I need to declare a fixed sequence of numbers. How do I do this?
For example, is it (I'm guessing here):
<xsl:element name="xsl:param">
<xsl:attribute name="name">MySequence</xsl:attribute>
<xsl:sequence>(1,2,3,4)</xsl:sequence>
</xsl:element>
or
<xsl:element name="xsl:param">
<xsl:attribute name="name">MySequence</xsl:attribute>
<xsl:sequence>1,2,3,4</xsl:sequence>
</xsl:element>
or what?
Thanks
If you're using XSLT 2.0, you can just create the sequence directly in the select like:
<xsl:param name="MySequence" select="('1','2','3','4')"/>
XSLT based verification...
XSLT 2.0
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:strip-space elements="*"/>
<xsl:param name="seq" select="('23453','74365','98','653')"/>
<xsl:template match="/">
<xsl:for-each select="$seq">
<xsl:value-of select="concat('Item ',position(),': ',.,'
')"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
applied to any XML input produces:
Item 1: 23453
Item 2: 74365
Item 3: 98
Item 4: 653
To build a sequence in the XSLT 2.0 sense you use a select e.g.
<xsl:sequence select="1 to 4" />
But if you're adding the value to an element you may prefer value-of
<xsl:value-of select="1 to 4" separator="," />
Given the snippet in the question, this would generate output XML of
<xsl:param name="MySequence">1,2,3,4</xsl:param>
Which makes the value of the generated param a comma separated string. If you actually want the param value to be a sequence in the generated XSLT then you need to generate a select attribute instead of using element content
<xsl:element name="xsl:param">
<xsl:attribute name="name" select="'MySequence'"/>
<xsl:attribute name="select">
<xsl:text>(</xsl:text>
<xsl:value-of select="1 to 4" separator=","/>
<xsl:text>)</xsl:text>
</xsl:attribute>
</xsl:element>
Giving output of
<xsl:param name="MySequence" select="(1,2,3,4)" />
Related
I have a large number of xml files with a structure similar to the following, although they are far larger:
<?xml version="1.0" encoding="UTF-8"?>
<a a1="3.0" a2="ABC">
<b b1="P1" b2="123">first
</b>
<b b1="P2" b2="456" b3="xyz">second
</b>
</a>
I want to get the following output:
1|1|b1
1|2|b2
2|1|b1
2|2|b2
2|3|b3
where:
Field 1 is the sequence number for nodes /a/b
Field 2 is the sequence number of the attribute as it appears in the xml file
Field 3 is the attribute name (not value)
I don't quite know how to calculate field 2 correctly.
I've prepared the following xslt file:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/">
<xsl:for-each select="a/b/#*">
<xsl:value-of select="count(../preceding-sibling::*)+1"/>
<xsl:text>|</xsl:text>
<!-- TODO: This is not correct -->
<xsl:value-of select="count(preceding-sibling::*)+1"/>
<xsl:text>|</xsl:text>
<xsl:value-of select="name()"/>
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
but when I run the following command:
xsltproc a.xslt a.xml > a.csv
I get an incorrect output, as field 2 does not represent the attribute sequence number:
1|1|b1
1|1|b2
2|1|b1
2|1|b2
2|1|b3
Do you have any suggestions on how to get the correct output please?
Please notice that the answers provided in XSLT to order attributes do not provide a solution to this problem.
The order of attributes is irrelevant in XML. For instance, <a a1="3.0" a2="ABC"> and <a a1="3.0" a2="ABC"> are equivalent.
However this specific question is part of a larger application where it is essential to establish the order in which attributes appear in given xml files (and not in xml files that are equivalent to them).
Although, as kjhughes says in comments, attribute order is insignificant. However, you can still select them, and use the position() element to get the numbers you are after (You just can't be sure the order they are output will be the order they appear in the XML, although generally this will be the case).
Try this XSLT. Do note the nested use of xsl:for-each to select only b elements first, to get their position, before getting the attributes, which then have their own separate position.
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" />
<xsl:template match="/">
<xsl:for-each select="a/b">
<xsl:variable name="bPosition" select="position()"/>
<xsl:for-each select="#*">
<xsl:value-of select="$bPosition"/>
<xsl:text>|</xsl:text>
<xsl:value-of select="position()"/>
<xsl:text>|</xsl:text>
<xsl:value-of select="name()"/>
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
You could use the position() of the items in the sequence of attributes that you are iterating over and combine with logic for the position of its parent element.
