Easily rename Django project - django

Is there an easy way to rename a project? I tried to rename the folder, but it didn't work.

Renaming the project is actually easier than renaming an app. This question explains how to rename an app.
To rename the project, you need to change the project name wherever it appears. grep -nir oldname . can help you find where it appears. In my case, I had to change the following places:
Rename the oldprojectname directory to newprojectname
manage.py: Change os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'oldprojectname.settings')
newprojectname/wsgi.py: Change os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'oldprojectname.settings')
newprojectname/settings.py: Change ROOT_URLCONF = 'oldprojectname.urls' and change WSGI_APPLICATION = 'oldprojectname.wsgi.application'
newprojectname/urls.py: Change oldprojectname in a line I had added

very simple and efficient
add this command to any app in your project like this ,
# app/management/commands/renameproject.py
import os
import glob
from django.conf import settings
from django.core.management.base import BaseCommand, CommandError
class Command(BaseCommand):
help = 'Renames the Project'
def add_arguments(self, parser):
parser.add_argument('old', nargs='+', type=str, help="current project name")
parser.add_argument('new', nargs='+', type=str, help="new project name")
def handle(self, *args, **options):
old = options["old"][0]
new = options["new"][0]
base = str(settings.BASE_DIR)
projectfiles = []
managefile = os.path.join(base, "manage.py")
projectfiles.append(managefile)
projectfiles += glob.glob(os.path.join(base, old, "*.py"))
projectfiles += glob.glob(os.path.join(base, old, "**", "*.py"))
for pythonfile in projectfiles:
with open(pythonfile, 'r') as file:
filedata = file.read()
filedata = filedata.replace(old, new)
with open(pythonfile, 'w') as file:
file.write(filedata)
os.rename(os.path.join(base, old), os.path.join(base, new))
Now just run this command
python manage.py renameproject oldname newname
have fun 😎
How it works:
Searches .py files across the project and replaces the old name with
new.

To rename a Django project, you need to change the project name wherever it appears.
First of all, rename both outer and inner project directory name from old_project_name to new_project_name
So if the project directory looks like this :
old_project_name // outer project directory old name
old_project_name// inner project directory old name
--__init__.py
--asgi.py
--settings.py
--urls.py
--wsgi.py
app_name // any app u created in the project
db.sqlite3
manage.py
then change to this :
new_project_name // outer project directory new name
new_project_name// inner project directory new name
--__init__.py
--asgi.py
--settings.py
--urls.py
--wsgi.py
app_name // any app u created in the project
db.sqlite3
manage.py
In 2021 with Django version 3.2.3, there are in total 9 places (including comments and codes both) in 5 files where the name of the project appears, which are :
In new_project_name/asgi.py file (comment) :
ASGI config for old_project_name project.
In new_project_name/asgi.py file (code) :
os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'old_project_name.settings')
In manage.py file (code) :
os.environ.setdefault('DJANGO_SETTINGS_MODULE', old_project_name.settings')
In new_project_name/settings.py file (comment) :
Django settings for old_project_name project.
In new_project_name/settings.py file (code) :
ROOT_URLCONF = 'old_project_name.urls'
In new_project_name/settings.py (code) :
WSGI_APPLICATION = 'old_project_name.wsgi.application'
In new_project_name/urls.py file (comment) :
old_project_name URL Configuration
In new_project_name/wsgi.py file (comment) :
WSGI config for old_project_name project.
In new_project_name/wsgi.py file (code) :
os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'old_project_name.settings')
Note : To change the old_project_name to new_project_name in the files you can use your IDE 's/ text editor's find & replace function to avoid any errors.
Tip : If you haven't done much work in the project then its better to create a new Django project and then just copy and paste the code which don't need any changes rather than changing project name.

I think the best solution here is to simply open your settings.py, urls.py, views.py and any other file that might rely on your project's name and then use the find&replace function in your text editor.
Or, if you haven't done much work yet, start a new project with django-admin.py and copy/paste.

