I need to generate the following output :
<x:Envelope xmlns:x='namespace1'>
<x:Root xmlns="namespace2">
<Header>
...
</Header>
</x:Root>
</x:Envelope>
I'm having trouble generating the default namespace for the x:Root element using xslt 1.0. I can get it to have no namespace ( but namespace2 will be specified on children of root - undesired behaviour ) or have it with a prefix :
<x:Root xmlns:x="namespace2">
but this fails schema validation. Any ideas ?
Edit : sorry for the ambiguous question and thanks for the answers. Root should be in namespace1 and Header should be in namespace2. However, the request is that namespace2 should not be declared in Header, but at Root level.
Regards,
It depends on how much of this is known statically. If you know everything statically, the literal result element
<x:Root xmlns="namespace2">..</x:Root>
will generate exactly what you want. In the more general case, you need to construct an element containing the required namespace node and then copy the namespace node:
<xsl:param name="ns">namespace2</xsl:param>
<xsl:variable name="temp">
<xsl:element name="dummy" namespace="{$ns}"/>
</xsl:variable>
...
<xsl:element name="Root">
<xsl:copy-of select="xx:node-set($temp)/namespace::*"/>
</xsl:element>
All so much easier in XSLT 2.0 with the xsl:namespace instruction.
You can't map two different namespaces to the same prefix "x". Instead, leave off the prefix for Root all together like this:
<Root xmlns="namespace2">
...
</Root>
Related
In below example which I found on this site, an empty xmlns="" gets copied in all child nodes. What can the reason be for this mistake?
My Template:
<xsl:element xmlns="http://www.element-examples.org" name="{local-name()}">
<xsl:apply-templates select="#*|node()"/>
</xsl:element>
</xsl:template>
OUTPUT:
<projectgegevens xmlns="http://www.element-examples.org">
<idopdracht **xmlns=""**>28062262</idopdracht>
<projectcode **xmlns=""**>160622</projectcode>
<projectnaam **xmlns=""**>FF0000390001</projectnaam>
<ordernummer xmlns="">M2M-2022010071</ordernummer>
<projectleider xmlns="">FF000039003</projectleider>
<opmerking xmlns=""></opmerking>
<status xmlns="">5</status>
<datumverwacht xmlns="">2022-06-29</datumverwacht>
<certificaatnummer xmlns="">2020083810</certificaatnummer>
<analysemonsters xmlns="">
We can't tell you specifically what you did wrong without seeing all your code, but the namespace declaration xmlns="" is generated by the serializer when it finds that the result tree has an element in no namespace, whose parent is in a namespace (but with no prefix).
To find out why the child elements are in no namespace, rather than in the same namespace as their parent, you need to look at the XSLT code that creates the child elements. Note that the namespace of an element is determined entirely by the instruction that creates the element; it is never inherited automatically from the namespace of its parent element in the result tree (though it may be inherited from the parent element in the stylesheet).
I need to pass a node as a parameter to an XSL stylesheet. The issue is that the parameter gets sent as a string. I have seen the several SO questions regarding this topic, and I know that the solution (in XSLT 1.0) is to use an external node-set() function to transform the string to a node set.
My issue is that I am using eXist DB I cannot seem to be able to get its XSLT processor to locate any such function. I have tried the EXSLT node-set() from the namespace http://exslt.org/common as well as both the Saxon and Xalan version (I think eXist used to use Xalan but now it might be Saxon).
Are these extensions even allowed in the XSLT processor used by eXist? If not, is there something else I can do?
To reference or transform documents from the database, you should pass the path as a parameter to the transformation, and then refer to it using a parameter and variable
(: xquery :)
let $path-to-document := "/db/test/testa.xml"
let $stylesheet :=
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:param name="source" required="no"/>
<xsl:variable name="error"><error>doc not available</error></xsl:variable>
<xsl:variable name="theDoc" select="if (doc-available($source)) then doc($source) else $error"/>
<xsl:template match="/">
<result><xsl:value-of select="$source"/> - <xsl:value-of select="node-name($theDoc/*)"/></result>
</xsl:template>
</xsl:stylesheet>
return transform:transform(<dummy/>,$stylesheet, <parameters><param name="source" value="xmldb:exist://{$path-to-document}"/></parameters>)
As per Martin Honnen's comments I don't think it is possible to pass an XML node via the <parameters> structure of the transform:transform() function in eXist. The function seems to strip away any XML tags passed to it as a value.
As a workaround I will wrap both my input XML and my parameter XML into a root element and pass that as input to the transform function.
Is it possible to get template name while inside template?
Example:
<xsl:template name="list">
<!-- Get name value (in this case "list") -->
</xsl:template>
As far as I am aware, neither XSLT 1.0 nor XSLT 2.0 offer such a feature.
As Martin says, there's probably no way to do this.
Even if such a capacity existed, surely using it couldn't be any simpler than just defining a variable with the value you want:
<xsl:template name="list">
<xsl:variable name="class" select="'list'" />
and then using that variable where you need it. This also has the benefit that you can change the template name without rewriting all your CSS, or change the class name without rewriting your XSLT.
One of the benefits of the fact that XSLT uses XML syntax is that it's easy to transform stylesheets. Modifying every named template to contain a variable holding the template name is dead easy.
#JLRishe's answer is a good approach. However, there is a trap. Any <xsl:param> must be declared before any <xsl:variable>.
