Given the following file path:
/Users/Lawrence/MyProject/some/very/interesting/Code.scala
I would like to generate the following using a single regex replace (the root can be a constant):
some.very.interesting
This is for the purpose of generating a snippet for Sublime Text which can automatically insert the correct package/namespace header for my scala/java classes :)
Sublime Text uses the following syntax for their regex replace patterns (aka 'substitutions'):
{input/regex/replace/flags}
Hence why an iterative approach cannot be taken - it has to be done in one pass! Also, substitutions cannot be nested :(
If you know the maximum number of nested folders.You can specify that in your regex.
For 1 to 3 nested folders
Regex:/Users/Lawrence/MyProject/(\w+)/?(\w+)?/?(\w+)?/[^/]+$
Replace:$1.$2.$3
For 1 to 5 nested folders
Regex:/Users/Lawrence/MyProject/(\w+)/?(\w+)?/?(\w+)?/?(\w+)?/?(\w+)?/[^/]+$
Replace:$1.$2.$3.$4.$5
Given the constraints this is only thing you can do
Input
/Users/Lawrence/MyProject/some/very/interesting/Code.scala
Regex
^/Users/Lawrence/MyProject/[^/]+/[^/]+/[^/]+/Code.scala
or
^/[^/]+/[^/]+/[^/]+/([^/]+)/([^/]+)/([^/]+)/
Replace
\1.\2.\3
Update
This gets you closer, but not exactly it:
Regex
(^/Users/Lawrence/MyProject/|/Code\.scala$|/)
Replacement
.
Output would be:
.some.very.interesting.
Without multiple replacements in a single line and without recursive back references it's going to be hard.
You might have to do a second replacement, replacing something like this with an empty string (if you can):
(^\.|\.$)
Related
We have an old, grown project with thousands of php files and need to clean it up.
Throughout the whole project we do have a lot of function calls similar to:
trans('somestring1');
trans("SomeString2");
trans('more_string',$somevar);
trans("anotherstring4",$somevar);
trans($tx_key);
trans($anotherKey,$somevar);
All of those are embedded into the code and represent translation keys. I would like to find a way to extract all "translation keys" in all occurrences.
The PHP project is in VS Code, so a RegEx Search would be helpful to list the results.
Or I could search through the project with any other tool you would recommend
However I would also need to "export" just the strings to a textfile or similar.
The ideal result would be:
somestring1
SomeString2
more_string
anotherstring4
$tx_key
$anotherKey
As a bonus - if someone knows, how I could get the above list including filename where the result has been found - that would be really fantastic!
Any help would be greatly appreciated!
Update:
The RegEx I came up with:
/(trans)+\([^\)]*\)(\.[^\)]*\))?/gim
list the full occurrence - How can I just get the first part of the result (between Single Quotes OR between Double Quotes OR beginning with $)
See here: regexr.com/548d4
Here are some steps to get exactly what you want. Using this you can do a find and replace on your search results!
So you could do sequential regex find/replaces in the right circumstances.
The replace can be just within the search results editor and not affect the underlying files at all - which is what you want.
You can also have the replace action actually edit the underlying files if you wish.
[Hint: This technique can also make doing a find item a / replace with b in files that contain term c much easier to do.]
(1) Open a new search editor: Ctrl+Shift+P
(That command is currently unbound to a keybinding.)
(2) Paste this regex into the Search input box (with the regex option .* selected):
`(.*?)(\btrans\(['"]?)([^,'")]+)(.*)` - a relatively simple regex
regex101 demo
See my other answer for a regex to work with up to 6 entries per line:
(\s*\d+:\s)?((.*?)(\btrans\(['"]?)([^,'")]*)((.*?)(\btrans\(['"]?)([^,'")]*))?((.*?)(\btrans\(['"]?)([^,'")]*))?((.*?)(\btrans\(['"]?)([^,'")]*))?((.*?)(\btrans\(['"]?)([^,'")]*))?((.*?)(\btrans\(['"]?)([^,'")]*))?)(.*)
(3) You will get a list of files with the search results. Now open a Find widget Shift+F in this Search editor.
(4) Put the same regex into that Find input. Regex option selected. Put $3 into the Replace field. This only replaces in this Search editor - not the original files (although that can be done if you want it in some case). Replace All.
If using the 1-6 version regex, replace with:
$1$5 $9 $13 $17 $21 $25
(5) Voila. You can now save this Search Editor as a file.
The first answer works for one desired capture per line as in the original question. But that relatively simple regex won't work if there are two or more per line.
The regex below works for up to 6 entries per line, like
trans('somestring1');
stuff trans("SomeString2"); some content trans("SomeString2a");more stuff [repeat, repeat]
But it doesn't for 7+ - you'll need a regex guru for that.
Here is the process again with a twist of using a snippet in the Search Editor instead of a Find/Replace. Using a snippet allows more control over the formatting of the final result.
(1) Open a new search editor: Ctrl+Shift+P (That command is currently unbound to a keybinding.)
