I have these images to compare with each other. However, there are too many blacks that I think I can crop out to make comparison more effective.
What I want to do is crop Mars. Rectangle or round whichever may yield better results when compared. I was worrying that if the cropping would result to images of different sizes, comparison wouldn't work out as well as expected? Ideas how to do it and sample codes if possible? Thanks in advance
UPDATE: Tried using cvHoughCircles() it won't detect the planet :/
Try to use color detection. You need to find all the colors except black. Here and here are nice explanations of this method.
You can convert these images to gray scale images using cvCvtColor(img,imgGrayScale,CV_BGR2GRAY)
Then threshold them using cvThreshold(imgGrayScale,imgThresh,x,255,CV_THRESH_BINARY). Here, you have to find a good value for x(I think x=50 is ok).
CvMoments *moments = (CvMoments*)malloc(sizeof(CvMoments));
cvMoments(imgThresh, moments, 1);
double moment10 = cvGetSpatialMoment(moments, 1, 0);
double moment01 = cvGetSpatialMoment(moments, 0, 1);
double area = cvGetCentralMoment(moments, 0, 0);
int x = moment10/area;
int y = moment01/area;
Now you know the (x.y) coordinate of the blob. Then you can crop the image using cvSetImageROI(imgThresh, cvRect(x-10, y-10, x+10, y+10)). Here I have assumed that the radius of this blob is less than 10 pixel.
All cropped images are of same size and the white blob (planet) is exactly at the middle of the image.
Then you can compare images using normalized cross-correlation.
There's no fundamental reason why a histogram would fail here. I would convert the image to greyscale before doing a histogram, just to make the numbers more manageable. A color image has a 3D histogram; the Red, Green, Blue and Greyscale histograms are all 1D projections of that 3D histogram.
Related
I have a camera and a lamp.
The camera takes pictures automatically and the lamp is rigid.
Each of my pictures has a bright spot in the middle and is getting darker on the outside (linear).
Is there an easy way to darken the middle, or brighten the outside to accommodate this (preferably with a gradient)?
I am using OpenCV with the C++ API.
Thank you for the help.
It's hard to say what exactly you want to do without an example. However, let's assume the effect is exactly the same in all images and you want to apply the same transformation to each of them.
You say the effect is linear, and assume you want to make the center darker by let's say 20% and the pixel furthest from the center brighter by 20%. Let's further assume the optical center is in the center of the image (needn't be true in practice).
So you have an image cv::Mat img; you want to manipulate, and I assume it contains data of type CV_32F (if not float or double-valued, convert, can be more than one channel). You create another cv::Mat
//first, make a mask image to multiply the image with
cv::Mat mask = cv::Mat::zeros(img.rows,img.cols,CV_32F);
float maxdist = std::sqrt(img.rows*img.rows+img.cols*img.cols)/2;
cv::Point2f center(img.cols*0.5,img.rows*0.5);
for (int j=0;j<img.rows;++j)
for (int i=0;i<img.cols;++i)
{
cv::Point2f p(i,j);
cv::Point2f diff(p-center);
float dist(std::sqrt(diff.dot(diff)));
float factor(0.8+0.4*dist/maxdist);
mask.at<float>(j,i) = factor;
}
//apply the transformation, to as many images as you like
img = img.mul(mask);
This doesn't check for overflows, you may or may not want to do this afterwards. But from your question, it would be a simple way to do this.
What I need
I'm currently working on an augmented reality kinda game. The controller that the game uses (I'm talking about the physical input device here) is a mono colored, rectangluar pice of paper. I have to detect the position, rotation and size of that rectangle in the capture stream of the camera. The detection should be invariant on scale and invariant on rotation along the X and Y axes.
The scale invariance is needed in case that the user moves the paper away or towards the camera. I don't need to know the distance of the rectangle so scale invariance translates to size invariance.
The rotation invariance is needed in case the user tilts the rectangle along its local X and / or Y axis. Such a rotation changes the shape of the paper from rectangle to trapezoid. In this case, the object oriented bounding box can be used to measure the size of the paper.
What I've done
At the beginning there is a calibration step. A window shows the camera feed and the user has to click on the rectangle. On click, the color of the pixel the mouse is pointing at is taken as reference color. The frames are converted into HSV color space to improve color distinguishing. I have 6 sliders that adjust the upper and lower thresholds for each channel. These thresholds are used to binarize the image (using opencv's inRange function).
