Another thread safe queue implementation - c++

I have a class, Queue, that I tried to make thread safe. It has these three member variables:
std::queue<T> m_queue;
pthread_mutex_t m_mutex;
pthread_cond_t m_condition;
and a push and pop implemented as:
template<class T> void Queue<T>::push(T value)
{
pthread_mutex_lock( &m_mutex );
m_queue.push(value);
if( !m_queue.empty() )
{
pthread_cond_signal( &m_condition );
}
pthread_mutex_unlock( &m_mutex );
}
template<class T> bool Queue<T>::pop(T& value, bool block)
{
bool rtn = false;
pthread_mutex_lock( &m_mutex );
if( block )
{
while( m_queue.empty() )
{
pthread_cond_wait( &m_condition, &m_mutex );
}
}
if( !m_queue.empty() )
{
value = m_queue.front();
m_queue.pop();
rtn = true;
}
pthread_mutex_unlock( &m_mutex );
return rtn;
}
Unfortunately there are occasional issues that may be the fault of this code. That is, there are two threads and sometimes thread 1 never comes out of push() and at other times thread 2 never comes out of pop() (the block parameter is true) though the queue isn't empty.
I understand there are other implementations available, but I'd like to try to fix this code, if needed. Anyone see any issues?
The constructor has the appropriate initializations:
Queue()
{
pthread_mutex_init( &m_mutex, NULL );
pthread_cond_init( &m_condition, NULL );
}
and the destructor, the corresponding 'destroy' calls.

As mentioned by Paul Rubel, you need to initialise the mutex first. It may be a good idea at this point to wrap the mutex in a class that will handle your initialisation and finalisation for you. For example:
class mutex {
private:
mutex(const mutex &m);
mutex &operator=(const mutex &m);
// OR inherit from boost::noncopyable
public:
mutex() {
pthread_mutex_init(&mut_, nullptr);
}
~mutex() {
pthread_mutex_destroy(&mut_);
}
pthread_mutex_t get() const { return mut_; }
private:
pthread_mutex_t mut_;
};
Of note is the Boost.Threading Library which contains very well-written synchronisation classes.

You must initialize the mutex before using it: pthread_mutex_init
//somewhere before push/pop
pthread_mutex_init(&m_mutex)

This is not related to your problem at all, but you could fix the push function :
template<class T> void Queue<T>::push(T value)
{
pthread_mutex_lock( &m_mutex );
if( m_queue.empty() )
{
m_queue.push(value);
pthread_cond_signal( &m_condition );
}
else
{
m_queue.push(value);
}
pthread_mutex_unlock( &m_mutex );
}

I realized the problems occurred when testing a build for ARM. The solution was to update the pthreads library. With the updated pthreads, everything runs fine.

Related

Add a std::packaged_task to an existing thread?

