I have an Ispell list of english words (nearly 50 000 words), my homework in Perl is to get quickly (like under one minute) list of all strings, that are substrings of some other word. I have tried solution with two foreach cycles comparing all words, but even with some optimalizations, its still too slow. I think, that right solution could be some clever use of regular expressions on array of words. Do you know how to solve this problem quicky (in Perl)?
I have found fast solution, which can find some all these substrings in about 15 seconds on my computer, using just one thread. Basically, for each word, I have created array of every possible substrings (eliminating substrings which differs only in "s" or "'s" endings):
#take word and return list of all valid substrings
sub split_to_all_valid_subwords {
my $word = $_[0];
my #split_list;
my ($i, $j);
for ($i = 0; $i < length($word); ++$i){
for ($j = 1; $j <= length($word) - $i; ++$j){
unless
(
($j == length($word)) or
($word =~ m/s$/ and $i == 0 and $j == length($word) - 1) or
($word =~ m/\'s$/ and $i == 0 and $j == length($word) - 2)
)
{
push(#split_list, substr($word, $i, $j));
}
}
}
return #split_list;
}
Then I just create list of all candidates for substrings and make intersection with words:
my #substring_candidates;
foreach my $word (#words) {
push( #substring_candidates, split_to_all_valid_subwords($word));
}
#make intersection between substring candidates and words
my %substring_candidates=map{$_ =>1} #substring_candidates;
my %words=map{$_=>1} #words;
my #substrings = grep( $substring_candidates{$_}, #words );
Now in substrings I have array of all words, that are substrings of some other words.
Perl regular expressions will optimize patterns like foo|bar|baz into an Aho-Corasick match - up to a certain limit of total compiled regex length. Your 50000 words will probably exceed that length, but could be broken into smaller groups. (Indeed, you probably want to break them up by length and only check words of length N for containing words of length 1 through N-1.)
Alternatively, you could just implement Aho-Corasick in your perl code - that's kind of fun to do.
update
Ondra supplied a beautiful solution in his answer; I leave my post here as an example of overthinking a problem and failed optimisation techniques.
My worst case kicks in for a word that doesn't match any other word in the input. In that case, it goes quadratic. The OPT_PRESORT was a try to advert the worst case for most words. The OPT_CONSECUTIVE was a linear-complexity filter that reduced the total number of items in the main part of the algorithm, but it is just a constant factor when considering the complexity. However, it is still useful with Ondras algorithm and saves a few seconds, as building his split list is more expensive than comparing two consecutive words.
I updated the code below to select ondras algorithm as a possible optimisation. Paired with zero threads and the presort optimisation, it yields maximum performance.
I would like to share a solution I coded. Given an input file, it outputs all those words that are a substring of any other word in the same input file. Therefore, it computes the opposite of ysth's ideas, but I took the idea of optimisation #2 from his answer. There are the following three main optimisations that can be deactivated if required.
Multithreading
The questions "Is word A in list L? Is word B in L?" can be easily parallelised.
Pre-sorting all the words for their length
I create an array that points to the list of all words that are longer than a certain length, for every possible length. For long words, this can cut down the number of possible words dramatically, but it trades quite a lot of space, as one word of length n appears in all lists from length 1 to length n.
Testing consecutive words
In my /usr/share/dict/words, most consecutive lines look quite similar:
Abby
Abby's
for example. As every word that would match the first word also matches the second one, I immediately add the first word to the list of matching words, and only keep the second word for further testing. This saved about 30% of words in my test cases. Because I do that before optimisation No 2, this also saves a lot of space. Another trade-off is that the output will not be sorted.
The script itself is ~120 lines long; I explain each sub before showing it.
head
This is just a standard script header for multithreading. Oh, and you need perl 5.10 or better to run this. The configuration constants define the optimisation behaviour. Add the number of processors of your machine in that field. The OPT_MAX variable can take the number of words you want to process, however this is evaluated after the optimisations have taken place, so the easy words will already have been caught by the OPT_CONSECUTIVE optimisation. Adding anything there will make the script seemingly slower. $|++ makes sure that the status updates are shown immediately. I exit after the main is executed.