After that I'm eroding and dilating the binary image to remove noise and unite nerby chunks (using opencv's erode and dilate functions).
The next step is finding contours (using opencv's findContours function) in the binary image. These contours are used to detect the smallest oriented rectangles (using opencv's minAreaRect function). As final result I'm using the rectangle with the largest area.
A short conclusion of the procedure:
Grab a frame
Convert that frame to HSV
Binarize it (using the color that the user selected and the thresholds from the sliders)
Apply morph ops (erode and dilate)
Find contours
Get the smallest oriented bouding box of each contour
Take the largest of those bounding boxes as result
As you may noticed, I don't make an advantage of the knowledge about the actual shape of the paper, simply because I don't know how to use this information properly.
I've also thought about using the tracking algorithms of opencv. But there were three reasons that prevented me from using them:
Scale invariance: as far as I read about some of the algorithms, some don't support different scales of the object.
Movement prediction: some algorithms use movement prediction for better performance, but the object I'm tracking moves completely random and therefore unpredictable.
Simplicity: I'm just looking for a mono colored rectangle in an image, nothing fancy like car or person tracking.
Here is a - relatively - good catch (binary image after erode and dilate)
and here is a bad one
The Question
How can I improve the detection in general and especially to be more resistant against lighting changes?
Update
Here are some raw images for testing.
Can't you just use thicker material?
Yes I can and I already do (unfortunately I can't access these pieces at the moment). However, the problem still remains. Even if I use material like cartboard. It isn't bent as easy as paper, but one can still bend it.
How do you get the size, rotation and position of the rectangle?
The minAreaRect function of opencv returns a RotatedRect object. This object contains all the data I need.
Note
Because the rectangle is mono colored, there is no possibility to distinguish between top and bottom or left and right. This means that the rotation is always in range [0, 180] which is perfectly fine for my purposes. The ratio of the two sides of the rect is always w:h > 2:1. If the rectangle would be a square, the range of roation would change to [0, 90], but this can be considered irrelevant here.
As suggested in the comments I will try histogram equalization to reduce brightness issues and take a look at ORB, SURF and SIFT.
I will update on progress.
The H channel in the HSV space is the Hue, and it is not sensitive to the light changing. Red range in about [150,180].
Based on the mentioned information, I do the following works.
Change into the HSV space, split the H channel, threshold and normalize it.
Apply morph ops (open)
Find contours, filter by some properties( width, height, area, ratio and so on).
PS. I cannot fetch the image you upload on the dropbox because of the NETWORK. So, I just use crop the right side of your second image as the input.
imgname = "src.png"
img = cv2.imread(imgname)
gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)
## Split the H channel in HSV, and get the red range
hsv = cv2.cvtColor(img, cv2.COLOR_BGR2HSV)
h,s,v = cv2.split(hsv)
h[h<150]=0
h[h>180]=0
## normalize, do the open-morp-op
normed = cv2.normalize(h, None, 0, 255, cv2.NORM_MINMAX, cv2.CV_8UC1)
kernel = cv2.getStructuringElement(shape=cv2.MORPH_ELLIPSE, ksize=(3,3))
opened = cv2.morphologyEx(normed, cv2.MORPH_OPEN, kernel)
res = np.hstack((h, normed, opened))
cv2.imwrite("tmp1.png", res)
Now, we get the result as this (h, normed, opened):
Then find contours and filter them.
contours = cv2.findContours(opened, cv2.RETR_LIST, cv2.CHAIN_APPROX_SIMPLE)
print(len(contours))[-2]
bboxes = []
rboxes = []
cnts = []
dst = img.copy()
for cnt in contours:
## Get the stright bounding rect
bbox = cv2.boundingRect(cnt)
x,y,w,h = bbox
if w<30 or h < 30 or w*h < 2000 or w > 500:
continue
## Draw rect
cv2.rectangle(dst, (x,y), (x+w,y+h), (255,0,0), 1, 16)
## Get the rotated rect
rbox = cv2.minAreaRect(cnt)
(cx,cy), (w,h), rot_angle = rbox
print("rot_angle:", rot_angle)
## backup
bboxes.append(bbox)
rboxes.append(rbox)
cnts.append(cnt)
The result is like this:
rot_angle: -2.4540319442749023
rot_angle: -1.8476102352142334
Because the blue rectangle tag in the source image, the card is splited into two sides. But a clean image will have no problem.
I know it's been a while since I asked the question. I recently continued on the topic and solved my problem (although not through rectangle detection).