Is there an standard way to add a std::packaged_task to an existing thread? There's a nontrivial amount of overhead that must happen before the task is run, so I want to do that once, then keep the thread running and waiting for tasks to execute. I want to be able to use futures so I can optionally get the result of the task and catch exceptions.
My pre-C++11 implementation requires my tasks to inherit from an abstract base class with a Run() method (a bit of a pain, can't use lambdas), and having a std::deque collection of those that I add to in the main thread and dequeue from in the worker thread. I have to protect that collection from simultaneous access and provide a signal to the worker thread that there's something to do so it isn't spinning or sleeping. Enqueing something returns a "result" object with a synchronization object to wait for the task to complete, and a result value. It all works well but it's time for an upgrade if there's something better.
Here is a toy thread pool:
template<class T>
struct threaded_queue {
using lock = std::unique_lock<std::mutex>;
void push_back( T t ) {
{
lock l(m);
data.push_back(std::move(t));
}
cv.notify_one();
}
boost::optional<T> pop_front() {
lock l(m);
cv.wait(l, [this]{ return abort || !data.empty(); } );
if (abort) return {};
auto r = std::move(data.back());
data.pop_back();
return std::move(r);
}
void terminate() {
{
lock l(m);
abort = true;
data.clear();
}
cv.notify_all();
}
~threaded_queue()
{
terminate();
}
private:
std::mutex m;
std::deque<T> data;
std::condition_variable cv;
bool abort = false;
};
struct thread_pool {
thread_pool( std::size_t n = 1 ) { start_thread(n); }
thread_pool( thread_pool&& ) = delete;
thread_pool& operator=( thread_pool&& ) = delete;
~thread_pool() = default; // or `{ terminate(); }` if you want to abandon some tasks
template<class F, class R=std::result_of_t<F&()>>
std::future<R> queue_task( F task ) {
std::packaged_task<R()> p(std::move(task));
auto r = p.get_future();
tasks.push_back( std::move(p) );
return r;
}
template<class F, class R=std::result_of_t<F&()>>
std::future<R> run_task( F task ) {
if (threads_active() >= total_threads()) {
start_thread();
}
return queue_task( std::move(task) );
}
void terminate() {
tasks.terminate();
}
std::size_t threads_active() const {
return active;
}
std::size_t total_threads() const {
return threads.size();
}
void clear_threads() {
terminate();
threads.clear();
}
void start_thread( std::size_t n = 1 ) {
while(n-->0) {
threads.push_back(
std::async( std::launch::async,
[this]{
while(auto task = tasks.pop_front()) {
++active;
try{
(*task)();
} catch(...) {
--active;
throw;
}
--active;
}
}
)
);
}
}
private:
std::vector<std::future<void>> threads;
threaded_queue<std::packaged_task<void()>> tasks;
std::atomic<std::size_t> active;
};
copied from another answer of mine.
A thread_pool with 1 thread matches your description pretty much.
The above is only a toy, a real thread pool I'd replace the std::packaged_task<void()> with a move_only_function<void()>, which is all I use it for. (A packaged_task<void()> can hold a packaged_task<R()> amusingly, if inefficiencly).
You will have to reason about shutdown and make a plan. The above code locks up if you try to shut it down without first clearing the threads.

