How does one convert a string to an array
<cfscript>
stResult = { strData = "[1,2,3,4,5,6]"
, arInstant = [1,2,3,4,5,6]
};
//stResult.arData = evaluate(stResult.strData); // this does not work
//stResult.arData = evaluate("#stResult.strData#"); // nor does this
writedump(stResult);
</cfscript>
I am trying to get something that looks like arInstant.
Is there a better way than striping the [], converting to a list, then converting to an array?
Your data is a JSON string so use deserializeJson() to convert it to an array.
Usage:
Result.Data = deserializeJson(Result.Input);
evaluate() should generally be avoided (ref: 1, 2, 3). How about trying:
stResult.arData = ListToArray(stResult.strData, "[],");
This is treating the whole string as a list, with possible delimiters of [ and ] and ,
It should give you an array with 6 elements in it.
Of course, it seems that your stResult.arInstant already has what you need... what are you trying to do?
For this specific question, "
Is there a better way than striping the [], converting to a list, then converting to an array?"
Actually, once you strip away the square brackets, it is a list so that's one step less.
Related
I am trying to use multiple characters as the delimeter in ColdFusion list like ,( comma and blank) but it ignores the blank.
I then tried to use:
<cfset title = listappend( title, a[ idx ].title, "#Chr(44)##Chr(32)#" ) />
But it also ignores the blank and without blanks the list items to diffucult to read.
Any ideas?
With ListAppend you can only use one delimiter. As the docs say for the delimiters parameter:
If this parameter contains more than one character, ColdFusion uses only the first character.
I'm not sure what a[ idx ].title contains or exactly what the expected result is (would be better if you gave a complete example), but I think something like this will do what you want or at least get you started:
<cfscript>
a = [
{"title"="One"},
{"title"="Two"},
{"title"="Three"}
];
result = "";
for (el in a) {
result &= el.title & ", ";
}
writeDump(result);
</cfscript>
I think there's a fundamental flaw in your approach here. The list delimiter is part of the structure of the data, whereas you are also trying to use it for "decoration" when you come to output the data from the list. Whilst often conveniently this'll work, it's kinda conflating two ideas.
What you should do is eschew the use of lists as a data structure completely, as they're a bit crap. Use an array for storing the data, and then deal with rendering it as a separate issue: write a render function which puts whatever separator you want in your display between each element.
function displayArrayAsList(array, separator){
var list = "";
for (var element in array){
list &= (len(list) ? separator : "");
list &= element;
}
return list;
}
writeOutput(displayAsList(["tahi", "rua", "toru", "wha"], ", "));
tahi, rua, toru, wha
Use a two step process. Step 1 - create your comma delimited list. Step 2
yourList = replace(yourList, ",", ", ", "all");
I have a string like this: 001,"John Marvin","doctor", "full time"
I want to delete everything after (001) with substr, but, the length of (001) is not always 3 so I can not put something like thie:
string chain = "001,\"John Marvin\",\"doctor\", \"full time\"";
std::string partial = chain.substr(0,3);
How can I proceed in this case?
You could find the index of the first comma and use that to determine where to cut off the string.
Something like:
string chain = "001,\"John Marvin\",\"doctor\", \"full time\"";
int cutoff = chain.find(',');
string newString = chain.substr(0, cutoff);
Tested here.
I have the following strings in a long string:
a=b=c=d;
a=b;
a=b=c=d=e=f;
I want to first search for above mentioned pattern (X=Y=...=Z) and then output like the following for each of the above mentioned strings:
a=d;
b=d;
c=d;
a=b;
a=f;
b=f;
c=f;
d=f;
e=f;
In general, I want all the variables to have an equal sign with the last variable on the extreme right of the string. Is there a way I can do it using regexprep in MATLAB. I am able to do it for a fixed length string, but for variable length, I have no idea how to achieve this. Any help is appreciated.
My attempt for the case of two equal signs is as follows:
funstr = regexprep(funstr, '([^;])+\s*=\s*+(\w+)+\s*=\s*([^;])+;', '$1 = $3; \n $2 = $3;\n');
Not a regexp but if you stick to Matlab you can make use of the cellfun function to avoid loop:
str = 'a=b=c=d=e=f;' ; %// input string
list = strsplit(str,'=') ;
strout = cellfun( #(a) [a,'=',list{end}] , list(1:end-1), 'uni', 0).' %'// Horchler simplification of the previous solution below
%// this does the same than above but more convoluted
%// strout = cellfun( #(a,b) cat(2,a,'=',b) , list(1:end-1) , repmat(list(end),1,length(list)-1) , 'uni',0 ).'