#!/usr/bin/perl
use strict; use warnings; use feature qw(say); use threads;
$|=1;
use constant PROCESSORS => 0; # (false, n) number of threads
use constant OPT_MAX => 0; # (false, n) number of words to check
use constant OPT_PRESORT => 0; # (true / false) sorts words by length
use constant OPT_CONSECUTIVE => 1; # (true / false) prefilter data while loading
use constant OPT_ONDRA => 1; # select the awesome Ondra algorithm
use constant BLABBER_AT => 10; # (false, n) print progress at n percent
die q(The optimisations Ondra and Presort are mutually exclusive.)
if OPT_PRESORT and OPT_ONDRA;
exit main();
main
Encapsulates the main logic, and does multi-threading. The output of n words will be matched will be considerably smaller than the number of input words, if the input was sorted. After I have selected all matched words, I print them to STDOUT. All status updates etc. are printed to STDERR, so that they don't interfere with the output.
sub main {
my #matching; # the matching words.
my #words = load_words(\#matching); # the words to be searched
say STDERR 0+#words . " words to be matched";
my $prepared_words = prepare_words(#words);
# do the matching, possibly multithreading
if (PROCESSORS) {
my #threads =
map {threads->new(
\&test_range,
$prepared_words,
#words[$$_[0] .. $$_[1]] )
} divide(PROCESSORS, OPT_MAX || 0+#words);
push #matching, $_->join for #threads;
} else {
push #matching, test_range(
$prepared_words,
#words[0 .. (OPT_MAX || 0+#words)-1]);
}
say STDERR 0+#matching . " words matched";
say for #matching; # print out the matching words.
0;
}
load_words
This reads all the words from the input files which were supplied as command line arguments. Here the OPT_CONSECUTIVE optimisation takes place. The $last word is either put into the list of matching words, or into the list of words to be matched later. The -1 != index($a, $b) decides if the word $b is a substring of word $a.
sub load_words {
my $matching = shift;
my #words;
if (OPT_CONSECUTIVE) {
my $last;
while (<>) {
chomp;
if (defined $last) {
push #{-1 != index($_, $last) ? $matching : \#words}, $last;
}
$last = $_;
}
push #words, $last // ();
} else {
#words = map {chomp; $_} <>;
}
#words;
}
prepare_words
This "blows up" the input words, sorting them after their length into each slot, that has the words of larger or equal length. Therefore, slot 1 will contain all words. If this optimisation is deselected, it is a no-op and passes the input list right through.
sub prepare_words {
if (OPT_ONDRA) {
my $ondra_split = sub { # evil: using $_ as implicit argument
my #split_list;
for my $i (0 .. length $_) {
for my $j (1 .. length($_) - ($i || 1)) {
push #split_list, substr $_, $i, $j;
}
}
#split_list;
};
return +{map {$_ => 1} map &$ondra_split(), #_};
} elsif (OPT_PRESORT) {
my #prepared = ([]);
for my $w (#_) {
push #{$prepared[$_]}, $w for 1 .. length $w;
}
return \#prepared;
} else {
return [#_];
}
}
test
This tests if the word $w is a substring in any of the other words. $wbl points to the data structure that was created by the previous sub: Either a flat list of words, or the words sorted by length. The appropriate algorithm is then selected. Nearly all of the running time is spent in this loop. Using index is much faster than using a regex.
sub test {
my ($w, $wbl) = #_;
my $l = length $w;
if (OPT_PRESORT) {
for my $try (#{$$wbl[$l + 1]}) {
return 1 if -1 != index $try, $w;
}
} else {
for my $try (#$wbl) {
return 1 if $w ne $try and -1 != index $try, $w;
}
}
return 0;
}
divide
This just encapsulates an algorithm that guarantees a fair distribution of $items items into $parcels buckets. It outputs the bounds of a range of items.
