i'm new in django and i have a problem with Uploading File Please Help me!! :X
here is my view.py
def uploadimg(request):
try:
user = request.session['user']
if request.method == 'POST':
form = User_image_form(request.POST, request.FILES)
#if form.is_valid():
usr_img = User_image(imgfile = request.FILES['imgfile'])
return HttpResponse("yes")
#usr_img.user = user
usr_img.save()
return HttpResponse("yees the first upload is right !! :X")
else:
return HttpResponse("Noooooo!!!")
except:
pass
this is my form.py
class User_image_form(forms.Form):
imgfile = forms.FileField()
and this is my models.py
class User_image(models.Model):
imgfile = models.ImageField(upload_to = 'User-Image')
#user = models.ForeignKey(User_account)
and i have problem in view.py at line which
usr_img = User_image(imgfile = request.FILES['imgfile'])
and it's never get to the
return HttpResponse("Yes")
error:
Exception Value: The view User.views.uploadimg didn't return an HttpResponse object.
Plz Help
If there is an exception, you are not returning an HttpResponse object. Hence the error.
use form.is_valid() to see if the form is valid.
Something like this:
if request.method == 'POST':
form = User_image_form(request.POST, request.FILES)
if form.is_valid():
usr_img = User_image(imgfile = form.cleaned_data['imgfile'])
usr_img.user = user
usr_img.save()
return HttpResponse("yees the first upload is right !! :X")
else:
print form.errors #for debugging purposes only.
return HttpResponse("Noooooo!!!")
Related
I have a model (grade) inside another model (homework) which is inside another model (activity) and when I submit the grade of a homework and try to get back to activty I loose the id of the activity. How do I get the right kwargs to get back to activity after submiting a grade? Or any other solution you may think about. Thanks in advance.
Views.py
def grade_homework(request, id):
if not request.user.is_authenticated:
return render(request, "auctions/login.html")
try:
activity = Activity.objects.get(id=id)
except Activity.DoesNotExist:
activity = None
try:
hw_upload = Hw_upload.objects.get(id=id)
except Hw_upload.DoesNotExist:
hw_upload = None
if request.method == 'POST':
form = Hw_gradeForm(request.POST, request.FILES or None)
if form.is_valid():
hw_grade = form.save(commit=False)
hw_grade.grader = request.user
hw_grade.hw_upload = Hw_upload.objects.get(id=id)
hw_grade.save()
url = reverse('activity', kwargs={'id': id})
return HttpResponseRedirect(url)
Urls.py
path("auction/course/module/activity/<str:id>", views.activity, name="activity"),
path("grade_hw/<int:id>", views.grade_homework, name="grade_hw"),
I have created a django form which at the moment I can only save the POST. Would like to add Save and Add another button in my templates and views function. Has anyone found a solutions.
if request.method == "POST":
form = StktxnsForm(request.POST )
if form.is_valid():
new_txns = form.save(commit=False)
new_txns.created_by = request.user
new_txns.save()
return redirect('pending_transactions')
else:
form = StktxnsForm()
return render(request,'new_transaction.html', {'form': form})
You may think use AJAX function to save and continue without reload. Send 'POST' request to save data in Ajax. It will help you.
I used like this in class-based view (vanilla method)
class PackageCreateView(View):
def get(self,request,*args,**kwargs):
return render(request,'package/create_package.html')
def post(self,request,*args,**kwargs):
if request.user.is_authenticated:
if request.method == 'POST':
data = request.POST
name = data.get('name')
detail = data.get('des')
price = data.get('price')
fname = Package.objects.all().filter(name=name)
if fname:
messages.info (request,'sorry name already exits')
return redirect ('create_package')
elif request.POST.get ('continue') :
pac = Package(name=name, detail=detail, price=price)
pac.save()
return redirect('create_package')
else:
pac = Package(name=name, detail=detail, price=price)
pac.save()
return redirect('packagelist')
else:
return redirect ('create_package')
else:
return redirect('login')
Here's one way to do it.
On your template:
<button type="submit" name="save_add" value="True">Save & Add another</button>
In your view:
if form.is_valid():
new_txns = form.save(commit=False)
new_txns.created_by = request.user
new_txns.save()
if request.POST.get('save_add'):
return redirect('create_transaction')
return redirect('pending_transactions')
Trying to save images to a specific folder in django. I get no error but the file doesn't show up where its supposed to.
