Match in XSLT by solr - xslt

Question

I have a problem with field of solr. when multiple nodes does not fit, and it shows empty field.
<field name="specs"/>
the xml original:
<?xml version="1.0" encoding="UTF-8"?>
<tire xmlns="http://schema.grabber" xmlns:x="http://www.w3.org/1999/xhtml"
tire-type="2" product-type="tire" id="102694" trademark="dunlop"
season="3" width="130" height="70" wheels="12" load="62" speed="l"
host="norauto" model="d207" hostDetailId="102694" hostDbID="6">
<url>product/_102694.html</url>
<price>49.95</price>
<ecorate>1.15</ecorate>
<currency>€</currency>
<vat>true</vat>
<img>images_produits/650x650/dunlop-d207-runscoot.jpg</img>
<content>DUNLOP D207 RUNSCOOT</content>
<specs>
<spec name="b_xl">0</spec>
</specs>
</tire>
Transformation XSLT at XML solr, this is xslt of solr:
<xsl:template match="/">
<docs>
<xsl:apply-templates select="cb:tire|cb:products" />
</docs>
</xsl:template>
<xsl:template match="cb:tire">
<doc>
<xsl:apply-templates select="#*|*" />
</doc>
</xsl:template>
<xsl:template match="cb:products">
<xsl:apply-templates select="#*|*" />
</xsl:template>
<xsl:template match="*/*[#name and not(parent::cb:products)]">
<xsl:call-template name="field">
<xsl:with-param name="name" select="concat(name(),'_',#name)"/>
</xsl:call-template>
</xsl:template>
<xsl:template match="*/*[not(#name) and not(parent::cb:products)]">
<xsl:call-template name="field"/>
</xsl:teplate>
<xsl:template match="*[parent::cb:products]">
<xsl:choose>
<xsl:when test="not(text())">
<doc>
<xsl:apply-templates select="*|#*"/>
</doc>
</xsl:when>
<xsl:otherwise>
<xsl:call-template name="field"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template match="*|#*">
<xsl:call-template name="field">
<xsl:with-param name="value" select="."/>
</xsl:call-template>
</xsl:template>
<xsl:template name="field">
<xsl:param name="name" select="name()" />
<xsl:param name="value" select="text()" />
<field name="{translate(lower-case($name),' ','_')}">
<xsl:value-of select="$value" />
</field>
</xsl:template>
<xsl:template match="text()"/>
</xsl:stylesheet>
The problem is the element <specs><spec name="b_xl">0</spec></specs>, the field is empty, the result not correct.
This is result XML:
<docs>
<doc>
<field name="tire-type">1</field>
<field name="product-type">tire</field>
<field name="season">1</field>
<field name="id">135-80-r13-70-t-kingstar-sk70</field>
<field name="trademark">kingstar</field>
<field name="model">sk70</field>
<field name="width">135</field>
<field name="height">80</field>
<field name="wheels">13</field>
<field name="load">70</field>
<field name="speed">t</field>
<field name="host">tires</field>
<field name="hostdetailid">135-80-r13-70-t-kingstar-sk70</field>
<field name="hostdbid">1000</field>
<field name="url">135-80-r13-70-t-kingstar-sk70.html</field>
<field name="price">29.73</field>
<field name="currency">€</field>
<field name="vat">true</field>
<field name="img">media/catalog/product/cache/1/image/9df78eab33525d08d6e5fb8d27136e95/0/1/0181050080001.png</field>
<field name="content">135/80 R13 70 T KINGSTAR SK70</field>
<field name="specs" />
</doc>
</docs>
I need to display the contents of the element if it contains specs.

Answer 1

To handle the children of specs as field you may add a template like this:
<xsl:template match="cb:specs" priority="1">
<xsl:apply-templates />
</xsl:template>
Which will generate following field:
<field name="spec_b_xl">0</field>
I do not know if this is as expected, because you didn't tell us who the output for specs should look like.