<xsl:template match="/">
<xsl:for-each select="a/b/#*">
<xsl:value-of select="count(../preceding-sibling::*)+1"/>
<xsl:text>|</xsl:text>
<!-- TODO: This is not correct -->
<xsl:value-of select="position() -
(if (count(../preceding-sibling::*)) then count(../preceding-sibling::*)+1 else 0)"/>
<xsl:text>|</xsl:text>
<xsl:value-of select="name()"/>
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
Which produces the following output:
1|1|b1
1|2|b2
2|1|b1
2|2|b2
2|3|b3
I am trying to merge the elements from two separate web.xml files using XSLT. For example, if web-1.xml and web-2.xml are being merged, and I'm processing web-1.xml, I want all elements in web-2.xml to be added into the result, except any that already exist in web-1.xml.
In the XSLT sheet, I have loaded the document whose servlet's are to be merged into the other document using:
<xsl:variable name="jandy" select="document('web-2.xml')"/>
I then have the following rule:
<xsl:template match="webapp:web-app">
<xsl:copy>
<!-- Copy all of the existing content from the document being processed -->
<xsl:apply-templates/>
<!-- Merge any <servlet> elements that don't already exist into the result -->
<xsl:for-each select="$jandy/webapp:web-app/webapp:servlet">
<xsl:variable name="servlet-name"><xsl:value-of select="webapp:servlet-name"/></xsl:variable>
<xsl:if test="not(/webapp:web-app/webapp:servlet/webapp:servlet-name[text() = $servlet-name])">
<xsl:copy-of select="."/>
</xsl:if>
</xsl:for-each>
</xsl:copy>
</xsl:template>
The problem I'm having is getting the test in the if correct. With the above code, the test always evaluates to false, whether a servlet-name element with the given node exists or not. I have tried all kinds of different tests but with no luck.
The relevant files are available at http://www.cs.hope.edu/~mcfall/stackoverflow/web-1.xml, and http://www.cs.hope.edu/~mcfall/stackoverflow/transform.xslt (the second web-2.xml is there as well, but StackOverflow won't let me post three links).
provide an anchor for the first document, just before the for-each loop:
<xsl:variable name="var" select="."/>
then, use it in your if:
<xsl:if test="not($var/webapp:servlet/webapp:servlet-name[text() = $servlet-name])">
Your template matches XPATH webapp:webapp from web-1.xml and
you are refencing absolute XPATH if your xsl:if condition: /webapp:web-app/webapp:servlet/webapp:servlet-name[text() = $servlet-name]. Try to do it using relative XPATH:
<xsl:if test="not(webapp:servlet/webapp:servlet-name[text() = $servlet-name])">
<xsl:copy-of select="."/>
</xsl:if>
I haven't checked it, so you have to give it a try.
Also, it would be easier if you could provide web-1.xml and web-2.xml files.
EDIT
The following XSLT merges two files - the only problem appears when there are sections of the same type (like listener) in two places of the input XML.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:webapp="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xpath-default-namespace="http://java.sun.com/xml/ns/javaee">
<xsl:output indent="yes"/>
<xsl:variable name="jandy" select="document('web-2.xml')"/>
<xsl:template match="/">
<xsl:element name="web-app">
<xsl:for-each select="webapp:web-app/*[(name() != preceding-sibling::node()[1]/name()) or (position() = 1)]">
<xsl:variable name="nodeName" select="./name()"/>
<xsl:variable name="web1" as="node()*">
<xsl:sequence select="/webapp:web-app/*[name()=$nodeName]"/>
</xsl:variable>
<xsl:variable name="web2" as="node()*">
<xsl:sequence select="$jandy/webapp:web-app/*[name() = $nodeName]"/>
</xsl:variable>
<xsl:copy-of select="$web1" copy-namespaces="no"/>
<xsl:for-each select="$web2">
<xsl:variable name="text" select="./*[1]/text()"/>
<xsl:if test="count($web1[*[1]/text() = $text]) = 0">
<xsl:copy-of select="." copy-namespaces="no"/>
</xsl:if>
</xsl:for-each>
</xsl:for-each>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
If have a big 'xsl:choose' chunk in which I need to set a number of defined sets of attributes on different elements.
I really do not like to repeat the definition of sets of attributes inside every branch of the 'choose'.
So I would like to work with a variable that contains those attributes.
A lot easier to maintain and less room for error...
So far I have not been able to call the attribute node out?
I thought they are just a node-set, so copy-of would do the trick.