sub divide {
my ($parcels, $items) = #_;
say STDERR "dividing $items items into $parcels parcels.";
my ($min_size, $rest) = (int($items / $parcels), $items % $parcels);
my #distributions =
map [
$_ * $min_size + ($_ < $rest ? $_ : $rest),
($_ + 1) * $min_size + ($_ < $rest ? $_ : $rest - 1)
], 0 .. $parcels - 1;
say STDERR "range division: #$_" for #distributions;
return #distributions;
}
test_range
This calls test for each word in the input list, and is the sub that is multithreaded. grep selects all those elements in the input list where the code (given as first argument) return true. It also regulary outputs a status message like thread 2 at 10% which makes waiting for completition much easier. This is a psychological optimisation ;-).
sub test_range {
my $wbl = shift;
if (BLABBER_AT) {
my $range = #_;
my $step = int($range / 100 * BLABBER_AT) || 1;
my $i = 0;
return
grep {
if (0 == ++$i % $step) {
printf STDERR "... thread %d at %2d%%\n",
threads->tid,
$i / $step * BLABBER_AT;
}
OPT_ONDRA ? $wbl->{$_} : test($_, $wbl)
} #_;
} else {
return grep {OPT_ONDRA ? $wbl->{$_} : test($_, $wbl)} #_;
}
}
invocation
Using bash, I invoked the script like
$ time (head -n 1000 /usr/share/dict/words | perl script.pl >/dev/null)
Where 1000 is the number of lines I wanted to input, dict/words was the word list I used, and /dev/null is the place I want to store the output list, in this case, throwing the output away. If the whole file should be read, it can be passed as an argument, like
$ perl script.pl input-file >output-file
time just tells us how long the script ran. Using 2 slow processors and 50000 words, it executed in just over two minutes in my case, which is actually quite good.
update: more like 6–7 seconds now, with the Ondra + Presort optimisation, and no threading.
further optimisations
update: overcome by better algorithm. This section is no longer completely valid.
The multithreading is awful. It allocates quite some memory and isn't exactly fast. This isn't suprising considering the amount of data. I considered using a Thread::Queue, but that thing is slow like $#*! and therefore is a complete no-go.
If the inner loop in test was coded in a lower-level language, some performance might be gained, as the index built-in wouldn't have to be called. If you can code C, take a look at the Inline::C module. If the whole script were coded in a lower language, array access would also be faster. A language like Java would also make the multithreading less painful (and less expensive).
Related
Imagine i have a sequence of files, e.g.:
...
segment8_400_av.ts
segment9_400_av.ts
segment10_400_av.ts
segment11_400_av.ts
segment12_400_av.ts
...
When the filenames are known, i can match against the filenames with a regular expression like:
/segment(\d+)_400_av\.ts/
Because i know the incremental pattern.
But what would be a generic approach to this? I mean how can i take two file names out of the list, compare them and find out where in the file name the counting part is, taking into account any other digits that can occur in the filename (the 400 in this case)?
Goal: What i want to do is to run the script against various file sequences to check for example for missing files, so this should be the first step to find out the numbering scheme. File sequences can occur in many different fashions, e.g.:
test_1.jpg (simple counting suffix)
test_2.jpg
...
or
segment9_400_av.ts (counting part inbetween, with other static digits)
segment10_400_av.ts
...
or
01_trees_00008.dpx (padded with zeros)
01_trees_00009.dpx
01_trees_00010.dpx
Edit 2: Probably my problem can be described more simple: With a given set of files, i want to:
Find out, if they are a numbered sequence of files, with the rules below
Get the first file number, get the last file number and file count
Detect missing files (gaps in the sequence)
Rules:
As melpomene summarized in his answer, the file names only differ in one substring, which consists only of digits
The counting digits can occur anywhere in the filename
The digits can be padded with 0's (see example above)
I can do #2 and #3, what i am struggling with is #1 as a starting point.
