ColdFusion date subtraction - coldfusion

I am converting a ColdFusion application to .NET, and I have a question about date subtraction.
In the following if statement, qTripID.etd is the utc date and time of a flight departure, the comment says that that it is testing whether the flight has already departed.
<cfif qTripID.etd - DateConvert("local2utc",Now()) LT 0.166666666666667>
What type of information does the expression above return?
minutes? days? hours?

The entire expression:
qTripID.etd - DateConvert("local2utc",Now()) LT 0.166666666666667
returns a boolean value: 'LT' is ColdFusion's 'less than' operator.
I think you're asking what units is the 0.166666666667? In which case it is days - the 0.1666... value being 4 hours.

Related

Google Sheets: IFS statement wont return date

I'm currently using the following formula:
=IFS(regexmatch(A2,"Malaysia"),
B2-dataset!B3,REGEXMATCH(A2,"Saudi Arabia"),
B2-dataset!B7,REGEXMATCH(A2,"Taiwan"),
B2-dataset!B11,REGEXMATCH(A2,"Russia"),
B2-dataset!B15,REGEXMATCH(A2,"Greece"),
B2-dataset!B19,REGEXMATCH(A2,"South Africa"),
B2-dataset!B23,REGEXMATCH(A2,"UAE"),
B2-dataset!B27,REGEXMATCH(A2,"Albania"),
B2-dataset!B31,REGEXMATCH(A2,"India"),
B2-dataset!B35,REGEXMATCH(A2,"South Korea"),
B2-dataset!B39,REGEXMATCH(A2,"Turkey"),
B2-dataset!B43)
The idea is that B2 (currently as =date(dd/mm/yyyy) has a deadline date. C2 (in which the formula houses) should show the date when everything should be delivered.
Currently the outcome is a number, not a date. I've tried IF statement, which delivers a date but I can only add 3 arguments. Can someone help me?
Kind regards
if your current output is number like 40000+ it's ok and it's just formatting issue. either you will format it internally or use a formula.
try:
=TEXT(IFS(regexmatch(A2,"Malaysia"),
B2-dataset!B3,REGEXMATCH(A2,"Saudi Arabia"),
B2-dataset!B7,REGEXMATCH(A2,"Taiwan"),
B2-dataset!B11,REGEXMATCH(A2,"Russia"),
B2-dataset!B15,REGEXMATCH(A2,"Greece"),
B2-dataset!B19,REGEXMATCH(A2,"South Africa"),
B2-dataset!B23,REGEXMATCH(A2,"UAE"),
B2-dataset!B27,REGEXMATCH(A2,"Albania"),
B2-dataset!B31,REGEXMATCH(A2,"India"),
B2-dataset!B35,REGEXMATCH(A2,"South Korea"),
B2-dataset!B39,REGEXMATCH(A2,"Turkey"),
B2-dataset!B43), "dd/mm/yyyy")

Finding time and date with Regular Expression (RegEx) in Dart language

I'm writing an application with Flutter. I read the times and dates from a source. The date and time format string sent by the resource is:
(Day, Month, Year, Hour, Minute, Second)
07.04.2021 13:30:00
03.04.2021 11:30:00
04.04.2021 17:30:00
03.04.2021 17:30:00
I want to convert this date and time format to DateTime data type with DateTime.parse() function. Here are some examples of what this function accepts as strings and what I need:
"2012-02-27 13:27:00"
"20120227 13:27:00"
"20120227T132700"
I have to convert the string type data coming to me from the source into one of these formats. But in Dart language I couldn't create the Regular Expression needed to do this and couldn't find it anywhere.
I would be very grateful if anyeone could help me understand what I should do.
If you have to play a lot with the dates, you could use the Jiffy package to ease your development.
DateTime yourDatetime = Jiffy("07.04.2021 13:30:00", "dd.MM.yyyy hh:mm:ss").dateTime;
This is a piece a cake by using regular expressions:
var regExp = RegExp(r'(\d{4}-?\d\d-?\d\d(\s|T)\d\d:?\d\d:?\d\d)');
use DateFormat.parse and DateFormat.format from intl package:
https://api.flutter.dev/flutter/intl/DateFormat/parse.html
https://api.flutter.dev/flutter/intl/DateFormat/format.html
final date = DateFormat("yyyy.MM.dd HH:mm:ss").parse("07.04.2021 13:30:00");
DateFormat("yyyy-MM-dd HH:mm:ss").format(date);
DateTime.parse accepts only a subset of ISO 8601 formats: https://api.flutter.dev/flutter/dart-core/DateTime/parse.html