As a beginner with Python and Django, the below simple steps worked for me.
Update both outer and inner folder names in your project (directly from windows explorer or from any editor like visual studio)
Search and replace your old project name with new one in below project files
a. manage.py
b. settings.py
c. wsgi.py
d.asgi.py
e. urls.py
Restart server and confirm if everything works fine again

Actually what you have to do is this:
Open your project in any code editor like Sublime or VSCode
Search for your current project name
In the replace box enter the new project folder name that you want.
Now the code editor will automatically search in the whole project folder and will replace the current project name with the new name.
Now just rename the main app name which is in your project folder
You can now rename your project folder name
Thats it. Hope that helps :)

Suppose your project name is old_project_name and you want to change it to new_project_name. Also you have created an app called my_app within old_project_name. Your directory structure will be something like -
old_project_name
--old_project_name
--__init__.py
--settings.py
--urls.py
--wsgi.py
my_app
--Files and folders under my_app
db.sqlite3
manage.py
Rename both inner and outer old_project_name directory name to new_project_name. After changing your directory structure will be as something like -
new_project_name
--new_project_name
--__init__.py
--settings.py
--urls.py
--wsgi.py
my_app
--Files and folders under my_app
db.sqlite3
manage.py
Change reference to old_project_name in your project files to new_project_name. Mostly you will need to change the reference in settings.py, wsgi.py and manage.py
After these changes run local server and check if your routes are working fine.
Change git repository name. This is optional, but it is advisable as it will be easy to track your projects. If you have added your project to bitbucket or github, then login into bitbucket or github and change the repository name to new_project_name. Suppose your old repository url is https://<yourusername>#bitbucket.org/<yourusername>/old_project_name.git
After renaming repository, your project git url will be changed to something like https://<yourusername>#bitbucket.org/<yourusername>/new_project_name.git>
Run in terminal
git remote -v
it will list your current remote repository url
origin https://<yourusername>#bitbucket.org/<yourusername>/old_project_name.git(fetch)
origin https://<yourusername>#bitbucket.org/<yourusername>/old_project_name.git(push)
Run following command in terminal. This will change your current remote repository url
git remote set-url origin https://<yourusername>#bitbucket.org/<yourusername>/new_project_name.git
Run in terminal
git remote -v
It will now list something like
origin https://<yourusername>#bitbucket.org/<yourusername>/new_project_name.git(fetch)
origin https://<yourusername>#bitbucket.org/<yourusername>/new_project_name.git(push)
Now you can push your new updates to your remote repository.
Update virtual environment. This is optional,but it will help to identify virtual environ mapping to project. I use virtualenvwrapper. If you are using a different one, you will have to update the commands as per your virtual environment.
Run following command in terminal. This will create a copy of old_project_name environment setting with name new_project_name.
cpvirtualenv old_project_name new_project_name
Remove old environment. This step is optional as well.
Run following command in terminal
rmvirtualenv old_project_name

Related

How to run django.setup() properly from within a stand-alone python file inside of a django app (on linux-ubuntu)?

Im trying to run a stand-alone python file in a django project. The problematic code is below (standalone.py):
import os
import django
# os.environ.setdefault("DJANGO_SETTINGS_MODULE", "myproject.settings") tried as well
os.environ["DJANGO_SETTINGS_MODULE"] = "myproject.settings"
django.setup()
The error i receive is: 'No module named myproject.settings'. Somehow the project settings file is not being recognized.
The file runs just fine on my local machine however the problem occurs when running the file on a linux-ubuntu server.
This file is being run from within an app: myproject>myapp>standalone.py
When i move this file to the same directory that myproject resides in, the file runs just fine, so im assuming that the myproject.settings module is not being recognized from within the app directory.
As a temp fix:
sys.path.append('path_to_myproject/')
seems to resolve the issue, but definitely not something i want in production code. Any suggestions on how to resolve this issue? Thanks in advance
If the settings module is myproject.settings, then the outer myproject directory must be on the python path. If the script is in the outer myproject directory (the one that contains manage.py) then you don't need to do anything because the current directory is on the path. Otherwise, you have to manually add the directory to the python path.
The way to add something to the python path is sys.path.append(), so you can't avoid having that in production code (unless you use the PYTHONPATH environment variable instead). Perhaps you would be happier with adding the parent directory instead of hardcoding the path.
sys.path.append('..')