Thread-safe reference-counted queue C++

I'm struggling to implement a thread-safe reference-counted queue. The idea is that I have a number of tasks that each maintain a shared_ptr to a task manager that owns the queue. Here is a minimal implementation that should encounter that same issue:
#include <condition_variable>
#include <deque>
#include <functional>
#include <iostream>
#include <memory>
#include <mutex>
#include <thread>
namespace {
class TaskManager;
struct Task {
std::function<void()> f;
std::shared_ptr<TaskManager> manager;
};
class Queue {
public:
Queue()
: _queue()
, _mutex()
, _cv()
, _running(true)
, _thread([this]() { sweepQueue(); })
{
}
~Queue() { close(); }
void close() noexcept
{
try {
{
std::lock_guard<std::mutex> lock(_mutex);
if (!_running) {
return;
}
_running = false;
}
_cv.notify_one();
_thread.join();
} catch (...) {
std::cerr << "An error occurred while closing the queue\n";
}
}
void push(Task&& task)
{
std::unique_lock<std::mutex> lock(_mutex);
_queue.emplace_back(std::move(task));
lock.unlock();
_cv.notify_one();
}
private:
void sweepQueue() noexcept
{
while (true) {
try {
std::unique_lock<std::mutex> lock(_mutex);
_cv.wait(lock, [this] { return !_running || !_queue.empty(); });
if (!_running && _queue.empty()) {
return;
}
if (!_queue.empty()) {
const auto task = _queue.front();
_queue.pop_front();
task.f();
}
} catch (...) {
std::cerr << "An error occurred while sweeping the queue\n";
}
}
}
std::deque<Task> _queue;
std::mutex _mutex;
std::condition_variable _cv;
bool _running;
std::thread _thread;
};
class TaskManager : public std::enable_shared_from_this<TaskManager> {
public:
void addTask(std::function<void()> f)
{
_queue.push({ f, shared_from_this() });
}
private:
Queue _queue;
};
} // anonymous namespace
int main(void)
{
const auto manager = std::make_shared<TaskManager>();
manager->addTask([]() { std::cout << "Hello world\n"; });
}
The problem I find is that on rare occasions, the queue will try to invoke its own destructor within the sweepQueue method. Upon further inspection, it seems that the reference count on the TaskManager hits zero once the last task is dequeued. How can I safely maintain the reference count without invoking the destructor?
Update: The example does not clarify the need for the std::shared_ptr<TaskManager> within Task. Here is an example use case that should illustrate the need for this seemingly unnecessary ownership cycle.
std::unique_ptr<Task> task;
{
const auto manager = std::make_shared<TaskManager>();
task = std::make_unique<Task>(someFunc, manager);
}
// Guarantees manager is not destroyed while task is still in scope.
The ownership hierarchy here is TaskManager owns Queue and Queue owns Tasks. Tasks maintaining a shared pointer to TaskManager create an ownership cycle which does not seem to serve a useful purpose here.
This is the ownership what is root of the problem here. A Queue is owned by TaskManager, so that Queue can have a plain pointer to TaskManager and pass that pointer to Task in sweepQueue. You do not need std::shared_pointer<TaskManager> in Task at all here.
I'd refactor the queue from the thread first.
But to fix your problem:
struct am_I_alive {
explicit operator bool() const { return m_ptr.lock(); }
private:
std::weak_ptr<void> m_ptr;
};
struct lifetime_tracker {
am_I_alive track_lifetime() {
if (!m_ptr) m_ptr = std::make_shared<bool>(true);
return {m_ptr};
}
lifetime_tracker() = default;
lifetime_tracker(lifetime_tracker const&) {} // do nothing, don't copy
lifetime_tracker& operator=(lifetime_tracker const&){ return *this; }
private:
std::shared_ptr<void> m_ptr;
};
this is a little utility to detect if we have been deleted. It is useful in any code that calls an arbitrary callback whose side effect could include delete(this).
Privately inherit your Queue from it.
Then split popping the task from running it.
std::optional<Task> get_task() {
std::unique_lock<std::mutex> lock(_mutex);
_cv.wait(lock, [this] { return !_running || !_queue.empty(); });
if (!_running && _queue.empty()) {
return {}; // end
}
auto task = _queue.front();
_queue.pop_front();
return task;
}
void sweepQueue() noexcept
{
while (true) {
try {
auto task = get_task();
if (!task) return;
// we are alive here
auto alive = track_lifetime();
try {
(*task).f();
} catch(...) {
std::cerr << "An error occurred while running a task\n";
}
task={};
// we could be deleted here
if (!alive)
return; // this was deleted, get out of here
}
} catch (...) {
std::cerr << "An error occurred while sweeping the queue\n";
}
}
}
and now you are safe.
After that you need to deal with the thread problem.
The thread problem is that you need your code to destroy the thread from within the thread it is running. At the same time, you also need to guarantee that the thread has terminated before main ends.
These are not compatible.
To fix that, you need to create a thread owning pool that doesn't have your "keep alive" semantics, and get your thread from there.
These threads don't delete themselves; instead, they return themselves to that pool for reuse by another client.
At shutdown, those threads are blocked on to ensure you don't have code running elsewhere that hasn't halted before the end of main.
To write such a pool without your inverted dependency mess, split the queue part of your code off. This queue owns no thread.
template<class T>
struct threadsafe_queue {
void push(T);
std::optional<T> pop(); // returns empty if thread is aborted
void abort();
~threadsafe_queue();
private:
std::mutex m;
std::condition_variable v;
std::deque<T> data;
bool aborted = false;
};
then a simple thread pool:
struct thread_pool {
template<class F>
std::future<std::result_of_t<F&()>> enqueue( F&& f );
template<class F>
std::future<std::result_of_t<F&()>> thread_off_now( F&& f ); // starts a thread if there aren't any free
void abort();
void start_thread( std::size_t n = 1 );
std::size_t count_threads() const;
~thread_pool();
private:
threadsafe_queue< std::function<void()> > tasks;
std::vector< std::thread > threads;
static void thread_loop( thread_pool* pool );
};
make a thread pool singleton. Get your threads for your queue from thread_off_now method, guaranteeing you a thread that (when you are done with it) can be recycled, and whose lifetime is handled by someone else.
But really, you should instead be thinking with ownership in mind. The idea that tasks and task queues mutually own each other is a mess.
If someone disposes of a task queue, it is probably a good idea to abandon the tasks instead of persisting it magically and silently.
Which is what my simple thread pool does.