Changes
Using wood to strengthen my controllers (the "rectangles") like below.
Placed 2 ArUco markers on each controller.
How it works
Convert the frame to grayscale,
downsample it (to increase performance during detection),
equalize the histogram using cv::equalizeHist,
find markers using cv::aruco::detectMarkers,
correlate markers (if multiple controllers),
analyze markers (position and rotation),
compute result and apply some error correction.
It turned out that the marker detection is very robust to lighting changes and different viewing angles which allows me to skip any calibration steps.
I placed 2 markers on each controller to increase the detection robustness even more. Both markers has to be detected only one time (to measure how they correlate). After that, it's sufficient to find only one marker per controller as the other can be extrapolated from the previously computed correlation.
Here is a detection result in a bright environment:
in a darker environment:
and when hiding one of the markers (the blue point indicates the extrapolated marker postition):
Failures
The initial shape detection that I implemented didn't perform well. It was very fragile to lighting changes. Furthermore, it required an initial calibration step.
After the shape detection approach I tried SIFT and ORB in combination with brute force and knn matcher to extract and locate features in the frames. It turned out that mono colored objects don't provide much keypoints (what a surprise). The performance of SIFT was terrible anyway (ca. 10 fps # 540p).
I drew some lines and other shapes on the controller which resulted in more keypoints beeing available. However, this didn't yield in huge improvements.
I have an image here with a table.. In the column on the right the background is filled with noise
How to detect the areas with noise? I only want to apply some kind of filter on the parts with noise because I need to do OCR on it and any kind of filter will reduce the overall recognition
And what kind of filter is the best to remove the background noise in the image?
As said I need to do OCR on the image
I tried some filters/operations in OpenCV and it seems to work pretty well.
Step 1: Dilate the image -
kernel = np.ones((5, 5), np.uint8)
cv2.dilate(img, kernel, iterations = 1)
As you see, the noise is gone but the characters are very light, so I eroded the image.
Step 2: Erode the image -
kernel = np.ones((5, 5), np.uint8)
cv2.erode(img, kernel, iterations = 1)
As you can see, the noise is gone however some characters on the other columns are broken. I would recommend running these operations on the noisy column only. You might want to use HoughLines to find the last column. Then you can extract that column only, run dilation + erosion and replace this with the corresponding column in the original image.
Additionally, dilation + erosion is actually an operation called closing. This you could call directly using -
cv2.morphologyEx(img, cv2.MORPH_CLOSE, kernel)
As #Ermlg suggested, medianBlur with a kernel of 3 also works wonderfully.
cv2.medianBlur(img, 3)
Alternative Step
As you can see all these filters work but it is better if you implement these filters only in the part where the noise is. To do that, use the following:
edges = cv2.Canny(img, 50, 150, apertureSize = 3) // img is gray here
lines = cv2.HoughLinesP(edges, 1, np.pi / 180, 100, 1000, 50) // last two arguments are minimum line length and max gap between two lines respectively.
for line in lines:
for x1, y1, x2, y2 in line:
print x1, y1
// This gives the start coordinates for all the lines. You should take the x value which is between (0.75 * w, w) where w is the width of the entire image. This will give you essentially **(x1, y1) = (1896, 766)**
Then, you can extract this part only like :
extract = img[y1:h, x1:w] // w, h are width and height of the image
Then, implement the filter (median or closing) in this image. After removing the noise, you need to put this filtered image in place of the blurred part in the original image.
image[y1:h, x1:w] = median
This is straightforward in C++ :
extract.copyTo(img, new Rect(x1, y1, w - x1, h - y1))
Final Result with alternate method
Hope it helps!
My solution is based on thresholding to get the resulted image in 4 steps.
Read image by OpenCV 3.2.0.
Apply GaussianBlur() to smooth image especially the region in gray color.
Mask the image to change text to white and the rest to black.
Invert the masked image to black text in white.
The code is in Python 2.7. It can be changed to C++ easily.
import numpy as np
import cv2
import matplotlib.pyplot as plt
%matplotlib inline
# read Danish doc image
img = cv2.imread('./imagesStackoverflow/danish_invoice.png')
# apply GaussianBlur to smooth image
blur = cv2.GaussianBlur(img,(5,3), 1)
# threshhold gray region to white (255,255, 255) and sets the rest to black(0,0,0)
mask=cv2.inRange(blur,(0,0,0),(150,150,150))
# invert the image to have text black-in-white
res = 255 - mask
plt.figure(1)
plt.subplot(121), plt.imshow(img[:,:,::-1]), plt.title('original')
plt.subplot(122), plt.imshow(blur, cmap='gray'), plt.title('blurred')
plt.figure(2)
plt.subplot(121), plt.imshow(mask, cmap='gray'), plt.title('masked')
plt.subplot(122), plt.imshow(res, cmap='gray'), plt.title('result')
plt.show()
The following is the plotted images by the code for reference.
