Opencart: How to render a template only on a specific page? - opencart

Question

In my catalog/controller/mycontroller.php, I have a script like this:
$this->data['settings'] = $this->config->get('my_module'); // retrieves data from "setting" table
foreach ($this->data['settings'] as $data) {
if ($data['pageurl'] == 'http://'.$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI']) {
$this->render();
}
}
In Extensions > Modules, I have my extension installed where I can set different page URLs to different Layouts and Positions like this:
Page URL Layout Position
================================================
http://...?product_id=10 Product Content Top
http://...?product_id=20 Product Content Top
http://... Home Content Top
My issue is - I'd like to render a template only ONCE on a specific page that meets the condition in the above script. What's currently happening is $this->render() is showing the template MULTIPLE times based on the Position and Layout in Extensions > Modules. For instance, when I visit http://...?product_id=10 page, it displays the template twice while it's only supposed to display it once because it only meets the condition for product_id=10 in the controller. How can I do this?

Answer 1

First of all, do this:
var_dump('http://'.$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI']);
I guess You may be missing also the $_SERVER['QUERY_STRING'] part...
to see, what URL are You building to compare to URLs You are setting in the backend...
Next, please, do not call $this->render() in a loop no matter why the condition succeed more times, instead of this do something like this:
$this->data['settings'] = $this->config->get('my_module'); // retrieves data from "setting" table
$render = false;
foreach ($this->data['settings'] as $data) {
if ($data['pageurl'] == HTTP_SERVER . $_SERVER['REQUEST_URI']) { // use defined constant HTTP_SERVER
$render = true;
}
}
if($render) {
$this->render();
}