C++ Thread safe queue shutdown

I'm using this class for producer-consumer setup in C++:
#pragma once
#include <queue>
#include <mutex>
#include <condition_variable>
#include <memory>
#include <atomic>
template <typename T> class SafeQueue
{
public:
SafeQueue() :
_shutdown(false)
{
}
void Enqueue(T item)
{
std::unique_lock<std::mutex> lock(_queue_mutex);
bool was_empty = _queue.empty();
_queue.push(std::move(item));
lock.unlock();
if (was_empty)
_condition_variable.notify_one();
}
bool Dequeue(T& item)
{
std::unique_lock<std::mutex> lock(_queue_mutex);
while (!_shutdown && _queue.empty())
_condition_variable.wait(lock);
if(!_shutdown)
{
item = std::move(_queue.front());
_queue.pop();
return true;
}
return false;
}
bool IsEmpty()
{
std::lock_guard<std::mutex> lock(_queue_mutex);
return _queue.empty();
}
void Shutdown()
{
_shutdown = true;
_condition_variable.notify_all();
}
private:
std::mutex _queue_mutex;
std::condition_variable _condition_variable;
std::queue<T> _queue;
std::atomic<bool> _shutdown;
};
And I use it like this:
class Producer
{
public:
Producer() :
_running(true),
_t(std::bind(&Producer::ProduceThread, this))
{ }
~Producer()
{
_running = false;
_incoming_packets.Shutdown();
_t.join();
}
SafeQueue<Packet> _incoming_packets;
private:
void ProduceThread()
{
while(_running)
{
Packet p = GetNewPacket();
_incoming_packets.Enqueue(p);
}
}
std::atomic<bool> _running;
std::thread _t;
}
class Consumer
{
Consumer(Producer* producer) :
_producer(producer),
_t(std::bind(&Consumer::WorkerThread, this))
{ }
~Consumer()
{
_t.join();
}
private:
void WorkerThread()
{
Packet p;
while(producer->_incoming_packets.Dequeue(p))
ProcessPacket(p);
}
std::thread _t;
Producer* _producer;
}
This works most of the time. But once in a while when I delete the producer (and causing it's deconstructor to call SafeQueue::Shutdown, the _t.join() blocks forever.
My guess is the that the problem is here (in SafeQueue::Dequeue):
while (!_shutdown && _queue.empty())
_condition_variable.wait(lock);
SafeQueue::Shutdown from thread #1 gets called while thread #2 finished checking _shutdown but before it executed _condition_variable.wait(lock), so it "misses" the notify_all(). Can this happen?
If that's the problem, what's the best way to solve it?
Since the SafeQueue object is owned by the producer, deleting the producer causes a race condition between the consumer being notified and the SafeQueue being deleted out from under it when ~Producer completes.
I suggest having the shared resource being owned by neither the producer nor consumer, but passed as a reference to the constructor of each.
Change the Producer and Consumer constructors;
Producer( SafeQueue<Packet> & queue ) :
_running(false), _incoming_packets(queue) {}
Consumer( SafeQueue<Packet> & queue ) :
_running(false), _incoming_packets(queue) {}
Use your instances this way;
SafeQueue<Packet> queue;
Producer producer(queue);
Consumer consumer(queue);
...do stuff...
queue.shutdown();
This also resolves a poor design issue you have in the Consumer class being so tightly coupled to the Producer class.
Also, it's probably a bad idea to kill and join threads in a destructor, as you do for ~Producer. Better to add a Shutdown() method to each thread class, and call them explicitly;
producer.shutdown();
consumer.shutdown();
queue.shutdown();
Shutdown order doesn't really matter, unless you are concerned about losing unprocessed packets that are still in the queue when you stop the consumer.
In your SafeQueue::Dequeue, you are probably using std::condition_variable the wrong way... Change this:
bool Dequeue(T& item)
{
std::unique_lock<std::mutex> lock(_queue_mutex);
while (!_shutdown && _queue.empty())
_condition_variable.wait(lock);
if(!_shutdown)
{
item = std::move(_queue.front());
_queue.pop();
return true;
}
return false;
}
to
bool Dequeue(T& item)
{
std::unique_lock<std::mutex> lock(_queue_mutex);
_condition_variable.wait(lock, []{ return _shutdown || !_queue.empty() });
if(!_shutdown)
{
item = std::move(_queue.front());
_queue.pop();
return true;
}
return false;
}
Secondly, the order of initialization of the data members in Consumer isn't right with regards to its constructor
class Consumer
{
Consumer(Producer* producer) :
_producer(producer),
_t(std::bind(&Consumer::WorkerThread, this))
{ }
......
// _t will be constructed first, regardless of your constructor initializer list
// Meaning, the thread can even start running using an unintialized _producer
std::thread _t;
Producer* _producer;
}
It should be reordered to:
class Consumer
{
Consumer(Producer* producer) :
_producer(producer),
_t(std::bind(&Consumer::WorkerThread, this))
{ }
......
Producer* _producer;
std::thread _t;
}
Another part of your problem is covered by CAB's answer