Will give you:
strout =
'a=f;'
'b=f;'
'c=f;'
'd=f;'
'e=f;'
Note: As Horchler rightly pointed out in comment, although the cellfun instruction allows to compact your code, it is just a disguised loop. Moreover, since it runs on cell, it is notoriously slow. You won't see the difference on such simple inputs, but keep this use when super performances are not a major concern.
Now if you like regex you must like black magic code. If all your strings are in a cell array from the start, there is a way to (over)abuse of the cellfun capabilities to obscure your code do it all in one line.
Consider:
strlist = {
'a=b=c=d;'
'a=b;'
'a=b=c=d=e=f;'
};
Then you can have all your substring with:
strout = cellfun( #(s)cellfun(#(a,b)cat(2,a,'=',b),s(1:end-1),repmat(s(end),1,length(s)-1),'uni',0).' , cellfun(#(s) strsplit(s,'=') , strlist , 'uni',0 ) ,'uni',0)
>> strout{:}
ans =
'a=d;'
'b=d;'
'c=d;'
ans =
'a=b;'
ans =
'a=f;'
'b=f;'
'c=f;'
'd=f;'
'e=f;'
This gives you a 3x1 cell array. One cell for each group of substring. If you want to concatenate them all then simply: strall = cat(2,strout{:});
I haven't had much experience w/ Matlab; but your problem can be solved by a simple string split function.
[parts, m] = strsplit( funstr, {' ', '='}, 'CollapseDelimiters', true )
Now, store the last part of parts; and iterate over parts until that:
len = length( parts )
for i = 1:len-1
print( strcat(parts(i), ' = ', parts(len)) )
end
I do not know what exactly is the print function in matlab. You can update that accordingly.
There isn't a single Regex that you can write that will cover all the cases. As posted on this answer:
https://stackoverflow.com/a/5019658/3393095
However, you have a few alternatives to achieve your final result:
You can get all the values in the line with regexp, pick the last value, then use a for loop iterating throughout the other values to generate the output. The regex to get the values would be this:
matchStr = regexp(str,'([^=;\s]*)','match')
If you want to use regexprep at any means, you should write a pattern generator and a replace expression generator, based on number of '=' in the input string, and pass these as parameters of your regexprep func.
You can forget about Regex and Split the input to generate the output looping throughout the values (similarly to alternative #1) .
With the url string below, I need to find the value of the parameter named construction.
<cfset understand = "http://www.example.com/ops.cfm?id=code&construction=148&construction=150&Building=852&Building=665&Building=348&Building=619&Building=625&Building=626&_=1426353166006&action=SUBMIT">
<cfset understand2 = "http://www.example.com/ops.cfm?id=code&construction=AVENT+Construction+Site&construction=Signore+upper+constructions&Building=852&Building=665&Building=348&Building=619&Building=625&Building=626&_=1426353166006&action=SUBMIT">
I then want to check if the value is numeric or a string. I am doing this:
isDefined('understand') and isnumeric(understand)
But it always returns "NO".
Seems like a good case for REGEX, but that's not my strength. If you are always looking for the value of the same item (construction), you could take advantage of the underlying Java and use the STRING.split() method. Then use the Coldfusion val() function to see what you get. The following solution assumes that 0 is not a valid value. If it is then you have more work to do.
<cfscript>
target=understand;
//target=understand2; //uncomment to try the second values
token="construction=";
potentialValues = target.split(token); //creates an array of values using the token as a separator
for (item in potentialValues )
{
writeoutput(val(item) & "<br />"); //val will grab the numerical value and ignore everything that follows. No number will become 0
}
</cfscript>
Try this:
constructionIsAt = find(understand, "construction");
characterAfterConstruction = mid(understand, constructionIsAt + 13, 1);
if isNumeric(characterAfterConstruction) {
code for numeric
}
else {
code for non numeric
}
IS there a function to change letters at a given index in SAS?
For example if my string is
string1 = 'abcd1234efgh'
I want to do somehing like:
string2 = somefunction(string1, 5, 'zzzz');
to produce
'abcdzzzzefgh'
Yes, substr() = is what you're looking for. See here for details.
substr(string2, 5) = 'zzzz';
The substr(variable,position<,length>) = function can also take an third argument to define the length of the segment to be replaced.