I made an article spinner that used regex to find words in this syntax:
{word1|word2}
And then split them up at the "|", but I need a way to make it support tier 2 brackets, such as:
{{word1|word2}|{word3|word4}}
What my code does when presented with such a line, is take "{{word1|word2}" and "{word3|word4}", and this is not as intended.
What I want is when presented with such a line, my code breaks it up as "{word1|word2}|{word3|word4}", so that I can use this with the original function and break it into the actual words.
I am using c#.
Here is the pseudo code of how it might look like:
Check string for regex match to "{{word1|word2}|{word3|word4}}" pattern
If found, store each one as "{word1|word2}|{word3|word4}" in MatchCollection (mc1)
Split the word at the "|" but not the one inside the brackets, and select a random one (aka, "{word1|word2}" or "{word3|word4}")
Store the new results aka "{word1|word2}" and "{word3|word4}" in a new MatchCollection (mc2)
Now search the string again, this time looking for "{word1|word2}" only and ignore the double "{{" "}}"
Store these in mc2.
I can not split these up normally
Here is the regex I use to search for "{word1|word2}":
Regex regexObj = new Regex(#"\{.*?\}", RegexOptions.Singleline);
MatchCollection m = regexObj.Matches(originalText); //How I store them
Hopefully someone can help, thanks!
Edit: I solved this using a recursive method. I was building an article spinner btw.
That is not parsable using a regular expression, instead you have to use a recursive descent parser. Map it to JSON by replacing:
{ with [
| with ,
wordX with "wordX" (regex \w+)
Then your input
{{word1|word2}|{word3|word4}}
becomes valid JSON
[["word1","word2"],["word3","word4"]]
and will map directly to PHP arrays when you call json_decode.
In C#, the same should be possible with JavaScriptSerializer.
I'm really not completely sure WHAT you're asking for, but I'll give it a go:
If you want to get {word1|word2}|{word3|word4} out of any occurrence of {{word1|word2}|{word3|word4}} but not {word1|word2} or {word3|word4}, then use this:
#"\{(\{[^}]*\}\|\{[^}]*\})\}"
...which will match {{word1|word2}|{word3|word4}}, but with {word1|word2}|{word3|word4} in the first matching group.
I'm not sure if this will be helpful or even if it's along the right track, but I'll try to check back every once in a while for more questions or clarifications.
s = "{Spinning|Re-writing|Rotating|Content spinning|Rewriting|SEO Content Machine} is {fun|enjoyable|entertaining|exciting|enjoyment}! try it {for yourself|on your own|yourself|by yourself|for you} and {see how|observe how|observe} it {works|functions|operates|performs|is effective}."
print spin(s)
If you want to use the [square|brackets|syntax] use this line in the process function:
'/[(((?>[^[]]+)|(?R))*)]/x',
Related
I have already implemented angular multi-select Dropdown. Now I want it to search using RegEx. Like if I have qwertyuiop, and if I wrote w*i than it should suggest me all the entries who contains 'W' and 'I' in the same string.
Do you want to know the whole thing, like how to bind the input of an input field, read the input, create an RegEx out of it, and then use the RegEx as a filter to the list you are showing in your dropdown ?
Or only the RegEx part?
For the part with RegEx:
You should take a look at the Javascript Defintion of RegEx (for example at Mozilla Developer Network ). It has a quite nice functionality.
let input:string = // the value the user typed, like w*i
const regEx = new RegExp(input)
let myDropdownList:string[] = // the list of strings i want to filter
let filteredDropdownList = myDropdownList.forEach((value:string)=>{
return regEx.test(value)
})
What happens here?
You are creating a regular Expressen with new RegExp(someString).
You can optimize it with RegEx flags.
Later you test a string with myRegEx.test(theString). It will return true if the regEx founds at least one match in the string.
I hope this helps you a bit.
warm regards.
I am trying to replace substrings that look like the following
Education|AAA|BBB|CCC|DDD|EEE
AAA|Educator|CCC|DDD|EEE
where Education or Educator could be in any position of the pipe delimited string. They are present at most only one time or zero times
I need to replace them with Educator/Education
What I want is
Educator/Education|AAA|BBB|CCC|DDD|EEE
AAA|Educator/Education|CCC|DDD|EEE
This works on the first pass with Education, I get
Educator/Education|AAA|BBB|CCC|DDD|EEE
AAA|Educator|CCC|DDD|EEE
But on the second pass replacing Educator, I get
Educator/Education/Education|AAA|BBB|CCC|DDD|EEE
AAA|Educator/Education|CCC|DDD|EEE
I think different a RegEx pattern for the ReplaceNth function would do it but cannot get what it should be
This is what I came up with in my limited ability with Google Script, which I got mostly from cobbling together from searches
Thanks
Edit: Updated with Wiktors solution given in a comment
function FRCrit_n(){
FRCrit("Elements", "Combined-What Are The Primary Role(s) Being Play?");
}
function FRCrit(shtName,cheader){
var sh = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(shtName);
var data = sh.getDataRange().getValues();
var col =HTN(shtName,cheader)-1; //Header to column index
for(n=1;n<data.length;++n){
data[n][col] = data[n][col].replace(/\bEducat(?:or|ion)\b/g, 'Educator/Education')[col],"Education","Educator/Education",1)
}
sh.getRange(1,1,data.length,data[0].length).setValues(data);
}
In regular expression syntax, you can create an 'or' condition using a vertical bar to search for multiple things in one go. You can test this out in G Suite Sheets without needing any code.
