I have some link templates and I need to replace substrings inside of that links.
Link templates:
"/all_news"
"/all_news/"
"/all_news/page1"
"/all_news/page1/"
All of these templates mean the same thing - first page of news page without filtering.
So I need to:
1st template - insert "/pageX"
2nd template - insert "pageX"
3rd and 4th templates - replace page number
Is it possible with only one regexp?
If yes, then please help me.
If no, then I have 2nd question:
maybe its possible to replace everything after "/all_news" on "/pageX"?
I mean next logic:
string started
ok, I see substring "/all_news"
I replace everything after "/all_news" even if nothing exist(if string ends by "/all_news")
I return "/all_news/pageX".
This'll do it.
'/all_news/page1'.replace(/(.*\/all_news).*/,'$1' + '/pageX');
Just one for all.
Java has lookbehind. It negates the need for the $1. The solution looks like:
String result = "/all_news/page1";
String pattern = "(?<=\\/all_news).*";
System.out.println(result.replaceAll(pattern,"/PageX"));
Cheers.
Related
I'm trying to create a custom filter in Google Analytic to remove the query parts of the url which I don't want to see. The url has the following structure
[domain]/?p=899:2000:15018702722302::NO:::
I would like to create a regex which skips the first 12 characters (that is until:/?p=899:2000), and what ever is going to be after that replace it with nothing.
So I made this one: https://regex101.com/r/Xgbfqz/1 (which could be simplified to .{0,12}) , but I actually would like to skip those and only let the regex match whatever is going to be after that, so that I'll be able to tell in Google Analytics to replace it with "".
The part in the url that is always the same is
?p=[3numbers]:[0-4numbers]
Thank you
Your regular expression:
\/\?p=\d{3}\:\d{0,4}(.*)
Tested in Golang RegEx 2 and RegEx101
It search for /p=###:[optional:####] and capture the rest of the right side string.
(extra) JavaScript:
paragraf='[domain]/?p=899:2000:15018702722302::NO:::'
var regex= /\/\?p=\d{3}\:\d{0,4}(.*)/;
var match = regex.exec(paragraf);
alert('The rest of the right side of the string: ' + match[1]);
Easily use "[domain]/?p=899:2000:15018702722302::NO:::".substr(12)
You can try this:
/\?p\=\d{3}:\d{0,4}
Which matches just this: ?p=[3numbers]:[0-4numbers]
Not sure about replacing though.
https://regex101.com/r/Xgbfqz/1
I wonder if someone has achieved what I'll post here. In order to allow a template to be created under a certain path, there is a flag allowedPaths that receives a regex.
So, if I want my template "test" to appear only under /content/www/xx/xx/test-templates and child elements, I can do this:
/content/www/.*/.*/test-templates(/.*)?
But what if I want to make the opposite? I want the template "test" to appear in every /content/www/xx/xx/ node and beyond, EXCEPT /content/www/xx/xx/test-templates and children?
I have tried several ways but no luck so far. Do you have some hint regarding this?
Thanks!
You can always restrict a more generic pattern with a lookahead. Here is an expression that should work for you:
^(?!/content/www/[^/]*/[^/]*/test-templates(?:/|$))/content/www/[^/]*/[^/]*(/.*)
See demo.
^ - matches the start of string
(?!/content/www/[^/]*/[^/]*/test-templates(?:/|$)) - makes sure the next substring is not /content/www/<some_node>/<some_node>/test-templates, followed by the end of string ($) or /
/content/www/[^/]*/[^/]*(/.*) - matches /content/www/<some_node>/<some_node> followed with optional / and zero or more characters other than a newline
There's undoubtedly a better way to do this but this is the way my requirements need me to do this.
I'm creating a search form for my web application. I want to use a tagged based search. So I'm using regex to make it work.
So I have a search string: 'c:john customer:15478'
The regex needs to find the tag (c:) and the argument (john), drop the tag, and give me the argument -- and it needs to do so for all of the instances of a tag and their arguments. The regex I have comes close, but it doesn't work correctly. It doesn't grab every argument, or drop the tags in a consistent way. So the question: what's wrong with my regex that needs to be fixed in order to achieve the correct results?
Currently it finds the first tag, grabs its argument, and everything else after it. I need it to stop the match after it finds an argument. i.e. in the case above it will match john customer:15478
Maybe a better question is how do I make VB's regex return everything between the first colon, and the beginning of the next tag (which is followed by another colon) or otherwise stop matching at the beginning of the next tag?
Regex:
(?<=({0}({1})??:)+?)(\S+\s*\S*)(?=\s+?\b\w+:.+?)??
The {0} and the {1} represent a String.format call using a string, say Customer (but it could be anything), to define the tag. the {0} is the first character, and the {1} are the rest of the characters. This regex will match anything that exists behind the tag including another tag and its argument if it exists. So for the string
"c:5401 4664 c:john smith p:joam d:domain.com p:1548 c:215-548-5487 d:""192.168.0.1"""
The matches would be
'5401 4664, john smith, 215-548-5487 d:"192.168.0.1"'
'domain.com p:1548, "192.168.0.1"'
'joam d:domain.com, 1548 c:215-548-5487'
given the tags I have defined. The regex fails to stop its matching at the start of the next tag.
