Using boost::assign::list_of - c++

Question

This compiles:
std::vector<int> value = boost::assign::list_of(1)(2);
But not this:
Constructor(std::vector<int> value)
{
}
Constructor (boost::assign::list_of(1)(2));
Is there a one-liner solution for initializing the vector passed to the constructor?
Better still, if the constructor copies to a class variable by taking a reference instead:
Constructor(std::vector<int>& value)
{
_value = value;
}
UPDATE
If I try the following:
enum Foo
{
FOO_ONE, FOO_TWO
};
class Constructor
{
public:
Constructor(const std::vector<Foo>& value){}
};
Constructor c(std::vector<Foo>(boost::assign::list_of(FOO_ONE)));
I get the compiler error:
error C2440: '<function-style-cast>' : cannot convert from 'boost::assign_detail::generic_list<T>' to 'std::vector<_Ty>'
1> with
1> [
1> T=Foo
1> ]
1> and
1> [
1> _Ty=Foo
1> ]
1> No constructor could take the source type, or constructor overload resolution was ambiguous

Answer 1

This is a annoying problem, we also had some time before. We fixed it by using the convert_to_container method:
Constructor c(boost::assign::list_of(1)(2).convert_to_container<std::vector<int> >() );
There are more issues with std::list using in constructor too. See Pass std::list to constructor using boost's list_of doesn't compile for the appropriate answer.

Answer 2

I'm using this template to make temporary instance of std::vector in-place:
#include <vector>
namespace Util {
//init vector
template <typename ELEMENT_TYPE > struct vector_of
: public std::vector<ELEMENT_TYPE>
{
vector_of(const ELEMENT_TYPE& t)
{
(*this)(t);
}
vector_of& operator()(const ELEMENT_TYPE& t)
{
this->push_back(t);
return *this;
}
};
}//namespace Util
Usage would look like this:
Constructor (Util::vector_of<int>(1)(2));
Constructor signature would look like this:
Constructor(const std::vector<int>& value)
{
_value = value;
}