But that gives me nothing on output.
Is this because attribute nodes are not really children?
But XSLT 1.O does not allow me to address them directly...<xsl:copy-of select="$attributes_body/#*/> returns an error
Here is the stylesheet fragment (reduced from original)
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="list">
<xsl:for-each select="figure">
<xsl:variable name="attributes_body">
<xsl:attribute name="chapter"><xsl:value-of select="#chapter"/></xsl:attribute>
<xsl:attribute name="id"><xsl:value-of select="#id"/></xsl:attribute>
</xsl:variable>
<xsl:variable name="attributes_other">
<xsl:attribute name="chapter"><xsl:value-of select="#book"/></xsl:attribute>
<xsl:attribute name="id"><xsl:value-of select="#id"/></xsl:attribute>
</xsl:variable>
<xsl:choose>
<xsl:when test="ancestor::body">
<xsl:element name="entry">
<xsl:copy-of select="$attributes_body"/>
<xsl:text>Body fig</xsl:text>
</xsl:element>
</xsl:when>
<xsl:otherwise>
<xsl:element name="entry">
<xsl:copy-of select="$attributes_other"/>
<xsl:text>other fig</xsl:text>
</xsl:element>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</xsl:template>
If this can not be done in XLST 1.0 would 2.0 be able to do this?
<xsl:variable name="attributes_body">
<xsl:attribute name="chapter"><xsl:value-of select="#chapter"/></xsl:attribute>
<xsl:attribute name="id"><xsl:value-of select="#id"/></xsl:attribute>
</xsl:variable>
You need to select the wanted attributes -- not to copy their contents in the body of the variable.
Remember: Whenever possible, try always to specify an XPath expression in the select attribute of xsl:variable -- avoid copying content in its body.
Solution:
Just use:
<xsl:variable name="attributes_body" select="#chapter | #id">
Here is a complete example:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="x/a">
<xsl:variable name="vAttribs" select="#m | #n"/>
<newEntry>
<xsl:copy-of select="$vAttribs"/>
<xsl:value-of select="."/>
</newEntry>
</xsl:template>
</xsl:stylesheet>
when applied on this:
<x>
<a m="1" n="2" p="3">zzz</a>
</x>
produces:
<newEntry m="1" n="2">zzz</newEntry>
in my case, I was trying to store a tag attribute into a variable
to do so, use this syntax tag-name/#attribute-inside-tag-name
here is an example
<xsl:variable name="articleLanguage" select="/article/#language"/><!--the tricky part -->
//<!--now you can use this this varialbe as you like -->
<xsl:apply-templates select="front/article-meta/kwd-group[#language=$articleLanguage]"/>
and the xml was
<article article-type="research-article" language="es" explicit-lang="es" dtd-version="1.0">
.....
hope this help you
I have an XML file which has some values in child Element aswell in attributes.
If i want to replace some text when specific value is matched how can i achieve it?
I tried using xlst:translate() function. But i cant use this function for each element or attribute in xml.
So is there anyway to replace/translate value at one shot?
<?xml version="1.0" encoding="UTF-8"?>
<Employee>
<Name>Emp1</Name>
<Age>40</Age>
<sex>M</sex>
<Address>Canada</Address>
<PersonalInformation>
<Country>Canada</country>
<Street1>KO 92</Street1>
</PersonalInformation>
</Employee>
Output :
<?xml version="1.0" encoding="UTF-8"?>
<Employee>
<Name>Emp1</Name>
<Age>40</Age>
<sex>M</sex>
<Address>UnitedStates</Address>
<PersonalInformation>
<Country>UnitedStates</country>
<Street1>KO 92</Street1>
</PersonalInformation>
</Employee>
in the output, replaced text from Canada to UnitedStates.
so, without using xslt:transform() functions on any element , i should be able to replace text Canada to UnitedStates irrespective of level nodes.
Where ever i find 'Canada' i should be able to replace to 'UnitedStates' in entire xml.
So how can i achieve this.?