If I undestood You correctly this should solve the problem in general:
/\w+:([^:]+)(?:\s|$)/g
https://regex101.com/r/vN6fH1/1
and with defined tag it would look like this:
/{0}({1})?:([^:]+)(?:\s|$)/g
but this still rely on semicolon not tag name
(so it won't match at all if You did not pass tag name that is in string)
I am trying to write a regex which will strip away the rest of the path after a particular folder name.
If Input is:
/Repository/Framework/PITA/branches/ChangePack-6a7B6/core/src/Pita.x86.Interfaces/IDemoReader.cs
Output should be:
/Repository/Framework/PITA/branches/ChangePack-6a7B6
Some constrains:
ChangePack- will be followed change pack id which is a mix of numbers or alphabets a-z or A-Z only in any order. And there is no limit on length of change pack id.
ChangePack- is a constant. It will always be there.
And the text before the ChangePack can also change. Like it can also be:
/Repository/Demo1/Demo2/4.3//PITA/branches/ChangePack-6a7B6/core/src/Pita.x86.Interfaces
My regex-fu is bad. What I have come up with till now is:
^(.*?)\-6a7B6
I need to make this generic.
Any help will be much appreciated.
Below regex can do the trick.
^(.*?ChangePack-[\w]+)
Input:
/Repository/Framework/PITA/branches/ChangePack-6a7B6/core/src/Pita.x86.Interfaces/IDemoReader.cs
/Repository/Demo1/Demo2/4.3//PITA/branches/ChangePack-6a7B6/core/src/Pita.x86.Interfaces
Output:
/Repository/Framework/PITA/branches/ChangePack-6a7B6
/Repository/Demo1/Demo2/4.3//PITA/branches/ChangePack-6a7B6
Check out the live regex demo here.
^(.*?ChangePack-[a-zA-Z0-9]+)
Try this.Instead of replace grab the match $1 or \1.See demo.
https://regex101.com/r/iY3eK8/17
Will you always have '/Repository/Framework/PITA/branches/' at the beginning? If so, this will do the trick:
/Repository/Framework/PITA/branches/\w+-\w*
Instead of regex you could can use split and join functions. Example python:
path = "/a/b/c/d/e"
folders = path.split("/")
newpath = "/".join(folders[:3]) #trims off everything from the third folder over
print(newpath) #prints "/a/b"
If you really want regex, try something like ^.*\/folder\/ where folder is the name of the directory you want to match.
I made an article spinner that used regex to find words in this syntax:
{word1|word2}
And then split them up at the "|", but I need a way to make it support tier 2 brackets, such as:
{{word1|word2}|{word3|word4}}
What my code does when presented with such a line, is take "{{word1|word2}" and "{word3|word4}", and this is not as intended.
What I want is when presented with such a line, my code breaks it up as "{word1|word2}|{word3|word4}", so that I can use this with the original function and break it into the actual words.
I am using c#.
Here is the pseudo code of how it might look like:
Check string for regex match to "{{word1|word2}|{word3|word4}}" pattern
If found, store each one as "{word1|word2}|{word3|word4}" in MatchCollection (mc1)
Split the word at the "|" but not the one inside the brackets, and select a random one (aka, "{word1|word2}" or "{word3|word4}")
Store the new results aka "{word1|word2}" and "{word3|word4}" in a new MatchCollection (mc2)
Now search the string again, this time looking for "{word1|word2}" only and ignore the double "{{" "}}"
Store these in mc2.
I can not split these up normally
Here is the regex I use to search for "{word1|word2}":
Regex regexObj = new Regex(#"\{.*?\}", RegexOptions.Singleline);
MatchCollection m = regexObj.Matches(originalText); //How I store them
Hopefully someone can help, thanks!
Edit: I solved this using a recursive method. I was building an article spinner btw.
That is not parsable using a regular expression, instead you have to use a recursive descent parser. Map it to JSON by replacing:
{ with [
| with ,
wordX with "wordX" (regex \w+)
Then your input
{{word1|word2}|{word3|word4}}
becomes valid JSON
[["word1","word2"],["word3","word4"]]
and will map directly to PHP arrays when you call json_decode.
In C#, the same should be possible with JavaScriptSerializer.
I'm really not completely sure WHAT you're asking for, but I'll give it a go:
If you want to get {word1|word2}|{word3|word4} out of any occurrence of {{word1|word2}|{word3|word4}} but not {word1|word2} or {word3|word4}, then use this:
#"\{(\{[^}]*\}\|\{[^}]*\})\}"
...which will match {{word1|word2}|{word3|word4}}, but with {word1|word2}|{word3|word4} in the first matching group.
I'm not sure if this will be helpful or even if it's along the right track, but I'll try to check back every once in a while for more questions or clarifications.
s = "{Spinning|Re-writing|Rotating|Content spinning|Rewriting|SEO Content Machine} is {fun|enjoyable|entertaining|exciting|enjoyment}! try it {for yourself|on your own|yourself|by yourself|for you} and {see how|observe how|observe} it {works|functions|operates|performs|is effective}."
print spin(s)
If you want to use the [square|brackets|syntax] use this line in the process function:
'/[(((?>[^[]]+)|(?R))*)]/x',