How do I find my project name in a Django project?

I have a pycharm project and, presumably, a Django project. Perhaps they are one and the same, perhaps not - I'm unsure as to the distinction.
Anyway, in my settings.py file (which is in the root of project directory, which is what I presume is my pycharm project) I have:
ROOT_URLCONF = 'dumpstown.urls'
Does that mean dumpstown is my project name? Or my pycharm project name? What is the distinction? Because I also have a folder called dumpstownapp and this has all my models.py and view.py files. I would have thought that dumpstownapp was the Django project, but I really don't know!
So, to be concise:
In this folder setup
folderA
folderB
views.py
models.py
<other stuff>
templates folder
settings.py
<other stuff>
which is the "Django project name" ~ and by that I mean, if I have a UserProfile defined in my models.py (shown above) what would be the AUTH_PROFILE_MODULE entry I'd need for it? I'm getting several understandings from the django docs - I'd assume
dumpstownapp.models.UserProfile
But from the docs I'd get
dumpstownapp.UserProfile
Or maybe my app is called dumpstown? and then what do I get?
FolderA is the Django project folder, and folderB is the Django app folder.
I haven't used a UserProfile, but according to the docs ( https://docs.djangoproject.com/en/dev/topics/auth/#storing-additional-information-about-users) it should contain a string containing the Django app name and the model name separated by a dot, so "dumpstownapp.UserProfile" should be correct. If you show the error someone can probably give you better help..
Django documentation used to say that the parent of the project folder (i.e. the parent of folderA) should be on the path, but I believe that has been changed to also include the project folder itself (i.e. folderA) -- since it makes sharing of Django apps much easier. PyCharm seems to assume that is the case, since pressing Alt+F7 to auto-add an import for a newly used module create an import statement that assumes folderA is on the import path (I'm a relative newcomer to PyCharm, and I'm using it on a project that started in the Django 0.96 era, so I might just have things set up wrong..) But folderA is both the Django and the PyCharm project (the .idea file is where PyCharm stores its project data).
In one of my django-app git-submodule projects I needed to find out the name of the Django project that django-app/library was used in. To that end, I tried to get the path of the file that was being executed, find my package in the path and take the folder above it. However, it turned out that on the production server the project was deployed in a folder with a different name (a standard name like www or something along those lines). So this way is not fully reliable.
So I ended up setting a PROJECT variable in the django settings file and using that instead.

Using a settings file other than settings.py in Django

I want to use a different settings file in django -- specifically settings_prod -- yet whenever I try to do a syncdb with --settings=settings_prod, it complains:
python2.6 manage.py syncdb --settings=settings_prod
Error: Can't find the file 'settings.py' in the directory containing 'manage.py'. It appears you've customized things.
You'll have to run django-admin.py, passing it your settings module.
(If the file settings.py does indeed exist, it's causing an ImportError somehow.)
I've also tried setting the environment variable DJANGO_SETTINGS_MODULE=settings_prod to no end.
Edit: I have also set the environment variable in my wsgi file, also to no end:
import os
import sys
from django.core.handlers.wsgi import WSGIHandler
os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings_prod'
application = WSGIHandler()
Suggestions?
Try creating a settings module.
Make a settings folder in the same directory as manage.py.
Put your different settings files in that folder (e.g. base.py and prod.py).
Make __init__.py and import whatever settings you want to use as your default. For example, your __init__.py file might look like this:
from base import *
Run your project and override the settings:
$ python2.6 manage.py syncdb --settings=settings.prod
I do know that no matter what you do with manage.py, you're going to get that error because manage.py does a relative import of settings:
try:
import settings # Assumed to be in the same directory.
http://docs.djangoproject.com/en/dev/ref/django-admin/#django-admin-option---settings
Note that this option is unnecessary
in manage.py, because it uses
settings.py from the current project
by default.
You should try django-admin.py syncdb --settings=mysettings instead
this works for me:
DJANGO_SETTINGS_MODULE=config.settings.abc python manage.py migrate
this will help you:
create a another file "setting_prod.py" with your original settings.py file.
write down your setting which you need to run, in setting_prod.py file.
Then import setting_prod.py file in your settings.py file.
for ex.
settings.py:
VARIABLE = 1
import setting_prod
setting_prod.py
VARIABLE = 2
After importing setting_prod.py file in settings.py file, VARIABLE will set to new value to "2" from "1".
We can use this method to set different settings file, for example, I use different settings file for my unit test (settings_unit_test.py). Also I do have other settings file for different infrastructure environment settings_dev.py, settings_test.py and settings_prod.py.
In windows environment(same can done in linux as well)
set DJANGO_SETTINGS_MODULE=settings_unit_test
set PYTHONPATH=<path_of_your_directory_where_this_file_'settings_unit_test.py'_is_kept>

