I am trying to find a piece of regex to match a currency value.
if the price is 1000 in USD then need to validate in the format 1,000.00 or 1,000 But in the case of German it is opposite like 1.000,00 or 1.000 I need to validate the entered amount is in usd format or german format.user can enter with or without decimal.
If you need to process such information, why not parseCurrency() function? Should there be any error it will yield false.
Regular expression, I think in this case at least, should be avoided since there is functionality which is already provided.
That being said, you could use something like so (^\d{1,3}(,\d{3})*(\.\d{2})?)$|(^\d{1,3}(\.\d{3})*(,\d{2})?$).
Related
I need a regex pattern for minimum currency, in this instance, so a number under $1000.00 cannot be input into the field. only $1000.00 and up to say $9999.00. This is for a DocuSign Template.
Number 1., The one-time transfer amount from the screenshot must be 1000.00 or higher.
Number 2., The monthly selection must be $100.00 or more.
Here is what I currently have to make them input it in Monetary form. I am struggling with adding the currency thresholds/minimums described above.
^[+-]?[0-9]{1,3}(?:,?[0-9]{3})*\.[0-9]{2}$
I am a novice at best so thank you for any help in advance.
I'm thinking you want something along these lines for 100.00 to 9999.99 you would want a different regex per field.
^[1-9]\d{2,3}\.\d{2}$
https://regex101.com/r/K2SnS7/1
Check that out and play with it. You just need to think in a regex manner, what are the values I can have first, probably not zero. So 1 to 9, with between two and three more numbers. Followed by a decimal and any two numbers. Good luck!
I am fairly new to RegEx and have had a search around online but am unable to find a regex that fits my requirements.
The ultimate aim is to search a string of text and extract the lowest monetary amount, however as the string may contain more than one £amount, then i'm happy for a regex to just extract all monetary values it can find and then I can write a calculation in order to return the lowest amount.
The string may have numbers that are not monetary values / numerous amounts, therefore the regex should always look for a £ symbol first OR it could end with a "p" or "P" to signify pence. For example "I need 2 of these at £10 each and one of those at 50p" - should return 10.00 & 0.50 - I can then calculate that 0.50 is the lowest amount.
As people also write their amounts in various ways, I need the regex to be able to spot different patterns - including the "," for every thousand. All below values should be valid:
£0
£0.00
£0.00p
£0000
£0000.00
£0000.00p
£0,000
£0,000.00
£0,000.00p
0p
Hopefully someone may be able to advise the best way to approach this.
Thanks
This works on your data set:
(?=^£|.*p$)£?\d*(?:,\d{3})*(\.\d{2})?p?
But it may improperly match some edge cases as well because everything is optional...
https://regex101.com/r/WptUn6/3
I am using a regular expression to match all UK bank card number formats; I have done research and managed to find/amend a regex that covers the majority of formats. However, I have a bit of an edge case where one is not matching and I do not know why, or how to resolve. This is what I am using:
(\b[4|5|6](\d){3}[\s|-]?((\d){4}[\s|-]?){2}(\d){4}\b)|(\b(\d){4}[\s|-]?(\d){6}[\s|-]?(\d){5}\b)
This is an example card number that does not work: 6759000000005
This is an example card number that does work: 675900000000555
Apologies if this is an easy question, I am fairly new to regular expression syntax. Any help to resolve would be greatly appreciated. Thanks.
See here the demo
The regex is (\b[4|5|6]\d{3}[\s-]?(\d{4}[\s-]?){2}\d{1,4}\b)|(\b\d{4}[\s-]?\d{6}[\s-]?\d{5}\b)
I'm not an expert of UK cards, so I can't tell what is the expected format as you did not gave exemples with spaces or hyphens in them...
If you can refine the requirements it's handlable.
A more generic card number validation (without separators, so you'll need to strip them before) would be
\d{6}\d{1,12}\d
As per the requirements of the norm (found nothing on the minimum length of the account identifier):
An ISO/IEC 7812 card number is most commonly 16 digits in length,[1]
and can be up to 19 digits. The structure is as follows:
a six-digit Issuer Identification Number (IIN) (previously called the
"Bank Identification Number" (BIN)) the first digit of which is the
Major Industry Identifier (MII), a variable length (up to 12 digits)
individual account identifier, a single check digit calculated using
the Luhn algorithm.[2]
I need an expression for the form yyyy-mm-dd(like date format), and I used regular expression : ^(19|20)\d\d[- /.](0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])$
But it only includes date till year 2099 but it is not the requirement, how to increase the upper limit to more ? Like 3000-01-01, 5000-01-01... etc
You need something like this:
^\d{4}[- /.](0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])$
I did not test it...