I think you want to search for
Education|Educator
and replace it with
Education/Educator
When you are happy with your results you can put it back into code - the same regex syntax should work in javascript.
I am new to regular expressions and stackoverflow. Any help would be greatly appreciated.
I am trying to remove unwanted data from a data set. The data is contained in a .csv file column with multiple cells, each cell containing data similar to this:
OSVDB #109124,OSVDB #109125,OSVDB #109126,OSVDB #109127,OSVDB #109128,OSVDB #109129,OSVDB #109130,OSVDB #109131,OSVDB #109132,OSVDB #109133,OSVDB #109134,OSVDB #109135,OSVDB #109136,OSVDB #109137,OSVDB #109138,OSVDB #109139,OSVDB #109140,OSVDB #109141,OSVDB #109142,OSVDB #109143,VMSA #2014-0012,OSVDB #102715,OSVDB #104972,OSVDB #106710,OSVDB #115364,IAVA #2014-A-0191,IAVB #2014-B-0160,IAVB #2014-B-0162,IAVB #2015-B-0007
I want to replace the above data with each occurrence of the strings beginning "IAV...". So, the above cell would read:
IAVA #2014-A-0191,IAVB #2014-B-0160,IAVB #2014-B-0162,IAVB #2015-B-0007
Below is a snippet of the script that imports the .csv and gets the column containing the data.
My regex, within powershell is:
$reg1 = '$1'
$reg2 = '(IAV[A|B]\s#[0-9]{4}-[A|B]-[0-9]{4}){1,}'
ForEach-Object {$_.IAVM = [regex]::replace($_.IAVM,$reg2,$reg1); $_}
The result is:
The entire cell contents posted above.
From my understanding {1,} at the end of the regex should return each occurrence of the string pattern, but I'm returning all contents of every cell containing my regex string.
Maybe instead of trying to pick out your string you just delete the stuff you don't want? Try something like:
$reg1=''
$reg2='((OSVDB|VMSA)\s#[M-S0-9-]{6,9}[,]?)'
You have .* in that regex at the very beginning. This will capture everything up to the last match of the pat that follows it. In your case I don't think you need that part anyway.
Also note that PowerShell has a handy -replace operator, so there's often no reason to use the static methods on the Regex type.
I have a string like "httpx://__URL__/__STUFF__?param=value"
This sample is a url by convention...it could be anything with zero or more __X__ tokens in it.
I want to use a regex to extract a list of all the tokens, so output here would be List("__URL__","__STUFF__"). Remember, I don't know beforehand how many (if any) tokens may be in the input string.
I've been struggling but unable to come up with a regex expression that will do the trick.
Something like this did not work:
(?:.?(__[a-zA-Z0-9]+__).?)+
Scala Regex, which is just a wrapper around Java Regex, will never return multiple subgroups for repetitions.
The only way about it is to have a regex for the token, and then find it multiple times. You pretty much already have everything you want:
"__[a-zA-Z0-9]+__".r findAllIn "httpx://__URL__/__STUFF__?param=value"
That returns an Iterator. Use .toSeq or similar to convert into a collection.
Greg, have you tried a simple
_+[^_]+_+
This will match all the __TOKENS__
It doesn't do any check for any __TOKENLIKE__ string after the ?params, but you have mentioned you are not only using that for urls. If you need some refinement, please let us know.
Combine a regex with split:
def urlPathComponents(s: String): Option[Array[String]] =
"""(?<=http(s?)://)[^?]+""".r findFirstIn s map (_.split("/"))
I'm trying to search a field in a database to extract URLs. Sometimes there will be more than 1 URL in a field and I would like to extract those in to separate variables (or an array).
I know my regex isn't going to cover all possibilities. As long as I flag on anything that starts with http and ends with a space I'm ok.
The problem I'm having is that my efforts either seem to get only 1 URL per record or they get only 1 the last letter from each URL. I've tried a couple different techniques based on solutions other have posted but I haven't found a solution that works for me.
Sample input line:
Testing http://marko.co http://tester.net Just about anything else you'd like.
Output goal
$var[0] = http://marko.co
$var[1] = http://tester.net
First try:
if ( $status =~ m/http:(\S)+/g ) {
print "$&\n";
}
Output:
http://marko.co
Second try:
#statusurls = ($status =~ m/http:(\S)+/g);
print "#statusurls\n";
Output:
o t
I'm new to regex, but since I'm using the same regex for each attempt, I don't understand why it's returning such different results.
Thanks for any help you can offer.
I've looked at these posts and either didn't find what I was looking for or didn't understand how to implement it:
This one seemed the most promising (and it's where I got the 2nd attempt from, but it didn't return the whole URL, just the letter: How can I store regex captures in an array in Perl?
This has some great stuff in it. I'm curious if I need to look at the URL as a word since it's bookended by spaces: Regex Group in Perl: how to capture elements into array from regex group that matches unknown number of/multiple/variable occurrences from a string?
This one offers similar suggestions as the first two. How can I store captures from a Perl regular expression into separate variables?
Solution:
#statusurls = ($status =~ m/(http:\S+)/g);
print "#statusurls\n";
Thanks!
I think that you need to capture more than just one character. Try this regex instead:
m/http:(\S+)/g