Here is the result image at 2197 x 3218 pixels.
As I know the median filter is the best solution to reduce noise. I would recommend to use median filter with 3x3 window. See function cv::medianBlur().
But be careful when use any noise filtration simultaneously with OCR. Its can lead to decreasing of recognition accuracy.
Also I would recommend to try using pair of functions (cv::erode() and cv::dilate()). But I'm not shure that it will best solution then cv::medianBlur() with window 3x3.
I would go with median blur (probably 5*5 kernel).
if you are planning to apply OCR the image. I would advise you to the following:
Filter the image using Median Filter.
Find contours in the filtered image, you will get only text contours (Call them F).
Find contours in the original image (Call them O).
isolate all contours in O that have intersection with any contour in F.
Faster solution:
Find contours in the original image.
Filter them based on size.
Blur (3x3 box)
Threshold at 127
Result:
If you are very worried of removing pixels that could hurt your OCR detection. Without adding artefacts ea be as pure to the original as possible. Then you should create a blob filter. And delete any blobs that are smaller then n pixels or so.
Not going to write code, but i know this works great as i use this myself, though i dont use openCV (i wrote my own multithreaded blobfilter out of speed reasons). And sorry but i cannot share my code here. Just describing how to do it.
If processing time is not an issue, a very effective method in this case would be to compute all black connected components, and remove those smaller than a few pixels. It would remove all the noisy dots (apart those touching a valid component), but preserve all characters and the document structure (lines and so on).
The function to use would be connectedComponentWithStats (before you probably need to produce the negative image, the threshold function with THRESH_BINARY_INV would work in this case), drawing white rectangles where small connected components where found.
In fact, this method could be used to find characters, defined as connected components of a given minimum and maximum size, and with aspect ratio in a given range.
I had already faced the same issue and got the best solution.
Convert source image to grayscale image and apply fastNlMeanDenoising function and then apply threshold.
Like this -
fastNlMeansDenoising(gray,dst,3.0,21,7);
threshold(dst,finaldst,150,255,THRESH_BINARY);
ALSO use can adjust threshold accorsing to your background noise image.
eg- threshold(dst,finaldst,200,255,THRESH_BINARY);
NOTE - If your column lines got removed...You can take a mask of column lines from source image and can apply to the denoised resulted image using BITWISE operations like AND,OR,XOR.
Try thresholding the image like this. Make sure your src is in grayscale. This method will only retain the pixels which are between 150 and 255 intensity.
threshold(src, output, 150, 255, CV_THRESH_BINARY | CV_THRESH_OTSU);
You might want to invert the image as you are trying to negate the gray pixels. After the operation, invert it again to get your desired result.
I am totally new to OpenCV and I have started to dive into it. But I'd need a little bit of help.
So I want to combine these 2 images:
I would like the 2 images to match along their edges (ignoring the very right part of the image for now)
Can anyone please point me into the right direction? I have tried using the findTransformECC function. Here's my implementation:
cv::Mat im1 = [imageArray[1] CVMat3];
cv::Mat im2 = [imageArray[0] CVMat3];
// Convert images to gray scale;
cv::Mat im1_gray, im2_gray;
cvtColor(im1, im1_gray, CV_BGR2GRAY);
cvtColor(im2, im2_gray, CV_BGR2GRAY);
// Define the motion model
const int warp_mode = cv::MOTION_AFFINE;
// Set a 2x3 or 3x3 warp matrix depending on the motion model.
cv::Mat warp_matrix;
// Initialize the matrix to identity
if ( warp_mode == cv::MOTION_HOMOGRAPHY )
warp_matrix = cv::Mat::eye(3, 3, CV_32F);
else
warp_matrix = cv::Mat::eye(2, 3, CV_32F);
// Specify the number of iterations.
int number_of_iterations = 50;
// Specify the threshold of the increment
// in the correlation coefficient between two iterations
double termination_eps = 1e-10;
// Define termination criteria
cv::TermCriteria criteria (cv::TermCriteria::COUNT+cv::TermCriteria::EPS, number_of_iterations, termination_eps);
// Run the ECC algorithm. The results are stored in warp_matrix.