The problem lies with the "19|20" you see at the beginning. That's saying that the year must start with 19 or 20. You can generalize with by substituting (19|20) with \d\d which is to say any two digits are allowed. So the following:
^\d\d\d\d[- /.](0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])$
Whether this is acceptable or not is entirely up to you, though the more flexible you are with these sorts of things, the easier it is for a user to insert a value which they probably didn't mean to insert.
Also do keep in mind that there are other date formats used in the world. :)
I am currently trying to validate UK telephone numbers:
The format I'm looking for is: 01234 567891 or 01234567891 - So I need the number to have 5 numbers then a space then 6 numbers or simply a 11 numbers.
The number must start with a 0.
I've had a look at a couple of examples:
/^[0-9]{10,11} - to check that the chars are all numbers
/^0[0-9]{9,10}$/ - to check that the first number is a 0
I'm just unsure how to put all these together and check if there is a space or not.
Could someone help me with this regex?
Thanks
Try this regex:
/^0\d{4}\s?\d{6}$/
Many people try to do input validation and formatting in a single step.
It is better to separate these processes.
Match UK telephone number in any format
^(?:(?:\(?(?:0(?:0|11)\)?[\s-]?\(?|\+)44\)?[\s-]?(?:\(?0\)?[\s-]?)?)|(?:\(?0))(?:(?:\d{5}\)?[\s-]?\d{4,5})|(?:\d{4}\)?[\s-]?(?:\d{5}|\d{3}[\s-]?\d{3}))|(?:\d{3}\)?[\s-]?\d{3}[\s-]?\d{3,4})|(?:\d{2}\)?[\s-]?\d{4}[\s-]?\d{4}))(?:[\s-]?(?:x|ext\.?|\#)\d{3,4})?$
The above pattern allows the user to enter the number in any format they are comfortable with. Don't constrain the user into entering specific formats.
Extract NSN, prefix and extension
^(\(?(?:0(?:0|11)\)?[\s-]?\(?|\+)(44)\)?[\s-]?)?\(?0?(?:\)[\s-]?)?([1-9]\d{1,4}\)?[\d[\s-]]+)((?:x|ext\.?|\#)\d{3,4})?$
Next, extract the various elements.
$2 will be '44' if international format was used, otherwise assume national format with leading '0'.
$4 contains the extension number if present.
$3 contains the NSN part.
Validation and formatting
Use further RegEx patterns to check the NSN has the right number of digits for this number range. Finally, store the number in E.164 format or display it in E.123 format.
There's a very detailed list of validation and display formatting RegEx patterns for UK numbers at:
http://www.aa-asterisk.org.uk/index.php/Regular_Expressions_for_Validating_and_Formatting_UK_Telephone_Numbers
It's too long to reproduce here and it would be difficult to maintain multiple copies of this document.
If you are looking for all UK numbers, I'd look for a bit more than just that number, some are in the format 020 7123 4567 etc.
^\s*\(?(020[7,8]{1}\)?[ ]?[1-9]{1}[0-9{2}[ ]?[0-9]{4})|(0[1-8]{1}[0-9]{3}\)?[ ]?[1-9]{1}[0-9]{2}[ ]?[0-9]{3})\s*$
/\d*(*)*+*-*/
Simple Telephone Regex includes + () and - anywhere, as well as digits
I think ^0[\d]{4}\s?[\d]{5,6}} will work for you. I have used [\d] instead of [0-9].
I find that RegExr is a useful online tool to check and try your regular expressions. It also has a nice library of examples to help point you in the right direction
you should just count the number of digits and check that it's 10,
Some UK numbers have only 9 digits, not 10 (not including the leading 0).
These include 40 of the 01 area codes (using "4+5" format), the 016977 area code (using "5+4" format), all 0500 numbers and some 0800 numbers.
There's a list at: http://www.aa-asterisk.org.uk/index.php/01_numbers
This US numbers pattern accepts following phones as well:
800-432-4500, Opt: 9, Ext: 100316
800-432-4500, Opt: 9, Ext: X100316
800-432-4500, Option #3
(?:(?:\+?1\s*(?:[.-]\s*)?)?(?:\(\s*([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9])\s*\)|([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9]))\s*(?:[.-]\s*)?)?([2-9]1[02-9]|[2-9][02-9]1|[2-9][02-9]{2})\s*(?:[.-]\s*)?([0-9]{4}),?(?:\s*(?:#|x\.?|opt(\.|:|\.:)?|option)\s*#?(\d+))?,?(?:\s*(?:#|x\.?|ext(\.|:|\.:)?|extension)\s*(\d+))?
(used this answer in other topic as start point)