I. XSLT 1.0 solution:
This transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:my="my:my" >
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<my:Reps>
<rep>
<old>replace this</old>
<new>replaced</new>
</rep>
<rep>
<old>cat</old>
<new>tiger</new>
</rep>
</my:Reps>
<xsl:variable name="vReps" select=
"document('')/*/my:Reps/*"/>
<xsl:template match="node()|#*" name="identity">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="#*">
<xsl:attribute name="{name()}">
<xsl:call-template name="replace">
<xsl:with-param name="pText" select="."/>
</xsl:call-template>
</xsl:attribute>
</xsl:template>
<xsl:template match="text()" name="replace">
<xsl:param name="pText" select="."/>
<xsl:if test="string-length($pText)">
<xsl:choose>
<xsl:when test=
"not($vReps/old[contains($pText, .)])">
<xsl:copy-of select="$pText"/>
</xsl:when>
<xsl:otherwise>
<xsl:variable name="vthisRep" select=
"$vReps/old[contains($pText, .)][1]
"/>
<xsl:variable name="vNewText">
<xsl:value-of
select="substring-before($pText, $vthisRep)"/>
<xsl:value-of select="$vthisRep/../new"/>
<xsl:value-of select=
"substring-after($pText, $vthisRep)"/>
</xsl:variable>
<xsl:call-template name="replace">
<xsl:with-param name="pText"
select="$vNewText"/>
</xsl:call-template>
</xsl:otherwise>
</xsl:choose>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
when applied on this XML document:
<t>
<a attr1="X replace this Y">
<b>cat mouse replace this cat dog</b>
</a>
<c/>
</t>
produces the wanted, correct result:
<t>
<a attr1="X replaced Y">
<b>tiger mouse replaced tiger dog</b>
</a>
<c/>
</t>
Explanation:
The identity rule is used to copy "as-is" some nodes.
We perform multiple replacements, parameterized in my:Reps
If a text node or an attribute doesn't contain any rep-target, it is copied as-is.
If a text node or an attribute contains text to be replaced (rep target), then the replacements are done in the order specified in my:Reps
If the string contains more than one string target, then all targets are replaced: first all occurences of the first rep target, then all occurences of the second rep target, ..., last all occurences of the last rep target.
II. XSLT 2.0 solution:
In XSLT 2.0 one can simply use the standard XPath 2.0 function replace(). However, for multiple replacements the solution would be still very similar to the XSLT 1.0 solution specified above.
Hi
I need get array of elements (before "-" if exist) by xsl.
xml is
<Cars>
<Car Trunck="511"/>
<Car Trunck="483-20"/>
<Car Trunck="745"/>
</Cars>
xsl is
<xsl:variable name="testarr">
<xsl:for-each select="//Cars//Car/#Trunck">
<xsl:value-of select="number(substring(.,1,3))" />
</xsl:for-each>
</xsl:variable>
(i suppose that all numbers is three-digit number, if someone knows a solution for all conditions will be glad to hear the proposal)
if i do this
i get all numbers in one line: 511483745
and i need get them in array
because i also need get the max value
thanks
Hi I need get array of elements
(before "-" if exist) [...] i need get
them in array because i also need get
the max value
This stylesheet:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:for-each select="/Cars/Car/#Trunck">
<xsl:sort select="concat(substring-before(.,'-'),
substring(., 1 div not(contains(.,'-'))))"
data-type="number" order="descending"/>
<xsl:if test="position()=1">
<xsl:value-of
select="concat(substring-before(.,'-'),
substring(.,1 div not(contains(.,'-'))))"/>
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Output:
745
XPath 2.0 one line:
max(/Cars/Car/#Trunck/number(replace(.,'-.*','')))
You could use the substring-before and substring-after functions: See the excellent ZVON tutorial
http://zvon.org/xxl/XSLTreference/Output/function_substring-after.html
In your example you are only extracting the values (which are strings) which get concatenated. Perhaps you need to wrap the result in your own element
<xsl:for-each select="//Cars//Car/#Trunck">
<truck>
<xsl:value-of select="number(substring(.,1,3))" />
</truck>
</xsl:for-each>
While you have two good answers (especially that by #Alejandro), here's one from me that I think is even better:
This transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:param name="pTopNums" select="2"/>
<xsl:template match="/*">
<xsl:apply-templates select="*">
<xsl:sort data-type="number" order="descending"
select="substring-before(concat(#Trunck,'-'),'-')"/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="Car">
<xsl:if test="not(position() > $pTopNums)">
<xsl:value-of select=
"substring-before(concat(#Trunck,'-'),'-')"/>
<xsl:text>
</xsl:text>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
when applied on this XML document (the originally provided one, slightly changed to be more challenging):
<Cars>
<Car Trunck="483-20"/>
<Car Trunck="311"/>
<Car Trunck="745"/>
</Cars>
produces the wanted, correct result (the top two numbers that are derived from #Trunck as specified in the question):
745
483