Read stdout file - c++

Question

I have create following test case for simulating the issue.I have compiled the source code and able to simulate the issue.
1)When the system command,we got some console out ( i.e your job submitted) which is redirect to file using dup2 and create file .stdout.
When I try to read this file as I need job submission information and I did not get data which was on console out. I was able to get data which I wrote it.( confirm file operation).
Can we not read console output from the file which is create by the child process.
*change rundir and cmd
#include <string>
#include <vector>
#include <utility>
#include <sstream>
#include <fstream>
#include <iostream>
#include <iterator>
#include <algorithm>
#include <functional>
#include <map>
#include <sys/stat.h>
#include <fcntl.h>
using namespace std;
int child();
int main()
{
string rundir = "/temp";
pid_t id =child();
string _xafile;
string _afile;
string _afilecmd;
string line;
stringstream ss(stringstream::in | stringstream::out);
ss<<int(id);
_xafile = rundir;
_xafile = _xafile + "/" + ss.str()+".stdout";
cout<<" _xafile is "<<_xafile<<endl;
string cmd ="cat "+ _xafile + ">" + rundir + "/" + "process.txt";
_afile = rundir;
_afile = _afile + "/" + "process.txt";
_afilecmd = "rm -rf "+ _afile;
system(cmd.c_str());
ifstream xafile(_afile.c_str());
while(xafile)
{
string word;
xafile >> word;
cout<<word<<" ";
/* try to read console output but did not read data */
}
system(_afilecmd.c_str());
return 0;
}
int child()
{
string rundir = "/tmp";
string cmd = " tool <input file> -o <outputfile>";
const char* std_out_file;
pid_t pid = fork();
if (pid < 0) {
return -1;
}
if (pid == 0) {
pid_t mypid = getpid();
stringstream sm;
sm << rundir << "/";
if (strlen(std_out_file) == 0)
sm << mypid << ".stdout";
else
sm << std_out_file;
int fd = open(sm.str().c_str(), O_WRONLY | O_CREAT | O_TRUNC, 0644);
dup2(fd, 1);
dup2(fd, 2);
int fd2 = open("/dev/zero", O_RDONLY);
dup2(fd2, 0);
cout<<cmd <<endl<<endl;
// execl("/bin/sh", "/bin/sh", "-c", cmd, NULL);
system(cmd.c_str());
/*When system call it generate console output like : your job submitted */
/* redirect to file */
exit(-1);
}
if (pid > 0)
return pid;
cout<<" child is done"<<endl;
return 0;
}

Answer 1

It's not entirely clear what your thinking is here - your code appears to fork a child which does a bunch of fancy io stuff to try and redirect your applications stdout to a file, and then runs a command with system(). The command in your code has it's own redirects, specifically via "-o" so it probably isn't writing to stdout.
Back in the parent process, you try to open for reading the same file your child process will open for writing. You've got no synchronization, so they could happen in any order. You appear to be trying to use "cat" to read the file and trying to read the stdout of the cat?
What I think you are actually trying to do is the C/C++ equivalent of Perl's
$foo = `ls -l /tmp`;
or something similar - to execute a command and capture the output.
A better way to do this would be to use pipes.
#include <iostream>
#include <fcntl.h>
#include <stdio.h>
#include <unistd.h>
enum { WritePipe = 1, ReadPipe = 0 };
int main(int argc, const char** argv)
{
int pipes[2]; // each process is going to have its own file descriptor.
if(pipe(pipes) != 0) {
perror("pipe failed");
return -1;
}
pid_t pid = fork();
if(pid == 0) {
// child
close(pipes[ReadPipe]); // close the parent pipe in our context.
// redirect stdout and stderr to the pipe.
dup2(pipes[WritePipe], STDOUT_FILENO);
dup2(pipes[WritePipe], STDERR_FILENO);
// close(STDERR_FILENO); // <- or just do this to close stderr.
int result = system("ls -ltr /etc");
close(pipes[WritePipe]);
return result;
}
if(pid < 0) {
perror("fork failed");
return -1;
}
// Parent process has launched the child.
close(pipes[WritePipe]);
char buffer[4097];
int bytesRead;
while((bytesRead = read(pipes[ReadPipe], buffer, sizeof(buffer) - 1)) > 0) {
buffer[bytesRead] = 0;
std::cout << buffer;
}
std::cout << std::endl;
close(pipes[ReadPipe]);
return 0;
}