])
i += 1
This is the error I keep getting:
not getting inside the if statement
So, I think this is what you're trying to do - find any line in your "missionPlan.txt" where the 4th word (after splitting on whitespace) matches the number that was input, and print the first word of such lines.
If that is indeed accurate, then perhaps something along this line would be a better approach.
choice = int(input('Which command would you like to alter: '))
allrecords = []
with open("missionPlan.txt", "r") as f:
for line in f:
words = line.split()
allrecords.append(words)
try:
if len(words) > 3 and int(words[3]) == choice:
print words[0]
except ValueError:
pass
Also, if, as your tags suggest, you are using Python 3.x, I'm fairly certain the from __future__ import with_statement isn't particularly necessary...
EDIT: added a couple lines based on comments below. Now in addition to examining every line as it's read, and printing the first field from every line that has a fourth field matching the input, it gathers each line into the allrecords list, split into separate words as a list - corresponding to the original questions listoflists. This will enable further processing on the file later on in the code. Also fixed one glaring mistake - need to split line into words, not f...
Also, to answer your "I cant seem to get inside that if statement" observation - that's because you're comparing a string (listoflists[i][3]) with an integer (choice). The code above addresses both that comparison mismatch and the check for there actually being enough words in a line to do the comparison meaningfully...
I'm working on a simple Python game where the computer tries to guess a number you think of. Every time it guesses the right answer, it saves the answer to a txt file. When the program is run again, it will guess the old answers first (if they're in the range the user specifies).
try:
f = open("OldGuesses.txt", "a")
r = open("OldGuesses.txt", "r")
except IOError as e:
f = open("OldGuesses.txt", "w")
r = open("OldGuesses.txt", "r")
data = r.read()
number5 = random.choice(data)
print number5
When I run that to pull the old answers, it grabs one item. Like say I have the numbers 200, 1242, and 1343, along with spaces to tell them apart, it will either pick a space, or a single digit. Any idea how to grab the full number (like 200) and/ or avoid picking spaces?
The r.read() call reads the entire contents of r and returns it as a single string. What you can do is use a list comprehension in combination with r.readlines(), like this:
data = [int(x) for x in r.readlines()]
which breaks up the file into lines and converts each line to an integer.