You tagged this question regex, so here's a regex-based solution:
use strict;
use warnings;
my $name1 = 'segment12_400_av.ts';
my $name2 = 'segment10_400_av.ts';
if (
"$name1\0$name2" =~ m{
\A
( \D*+ (?: \d++ \D++ )* ) # prefix
( \d++ ) # numeric segment 1
( [^\0]* ) # suffix
\0 # separator
\1 # prefix
( \d++ ) # numeric segment 2
\3 # suffix
\z
}xa
) {
print <<_EOT_;
Result of comparing "$name1" and "$name2"
Common prefix: $1
Common suffix: $3
Varying numeric parts: $2 / $4
Position of varying numeric part: $-[2]
_EOT_
}
Output:
Result of comparing "segment12_400_av.ts" and "segment10_400_av.ts"
Common prefix: segment
Common suffix: _400_av.ts
Varying numeric parts: 12 / 10
Position of varying numeric part: 7
It assumes that
the strings are different (guard the condition with $name1 ne $name2 && ... if that's not guaranteed)
there's only one substring that's different between the input strings (otherwise it won't find any match)
the differing substring consists of digits only
all digits surrounding the first point of difference are part of the varying increment (e.g. the example above recognizes segment as the common prefix, not segment1)
The idea is to combine the two names into a single string (separated by NUL, which is unambiguous because filenames can't contain \0), then let the regex engine do the hard work of finding the longest common prefix (using greediness and backtracking).
Because we're in a regex, we can get a bit more fancy than just finding the longest common prefix: We can make sure that the prefix doesn't end with a digit (see the segment1 vs. segment case above) and we can verify that the suffix is also the same.
See if this works for you:
use strict;
use warnings;
sub compare {
my ( $f1, $f2 ) = #_;
my #f1 = split /(\d+)/sxm, $f1;
my #f2 = split /(\d+)/sxm, $f2;
my $i = 0;
my $out1 = q{};
my $out2 = q{};
foreach my $p (#f1) {
if ( $p eq $f2[$i] ) {
$out1 .= $p;
$out2 .= $p;
}
else {
$out1 .= sprintf ' ((%s)) ', $p;
$out2 .= sprintf ' ((%s)) ', $f2[$i];
}
$i++;
}
print $out1 . "\n";
print $out2 . "\n";
return;
}
print "Test1:\n";
compare( 'segment8_400_av.ts', 'segment9_400_av.ts' );
print "\n\nTest2:\n";
compare( 'segment999_8_400_av.ts', 'segment999_9_400_av.ts' );
You basically split strings by starting/ending digits, the loop through the items and compare each of the 'pieces'. If they are equal, you accumulate. If not, then you highlight the differences and accumulate.
Output (I'm using ((number)) for the highlight)
Test1:
segment ((8)) _400_av.ts
segment ((9)) _400_av.ts
Test2:
segment999_ ((8)) _400_av.ts
segment999_ ((9)) _400_av.ts
I assume that only the counter differs across the strings
use warnings;
use strict;
use feature 'say';
my ($fn1, $fn2) = ('segment8_400_av.ts', 'segment12_400_av.ts');
# Collect all numbers from all strings
my #nums = map { [ /([0-9]+)/g ] } ($fn1, $fn2);
my ($n, $pos); # which number in the string, at what position
# Find which differ
NUMS:
for my $j (1..$#nums) { # strings
for my $i (0..$#{$nums[0]}) { # numbers in a string
if ($nums[$j]->[$i] != $nums[0]->[$i]) { # it is i-th number
$n = $i;
$fn1 =~ /($nums[0]->[$i])/g; # to find position
$pos = $-[$i];
say "It is $i-th number in a string. Position: $pos";
last NUMS;
}
}
}
We loop over the array with arrayrefs of numbers found in each string, and over elements of each arrayref (eg [8, 400]). Each number in a string (0th or 1st or ...) is compared to its counterpart in the 0-th string (array element); all other numbers are the same.
The number of interest is the one that differs and we record which number in a string it is ($n-th).
Then its position in the string is found by matching it again and using #- regex variable with (the just established) index $n, so the offset of the start of the n-th match. This part may be unneeded; while question edits helped I am still unsure whether the position may or not be useful.
Prints, with position counting from 0
It is 0-th number in a string. Position: 7
Note that, once it is found that it is the $i-th number, we can't use index to find its position; an number earlier in strings may happen to be the same as the $i-th one, in this string.
To test, modify input strings by adding the same number to each, before the one of interest.