(2) Paste this regex into the Search input box (with the regex option .* selected):
`((.*?)(\btrans\(['"]?)([^,'")]*)((.*?)(\btrans\(['"]?)([^,'")]*))?((.*?)(\btrans\(['"]?)([^,'")]*))?((.*?)(\btrans\(['"]?)([^,'")]*))?((.*?)(\btrans\(['"]?)([^,'")]*))?((.*?)(\btrans\(['"]?)([^,'")]*))?)(.*)`
regex101 demo
(3) You will get a list of files with the search results. Now select all your results individually with Ctrl+Shift+L.
(4) Trigger this keybinding:
{
"key": "alt+i", // whatever keybinding you like
"command": "editor.action.insertSnippet",
"when": "editorTextFocus",
"args": {
"snippet": "${TM_SELECTED_TEXT/((.*?)(\\btrans\\([\\'\\\"]?)([^,\\'\\\")]*)((.*?)(\\btrans\\([\\'\\\"]?)([^,\\'\\\")]*))?((.*?)(\\btrans\\([\\'\\\"]?)([^,\\'\\\")]*))?((.*?)(\\btrans\\([\\'\\\"]?)([^,\\'\\\")]*))?((.*?)(\\btrans\\([\\'\\\"]?)([^,\\'\\\")]*))?((.*?)(\\btrans\\([\\'\\\"]?)([^,\\'\\\")]*))?)(.*)/$4${8:+\n }$8${12:+\n }$12${16:+\n }$16${20:+\n }$20${24:+\n }$24/g}"
}
},
That snippet will be applied to each selection in your search result. This part ${8:+\n } is a conditional which adds a newline and some spaces if there is a capture group 8 - which would be a second trans(...) on a line.
Demo: (unfortunately, it doesn't properly show the Ctrl+Shift+L selecting all lines individually or the Alt+i snippet trigger)
I'm working on a project where I'm converting an implementation of a binary tree to an AVL tree, so I have a few files that contain lines like:
Tree<int>* p = new Tree<int>(*t);
all over the place. The goal I have in mind is to use a vim regex to turn all instances of the string Tree into the string AVLTree, so the line above would become:
AVLTree<int>* p = new AVLTree<int>(*t);
the regex I tried was :%s/Tree/AVLTree/g, but the result was:
AVLTree<int>* p = new Tree<int>(*t);
I looks to me like when vim finds something to replace on a line it jumps to the next one, so is there a way to match multiple strings on the same line? I realize that this can be accomplished with multiple regex's, so my question is mostly academic.
Credit on this one goes to Marth for pointing this out. My issue was with vim's gdefault. By default it's set to 'off', which means you need the /g tag to make your search global, which is what I wanted. I think mine was set to 'on', which means without the tag the search is global, but with the tag the search is not. I found this chart from :help 'gdefault' helpful:
command 'gdefault' on 'gdefault' off
:s/// subst. all subst. one
:s///g subst. one subst. all
:s///gg subst. all subst. one
I have a text file in Notepad++ that contains about 66,000 words all in 1 line, and it is a set of 200 "lines" of output that are all unique and placed in 1 line in the basic JSON form {output:[{output1},{output2},...}]}.
There is a set of characters matching the RegEx expression "id":.........,"kind":"track" that occurs about 285 times in total, and I am trying to either single them out, or copy all of them at once.
Basically, without some super complicated RegEx terms, I am stuck because I can't figure out how to highlight all of them at once, and also the Remove Unbookmarked Lines feature does not apply because this is all in one line. I have only managed to be able to Mark every single occurrence.
So does this require a large number of steps to get the file into multiple lines and work from there, or is there something else I am missing?
Edit: I have come up with a set of Macro schemes that make the process of doing this manually work much faster. It's another alternative but still takes a few steps and quite some time.
Edit 2: I intended there to be an answer for actually just highlighting the different sections all at once, but I guess that it not possible. The answer here turns out to be more useful in my case, allowing me to have a list of IDs without everything else.
You seem to already have a regex which matches single instances of your pattern, so assuming it works and that we must use Notepad++ for this:
Replace .*?("id":.........,"kind":"track").*?(?="id".........,"kind":"track"|$) with \1.
If this textfile is valid JSON, this opens you up to other, non-notepad++ options, like using Python with the json module.
Edited to remove unnecessary steps
I'm trying to change the case of method names for some functions from lowercase_with_underscores to lowerCamelCase for lines that begin with public function get_method_name(). I'm struggling to get this done in a single step.
So far I have used the following
:%s/\(get\)\([a-zA-Z]*\)_\(\w\)/\1\2\u\3/g
However, this only replaces one _ character at a time. What I would like it a search and replace that does something like the following:
Identify all lines containing the string public function [gs]et.
On these lines, perform the following search and replace :s/_\(\w\)/\u\1/g
(
EDIT:
Suppose I have lines get_method_name() and set_method_name($variable_name) and I only want to change the case of the method name and not the variable name, how might I do that? The get_method_name() is more simple of course, but I'd like a solution that works for both in a single command. I've been able to use :%g/public function [gs]et/ . . . as per the solution listed below to solve for the get_method_name() case, but unfortunately not the set_method_name($variable_name) case.
