From OpenCV documentation, source image in cv::findContours is aquired as const, but something strange is going on with my application. I'm using cv::inRange function to get thresholded image over specific color, and after that, using cv::moments, I can get the center of white pixels in thresholded image and this is working ok.
In addition, I would like to implement the code for finding biggest contour and locating central moment in that contour. After adding just cv::findContours in the code, I spotted strange behavior in the output and after that I wanted to check what is going on with source image using this code:
cv::Mat contourImage;
threshedImage.copyTo(contourImage); // threshedImage is the output from inRange
cv::findContours(threshedImage, contours, CV_RETR_LIST, CV_CHAIN_APPROX_NONE, cv::Point(0,0));
cv::Mat temp;
cv::absdiff(threshedImage,contourOutput, temp);
cv::namedWindow("absdiff");
cv::imshow("absdiff",temp);
After this, output is showing that there is a difference between threshedImage and contourImage. How this is possible? Does anyone have similar results with cv::findContours?
Wrong! The docs clear states that:
Source image is modified by this function.
So if you need the original image intact, make a copy of this image and pass the copy to cv::findContours().
Related
I have a source image. I need a particular portion to be segmented from it and save it as another image. I have the canny outline of the portion I need to be segmented out,but how do I use it to cut the portion from the source image? I have attached both the source image and the canny edge outline. Please help me and suggest me a solution.
EDIT-1: Alexander Kondratskiy,Is this what you meant by filling the boundary?
EDIT-2 : according to Kannat, I have done this
Now how do I separate the regions that are outside and inside of the contour into two separate images?
Edit 3- I thought of 'And-ing'the mask and the contour lined source image.Since I am using C, I am having a little difficulty.
this is the code I use to and:-
hsv_gray = cvCreateImage( cvSize(seg->width, seg->height), IPL_DEPTH_8U, 1 );
cvCvtColor( seg, hsv_gray, CV_BGR2GRAY );
hsv_mask=cvCloneImage(hsv_gray);
IplImage* contourImg =cvCreateImage( cvSize(hsv_mask->width, hsv_mask->height), IPL_DEPTH_8U, 3 );
IplImage* newImg=cvCreateImage( cvSize(hsv_mask->width, hsv_mask->height), IPL_DEPTH_8U, 3 );
cvAnd(contourImg, hsv_mask,newImg,NULL);
I always get an error of mismatch size or Type. I adjusted the size but I can't seem to adjust the type,since one(hsv_mask) is 1 channel and the others are 3 channels.
#kanat- I also tried your boundingrect but could not seem to get in right in C format.
Use cv::findContours on your second image to find the contour of the segment. Then use cv::boundingRect to find bounding box for this segment. After that you can create matrix and save in it cropped bounding box from your second image (as I see it is a binary image). To crop needed region use this:
cv::getRectSubPix(your_image, BB_size, cv::Point(BB.x + BB.width/2,
BB.y + BB.height/2), new_image).
Then you can save new_image using cv::imwrite. That's it.
EDIT:
If you found only one contour then use this (else you will iterate through elements of found contours). The following code shows the steps but sorry I can't test it now:
std::vector<std::vector<cv::Point>> contours;
// cv::findContours(..., contours, ...);
cv::Rect BB = cv::boundingRect(cv::Mat(contours[0]));
cv::Mat new_image;
cv::getRectSubPix(your_image, BB.size(), cv::Point(BB.x + BB.width/2,
BB.y + BB.height/2), new_image);
cv::imwrite("new_image_name.jpg", new_image);
You could fill the boundary created by the canny-edge detector, and use that as an alpha mask on the original image.
my matlab code is:
h = fspecial('average', filterSize);
imageData = imfilter(imageData, h, 'replicate');
bwImg = im2bw(imageData, grayThresh);
cDist=regionprops(bwImg, 'Area');
cDist=[cDist.Area];
opencv code is:
cv::blur(dst, dst,cv::Size(filterSize,filterSize));
dst = im2bw(dst, grayThresh);
cv::vector<cv::vector<cv::Point> > contours;
cv::vector<cv::Vec4i> hierarchy;
cv::findContours(dst,contours,hierarchy,CV_RETR_CCOMP, CV_CHAIN_APPROX_NONE);
here is my image2blackand white function
cv::Mat AutomaticMacbethDetection::im2bw(cv::Mat src, double grayThresh)
{
cv::Mat dst;
cv::threshold(src, dst, grayThresh, 1, CV_THRESH_BINARY);
return dst;
}
I'm getting an exception in findContours() C++ exception: cv::Exception at memory location 0x0000003F6E09E0A0.