Per question update, to examine the sequence (for missing files for instance), with the above findings you can collect counters for all strings in an array with hashrefs (num => filename)
use Data::Dump qw(dd);
my #seq = map { { $num[$_]->[$n] => $fnames[$_] } } 0..$#fnames;
dd \#seq;
where #fnames contains filenames (like two picked for the example above, $fn1 and $fn2). This assumes that the file list was sorted to begin with, or add the sort if it wasn't
my #seq =
sort { (keys %$a)[0] <=> (keys %$b)[0] }
map { { $num[$_]->[$n] => $fnames[$_] } }
0..$#fnames;
The order is maintained by array.
Adding this to the above example (with two strings) adds to the print
[
{ 8 => "segment8_400_av.ts" },
{ 12 => "segment12_400_av.ts" },
]
With this all goals in "Edit 2" should be straighforward.
I suggest that you build a regex pattern by changing all digit sequences to (\d+) and then see which captured values have changed
For instance, with segment8_400_av.ts and
segment9_400_av.ts you would generate a pattern /segment(\d+)_(\d+)_av\.ts/. Note that s/\d+/(\d+)/g will return the number of numeric fields, which you will need for the subsequent check
The first would capture 8 and 400 which the second would capture 9 and 400. 8 is different from 9, so it is in that region of the string where the number varies
I can't really write much code as you don't say what sort of result you want from this process
I have two lists stored in variables: $list1 and $list2, for example:
$list1:
a
b
c
d
$list2:
1
2
3
4
How do I merge them together line by line so that I end up with:
a1
b2
c3
d4
I have tried using array (#) but it just combines them one after the other, not line by line, example:
$list1 = #(command)
$list1 += #($list2)
If you prefer pipelining, you can also do it in one line:
0 .. ($list1.count -1) | ForEach-Object { $list1[$_]+$list2[$_] }
You could do this with a For loop that uses iterates through the index of each object until it reaches the total (.count) of the first object:
$list1 = 'a','b','c','d'
$list2 = 1,2,3,4
For ($i=0; $i -lt $list1.count; $i++) {
$list1[$i]+$list2[$i]
}
Output:
a1
b2
c3
d4
If you want the results to go to a variable, you could put (for example) $list = before the For.
To complement Mark Wragg's helpful for-based answer and Martin Brandl's helpful pipeline-based answer:
Combining foreach with .., the range operator allows for a concise solution that also performs well:
foreach ($i in 0..($list1.count-1)) { "$($list1[$i])$($list2[$i])" }
Even though an entire array of indices is constructed first - 0..($list1.count-1) - this slightly outperforms the for solution with large input lists, and both foreach and for will be noticeably faster than the pipeline-based solution - see below.
Also note how string interpolation (variable references and subexpressions inside a single "..." string) are used to ensure that the result is always a string.
By contrast, if you use +, it is the type of the LHS that determines the output type, which can result in errors or unwanted output; e.g., 1 + 'a' causes an error, because 1 is an integer and 'a' cannot be converted to an integer.
Optional reading: performance considerations
Generally, foreach and for solutions are noticeably faster than pipeline-based (ForEach-Object cmdlet-based) solutions.
Pipelines are elegant and concise, but they are comparatively slow.
That shouldn't stop you from using them, but it's important to be aware that they can be a performance bottleneck.
Pipelines are memory-efficient, and for processing large collections that don't fit into memory as a whole they are always the right tool to use.
PSv4 introduced the little-known .ForEach() collection operator (method), whose performance is in between that of for / foreach and the ForEach-Object cmdlet.
