How to make localized duration string? - c++

I'm making an app in which I need to show duration string. A few examples:
1 hour 2 minutes left to break,
2 minutes 8 seconds left to break
For the moment I have a C++ function which for a given amount of seconds/milliseconds/minutes gives you a string:
wxString getTimeStr(int value,
ETimeUnit time_unit, // milliseconds or seconds or minutes or hours
wxString const & lang) // english or russian
It consists of lots of conditions depending on language, time units and existing value. Now I'm considering porting the app to other languages and it would be a bit painful to write c++ code for each new language. Is there a way to make that string using standard functions?
The app is written in C++ using wxWidgets and so far works only on Windows. I would prefer not to use platform-dependent functions, although it would be nice to know them.

You won't be able to do it perfectly without writing different code for different languages. For example, I bet your existing code doesn't allow to produce times like "5 minutes before half past threee" which are nevertheless used in (spoken) German. And even without going to such extends, consider that English "half past three" is translated to "half to four" actually.
So if using the official time is not enough (and if it is, look at wxLocale::GetInfo(wxLOCALE_TIME_FMT)), you will indeed need to write code to handle at least some languages specially.

I suggest splitting your function into two.
The first part would return the time remaining as a wxTimeSpan.
The second part 'translates' the wxTimeSpan into the required language and returns a string. This is the only part you need to change for each language.
For the sake of explanation, let's assume that
we only care about hours and minutes
Klingons like to see hours/mins
Vulcans like to see mins:hours
Russians have various forms of the word for minutes
Then your second function would be written something like this
// extract hours and residual minutes into CSV
wxString csv = theTimeSpan.Format("%H,%M);
// extract tokens for csv
wxString hours, mins
...
if( lang == "Klingon" ) {
return hours + "/" + mins
} else if ( lang == "Vulcan" ) {
return mins + ":" + hours
} else if ( lang == "Russian" ) {
wxString min_name;
switch( mins.ToLong() ) {
case 1: min_name = "---"; break;
...
}
return mins + " " + min_name;
}
Unfortunately you can NOT use Format to get an arbitrary 'time structure' because of an essential ambiguity in, for example, the number of hours in a time span. It can be either the total number of hours (for example, for a time span of 50 hours this would be 50) or just the hour part of the time span, which would be 2 in this case as 50 hours is equal to 2 days and 2 hours.
wxTimeSpan resolves this ambiguity in the following way: if there had been, indeed, the D format specified preceding the H, then it is interpreted as 2. Otherwise, it is 50. The same applies to all other format specifiers: if they follow a specifier of larger unit, only the rest part is taken, otherwise the full value is used.
So, you have to muck around with the csv tokens as shown in my code sample.

The traditional approach to the problem of localization is to build a map of label name -> label value and use place holders in the values.
In the code, you only reference the label name, and provide the values for the place holders
To port to another language, you just need to translate the map
Depending on the degree of sophistication you need, you might have a simple placeholder mechanism (snprintf-like), or one that allows a mini-language to build the value at runtime depending on simple parameters (for example, distinguishing between singular and plural).
In this example, it would be as simple as:
using LabelsType = std::map<LabelName, std::string>;
using LangToLabelsType = std::map<Language, LabelsType>;
Note: I advise an enum for the languages, rather than a plain string.
If you were on Linux I would recommend gettext, however I am unsure whether it works on Windows. Still, you can look it up and see how it works, it might help you.

Sometimes, it is better to make the program more technical rather than closer to natural language. I have also found myself in such situations (to make it looking really cool). It often was the case that the customer did not care. The information is sometimes much more important than its exact form.
A programmer should sometimes choose the tradeoffs -- a kind of meta-solution that is not related to the programming language/framework. In other words, you should weight the correctness of the solution and the correctness of the expectation.

