Find text enclosed by # and replace the inside - regex

Question

The problem:
Find pieces of text in a file enclosed by # and replace the inside
Input:
#abc# abc #ABC#
cba #cba CBA#
Deisred output:
абц abc АБЦ
cba цба ЦБА
I have the following:
#!/usr/bin/perl
use strict;
use warnings;
use Encode;
my $output;
open FILE,"<", 'test.txt';
while (<FILE>) {
chomp(my #chars = split(//, $_));
for (#chars) {
my #char;
$_ =~ s/a/chr(0x430)/eg;
$_ =~ s/b/chr(0x431)/eg;
$_ =~ s/c/chr(0x446)/eg;
$_ =~ s/d/chr(0x434)/eg;
$_ =~ s/e/chr(0x435)/eg;
$_ =~ s/A/chr(0x410)/eg;
$_ =~ s/B/chr(0x411)/eg;
$_ =~ s/C/chr(0x426)/eg;
push #char, $_;
$output = join "", #char;
print encode("utf-8",$output);}
print "\n";
}
close FILE;
But I'm stuck on how to process further
Thanks for help in advance!
Kluther

Answer 1

Here my solution. (you will fixed it, yes. It is prototype)
for (my $data = <DATA>){
$data=~s/[#]([\s\w]+)[#]/func($1)/ge;
print $data;
# while($data=~m/[#]([\s\w]+)[#]/g){
# print "marked: ",$1,"\n";
# print "position:", pos();
# }
# print "not marked: ";
}
sub func{
#do your magic here ;)
return "<< #_ >>";
}
__DATA__
#abc# abc #ABC# cba #cba CBA#
What happens here?
First, I read data. You can do it yourself.
for (my $data = <DATA>){...}
Next, I need to search your pattern and replace it.
What should I do?
Use substition operator: s/pattern/replace/
But in interesting form:
s/pattern/func($1)/ge
Key g mean Global Search
Key e mean Evaluate
So, I think, that you need to write your own func function ;)
Maybe better to use transliteration operator: tr/listOfSymbolsToBeReplaced/listOfSymbolsThatBePlacedInstead/

Answer 2

With minimal changes to your algorithm you need to keep track of whether you are inside the #marks or not. so add something like this
my $bConvert = 0;
chomp(my #chars = split(//, $_));
for (#chars) {
my $char = $_;
if (/#/) {
$bConvert = ($bConvert + 1) % 2;
next;
}
elsif ($bConvert) {
$char =~ s/a/chr(0x430)/eg;
$char =~ s/b/chr(0x431)/eg;
$char =~ s/c/chr(0x446)/eg;
$char =~ s/d/chr(0x434)/eg;
$char =~ s/e/chr(0x435)/eg;
$char =~ s/A/chr(0x410)/eg;
$char =~ s/B/chr(0x411)/eg;
$char =~ s/C/chr(0x426)/eg;
}
print encode("utf-8",$char);
}

Answer 3

Try this after $output is processed.
$output =~ s/\#//g;
my #split_output = split(//, $output);
$output = "";
my $len = scalar(#split_output) ;
while ($len--) {
$output .= shift(#split_output);
}
print $output;

Answer 4

It can be done with a single regex and no splitting of the string:
use strict;
use warnings;
use Encode;
my %chars = (
a => chr(0x430),
b => chr(0x431),
c => chr(0x446),
d => chr(0x434),
e => chr(0x435),
A => chr(0x410),
B => chr(0x411),
C => chr(0x426),
);
my $regex = '(' . join ('|', keys %chars) . ')';
while (<DATA>) {
1 while ($_ =~ s|\#(?!\s)[^#]*?\K$regex(?=[^#]*(?!\s)\#)|$chars{$1}|eg);
print encode("utf-8",$_);
}
It does require repeated runs of the regex due to the overlapping nature of the matches.