The following compares the relative performance with large lists (100,000 items); the absolute timing numbers will vary based on many factors, but they should give you a general sense:
# Define two large lists.
$list1 = 1..100000
$list2 = 1..100000
# Define the commands as script blocks:
$cmds = { foreach ($i in 0..($list1.count-1)) { "$($list1[$i])$($list2[$i])" } },
{ for ($i=0; $i -lt $list1.count; $i++) { "$($list1[$i])$($list2[$i])" } },
{ 0..($list1.count -1) | ForEach-Object { "$($list1[$_])$($list2[$_])" } },
{ (0..($list1.count-1)).ForEach({ "$($list1[$_])$($list2[$_])" }) }
# Time each command.
$cmds | ForEach-Object { '{0:0.0}' -f (Measure-Command $_).TotalSeconds }
In a 2-core Windows 10 VM running PSv5.1 I get the following results after running the tests several times:
0.5 # foreach
0.7 # for
1.8 # ForEach-Object (pipeline)
1.2 # .ForEach() operator
I want to test the performance of two different approaches, in perl, of checking that one string is contained entirely within another.
The first approach is to take a string convert it to an array and test character by character whilst the second approach simply evaluates a regular expression (which I believe has the same order as a linear search through all the characters but doesn't incur the cost of assigning memory for an array, and copying characters into it (though it might have other costs involved)).
My initial approach to doing this test was to just stick both procedures (see below) in a big for loop (0 to 999999) and then time how long it takes for the program to finish; and at first it looked as though a regex match was much faster (12.926s vs 0.318s); but I then considered the possibility that upon evaluating the regex once the following iterations are trivial because it is cached. To test this I instead put my for loop on the command line (making each iteration of the perl script looping through 0 to 0 "memory-less") and noticed that they are both similar (albeit with some wild divergence from the average at times). But I strongly suspect this might be a poor conclusion because the time taken to start the script probably dominates the execution time of the script.
Is there a way (especially for when I want to look at something less trivial), of turning off the caching (if that's what is happening of course) so that I can fairly run procedures within a for loop (so I can call the script only once)?
Or is it the case that there is nothing clever going on and that a regex search really is much quicker in this example!?
my $teststr = "testing testing";
my $teststr2 = "testing tasted";
my $match = 1;
#procedure one - character by character checking
for (my $i = 0; $i < 1; $i++)
{
my #chrArr = split //, $teststr;
my #chrArr2 = split //, $teststr2;
for (my $j = 0; $j < #chrArr2; $j++)
{
if($chrArr[$j] != $chrArr2[$j])
{
$match = 0;
break;
}
}
}
#procedure 2 - regex matching
for (my $i = 0; $i < 1; $i++)
{
if($teststr !~ m/$teststr2/)
{
$match = 0;
}
}
Why don't you use the Banchmark module. It should fit perfectly here.
use Benchmark qw( timethese cmpthese);
--
cmic
Regular expression matching/searching is linear. Compiling the pattern is expensive. If you change $teststr2 on every iteration, no caching will be possible. For example:
#procedure 2 - regex matching
for (my $i = 0; $i < 1; $i++)
{
if($teststr !~ m/${i}$teststr2/)
{
$match = 0;
}
}
I'm trying to construct some regex to extract stats on queue statuses in Asterisk. I'm relatively new to regex so am quite far off a solution. I have the following output to parse:
Parsing /etc/asterisk/extconfig.conf
0009*007 has 2 calls (max unlimited) in 'ringall' strategy (0s holdtime), W:0, C:0, A:7, SL:0.0% within 0s
Members:
0009*001 (Local/0009*001#queue/nj) (In use) has taken no calls yet
Callers:
1. SIP/chan5-000a29f2 (wait: 0:08, prio: 0)
2. SIP/0139*741-000a29f7 (wait: 0:03, prio: 0)
The real output will have info for multiple queues, so it will repeat from the second line. The first line is only displayed once.
I need to end up with the queue ID (in this example 0009*007) and a list of calls with their respective wait time.
So far I have used the following regex to match the queue number:
\b^[0-9]{4}\*[0-9]{3}\b
But this doesn't work. Not sure how to match the call with the wait time.
Ideally I would like output like this:
0009*007,1,0:08
0009*007,2,0:03
I will be writing the final script in Perl most likely.