C++11 thread-safe queue

A project I'm working on uses multiple threads to do work on a collection of files. Each thread can add files to the list of files to be processed, so I put together (what I thought was) a thread-safe queue. Relevant portions follow:
// qMutex is a std::mutex intended to guard the queue
// populatedNotifier is a std::condition_variable intended to
// notify waiting threads of a new item in the queue
void FileQueue::enqueue(std::string&& filename)
{
std::lock_guard<std::mutex> lock(qMutex);
q.push(std::move(filename));
// Notify anyone waiting for additional files that more have arrived
populatedNotifier.notify_one();
}
std::string FileQueue::dequeue(const std::chrono::milliseconds& timeout)
{
std::unique_lock<std::mutex> lock(qMutex);
if (q.empty()) {
if (populatedNotifier.wait_for(lock, timeout) == std::cv_status::no_timeout) {
std::string ret = q.front();
q.pop();
return ret;
}
else {
return std::string();
}
}
else {
std::string ret = q.front();
q.pop();
return ret;
}
}
However, I am occasionally segfaulting inside the if (...wait_for(lock, timeout) == std::cv_status::no_timeout) { } block, and inspection in gdb indicates that the segfaults are occurring because the queue is empty. How is this possible? It was my understanding that wait_for only returns cv_status::no_timeout when it has been notified, and this should only happen after FileQueue::enqueue has just pushed a new item to the queue.
It is best to make the condition (monitored by your condition variable) the inverse condition of a while-loop:
while(!some_condition). Inside this loop, you go to sleep if your condition fails, triggering the body of the loop.
This way, if your thread is awoken--possibly spuriously--your loop will still check the condition before proceeding. Think of the condition as the state of interest, and think of the condition variable as more of a signal from the system that this state might be ready. The loop will do the heavy lifting of actually confirming that it's true, and going to sleep if it's not.
I just wrote a template for an async queue, hope this helps. Here, q.empty() is the inverse condition of what we want: for the queue to have something in it. So it serves as the check for the while loop.
#ifndef SAFE_QUEUE
#define SAFE_QUEUE
#include <queue>
#include <mutex>
#include <condition_variable>
// A threadsafe-queue.
template <class T>
class SafeQueue
{
public:
SafeQueue(void)
: q()
, m()
, c()
{}
~SafeQueue(void)
{}
// Add an element to the queue.
void enqueue(T t)
{
std::lock_guard<std::mutex> lock(m);
q.push(t);
c.notify_one();
}
// Get the "front"-element.
// If the queue is empty, wait till a element is avaiable.
T dequeue(void)
{
std::unique_lock<std::mutex> lock(m);
while(q.empty())
{
// release lock as long as the wait and reaquire it afterwards.
c.wait(lock);
}
T val = q.front();
q.pop();
return val;
}
private:
std::queue<T> q;
mutable std::mutex m;
std::condition_variable c;
};
#endif
According to the standard condition_variables are allowed to wakeup spuriously, even if the event hasn't occured. In case of a spurious wakeup it will return cv_status::no_timeout (since it woke up instead of timing out), even though it hasn't been notified. The correct solution for this is of course to check if the wakeup was actually legit before proceding.
The details are specified in the standard §30.5.1 [thread.condition.condvar]:
—The function will unblock when signaled by a call to notify_one(), a call to notify_all(), expiration of the absolute timeout (30.2.4) specified by abs_time, or spuriously.
...
Returns: cv_status::timeout if the absolute timeout (30.2.4) specifiedby abs_time expired, other-ise cv_status::no_timeout.
This is probably how you should do it:
void push(std::string&& filename)
{
{
std::lock_guard<std::mutex> lock(qMutex);
q.push(std::move(filename));
}
populatedNotifier.notify_one();
}
bool try_pop(std::string& filename, std::chrono::milliseconds timeout)
{
std::unique_lock<std::mutex> lock(qMutex);
if(!populatedNotifier.wait_for(lock, timeout, [this] { return !q.empty(); }))
return false;
filename = std::move(q.front());
q.pop();
return true;
}
Adding to the accepted answer, I would say that implementing a correct multi producers / multi consumers queue is difficult (easier since C++11, though)
