Extract matched strings in C++ with regex - c++

Question

I have following test strings.
#5=BUILDING('xxxcdccx',#5,$,$,$,#21,$,$,.ELEMENT.,$,$,$);
#6=BUILDING('xxxcdccx',#5,$,$,$,#21,$,$,.ELEMENT.,$,$,$);
#7=BUILDING('xxxcdccx',#5,$,$,$,#21,$,$,.ELEMENT.,$,$,$);
I need to extract:
"#integer" (that always starts at the beginning of the string) from above strings and store it in a variable.
the string between "(" and ")" from above test string.
Can someone please suggest how I can achieve this in C++ with regex.
I tried following as simple example (it's a loop that processes one line at a time):
std::regex e ("\#[:d:]+");
if (std::regex_match(sLine,e)){
//store it and process it
}
output should be:
#5
and
'xxxcdccx',#5,$,$,$,#21,$,$,.ELEMENT.,$,$,$ ?? (not sure)

Answer 1

Description
This expression will:
capture the initial # and integer
capture the value between the parentheses
^(\#\d+).*?\(([^)]*)\)
Example
Live Demo
Sample Text
#5=BUILDING('xxxcdccx',#5,$,$,$,#21,$,$,.ELEMENT.,$,$,$);
#6=BUILDING('xxxcdccx',#5,$,$,$,#21,$,$,.ELEMENT.,$,$,$);
#7=BUILDING('xxxcdccx',#5,$,$,$,#21,$,$,.ELEMENT.,$,$,$);
Capture Groups
Group 0 gets the entire matched string
Group 1 gets the # and integer
Group 2 gets the value between the parentheses
[0][0] = #5=BUILDING('xxxcdccx',#5,$,$,$,#21,$,$,.ELEMENT.,$,$,$)
[0][1] = #5
[0][2] = 'xxxcdccx',#5,$,$,$,#21,$,$,.ELEMENT.,$,$,$
[1][0] = #6=BUILDING('xxxcdccx',#5,$,$,$,#21,$,$,.ELEMENT.,$,$,$)
[1][1] = #6
[1][2] = 'xxxcdccx',#5,$,$,$,#21,$,$,.ELEMENT.,$,$,$
[2][0] = #7=BUILDING('xxxcdccx',#5,$,$,$,#21,$,$,.ELEMENT.,$,$,$)
[2][1] = #7
[2][2] = 'xxxcdccx',#5,$,$,$,#21,$,$,.ELEMENT.,$,$,$