If I've understood you correctly, I don't know why the things you've tried haven't worked but you can use g to perform a normal mode command on lines matchings a pattern.
Your example would be something like:
:%g/public function [gs]et/:s/_\(\w\)/\u\1/g
Update:
To match only the method names, we can use the fact that there will only be method names before the first $, as this looks to be PHP.
To do that, we can use a negative lookbehind, #<!:
:%g/public function [gs]et/:s/\(\$.\+\)\#<!_\(\w\)/\u\2/g
This will look behind #<! for any $ followed by any number of characters and only match _\(\w\) if no $s are found.
Bonus points(?):
To do this for multiple buffers stick a bufdo in front of the %g
You want to use a substitute with an expression (:h sub-replace-expression)
Match the complete string you want to process then pass that string to a second substitute command to actually change the string
:%s/\(get\|set\)\zs_\w\+/\=substitute(submatch(0), '_\([A-Za-z]\)', '\U\1', 'g')
Running the above on
get_method_name($variable_name)
set_method_name($variable_name)
returns
getMethodName($variable_name)
setMethodName($variable_name)
To have vi do replace sad with happy, on all lines, in a file:
:1, $ s/sad/happy/g
(It is the :1, $ before the sed command that instructs vi to execute the command on every line in the file.)
I am using the maven replacer plugin and I've run into a situation where I have a regular expression that matches across lines which I need to run on the input file until all matches have been replaced. The configuration for this expression looks like this:
<regexFlags>
<regexFlag>DOTALL</regexFlag>
</regexFlags>
<replacements>
<replacement>
<token>\#([^\n\r=\#]+)\#=([^\n\r]*)(.*)(\#default\.\1\#=[^\n\r]*)(.*)</token>
<value>#$1#=$2$3$5</value>
<replacement>
<replacements>
The input could look like this:
#d.e.f#=y
#a.b.c#=x
#h.i.j#=aaaa
#default.a.b.c#=QQQ
#asdfasd.fasdfs.asdfa#=23423
#default.h.i.j#=234
#default.RR.TT#=393993
and I want the output to look like this:
#d.e.f#=y
#a.b.c#=x
#h.i.j#=aaaa
#asdfasd.fasdfs.asdfa#=23423
#default.RR.TT#=393993
The intention is to re-write the file, but without the tokens with a #default prefix, where another token without the prefix has already been defined.
#default.a.b.c#=QQQ and #default.h.i.j#=234 have been removed from the output because other tokens already contains a.b.c and h.i.j.
The current problem I have is that the replacer plugin only replaces the first match, so my output looks like this:
#d.e.f#=y
#a.b.c#=x
#h.i.j#=aaaa
#asdfasd.fasdfs.asdfa#=23423
#default.h.i.j#=234
#default.RR.TT#=393993
Here, #default.a.b.c=QQQ is gone, which is correct, but #default.h.i.j#=234 is still present.
If I were writing this in code, I think I could probably just loop while attempting to match on the entire output, and break when there are no matches. Is there a way to do this with the replacer plugin?
Edit: I may have over simplified my example. A more realistic one is:
#d.e.f#=y
#a.b.c#=x
#h.i.j#=aaaa
#default.a.b.c#=QQQ
#asdfasd.fasdfs.asdfa#=23423
#default.h.i.j#=234
#default.RR.TT#=393993
#x.y.z#=0
#default.q.r.s#=1
#l.m.n#=8.3
#q.r.s#=78
#blah.blah.blah#=blah
This shows that it's possible for a default.x.x.x=y to precede a x.x.x=y token (as #default.q.r.s#=1 preceedes #q.r.s#=78`), my prior example wasn't clear about this. I do actually have an expression to capture this, it looks a bit like this:
\#default\.([^\n\r=#|]+)#=([^\n\r|]*)(.*)#\1#=([^\n\r|]*)(.*)
I know line separators are missing from this even though they were in the other one - I was experimenting with removing all line separators and treating it as a single line but that hasn't helped. I can resolve this problem simply by running each replacement multiple times by copying and pasting the configurations a few times, but that is not a good solution and will fail eventually.
I don't believe you could solve this problem as is, a work-around is to reverse the order of the file top to bottom, perform lookahead regex and then reverse the result order
pattern = #default\.(.*?)#[^\r\n]+(?=[\s\S]*#\1#) Demo
another way (depending on the capabilities of "Maven") is to run this pattern
#(.*)(#[\s\S]*)#default\.\1.*
and replace with #$1$2 Demo in a loop until there are no matches
then run this pattern
#default\.(.*)#.*(?=[\s\S]*\1)
and replace with nothing Demo in a loop until there are no matches
It doesn't look like the replacer plugin can actually do what I want. I got around this by using regular expressions to build multiple filter files, and then applying them to the resource files.
My original goal had been to use regular expressions to build a single, clean, and tidy filter file. In the end, I discovered that I was able to get away with just using multiple filters (not as clean or tidy) and apply them in the correct order.