I would suggest you to try the (very good) lock free boost library, the "queue" structure will do what you want, with wait-free/lock-free guarantees and without the need for a C++11 compiler.
I am adding this answer now because the lock-free library is quite new to boost (since 1.53 I believe)
I would rewrite your dequeue function as:
std::string FileQueue::dequeue(const std::chrono::milliseconds& timeout)
{
std::unique_lock<std::mutex> lock(qMutex);
while(q.empty()) {
if (populatedNotifier.wait_for(lock, timeout) == std::cv_status::timeout )
return std::string();
}
std::string ret = q.front();
q.pop();
return ret;
}
It is shorter and does not have duplicate code like your did. Only issue it may wait longer that timeout. To prevent that you would need to remember start time before loop, check for timeout and adjust wait time accordingly. Or specify absolute time on wait condition.
There is also GLib solution for this case, I did not try it yet, but I believe it is a good solution.
https://developer.gnome.org/glib/2.36/glib-Asynchronous-Queues.html#g-async-queue-new
BlockingCollection is a C++11 thread safe collection class that provides support for queue, stack and priority containers. It handles the "empty" queue scenario you described. As well as a "full" queue.
You may like lfqueue, https://github.com/Taymindis/lfqueue.
It’s lock free concurrent queue. I’m currently using it to consuming the queue from multiple incoming calls and works like a charm.
This is my implementation of a thread-queue in C++20:
#pragma once
#include <deque>
#include <mutex>
#include <condition_variable>
#include <utility>
#include <concepts>
#include <list>
template<typename QueueType>
concept thread_queue_concept =
std::same_as<QueueType, std::deque<typename QueueType::value_type, typename QueueType::allocator_type>>
|| std::same_as<QueueType, std::list<typename QueueType::value_type, typename QueueType::allocator_type>>;
template<typename QueueType>
requires thread_queue_concept<QueueType>
struct thread_queue
{
using value_type = typename QueueType::value_type;
thread_queue();
explicit thread_queue( typename QueueType::allocator_type const &alloc );
thread_queue( thread_queue &&other );
thread_queue &operator =( thread_queue const &other );
thread_queue &operator =( thread_queue &&other );
bool empty() const;
std::size_t size() const;
void shrink_to_fit();
void clear();
template<typename ... Args>
requires std::is_constructible_v<typename QueueType::value_type, Args ...>
void enque( Args &&... args );
template<typename Producer>
requires requires( Producer producer ) { { producer() } -> std::same_as<std::pair<bool, typename QueueType::value_type>>; }
void enqueue_multiple( Producer producer );
template<typename Consumer>
requires requires( Consumer consumer, typename QueueType::value_type value ) { { consumer( std::move( value ) ) } -> std::same_as<bool>; }
void dequeue_multiple( Consumer consumer );
typename QueueType::value_type dequeue();
void swap( thread_queue &other );
private:
mutable std::mutex m_mtx;
mutable std::condition_variable m_cv;
QueueType m_queue;
};
template<typename QueueType>
requires thread_queue_concept<QueueType>
thread_queue<QueueType>::thread_queue()
{
}
template<typename QueueType>
requires thread_queue_concept<QueueType>
thread_queue<QueueType>::thread_queue( typename QueueType::allocator_type const &alloc ) :
m_queue( alloc )
{
}
template<typename QueueType>
requires thread_queue_concept<QueueType>
thread_queue<QueueType>::thread_queue( thread_queue &&other )
{
using namespace std;
lock_guard lock( other.m_mtx );
m_queue = move( other.m_queue );
}
template<typename QueueType>
requires thread_queue_concept<QueueType>
thread_queue<QueueType> &thread_queue<QueueType>::thread_queue::operator =( thread_queue const &other )
{
std::lock_guard
ourLock( m_mtx ),
otherLock( other.m_mtx );
m_queue = other.m_queue;
return *this;
}
template<typename QueueType>
requires thread_queue_concept<QueueType>
thread_queue<QueueType> &thread_queue<QueueType>::thread_queue::operator =( thread_queue &&other )
{
using namespace std;
lock_guard
ourLock( m_mtx ),
otherLock( other.m_mtx );
m_queue = move( other.m_queue );
return *this;
}
template<typename QueueType>
requires thread_queue_concept<QueueType>