Related

OpenOffice Calc SUM of TRUNC number cells, with rows that include text cells

RE: Apache OpenOffice 4.1.7, AOO417m1(Build:9800) - Rev. 46059c9192, 2019-09-03 12:04.
I need to sum non-integer entries across a range of cells, but without including the decimal values (complicated by some cells being text). I started with ROUNDDOWN, then TRUNC, then FLOOR. I'm driving myself nuts trying to find a clean code (or even an arbitrarily extensible ugly code) for what would be the following:
=SUMIF(ISTEXT(R7:CL7);0;TRUNC(R7:CL7))
The above doesn't work, of course, since TRUNC() doesn't apply to ranges, but it conveys what I'm trying to do in a nutshell -- some of the cells contain text, which SUM() ignores (luckily), but they flummox TRUNC, so I needed to handle the text problem.
I started with ISNUMBER, just to get the ball rolling; ISTEXT has fewer characters, but it's not worth fixing that right now.
FLOOR was equally disappointing for ranges:
=SUM(FLOOR(R7:T7;1))
I tried variations of =SUM(IF(... and searches for ROUNDDOWN range (and variations on that) and such pseudocode as "IFTEXT" and "SUMTRUNC" (and variations on that). I found info on ROUNDDOWN(SUM(... and so forth, but not "SUM(ROUNDDOWN(..." or any equivalent.
In my delirium, I got silly and even tried:
=SUMIF(ISTEXT(S7:U7);0;AND(TRUNC(S7);TRUNC(T7);TRUNC(U7)))
To be clear: {2.9→2 + 2.9→2 + 2.9→2 = 6} ≠ {2.9+2.9+2.9 = 8.7→8}. I'm looking for a 6, not an 8 (I'd joke about sixes and sevens, but I'm way past pumpkin o'clock and 2.428571 takes up too much space).
My current test-kludge is:
=SUM(IF(ISNUMBER(R7);ROUNDDOWN(R7);0);IF(ISNUMBER(S7);ROUNDDOWN(S7);0);IF(ISNUMBER(T7);ROUNDDOWN(T7);0); ... ;IF(ISNUMBER(AX7);ROUNDDOWN(AX7);0))
It ends at AX7 only because of the char count. I hope to SUM the whole row in a single sweep, but that ain't gonna cut it. I could do it in large chunks in multiple cells, and then add those cells up, but oy gevalt.
Since it's already ugly anyway, I could use the following to save a few characters, but this would only mean being able to extend the range maybe 6 further cells (not much point in that):
=IF(ISTEXT(R7);0;TRUNC(R7))+IF(ISTEXT(S7);0;TRUNC(S7))+IF(ISTEXT(S7);0;TRUNC(S7))
I'm seriously considering simply going down a bunch of rows (to below my data cells) and entering the following, then copying the cell and pasting it to a complementary range, and telling the SUM cells to just sum up their respectively shadowed rows (instead of the data rows that they sit in):
=IF(ISTEXT(R7);0;TRUNC(R7))
Sorry for the rambling; I need sleep. This started as a need, then multiple failed attempts became a grudge match of principle and obstinacy, and now I'm just plugging away at it out of blind habit developed over the past 2-3 days (hopefully I won't forget what the purpose was).
In summary...: ++?????++ Out of Cheese Error +++DIVIDE BY CUCUMBER.
I'm comfortable enough with macros, though it's been ~7 years (and that was in Excel). Thanks in advance, even if the answer is that I'm stuck with one of these! 🙂
EDIT: I don't see a way to attach a .csv here (though I could open the .csv with Notepad, and copy-and-paste the contents if that would help anyone), so here's a set of pics:

Extracting number of bits in a macroblock from VVC VTM reference software

Final:Result after calculating and displaying the differenceI am new to VVC and I am going through the reference software's code trying to understand it. I have encoded and decoded videos using the reference software. I want to extract the bitstream from it, I want to know the number of bits there are in each macroblock. I am not sure which class I should be working with, for now I am looking at, mv.cpp, QuantRDOQ.cpp, and TrQuant.cpp.
I am afraid to mess the code up completely, I don't know where to add what lines of code. Start: Result after calculating and displaying the difference
P.S. The linked pictures are after my problem has been solved, I attached these pictures because of my query in the comments.
As the error says, getNumBins() is not supported by the CABAC estimator. So you should make sure you call it "only" during the encoding, and not during the RDO.
This should do the job:
if (isEncoding())
before = m_BinEncoder.getNumBins()
coding_unit( cu, partitioner, cuCtx );
if (isEncoding())
{
after = m_BinEncoder.getNumBins();
diff = after - before;
}
The simpleset solution that I'm aware of is at the encoder side.
The trick is to compute the difference in the number of written bits "before" and "after" encoding a Coding Unit (CU) (aka macroblock). This stuff happens in the CABACWriter.cpp file.
You should go to to coding_tree() function, where coding_unit() function is called, which is responsible for context-coding all syntax elementes in the current CU.
There, you may call the function getNumBins() twice: once before and once after coding_unit(). The difference of the two value should do the job for you.