Here's a simple state machine solution. The regexes may need to change depending on what kind of variation you expect in the log file.
use Modern::Perl;
my $current_queue;
my $in_callers = 0;
while (<DATA>)
{
if (!defined $current_queue)
{
/(\d{4}\*\d{3})/ and $current_queue = $1;
}
elsif (!$in_callers)
{
/Callers:/ and $in_callers++;
}
elsif (/^\s*(\d+)\..*wait:\s+(\d+:\d+),\s+prio:\s+(\d+)/)
{
say "$current_queue,$1,$2,$3";
}
else
{
#end of this queue; reset.
undef $current_queue; $in_callers = 0;
}
}
__DATA__
Parsing /etc/asterisk/extconfig.conf
0009*007 has 2 calls (max unlimited) in 'ringall' strategy
Members:
0009*001 (Local/0009*001#queue/nj) (In use) has taken no calls yet
Callers:
1. SIP/chan5-000a29f2 (wait: 0:08, prio: 0)
2. SIP/0139*741-000a29f7 (wait: 0:03, prio: 0)
As m.buettner indicated, you won't be able to do this with one regex. You can rely on your knowledge of the repeating nature of the data to generate a hash with the data you need, however, and then print the hash at the end:
#!/usr/bin/perl
my %queues;
my $current_queue;
while (<DATA>) {
chomp;
if (m/^(\d+\*\d+)/) {
$current_queue = $1;
}
elsif (m/^\s+(\d)\..+?\(wait:\s+([\d\:]+),/) {
$queues{$current_queue}{$1} = $2;
}
}
foreach my $queue (sort keys %queues) {
foreach my $caller (sort keys %{ $queues{$queue} }) {
print join (',', $queue, $caller, $queues{$queue}{$caller}) . "\n";
}
}
exit;
__DATA__
Parsing /etc/asterisk/extconfig.conf
0009*007 has 2 calls (max unlimited) in 'ringall' strategy (0s holdtime), W:0, C:0, A:7, SL:0.0% within 0s
Members:
0009*001 (Local/0009*001#queue/nj) (In use) has taken no calls yet
Callers:
1. SIP/chan5-000a29f2 (wait: 0:08, prio: 0)
2. SIP/0139*741-000a29f7 (wait: 0:03, prio: 0)
When trying to validate that a string is made up of alphabetic characters only, two possible regex solutions come to my mind.
The first one checks that every character in the string is alphanumeric:
/^[a-z]+$/
The second one tries to find a character somewhere in the string that is not alphanumeric:
/[^a-z]/
(Yes, I could use character classes here.)
Is there any significant performance difference for long strings?
(If anything, I'd guess the second variant is faster.)
Just by looking at it, I'd say the second method is faster.
However, I made a quick non-scientific test, and the results seem to be inconclusive:
Regex Match vs. Negation.
P.S. I removed the group capture from the first method. It's superfluous, and would only slow it down.
Wrote this quick Perl code:
#testStrings = qw(asdfasdf asdf as aa asdf as8up98;n;kjh8y puh89uasdf ;lkjoij44lj 'aks;nasf na ;aoij08u4 43[40tj340ij3 ;salkjaf; a;lkjaf0d8fua ;alsf;alkj
a a;lkf;alkfa as;ldnfa;ofn08h[ijo ok;ln n ;lasdfa9j34otj3;oijt 04j3ojr3;o4j ;oijr;o3n4f;o23n a;jfo;ie;o ;oaijfoia ;aosijf;oaij ;oijf;oiwj;
qoeij;qwj;ofqjf08jf0 ;jfqo;j;3oj4;oijt3ojtq;o4ijq;onnq;ou4f ;ojfoqn;aonfaoneo ;oef;oiaj;j a;oefij iiiii iiiiiiiii iiiiiiiiiii);
print "test 1: \n";
foreach my $i (1..1000000) {
foreach (#testStrings) {
if ($_ =~ /^([a-z])+$/) {
#print "match"
} else {
#print "not"
}
}
}
print `date` . "\n";
print "test 2: \n";
foreach my $j (1..1000000) {
foreach (#testStrings) {
if ($_ =~ /[^a-z]/) {
#print "match"
} else {
#print "not"
}
}
}
then ran it with:
date; <perl_file>; date
it isn't 100% scientific, but it gives us a good idea. The first Regex took 10 or 11 seconds to execute, the second Regex took 8 seconds.