bool thread_queue<QueueType>::thread_queue::empty() const
{
std::lock_guard lock( m_mtx );
return m_queue.empty();
}
template<typename QueueType>
requires thread_queue_concept<QueueType>
std::size_t thread_queue<QueueType>::thread_queue::size() const
{
std::lock_guard lock( m_mtx );
return m_queue.size();
}
template<typename QueueType>
requires thread_queue_concept<QueueType>
void thread_queue<QueueType>::thread_queue::shrink_to_fit()
{
std::lock_guard lock( m_mtx );
return m_queue.shrink_to_fit();
}
template<typename QueueType>
requires thread_queue_concept<QueueType>
void thread_queue<QueueType>::thread_queue::clear()
{
std::lock_guard lock( m_mtx );
m_queue.clear();
}
template<typename QueueType>
requires thread_queue_concept<QueueType>
template<typename ... Args>
requires std::is_constructible_v<typename QueueType::value_type, Args ...>
void thread_queue<QueueType>::thread_queue::enque( Args &&... args )
{
using namespace std;
unique_lock lock( m_mtx );
m_queue.emplace_front( forward<Args>( args ) ... );
m_cv.notify_one();
}
template<typename QueueType>
requires thread_queue_concept<QueueType>
typename QueueType::value_type thread_queue<QueueType>::thread_queue::dequeue()
{
using namespace std;
unique_lock lock( m_mtx );
while( m_queue.empty() )
m_cv.wait( lock );
value_type value = move( m_queue.back() );
m_queue.pop_back();
return value;
}
template<typename QueueType>
requires thread_queue_concept<QueueType>
template<typename Producer>
requires requires( Producer producer ) { { producer() } -> std::same_as<std::pair<bool, typename QueueType::value_type>>; }
void thread_queue<QueueType>::enqueue_multiple( Producer producer )
{
using namespace std;
lock_guard lock( m_mtx );
for( std::pair<bool, value_type> ret; (ret = move( producer() )).first; )
m_queue.emplace_front( move( ret.second ) ),
m_cv.notify_one();
}
template<typename QueueType>
requires thread_queue_concept<QueueType>
template<typename Consumer>
requires requires( Consumer consumer, typename QueueType::value_type value ) { { consumer( std::move( value ) ) } -> std::same_as<bool>; }
void thread_queue<QueueType>::dequeue_multiple( Consumer consumer )
{
using namespace std;
unique_lock lock( m_mtx );
for( ; ; )
{
while( m_queue.empty() )
m_cv.wait( lock );
try
{
bool cont = consumer( move( m_queue.back() ) );
m_queue.pop_back();
if( !cont )
return;
}
catch( ... )
{
m_queue.pop_back();
throw;
}
}
}
template<typename QueueType>
requires thread_queue_concept<QueueType>
void thread_queue<QueueType>::thread_queue::swap( thread_queue &other )
{
std::lock_guard
ourLock( m_mtx ),
otherLock( other.m_mtx );
m_queue.swap( other.m_queue );
}
The only template-parameter is BaseType, which can be a std::deque type or std::list type, restricted with thread_queue_concept. This class uses this type as the internal queue type. Chose that BaseType that is most efficient for your application. I might have restricted the class on a more differentiated thread_queue_concepts that checks for all the used parts of BaseType so that this class might apply for other types compatible to std::list<> or std::deque<> but I was too lazy to implement that for the unlikely case that someone implements something like that on his own.
One advantage of this code are enqueue_multiple and dequeue_multiple. These functions are given a function-object, usually a lambda, which can enqueue or dequeue multiple items with only one locking step. For enqueue this always holds true, for dequeue this depends on if the queue has elements to fetch or not.
enqueue_multiple usually makes sense if you have one producer and multiple consumers. It results in longer periods holding the lock and therefore it makes sense only if the items can be produced or move fast.
dequeue_multiple usually makes sense if you have multiple producers and one consumer. Here we also have longer locking periods, but as objects are usually only have fast moves here, this normally doesn't hurt.
If the consumer function object of the dequeue_multiple throws an exception while consuming, the exception is caugt and the element provided to the consumer (rvalue-refernce inside the underlying queue types object) is removed.
If you like to use this class with C++11 you have to remove the concepts or disable them with #if defined(__cpp_concepts).

