xsl get array of elements - xslt

Hi
I need get array of elements (before "-" if exist) by xsl.
xml is
<Cars>
<Car Trunck="511"/>
<Car Trunck="483-20"/>
<Car Trunck="745"/>
</Cars>
xsl is
<xsl:variable name="testarr">
<xsl:for-each select="//Cars//Car/#Trunck">
<xsl:value-of select="number(substring(.,1,3))" />
</xsl:for-each>
</xsl:variable>
(i suppose that all numbers is three-digit number, if someone knows a solution for all conditions will be glad to hear the proposal)
if i do this
i get all numbers in one line: 511483745
and i need get them in array
because i also need get the max value
thanks

Hi I need get array of elements
(before "-" if exist) [...] i need get
them in array because i also need get
the max value
This stylesheet:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:for-each select="/Cars/Car/#Trunck">
<xsl:sort select="concat(substring-before(.,'-'),
substring(., 1 div not(contains(.,'-'))))"
data-type="number" order="descending"/>
<xsl:if test="position()=1">
<xsl:value-of
select="concat(substring-before(.,'-'),
substring(.,1 div not(contains(.,'-'))))"/>
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Output:
745
XPath 2.0 one line:
max(/Cars/Car/#Trunck/number(replace(.,'-.*','')))

You could use the substring-before and substring-after functions: See the excellent ZVON tutorial
http://zvon.org/xxl/XSLTreference/Output/function_substring-after.html
In your example you are only extracting the values (which are strings) which get concatenated. Perhaps you need to wrap the result in your own element
<xsl:for-each select="//Cars//Car/#Trunck">
<truck>
<xsl:value-of select="number(substring(.,1,3))" />
</truck>
</xsl:for-each>

While you have two good answers (especially that by #Alejandro), here's one from me that I think is even better:
This transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:param name="pTopNums" select="2"/>
<xsl:template match="/*">
<xsl:apply-templates select="*">
<xsl:sort data-type="number" order="descending"
select="substring-before(concat(#Trunck,'-'),'-')"/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="Car">
<xsl:if test="not(position() > $pTopNums)">
<xsl:value-of select=
"substring-before(concat(#Trunck,'-'),'-')"/>
<xsl:text>
</xsl:text>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
when applied on this XML document (the originally provided one, slightly changed to be more challenging):
<Cars>
<Car Trunck="483-20"/>
<Car Trunck="311"/>
<Car Trunck="745"/>
</Cars>
produces the wanted, correct result (the top two numbers that are derived from #Trunck as specified in the question):
745
483

Related

XSLT List attributes in the order they appear in the xml file

I have a large number of xml files with a structure similar to the following, although they are far larger:
<?xml version="1.0" encoding="UTF-8"?>
<a a1="3.0" a2="ABC">
<b b1="P1" b2="123">first
</b>
<b b1="P2" b2="456" b3="xyz">second
</b>
</a>
I want to get the following output:
1|1|b1
1|2|b2
2|1|b1
2|2|b2
2|3|b3
where:
Field 1 is the sequence number for nodes /a/b
Field 2 is the sequence number of the attribute as it appears in the xml file
Field 3 is the attribute name (not value)
I don't quite know how to calculate field 2 correctly.
I've prepared the following xslt file:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/">
<xsl:for-each select="a/b/#*">
<xsl:value-of select="count(../preceding-sibling::*)+1"/>
<xsl:text>|</xsl:text>
<!-- TODO: This is not correct -->
<xsl:value-of select="count(preceding-sibling::*)+1"/>
<xsl:text>|</xsl:text>
<xsl:value-of select="name()"/>
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
but when I run the following command:
xsltproc a.xslt a.xml > a.csv
I get an incorrect output, as field 2 does not represent the attribute sequence number:
1|1|b1
1|1|b2
2|1|b1
2|1|b2
2|1|b3
Do you have any suggestions on how to get the correct output please?
Please notice that the answers provided in XSLT to order attributes do not provide a solution to this problem.
The order of attributes is irrelevant in XML. For instance, <a a1="3.0" a2="ABC"> and <a a1="3.0" a2="ABC"> are equivalent.
However this specific question is part of a larger application where it is essential to establish the order in which attributes appear in given xml files (and not in xml files that are equivalent to them).
Although, as kjhughes says in comments, attribute order is insignificant. However, you can still select them, and use the position() element to get the numbers you are after (You just can't be sure the order they are output will be the order they appear in the XML, although generally this will be the case).
Try this XSLT. Do note the nested use of xsl:for-each to select only b elements first, to get their position, before getting the attributes, which then have their own separate position.
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" />
<xsl:template match="/">
<xsl:for-each select="a/b">
<xsl:variable name="bPosition" select="position()"/>
<xsl:for-each select="#*">
<xsl:value-of select="$bPosition"/>
<xsl:text>|</xsl:text>
<xsl:value-of select="position()"/>
<xsl:text>|</xsl:text>
<xsl:value-of select="name()"/>
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
You could use the position() of the items in the sequence of attributes that you are iterating over and combine with logic for the position of its parent element.
<xsl:template match="/">
<xsl:for-each select="a/b/#*">
<xsl:value-of select="count(../preceding-sibling::*)+1"/>
<xsl:text>|</xsl:text>
<!-- TODO: This is not correct -->
<xsl:value-of select="position() -
(if (count(../preceding-sibling::*)) then count(../preceding-sibling::*)+1 else 0)"/>
<xsl:text>|</xsl:text>
<xsl:value-of select="name()"/>
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
Which produces the following output:
1|1|b1
1|2|b2
2|1|b1
2|2|b2
2|3|b3