Can you please explain what am I doing wrong.
dst is cv::Mat and I used it all along it has my original values.
Update here is my matrix written into *.txt file:
http://www.filedropper.com/gili
UPDATE 2:
I have added dst.convertTo(dst,CV_8U); like Micka suggested, I no longer have an exception. however values are nothing like expected.
Take a look at this question which has a similar problem to what you're encountering: Matlab and OpenCV calculate different image moment m00 for the same image.
Basically, the OP in the linked post is trying to find the zeroth image moment for both x and y of all closed contours - which is actually just the area, by using findContours in OpenCV and regionprops in MATLAB. In MATLAB, that can be accessed by the Area property from regionprops, and judging from your MATLAB code, you wish to find the same quantity.
From the post, there is most certainly a difference between how OpenCV and MATLAB finds contours in an image. This boils down to the way both platforms consider what is a "connected pixel". OpenCV only uses a four-pixel neighbourhood while MATLAB uses an eight-pixel neighbourhood.
As such, there is nothing wrong with your implementation, and converting to 8UC1 is good. However, the areas (and ultimately the total number of connected components and contours themselves) between both contours found with MATLAB and OpenCV are not the same. The only way for you to get exactly the same result is if you manually draw the contours found by findContours on a black image, and using the cv::moments function directly on this image.
However, because of the differing implementations of cv::blur() in comparison to fspecial with an averaging mask that is even, you still may not be able to get the same results along the borders of the image. If there are no important contours around the borders of your image, then hopefully this will give you the right result.
Good luck!
Looking for a way for taking a screenshot of a particular area on the screen in C++. (So not the whole screen) Then it should save it as .png .jpg whatever to use it with another function afterwards.
Also, I am going to use it, somehow, with openCV. Thought i'd mention that, maybe it's a helpful detail.
OpenCV cannot take screenshots from your computer directly. You will need a different framework/method to do this. #Ben is correct, this link would be worth investigating.
Once you have read this image in, you will need to store it into a cv:Mat so that you are able to perform OpenCV operations on it.
In order to crop an image in OpenCV the following code snippet would help.
CVMat * imagesource;
// Transform it into the C++ cv::Mat format
cv::Mat image(imagesource);
// Setup a rectangle to define your region of interest
cv::Rect myROI(10, 10, 100, 100);
// Crop the full image to that image contained by the rectangle myROI
// Note that this doesn't copy the data
cv::Mat croppedImage = image(myROI);
Ok sorry for asking pretty much the same question again but I've tried many methods and I still can't do what I'm trying to do and I'm not even sure it's possible with opencv alone.
I have rotated an image and I want to copy it inside another image. The problem is that no matter what way I crop this rotated image it always copies inside this second image with a non rotated square around it. As can be seen in the image below.(Forget the white part thats ok). I just want to remove the striped part.
I believe my problem is with my ROI that I copy the image to as this ROI is a rect and not a RotatedRect. As can be seen in the code below.
cv::Rect roi(Pt1.x, Pt1.y, ImageAd.cols, ImageAd.rows);
ImageAd.copyTo(ImageABC(roi));
But I can't copyTo with a rotatedRect like in the code below...
cv::RotatedRect roi(cent, sizeroi, angled);
ImageAd.copyTo(ImageABC(roi));
So is there a way of doing what I want in opencv?
Thanks!
After using method below with masks I get this image which as seen is cut off by the roi in which I use to say where in the image I want to copy my rotated image. Basically now that I've masked the image, how can I select where to put this masked image into my second image. At the moment I use a rect but that won't work as my image is no longer a rect but a rotated rect. Look at the code to see how I wrongly do it at the moment (it cuts off and if I make the rect bigger an exception is thrown).
cv::Rect roi(Pt1.x, Pt1.y, creditcardimg.cols, creditcardimg.rows);
creditcardimg.copyTo(imagetocopyto(roi),mask);
Instead of ROI you can use mask to copy,
First create mask using rotated rect.
Copy your source image to destination image using this mask
See below C++ code
Your rotated rect and I calculated manually.