Boost thread disabling

I try to implement blocking queue. the main parts are the following (it's a kind of educational task)
template <typename T>
class Blocking_queue
{
public:
std::queue<T> _queue;
boost::mutex _mutex;
boost::condition_variable _cvar;
void Put(T& object);
T Get();
void Disable()
};
template<typename T>
void Blocking_queue::Put(T& object)
{
boost::mutex::scoped_lock lock(_mutex);
_queue.push(T);
lock.unlock();
_cvar.notify_one();
}
template<typename T>
T Blocking_queue::Get()
{
boost::mutex::scoped_lock lock(_mutex);
while(_queue.empty())
{
_cvar.wait(_mutex);
}
T last_el = _queue.front();
_queue.pop();
return last_el;
}
template<typename T>
void Blocking_queue::Disable()
{
}
And i need to implement a function Disable() "releasing" all waiting threads (as written in the task). The problem is that i don't fully understand what "releasing" in this terms means, and what methods should i apply. So my idea - is the following: when Disable() is called we should call some method for current thread in this place (inside the loop)
while(_queue.empty())
{
//here
_cvar.wait(_mutex);
}
which will release current thread, am i right? Thanks.
"releasing all threads that are waiting" is an operation that is hardly useful. What do you want to do with this operation?
What is useful, is to shutdown the queue, thus every thread waiting on the queue will be unblocked and every thread that is going to call Get() will return immediately. To implement such a behaviour, simply add a shutdown flag to the queue and wait for "not empty or shutdown":
template<typename T>
void Blocking_queue::Disable()
{
boost::mutex::scoped_lock lock(_mutex);
_shutdown = true;
_cvar.notify_all()
}
To indicate that there is no data, to the caller of Get(), you could return a pair with an additional bool or throw a special exception. There is no way to return null, as not for all types T there is a null value.
template<typename T>
std::pair< bool, T > Blocking_queue::Get()
{
boost::mutex::scoped_lock lock(_mutex);
while (_queue.empty() && !_shutdown )
_cvar.wait(_mutex);
if ( _shutdown )
return std::make_pair( false, T() );
T last_el = _queue.front();
_queue.pop();
return std::make_pair( true, last_el );
}