This will not work:
<xsl:template name="foobarsnafu">
<xsl:variable name="foo" value="bar">
<xsl:param name="snafu"/>
But this will:
<xsl:template name="foobarsnafu">
<xsl:param name="snafu"/>
<xsl:variable name="foo" value="bar">
This might be a problem if, for example, you want the default value of your snafu <xsl:param> to be the value of your foo <xsl:variable>. The way around it would be to use <xsl:param> with a default value for your template name, i.e.:
<xsl:template name="foobarsnafu">
<xsl:param name="template_name" select="foobarsnafu"/>
I'm processing an XMI document exported from ArgoUML. It has elements of the form
<UML:DataType href='http://argouml.org/profiles/uml14/default-uml14.xmi#-84-17--56-5-43645a83:11466542d86:-8000:000000000000087C'/>
which points to an item of the form
<UML:DataType xmi.id="-84-17--56-5-43645a83:11466542d86:-8000:000000000000087C"
name="Integer"
isSpecification="false"
isRoot="false"
isLeaf="false"
isAbstract="false"/>
I've already declared xmlns:UML="org.omg.xmi.namespace.UML" at the top of the xslt file. I think I should be using something like :
<xsl:variable name="typeref" select="#href"/>
<xsl:variable name="ns" select='substring-before($typeref, "#")'/>
<xsl:variable name="identifier" select='substring-after($typeref, "#")'/>
<xsl:value-of xmlns:UML="$ns"
select='//UML:DataType[#xmi.id="$identifier"]/#name'/>
to deduce that my UML attributes type is Integer but this gives me
SystemId Unknown; Line #136; Column #94; A location step was expected following the '/' or '//' token.
If I change the xmlns to AAA then I get no error but an empty tag. I'm using Xalan2 on Debian squeeze. What am I missing?
Don't mind me. Just making the classic mistake of conflating namespaces and URIs. What I really needed was <xsl:value-of select='document($ns)//UML:DataType[#xmi.id=$identifier]/#name'/>
Greetings!
I want to extract some properties from different Maven POMs in a XSLT via the document function. The script itself works fine but the document function returns an empty result for the POM as long as I have the xmlns="http://maven.apache.org/POM/4.0.0" in the project tag. If I remove it, everything works fine.
Any idea how the make this work while leaving the xmlns attribute where it belongs or why this doesn't work with the attribute in place?
Here comes the relevant portion of my XSLT:
<xsl:template match="abcs">
<xsl:variable name="artifactCoordinate" select="abc"/>
<xsl:choose>
<xsl:when test="document(concat($artifactCoordinate,'-pom.xml'))">
<abc>
<ID><xsl:value-of select="$artifactCoordinate"/></ID>
<xsl:copy-of select="document(concat($artifactCoordinate,'-pom.xml'))/project/properties"/>
</abc>
</xsl:when>
<xsl:otherwise>
<xsl:message terminate="yes">
Transformation failed: POM "<xsl:value-of select="concat($artifactCoordinate,'-pom.xml')"/>" doesn't exist.
</xsl:message>
</xsl:otherwise>
</xsl:choose>
And, for completeness, a POM extract with the "bad" attribute:
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
<modelVersion>4.0.0</modelVersion>
<!-- ... -->
<properties>
<proalpha.version>[5.2a]</proalpha.version>
<proalpha.openedge.version>[10.1B]</proalpha.openedge.version>
<proalpha.optimierer.version>[1.1]</proalpha.optimierer.version>
<proalpha.sonic.version>[7.6.1]</proalpha.sonic.version>
</properties>
</project>
Your problem is that the POM extract uses default namespace. This means that the elements, although unprefixed, are in the "http://maven.apache.org/POM/4.0.0" -- not in the "no namespace".
However, in this XPath expression, in the XSLT code:
document(concat($artifactCoordinate,'-pom.xml'))/project/properties
the names project and properties are unprefixed. XPath always treats unprefixed names as belonging to "no namespace". Hence, no such elements are found and no node is selected.
Solution: Add a namespace definition to your <xsl:stylesheet>, lets say:
xmlns:p="http://maven.apache.org/POM/4.0.0"
Then rewrite element names in any expressions referencing POM nodes from someElement to p:someElement. For example:
document(concat($artifactCoordinate,'-pom.xml'))/p:project/p:properties
This is a namespace problem. The xmlns="http://maven.apache.org/POM/4.0.0" in the source document means that all the elements are by default put into the "http://maven.apache.org/POM/4.0.0" namespace in the XML document.
If you want to get ahold of them in your xslt, you need to declare that namespace in your xslt (with or without a prefix to use) and then use that namespace when selecting your elements.
For example, I'm guessing that the template in your example is meant to match an "abcs" element in your POM, yes? Try adding a namespace declaration in your xsl:stylesheet, e.g.:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:pom="http://maven.apache.org/POM/4.0.0" version="1.0">
That says to the XSL "I want to add 'pom' as a prefix that identifies the 'http://maven.apache.org/POM/4.0.0' namespace in this document."
Then when selecting elements or matching templates, use that prefix, e.g.:
<xsl:template match="pom:abcs">
Or try it without the prefixes by declaring your stylesheet with the POM namespace as default, something like:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="http://maven.apache.org/POM/4.0.0" version="1.0">
Node can (if using XSLT 2.0+) also be adressed via * because they lie in another namespace .
<xsl:copy-of select="document(concat($artifactCoordinate,'-pom.xml'))/*:project/*:properties)"/>
This can be just convienent or especially useful if the namespace is unknown. In this case the nice side effect is that if the namespace is marked this way the nodes from the other namespace don't get an annotation - which is not wanted in our case.