RotatedRect rRect = RotatedRect(Point2f(140,115),Size2f(115,80),192);
Create mask using draw contour.
Point2f vertices[4];
rRect.points(vertices);
Mat mask(src.rows, src.cols, CV_8UC1, cv::Scalar(0));
vector< vector<Point> > co_ordinates;
co_ordinates.push_back(vector<Point>());
co_ordinates[0].push_back(vertices[0]);
co_ordinates[0].push_back(vertices[1]);
co_ordinates[0].push_back(vertices[2]);
co_ordinates[0].push_back(vertices[3]);
drawContours( mask,co_ordinates,0, Scalar(255),CV_FILLED, 8 );
Finally copy source to destination using above mask.
Mat dst;
src.copyTo(dst,mask);
I am currently working on image processing project. I am using Opencv2.3.1 with VC++.
I have written the code such that, the input image is filtered to only blue color and converted to a binary image. The binary image has some small objects which I don't want. I wanted to eliminate those small objects, so i used openCV's cvFindContours() method to detect contours in Binary image. but the problem is I cant eliminate the small objects in the image output. I used cvContourArea() function , but didn't work properly.. , erode function also didn't work properly.
So please someone help me with this problem..
The binary image which I obtained :
The result/output image which I want to obtain :
Ok, I believe your problem could be solved with the bounding box demo recently introduced by OpenCV.
As you have probably noticed, the object you are interested at should be inside the largest rectangle draw in the picture. Luckily, this code is not very complex and I'm sure you can figure it all out by investigating and experimenting with it.
Here is my solution to eliminate small contours.
The basic idea is check the length/area for each contour, then delete the smaller one from vector container.
normally you will get contours like this
Mat canny_output; //example from OpenCV Tutorial
vector<vector<Point> > contours;
vector<Vec4i> hierarchy;
Canny(src_img, canny_output, thresh, thresh*2, 3);//with or without, explained later.
findContours(canny_output, contours, hierarchy, CV_RETR_TREE, CV_CHAIN_APPROX_SIMPLE, Point(0,0));
With Canny() pre-processing, you will get contour segments, however each segment is stored with boundary pixels as a closed ring. In this case, you can check the length and delete the small one like
for (vector<vector<Point> >::iterator it = contours.begin(); it!=contours.end(); )
{
if (it->size()<contour_length_threshold)
it=contours.erase(it);
else
++it;
}
Without Canny() preprocessing, you will get contours of objects.
Similarity, you can also use area to define a threshold to eliminate small objects, as OpenCV tutorial shown
vector<Point> contour = contours[i];
double area0 = contourArea(contour);
this contourArea() is the number of non-zero pixels
Are you sure filtering by small contour area didn't work? It's always worked for me. Can we see your code?
Also, as sue-ling mentioned, it's a good idea to use both erode and dilate to approximately preserve area. To remove small noisy bits, use erode first, and to fill in holes, use dilate first.
And another aside, you may want to check out the new C++ versions of the cv* functions if you weren't aware of them already (documentation for findContours). They're much easier to use, in my opinion.
Judging by the before and after images, you need to determine the area of all the white areas or blobs, then apply a threshold area value. This would eliminate all areas less than the value and leave only the large white region which is seen in the 2nd image. After using the cvFindContours function, try using 0 order moments. This would return the area of the blobs in the image. This link might be helpful in implementing what I've just described.
http://www.aishack.in/2010/07/tracking-colored-objects-in-opencv/
I believe you can use morphological operators like erode and dilate (read more here)
You need to perform erosion with a kernel size near to the radius of the circle on the right (the one you want to eliminate).
followed by dilation using the same kernel to fill the gaps created by the erosion step.
FYI erosion followed by dilation using the same kernel is called opening.
the code will be something like this
int erosion_size = 30; // adjust with you application
Mat erode_element = getStructuringElement( MORPH_ELLIPSE,
Size( 2*erosion_size + 1, 2*erosion_size+1 ),
Point( erosion_size, erosion_size ) );
erode( binary_img, binary_img, erode_element );
dilate( binary_img, binary_img, erode_element );
It is not a fast way but may be usefull in some cases.
There is a new function in OpencCV 3.0 - connectedComponentsWithStats. With it we can get area of connected components and eliminate unnecessary. So we can easy remove circle with holes, with the same bounding box as solid circle.