NiFi toDate() Function altering the content

i have been trying to convert a string to date using
${test:toString():toDate('dd-MMM-yy HH.mm.ss.SSSSSSSSS'):format('dd-MMM-yy HH.mm.ss.SSSSSSSSS')}
my value for test attribute is like 13-MAR-20 15.50.41.396000000
when i'm using the above mentioned expression to convert the string to Date, it actually is changing the date as below:
test (input value):
13-MAR-20 15.50.41.396000000
time (output value)
18-Mar-20 05.50.41.000000000
please advise!
I ran into a similar issue with date time encoded in ISO 8601.
The problem is, that the digits after the second are defined as fragment of a second, not milliseconds. If it has 3 digits, it equivalent to milliseconds. If more than 3, the toDate() function parse the fragment of a second as milliseconds. In your case 396000000 milliseconds = 4,58333333 days.
I solved my issue with replaceAll() by cutting digits to first 3.
${test:replaceAll('(\.[0-9]{3})([0-9]+)','$1')}
But my value was formatted as 18-06-20T05:50:41.396000000, so maybe you have to adjust the regex.

PARSE_DATETIME formatting with day of year

Having an issue with the PARSE_DATETIME function in BigQuery used with the day of year (%j) formatting element. The function seems to ignore the day of year element.
Eg.
select PARSE_DATETIME("%Y%j", "2013243")
returns 2013-01-01T00:00:00, lacking day of year component.
However the reverse function with the same date formatting elements works as expected:
select FORMAT_DATETIME("%Y%j", "2013-02-02T00:00:00")
returns: 2013033
Bug? or user error?
Cheers
I think that this is a bug that could be fixed! there is no logic in it working one way but not opposite!
Meantime, you can use below to achieve goal
#standardSQL
CREATE TEMP FUNCTION PARSE_DATETIME_WITH_DAYS(x STRING) AS (
DATETIME_ADD(PARSE_DATETIME('%Y%j', x), INTERVAL CAST(SUBSTR(x, -3) AS INT64) - 1 DAY)
);
SELECT PARSE_DATETIME_WITH_DAYS('2013243')
with result -
Row f0_
1 2013-08-31T00:00:00
Not a bug, neither an error! PARSE_DATETIME uses a format_string and a STRING representation of a DATETIME to return a DATETIME -> "2013243" does not represent a DATETIME string, not a DATE...
To achieve what you are looking for first get the day number - 1 and add it to date (first day of the year) and format the output to DATETIME
SELECT DATETIME(DATE_ADD((SELECT PARSE_DATE("%Y%j", "2013243")), INTERVAL CAST((SELECT SUBSTR("2013243", -3)) AS INT64) -1 DAY));
Output:
2013-08-31T00:00:00

Data validation using regular expressions in Google Sheets

I am using the below date/time format in gSheets:
01 Apr at 11:00
I wonder whether it is possible to use Data Validation (or any other function) to report error (add the small red triangle to the corner of the cell) when the format differs in any way.
Possible values in the given format:
01 -> any number between 01-31 (but not "1", there must be the leading zero)
space
Apr -> 3 letters for month (Jan, Feb, Mar... Dec)
space
at
space
11 -> hours in 24h format (00, 01...23)
:
00 -> minutes (00, 01,...59)
Is there any way to validate that the cell contains "text/data" exactly in the above mentioned format?
The right way to do this is using Regular Expression and "regexmatch()" function in Google Sheets. For the given example, I made the below regular expression:
[0-3][0-9] (Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec) at [0-2][0-9]\:[0-5][0-9]
Process:
Select range of cells to be validated
Go to Data > Data Validation
Under Criteria select "Own pattern is" (not sure the exact translation used in EN)
Paste: =regexmatch(to_text(K4); "[0-3][0-9] (Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec) at [0-2][0-9]\:[0-5][0-9]")
Make sure that instead of K4 in "to_text(K4)" there is a upper-left cell from the selected range
Save
Hope it helps someone :)
You may try the formula for data validation:
=not(iserror(SUBSTITUTE(A1," at","")*1))*(len(A1)=15)*(right(A1,2)*1<61)
not(iserror(SUBSTITUTE(A1," at","")*1)) checks all statemant is legal date
(len(A1)=15) checks dates are entered with 2 digits
(right(A1,2)*1<61) cheks too much minutes, for some reason 01 Apr at 11:99 is a legal date..
Select the range of fields, where you need the data validation to occur to.
Press on -> Data -> Data validation
For "Criteria" select "Custom formula is"
Enter the following in the textfield next to "Custom formula is":
=regexmatch(Tablename!B2; "^[a-z_]*$")
Where as "Tablename" should be replaced by the table name and "B2" should be replaced by the first cell of the range.
Inside the "" you enter then your regex-expression. Here this would allow only small letters and underscores.
Using the to_text() function additionally didn't work for me. So you should maybe avoid it in order to make sure, that it works.
Press save