XSLT transform a document with group element - xslt

Question

I have a document like this:
<?xml version="1.0" encoding="UTF-8"?>
<document>
<data attribute1="12" attribute2="1" attribute3="1">Director</data>
<data attribute1="12" attribute2="1" attribute3="5">James</data>
<data attribute1="12" attribute2="1" attribute3="8">Male</data>
<data attribute1="12" attribute2="1" attribute3="9">10-Dec-1965</data>
<data attribute1="12" attribute2="2" attribute3="18">James#gmail.com</data>
<data attribute1="12" attribute2="2" attribute3="1">Chief Account</data>
<data attribute1="12" attribute2="2" attribute3="5">Anna</data>
<data attribute1="12" attribute2="2" attribute3="8">Female</data>
<data attribute1="12" attribute2="1" attribute3="9">5-Aug-1980</data>
<data attribute1="12" attribute2="2" attribute3="18">Anna#gmail.com</data>
</document>
I want to transform it to this:
<Person>
<Title>Director</Title>
<FullName>James</FullName>
<Gender>Male</Gender>
<DateOfBirth>10-Dec-1965</DateOfBirth>
<EmailAddress>James#gmail.com</EmailAddress>
</Person>
<Person>
<Title>Chief Account</Title>
<FullName>Anna</FullName>
<Gender>Female</Gender>
<DateOfBirth>5-Aug-1980</DateOfBirth>
<EmailAddress>Anna#gmail.com</EmailAddress>
</Person>
I am using this xslt:
<xsl:for-each select="document/data[#attribute1=12]">
<Person>
<xsl:choose>
<xsl:when test="boolean(./#attribute3 = '1')">
<Title>
<xsl:value-of select="./."/>
</Title>
</xsl:when>
<xsl:when test="boolean(./#attribute3 = '5')">
<FullName>
<xsl:value-of select="./."/>
</FullName>
</xsl:when>
<xsl:when test="boolean(./#attribute3 = '8')">
<Gender>
<xsl:value-of select="./."/>
</Gender>
</xsl:when>
<xsl:when test="boolean(./#attribute3 = '9')">
<DateOfBirth>
<xsl:value-of select="./."/>
</DateOfBirth>
</xsl:when>
<xsl:when test="boolean(./#attribute3 = '18')">
<EmailAddress>
<xsl:value-of select="./."/>
</EmailAddress>
</xsl:when>
</xsl:choose>
</Person>
</xsl:for-each>
The problem is that I get the following output, where the <Person> tag is duplicated.
<Person>
<Title>Director</Title>
</Person>
<Person>
<FullName>James</FullName>
</Person>
<Person>
<Gender>Male</Gender>
</Person>
<Person>
<DateOfBirth>10-Dec-1965</DateOfBirth>
</Person>
<Person>
<EmailAddress>James#gmail.com</EmailAddress>
</Person>
<Person>
<Title>Chief Account</Title>
</Person>
<Person>
<FullName>Anna</FullName>
</Person>
<Person>
<Gender>Female</Gender>
</Person>
<Person>
<DateOfBirth>5-Aug-1980</DateOfBirth>
</Person>
<Person>
<EmailAddress>Anna#gmail.com</EmailAddress>
</Person>
Could anyone help me solving this problem? Thank you!

Answer 1

It looks like you wish to create a new Person element for each data element with an attribute3 value of 1. Rather than iterate over all data elements as you are currently doing, just select the elements with the relevant attribute
<xsl:apply-templates select="data[#attribute3='1']"/>
Then, you would have a template to output the Person element only for these data elements.
<xsl:template match="data[#attribute3='1']">
<Person>
<Title><xsl:value-of select="." /></Title>
<!-- Select other elements here -->
</Person>
</xsl:template>
Now, to get the other elements, another way to achieve this is to make use of a key. Effectively, you will group the data elements by the first most preceding data element with an attribute3 value of "1".
<xsl:key name="data"
match="data[#attribute3 != '1']"
use="generate-id(preceding-sibling::data[#attribute3 = '1'][1])" />
Then, to select the other elements, you can use this key, using the unique ID of the current data element as the lookup.
<xsl:apply-templates select="key('data', generate-id())" />
This would only select the data elements that make up that particular person element. You would then have template to match the other data elements for each possible attribute value:
Try this XSLT :
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:key name="data" match="data[#attribute3 != '1']" use="generate-id(preceding-sibling::data[#attribute3 = '1'][1])" />
<xsl:template match="document">
<xsl:apply-templates select="data[#attribute3='1']"/>
</xsl:template>
<xsl:template match="data[#attribute3='1']">
<Person>
<Title><xsl:value-of select="." /></Title>
<xsl:apply-templates select="key('data', generate-id())" />
</Person>
</xsl:template>
<xsl:template match="data[#attribute3='5']">
<FullName><xsl:value-of select="." /></FullName>
</xsl:template>
<xsl:template match="data[#attribute3='8']">
<Gender><xsl:value-of select="." /></Gender>
</xsl:template>
<xsl:template match="data[#attribute3='9']">
<DateOfBirth><xsl:value-of select="." /></DateOfBirth>
</xsl:template>
<xsl:template match="data[#attribute3='18']">
<EmailAddress><xsl:value-of select="." /></EmailAddress>
</xsl:template>
</xsl:stylesheet>

Answer 2

Here is my suggestion based on the position of elements:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:param name="size" select="5"/>
<xsl:template match="document">
<Persons>
<xsl:apply-templates select="data[position() mod $size = 1]" mode="group"/>
</Persons>
</xsl:template>
<xsl:template match="data" mode="group">
<Person>
<xsl:apply-templates select=". | following-sibling::data[position() < $size]"/>
</Person>
</xsl:template>
<xsl:template match="data[#attribute3 = '1']">
<Title>
<xsl:value-of select="."/>
</Title>
</xsl:template>
<xsl:template match="data[#attribute3 = '5']">
<FullName>
<xsl:value-of select="."/>
</FullName>
</xsl:template>
<xsl:template match="data[#attribute3 = '8']">
<Gender>
<xsl:value-of select="."/>
</Gender>
</xsl:template>
<xsl:template match="data[#attribute3 = '9']">
<DateOfBirth>
<xsl:value-of select="."/>
</DateOfBirth>
</xsl:template>
<xsl:template match="data[#attribute3 = '18']">
<EmailAddress>
<xsl:value-of select="."/>
</EmailAddress>
</xsl:template>
</xsl:stylesheet>