check for successively numbered attributes

I have a situation where I need to check for attribute values that may be successively numbered and input a dash between the start and end values.
<root>
<ref id="value00008 value00009 value00010 value00011 value00020"/>
</root>
The ideal output would be...
8-11, 20
I can tokenize the attribute into separate values, but I'm unsure how to check if the number at the end of "valueXXXXX" is successive to the previous value.
I'm using XSLT 2.0
You can use xsl:for-each-group with #group-adjacent testing for the number() value subtracting the position().
This trick was apparently invented by David Carlisle, according to Michael Kay.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0">
<xsl:output indent="yes"/>
<xsl:template match="/">
<xsl:variable name="vals"
select="tokenize(root/ref/#id, '\s?value0*')[normalize-space()]"/>
<xsl:variable name="condensed-values" as="item()*">
<xsl:for-each-group select="$vals"
group-adjacent="number(.) - position()">
<xsl:choose>
<xsl:when test="count(current-group()) > 1">
<!--a sequence of successive numbers,
grab the first and last one and join with '-' -->
<xsl:sequence select="
string-join(current-group()[position()=1
or position()=last()]
,'-')"/>
</xsl:when>
<xsl:otherwise>
<!--single value group-->
<xsl:sequence select="current-group()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each-group>
</xsl:variable>
<xsl:value-of select="string-join($condensed-values, ',')"/>
</xsl:template>
</xsl:stylesheet>

How to declare a sequence in XSLT?

I need to declare a fixed sequence of numbers. How do I do this?
For example, is it (I'm guessing here):
<xsl:element name="xsl:param">
<xsl:attribute name="name">MySequence</xsl:attribute>
<xsl:sequence>(1,2,3,4)</xsl:sequence>
</xsl:element>
or
<xsl:element name="xsl:param">
<xsl:attribute name="name">MySequence</xsl:attribute>
<xsl:sequence>1,2,3,4</xsl:sequence>
</xsl:element>
or what?
Thanks
If you're using XSLT 2.0, you can just create the sequence directly in the select like:
<xsl:param name="MySequence" select="('1','2','3','4')"/>
XSLT based verification...
XSLT 2.0
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:strip-space elements="*"/>
<xsl:param name="seq" select="('23453','74365','98','653')"/>
<xsl:template match="/">
<xsl:for-each select="$seq">
<xsl:value-of select="concat('Item ',position(),': ',.,'
')"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
applied to any XML input produces:
Item 1: 23453
Item 2: 74365
Item 3: 98
Item 4: 653
To build a sequence in the XSLT 2.0 sense you use a select e.g.
<xsl:sequence select="1 to 4" />
But if you're adding the value to an element you may prefer value-of
<xsl:value-of select="1 to 4" separator="," />
Given the snippet in the question, this would generate output XML of
<xsl:param name="MySequence">1,2,3,4</xsl:param>
Which makes the value of the generated param a comma separated string. If you actually want the param value to be a sequence in the generated XSLT then you need to generate a select attribute instead of using element content
<xsl:element name="xsl:param">
<xsl:attribute name="name" select="'MySequence'"/>
<xsl:attribute name="select">
<xsl:text>(</xsl:text>
<xsl:value-of select="1 to 4" separator=","/>
<xsl:text>)</xsl:text>
</xsl:attribute>
</xsl:element>
Giving output of
<xsl:param name="MySequence" select="(1,2,3,4)" />