findTransformECC(
im1_gray,
im2_gray,
warp_matrix,
warp_mode,
criteria
);
// Storage for warped image.
cv::Mat im2_aligned;
if (warp_mode != cv::MOTION_HOMOGRAPHY)
// Use warpAffine for Translation, Euclidean and Affine
warpAffine(im2, im2_aligned, warp_matrix, im1.size(), cv::INTER_LINEAR + cv::WARP_INVERSE_MAP);
else
// Use warpPerspective for Homography
warpPerspective (im2, im2_aligned, warp_matrix, im1.size(),cv::INTER_LINEAR + cv::WARP_INVERSE_MAP);
UIImage* result = [UIImage imageWithCVMat:im2_aligned];
return result;
I have tried playing around with the termination_eps and number_of_iterations and increased/decreased those values, but they didn't really make a big difference.
So here's the result:
What can I do to improve my result?
EDIT: I have marked the problematic edges with red circles. The goal is to warp the bottom image and make it match with the lines from the image above:
I did a little bit of research and I'm afraid the findTransformECC function won't give me the result I'd like to have :-(
Something important to add:
I actually have an array of those image "stripes", 8 in this case, they all look similar to the images shown here and they all need to be processed to match the line. I have tried experimenting with the stitch function of OpenCV, but the results were horrible.
EDIT:
Here are the 3 source images:
The result should be something like this:
I transformed every image along the lines that should match. Lines that are too far away from each other can be ignored (the shadow and the piece of road on the right portion of the image)
By your images, it seems that they overlap. Since you said the stitch function didn't get you the desired results, implement your own stitching. I'm trying to do something close to that too. Here is a tutorial on how to implement it in c++: https://ramsrigoutham.com/2012/11/22/panorama-image-stitching-in-opencv/
You can use Hough algorithm with high threshold on two images and then compare the vertical lines on both of them - most of them should be shifted a bit, but keep the angle.
This is what I've got from running this algorithm on one of the pictures:
Filtering out horizontal lines should be easy(as they are represented as Vec4i), and then you can align the remaining lines together.
Here is the example of using it in OpenCV's documentation.
UPDATE: another thought. Aligning the lines together can be done with the concept similar to how cross-correlation function works. Doesn't matter if picture 1 has 10 lines, and picture 2 has 100 lines, position of shift with most lines aligned(which is, mostly, the maximum for CCF) should be pretty close to the answer, though this might require some tweaking - for example giving weight to every line based on its length, angle, etc. Computer vision never has a direct way, huh :)
UPDATE 2: I actually wonder if taking bottom pixels line of top image as an array 1 and top pixels line of bottom image as array 2 and running general CCF over them, then using its maximum as shift could work too... But I think it would be a known method if it worked good.
First of all: I'm new to opencv :-)
I want to perform a vignetting correction on a 24bit RGB Image. I used an area scan camera as a line camera and put together an image from 1780x2 px parts to get an complete image with 1780x3000 px. Because of the vignetting, i made a white reference picture with 1780x2 px to calculate a LUT (with correction factor in it) for the vignetting removal. Here is my code idea:
Mat white = imread("WHITE_REF_2L.bmp", 0);
Mat lut(2, 1780, CV_8UC3, Scalar(0));
lut = 255 / white;
imwrite("lut_test.bmp", lut*white);
As i understood, what the second last line will (hopefully) do, is to divide 255 with every intensity value of every channel and store this in the lut matrice.
I want to use that lut then to to calculate the “real” (not distorted) intensity
level of each pixel by multiplying every element of the src img with every element of the lut matrice.
obviously its not working how i want to do it, i get a memory exception.
Can anybody help me with that problem?
edit: i'm using opencv 3.1.0 and i solved the problem like this:
// read white reference image
Mat white = imread("WHITE_REF_2L_D.bmp", IMREAD_COLOR);
white.convertTo(white, CV_32FC3);
// calculate LUT with vignetting correction factors
Mat vLUT(2, 1780, CV_32FC3, Scalar(0.0f));
divide(240.0f, white, vLUT);
of course that's not optimal, i will read in more white references and calculate the mean value to optimize.
Here's the 2 lines white reference, you can see the shadows at the image borders i want to correct
when i multiply vLUT with the white reference i obviously get a homogenous image as the result.
thanks, maybe this can help anyone else ;)