Here is the model:
class FileUploadHandler(models.Model):
title = models.CharField(max_length=100)
file = models.ImageField(upload_to='/wiki/static/')
View:
def image_upload(request):
if request.method == 'POST':
form = UploadImageForm(request.POST, request.FILES)
if form.is_valid():
FileUploadHandler(request.FILES['image'])
form.save
return render_to_response('wiki/gallery.html')
else:
form = UploadImageForm()
return render_to_response('wiki/gallery.html', RequestContext(request, {'form': form}))
Totally stumped since I don't get an error.
don't you need parenthesis at the end of form.save,
i.e. form.save()
FileUploadHandler.objects.create(file=request.FILES['image'])
https://docs.djangoproject.com/en/dev/ref/models/querysets/#django.db.models.query.QuerySet.create
https://docs.djangoproject.com/en/dev/topics/http/file-uploads/#handling-uploaded-files
I have settings form page. If user filled the form once; it must display those values. But if there is no data [first time] I get query error. I need that query, because the form data must be written as related with current user [logged in].
here is my view part :
#login_required(login_url='/login/')
def profile_page(request,username):
query = Profile.objects.get(owner__username = username) ##error!
if request.method == 'POST':
form = profile_form(request.POST,instance=query)
form.save()
return HttpResponseRedirect('/admin/')
else:
form = profile_form(instance=query)
return render_to_response('profile_save.html',{'form':form},context_instance = RequestContext(request))
I think I need to check the model and if it is empty I should do something different.
I am stuck.
Thank you
You want to make use of the .exists() queryset option
#login_required(login_url='/login/')
def profile_page(request,username):
form = profile_form()
if Profile.objects.get(owner__username = username).exists():
query = Profile.objects.get(owner__username = username)
if request.method == 'POST':
form = profile_form(request.POST,instance=query)
form.save()
return HttpResponseRedirect('/admin/')
else:
form = profile_form(instance=query)
return render_to_response('profile_save.html',{'form':form},context_instance = RequestContext(request))
see QuerytSet API reference for more information
You just need to wrap that get query in try ... except and set instance to none, like this.
from django.core.exceptions import ObjectDoesNotExist
#login_required(login_url='/login/')
def profile_page(request,username):
try:
query = Profile.objects.get(owner__username = username)
#to be more specific you can except ProfileObjectDoesNotExist
except ObjectDoesNotExist:
query = None #Doesn't exist, set to None
if request.method == 'POST':
form = profile_form(request.POST,instance=query)
form.save()
return HttpResponseRedirect('/admin/')
else:
form = profile_form(instance=query)
return render_to_response('profile_save.html',{'form':form},
context_instance = RequestContext(request))
I think i may have use get_or_create for this purpose.
Profile.objects.get_or_create(owner__username = username)
I am a real beginner in web development. The following code is failing at the is_valid() check. But I do not understand why: The form should get its data filled from the POST-data or not?
Model:
class Statement(models.Model):
text = models.CharField(max_length=255)
user = models.ForeignKey(User)
time = models.DateField()
views = models.IntegerField()
ModelForm:
class StatementForm(ModelForm):
class Meta:
model = Statement
widgets = {
'time':forms.HiddenInput(),
'user':forms.HiddenInput(),
'views':forms.HiddenInput(),
}
View function:
def new(request):
if request.method == 'POST': # If the form has been submitted...
form = StatementForm(request.POST) # A form bound to the POST data
if form.is_valid():
stmt = form.save()
path = 'stmt/' + stmt.id
return render_to_response(path, {'stmt': stmt})
else:
c = {}
c.update(csrf(request))
loggedin_user = request.user
d = datetime.now()
form = StatementForm(request.POST, initial={'time': d.strftime("%Y-%m-%d %H:%M:%S"), 'user':loggedin_user, 'views':0})
return render_to_response('new_stmt.html', {'form': form, },context_instance=RequestContext(request))
I found similar topics and tried a lot. This is how i think it should work. I really need advice.
All fields of your model are required. So, form.is_valid() will be True, if all fields are filled with correct values and are not blanked.
You have declared fields time, user, views as hidden fields. Are you sure, that you have filled them in your template form?
Also, you may want to auto stamp field time = models.DateField(). Modify your model field like
time = models.DateField(auto_now=True)`.
After this you don't have to fill it by yourself in template form.
Your view must return HttpResponse object in all cases. If your form is not valid, i.e. if form.is_valid() will return False, then no HttpResponse object will be returned by your view. This can be the source of your fail. Add else statement for if form.is_valid():
from django.http import Http404
def new(request):
if request.method == 'POST': # If the form has been submitted...
form = StatementForm(request.POST) # A form bound to the POST data
if form.is_valid():
stmt = form.save()
path = 'stmt/' + stmt.id
return render_to_response(path, {'stmt': stmt})
else:
# Do something in case if form is not valid
raise Http404
else:
# Your code without changes
Change this line:
form = StatementForm(request.POST, initial={'time': d.strftime("%Y-%m-%d %H:%M:%S"), 'user':loggedin_user, 'views':0})
For this:
form = StatementForm(initial={'time': d.strftime("%Y-%m-%d %H:%M:%S"), 'user':loggedin_user, 'views':0})