Getting current date and time in C++

I am doing a school project which basically records the in and out time of an employee(of an particular company).The employee while checking in or out should enter a unique key generated specially for him so that no one else can check in and out for him.Then referring to the employees position( A worker or a manager or something like that) his total working time each day , for a week and a month is calculated. The company starts at 8 am and ends at 5 pm for 1st shift and for second shift from 3.30 pm to 2.30 am.Plus Saturday and Sunday off.
Then after a month the program refers to the working time date stored in a file and calculates his pay(For workers its per hour salary and for managers it aint). If an employee is consistently late the details are forwarded to the HR account( so that necessary steps are taken).This will help the company log the details of their employees duty time plus give enough detail to take action if someones always late.
I'm doing this as a school project and it needn't be of enterprise class and all.. But i want the coding to perform as it should.Also i'm forced to use the old Turbo C++.
Now i'm struck in the place where the time of the employees in and out time is logged.
This coding does the work
void main( )
{
clrscr();
char dateStr [9],timeStr [9];
_strdate( dateStr);
cout<<" The current date is "<<dateStr<<'\n';
_strtime( timeStr );
cout<<" The current time is "<<timeStr<<'\n';
getch();
}
I saw it somewhere on the web but can someone help me understand how it works.
I also saw another coding
typedef struct _SYSTEMTIME {
WORD wYear;
WORD wMonth;
WORD wDayOfWeek;
WORD wDay;
WORD wHour;
WORD wMinute;
WORD wSecond;
WORD wMilliseconds;
} SYSTEMTIME;
#include <Windows.h>
#include <stdio.h>
int main()
{
SYSTEMTIME st;
GetSystemTime(&st);
printf("Year:%dnMonth:%dnDate:%dnHour:%dnMin:%dnSecond:% dn"
st.wYear,st.wMonth,st.wDay,st.wHour,st.wMinute,st.wSecond);
}
I think the second one is better as it not only gives me date but also gives me the day so i can check easily for the weekends.
So help me understand how these time functions work. Also if you have any suggestions for my project they are welcome.
You need to decide the format you want to store these clock "events", both for in-memory storage and manipulation and the persistent (on-disk) storage format. When you use different formats for in-memory and on-disk (or in-database) storage, you would use methods to "marshall" or "serialize"/"de-serialize" the data (look up and read about these terms). You also want to decide whether these datetime "events" will be stored or displayed in UTC (Zulu-time, GMT), or local time. You may find that storing these 'timestamps' in UTC is the best, and then you need functions/methods/routines to convert human-readable, displayable values to/from local time to UTC time.
Consider defining a "class" that has the above methods. Your class should have a method to record the current time, convert to human readable, and serialize/de-serialize the data.
Though printf works in C++, you might want to use the stream operators you have used in your first example, as they are more in the spirit of C++. Consider defining a parse method to de-serialize the data, and a to_string method (ruby uses to_s) to serialize (though reading up on stream operator overloading, and overloading the '<<' operator is more the C++ way).
The first uses C library functions (though Microsoft extensions to the standard libc). The second uses the winapi function GetSytemTime.
Both will give the system time.
The first thing I'd look at is what the rest of your code uses. You should distinguish between what is winapi code, C code and C++ code, currently your question uses a mixture of all three.
The C++ method is preferred (if you are intending to write in C++) which would be to use the newer library. The C method is as per your first example, though without mixing libc functions with stream operators (a c++ feature). The winapi method is as per your second example (I'll forgive the use of printf as FormatMessage is a pain).

VBS If Variable > Variable Then

I am writing a script to delete folders older than a certain time window.
The issue I am having is with an If then statement.
If strCurrentAge > strAgeCutoff Then
strCurrentAge = date diff calculation (calculates days between now and the last modified date of the folder)
strAgeCutOff = AgeCutOff.value (textbox input value from an HTA... Typical value would be 30)
strAgeCutOff as a number.
strCurrentAge seems to be recognized as a number though.
Banging my head against the wall trying to figure this out.
If AgeCutOff is a text box, then AgeCutOff.value won't actually be a number, it will be text.
If you want a number from it, look into the CInt() function. You could also use CLng for a greater range but, unless you're talking about the ages of thngs that live substantially longer than humans, integers up to 32,000 should suffice.

Library to discover dates from text?

I need to pull a date out of a string. Since not everyone uses the official ISO format when printing their dates, it is impractical to write a date parser for every possible date format that could be used, and I need to handle as many date formats as possible - I don't control the data and can't expect it to come in a specific format.
This seems like a problem that has probably already been solved ages ago, but my Google-fu is too weak to find the solution. :(
Does there already exist a C++ library that, given a string, will return the month, day, year, hour, minute, second, etc that is referenced in that string, if any?
Pseudocode:
string s1 = "There is an expected meteor shower this Thursday,"
"August 15th 2013 at 4:39 AM.";
string s2 = "20130815T04:39:00";
date d1 = magicConverter(s1);
date d2 = magicConverter(s2);
assert(d1 == d2);
You might use the code from here, but you need to configure a mask, that tells the code which time format is used. If you write a class routine, that takes a mask and a string and gets you out the time and is able to print in any format you like, you should be well prepared. You have to look in more detail, if it also supports Daynames and Monthnames. I got it to work in python with a module providing a function that seems pretty much the same.
For more detail:
Please look at the example 2013-08-03 again. Nobody and as follows no computer is able to tell you if this date belongs to August or April, except of having a mask telling JJJJ-MM-DD or JJJJ-DD-MM. Also this library may tell you only standard masked times. So it might lead you to August in this case. But as you said it can be any date declaration, thus it does not need to follow standards, thus it can also mean March. An other possibility is to tell you about the date from the context (e.g. a table with a column of all te same time formats by looking for the increase (which would also fail if you just look at one day per month for just one year).
Another example... if I ask you 2013-05-04... to which month does it belong? You might tell me... April. I would reply "no, to the 4th of May" and vice versa for May and 5th of April. If you tell me how to solve this puzzle with two possible solutions I would understand your downvote... please think before downvoting someone trying to help you.