c++ XOR string key hex - c++

Question

I am trying to XOR some already encrypted files.
I know that the XOR key is 0x14 or dec(20).
My code works except for one thing. All the '4' is gone.
Here is my function for the XOR:
void xor(string &nString) // Time to undo what we did from above :D
{
const int KEY = 0x14;
int strLen = (nString.length());
char *cString = (char*)(nString.c_str());
for (int i = 0; i < strLen; i++)
{
*(cString+i) = (*(cString+i) ^ KEY);
}
}
Here is part of my main:
ifstream inFile;
inFile.open("ExpTable.bin");
if (!inFile) {
cout << "Unable to open file";
}
string data;
while (inFile >> data) {
xor(data);
cout << data << endl;
}
inFile.close();
Here is a part of the encypted file:
$y{bq //0 move
%c|{ //1 who
&c|qfq //2 where
'saufp //3 guard
x{wu`}{z //4 location
But x{wu}{z` is returning //location. Its not displaying the 4.
Note the space infront of the X. thats supposed to be decoded to 4.
What am I missing? Why is it not showing all the 4? <space> = 4 // 4 = <space>
UPDATE
This is the list of all the specific conversions:
HEX(enc) ASCII(dec)
20 4
21 5
22 6
23 7
24 0
25 1
26 2
27 3
28 <
29 =
2a >
2b ?
2c 8
2d 9
2e :
2f ;
30 $
31 %
32 &
33 '
34
35 !
36 "
37 #
38 ,
39 -
3a .
3b /
3c (
3d )
3e *
3f +
40 T
41 U
42 V
43 W
44 P
45 Q
46 R
47 S
48 \
49 ]
4a ^
4b _
4c X
4d Y
4e Z
4f [
50 D
51 E
52 F
53 G
54 #
55 A
56 B
57 C
58 L
59 M
5a N
5b O
5c H
5d I
5e J
5f K
60 t
61 u
62 v
63 w
64 p
65 q
66 r
67 s
68 |
69 }
6a
6b
6c x
6d y
6e z
6f {
70 d
71 e
72 f
73 g
75 a
76 b
77 c
78 l
79 m
7a n
7b o
7c h
7d i
7e j
7f k
1d /tab
1e /newline

Answer 1

Get rid of all casts.
Don't use >> for input.
That should fix your problems.
Edit:
// got bored, wrote some (untested) code
ifstream inFile;
inFile.open("ExpTable.bin", in | binary);
if (!inFile) {
cerr << "Unable to open ExpTable.bin: " << strerror(errno) << "\n";
exit(EXIT_FAILURE);
}
char c;
while (inFile.get(c)) {
cout.put(c ^ '\x14');
}
inFile.close();

Answer 2

Are you sure that it is printing '//location'? I think it would print '// location' -- note the space after the double-slash. You are XORing 0x34 with 0x14. The result is 0x20, which is a space character. Why would you want to xor everything with 0x14 anyway?
** edit ** ignore the above; I missed part of your question. The real answer:
Are you entirely sure that the character before the x is a 0x20? Perhaps it's some unprintable character that looks like a space? I would check the hex value.