Testing whether a node with particular content exists using xslt

I am trying to merge the elements from two separate web.xml files using XSLT. For example, if web-1.xml and web-2.xml are being merged, and I'm processing web-1.xml, I want all elements in web-2.xml to be added into the result, except any that already exist in web-1.xml.
In the XSLT sheet, I have loaded the document whose servlet's are to be merged into the other document using:
<xsl:variable name="jandy" select="document('web-2.xml')"/>
I then have the following rule:
<xsl:template match="webapp:web-app">
<xsl:copy>
<!-- Copy all of the existing content from the document being processed -->
<xsl:apply-templates/>
<!-- Merge any <servlet> elements that don't already exist into the result -->
<xsl:for-each select="$jandy/webapp:web-app/webapp:servlet">
<xsl:variable name="servlet-name"><xsl:value-of select="webapp:servlet-name"/></xsl:variable>
<xsl:if test="not(/webapp:web-app/webapp:servlet/webapp:servlet-name[text() = $servlet-name])">
<xsl:copy-of select="."/>
</xsl:if>
</xsl:for-each>
</xsl:copy>
</xsl:template>
The problem I'm having is getting the test in the if correct. With the above code, the test always evaluates to false, whether a servlet-name element with the given node exists or not. I have tried all kinds of different tests but with no luck.
The relevant files are available at http://www.cs.hope.edu/~mcfall/stackoverflow/web-1.xml, and http://www.cs.hope.edu/~mcfall/stackoverflow/transform.xslt (the second web-2.xml is there as well, but StackOverflow won't let me post three links).
provide an anchor for the first document, just before the for-each loop:
<xsl:variable name="var" select="."/>
then, use it in your if:
<xsl:if test="not($var/webapp:servlet/webapp:servlet-name[text() = $servlet-name])">
Your template matches XPATH webapp:webapp from web-1.xml and
you are refencing absolute XPATH if your xsl:if condition: /webapp:web-app/webapp:servlet/webapp:servlet-name[text() = $servlet-name]. Try to do it using relative XPATH:
<xsl:if test="not(webapp:servlet/webapp:servlet-name[text() = $servlet-name])">
<xsl:copy-of select="."/>
</xsl:if>
I haven't checked it, so you have to give it a try.
Also, it would be easier if you could provide web-1.xml and web-2.xml files.
EDIT
The following XSLT merges two files - the only problem appears when there are sections of the same type (like listener) in two places of the input XML.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:webapp="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xpath-default-namespace="http://java.sun.com/xml/ns/javaee">
<xsl:output indent="yes"/>
<xsl:variable name="jandy" select="document('web-2.xml')"/>
<xsl:template match="/">
<xsl:element name="web-app">
<xsl:for-each select="webapp:web-app/*[(name() != preceding-sibling::node()[1]/name()) or (position() = 1)]">
<xsl:variable name="nodeName" select="./name()"/>
<xsl:variable name="web1" as="node()*">
<xsl:sequence select="/webapp:web-app/*[name()=$nodeName]"/>
</xsl:variable>
<xsl:variable name="web2" as="node()*">
<xsl:sequence select="$jandy/webapp:web-app/*[name() = $nodeName]"/>
</xsl:variable>
<xsl:copy-of select="$web1" copy-namespaces="no"/>
<xsl:for-each select="$web2">
<xsl:variable name="text" select="./*[1]/text()"/>
<xsl:if test="count($web1[*[1]/text() = $text]) = 0">
<xsl:copy-of select="." copy-namespaces="no"/>
</xsl:if>
</xsl:for-each>
</xsl:for-each>
</xsl:element>
</xsl:template>
</xsl:stylesheet>

simple loop in xslt

Having trouble figuring out a simple XSLT loop that counts and returns the name of the actor.
<stars>
<star ID="001">Leonardo DiCaprio</star>
<star ID="002">Matt Damon</star>
<star ID="003">Jack Nicholson</star>
</stars>
This is what I made to give the result I wanted but if there was a fourth or fifth actor I would need to add to the code.
<xsl:value-of select="stars/star[#ID='001']"/>
<xsl:text>, </xsl:text>
<xsl:value-of select="stars/star[#ID='002']"/>
<xsl:text>, </xsl:text>
<xsl:value-of select="stars/star[#ID='003']"/>
Basically I need the loop to display the name of the star separated by a comma. Any help is appreciated.
Use a template instead of looping. XSLT processors are optimized for template matching.
<xsl:template match="star">
<xsl:value-of select="." />
<xsl:if test="position() != last()">
<xsl:text>, </xsl:text>
</xsl:if>
</xsl:template>
You can use repetition instruction (without any worry about performance):
<xsl:template match="stars">
<xsl:value-of select="star[1]"/>
<xsl:for-each select="star[position()>1]">
<xsl:value-of select="concat(', ',.)"/>
</xsl:for-each>
</xsl:template>
gets:
Leonardo DiCaprio, Matt Damon, Jack Nicholson
This is probably one of the simplest transformations -- note that there is neither need for xsl:for-each nor for any explicit XSLT conditional instruction:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:strip-space elements="*"/>
<xsl:template match="star[position() >1]">
<xsl:text>, </xsl:text><xsl:apply-templates/>
</xsl:template>
</xsl:stylesheet>
when applied on the provided source XML document:
<stars>
<star ID="001">Leonardo DiCaprio</star>
<star ID="002">Matt Damon</star>
<star ID="003">Jack Nicholson</star>
</stars>
the wanted, correct output is produced:
Leonardo DiCaprio, Matt Damon, Jack Nicholson