How to copy a django project from one folder location to another?

Am using eclipse+pydev to build my django apps. I created a new workspace, built a new pydev project then created an empty folder in the new pydev project. In that empty folder i imported my old django application. Eclipse copied all the files & folders from my old django location to the new workspace.
I made the necessary changes in the settings.py on my new location, pointed the templates & data location to my new location workspace folder.
But when i run manage.py runserver from the new location workspace folder, django seems to point to my old folder location. All the html templates seems to point to the old location.
How can i make django execute stuff in my new location?
What am i missing?
Edit:
When i run the server inside eclipse, everything seems to be OK! funny.
Gath
There is no reason why you could not move your django folder, except for the presence of some absolute file path that you added. You should never have an absolute path in your project.
You should use the following trick in the settings.py file, as explained in the django wiki:
import os
BASE_DIR = os.path.dirname(os.path.abspath(__file__))
# then for each subdirectory:
SOME_DIR = os.path.join(BASE_DIR, 'my_dir')
Then you can move your whole project without ever changing a single character inside.
I agree that something seems odd. Not hardcoding your paths is of course the first place to start. One other possible cause of the error could be that you have added your original project/app to the PYTHONPATH and that it gets imported from there instead of the new place.
If being on a *NIX-system you could symlink your old location to the Eclipse workspace.

Django sys.path.append for project *and* app needed under WSGI

Could somebody give me a pointer on why I need to add my project root path to the python path as well as the application itself in my WSGI file?
Project base is called 'djapp', the application is called 'myapp'.
sys.path.append(os.path.dirname(os.path.abspath(__file__)) + '/..')
sys.path.append(os.path.dirname(os.path.abspath(__file__)) + '/../djapp')
os.environ['DJANGO_SETTINGS_MODULE'] = 'djapp.settings'
If I omit the line with "/../djapp/" the log tells my that 'myapp' can not be imported, even though 'djapp.settings' is. (validating 'djapp' was imported)
It al runs properly with the ./manage.py command. there's a __init__ in the project folder.
For testings sake, I see the same issue using addsitedir:
site.addsitedir('/home/user/web/project/')
site.addsitedir('/home/user/web/project/djapp')
Since djapp (the django project folder) is in a parent folder that also belongs to the deployment I renamed the djapp folder simply to project.
Then this code is always correct:
sys.path.append(os.path.dirname(os.path.abspath(__file__)) + '/..' )
sys.path.append(os.path.dirname(os.path.abspath(__file__)) + '/../project')
os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings'
The complete folder layout being:
host.example.com\
etc\
bin\
project\
logs\
And what have you. This way project can always be called project :)
Hope that helps.
GrtzG
Presumably you've got code within your project which is doing from myapp import foo.
Two options:
change that to from djapp.myapp import foo, which is not recommended as it prevents portability;
only add djapp in your WSGI, and set the DJANGO_SETTINGS_MODULE to just 'settings'.