I'm somewhat new to ruby and have done a ton of google searching but just can't seem to figure out how to match this particular pattern. I have used rubular.com and can't seem to find a simple way to match. Here is what I'm trying to do:
I have several types of hosts, they take this form:
Sample hostgroups
host-brd0000.localdomain
host-cat0000.localdomain
host-dog0000.localdomain
host-bug0000.localdomain
Next I have a case statement, I want to keep out the bugs (who doesn't right?). I want to do something like this to match the series of characters. However, it starts matching at host-b, host-c, host-d, and matches only a single character as if I did a [brdcatdog].
case $hostgroups { #variable takes the host string up to where the numbers begin
# animals to keep
/host-[["brd"],["cat"],["dog"]]/: {
file {"/usr/bin/petstore-friends.sh":
owner => petstore,
group => petstore,
mode => 755,
source => "puppet:///modules/petstore-friends.sh.$hostgroups",
}
}
I could do something like [bcd][rao][dtg] but it's not very clean looking and will match nonsense like "bad""cot""dat""crt" which I don't want.
Is there a slick way to use \A and [] that I'm missing?
Thanks for your help.
-wootini
How about using negative lookahead?
host-(?!bug).*
Here is the RUBULAR permalink matching everything except those pesky bugs!
Is this what you're looking for?
host-(brd|cat|dog)
(Following gtgaxiola's example, here's the Rubular permalink)
Related
I'm using the following regex to find URLs in a text file:
/http[s]?://(?:[a-zA-Z]|[0-9]|[$-_#.&+]|[!*\(\),]|(?:%[0-9a-fA-F][0-9a-fA-F]))+/
It outputs the following:
http://rda.ucar.edu/datasets/ds117.0/.
http://rda.ucar.edu/datasets/ds111.1/.
http://www.discover-earth.org/index.html).
http://community.eosdis.nasa.gov/measures/).
Ideally they would print out this:
http://rda.ucar.edu/datasets/ds117.0/
http://rda.ucar.edu/datasets/ds111.1/
http://www.discover-earth.org/index.html
http://community.eosdis.nasa.gov/measures/
Any ideas on how I should tweak my regex?
Thank you in advance!
UPDATE - Example of the text would be:
this is a test http://rda.ucar.edu/datasets/ds117.0/. and I want this to be copied over http://rda.ucar.edu/datasets/ds111.1/. http://www.discover-earth.org/index.html). http://community.eosdis.nasa.gov/measures/).
This will trim your output containing trail characters, ) .
import re
regx= re.compile(r'(?m)[\.\)]+$')
print(regx.sub('', your_output))
And this regex seems workable to extract URL from your original sample text.
https?:[\S]*\/(?:\w+(?:\.\w+)?)?
Demo,,, ( edited from https?:[\S]*\/)
Python script may be something like this
ss=""" this is a test http://rda.ucar.edu/datasets/ds117.0/. and I want this to be copied over http://rda.ucar.edu/datasets/ds111.1/. http://www.discover-earth.org/index.html). http://community.eosdis.nasa.gov/measures/). """
regx= re.compile(r'https?:[\S]*\/(?:\w+(?:\.\w+)?)?')
for m in regx.findall(ss):
print(m)
So for the urls you have here:
https://regex101.com/r/uSlkcQ/4
Pattern explanation:
Protocols (e.g. https://)
^[A-Za-z]{3,9}:(?://)
Look for recurring .[-;:&=+\$,\w]+-class (www.sub.domain.com)
(?:[\-;:&=\+\$,\w]+\.?)+`
Look for recurring /[\-;:&=\+\$,\w\.]+ (/some.path/to/somewhere)
(?:\/[\-;:&=\+\$,\w\.]+)+
Now, for your special case: ensure that the last character is not a dot or a parenthesis, using negative lookahead
(?!\.|\)).
The full pattern is then
^[A-Za-z]{3,9}:(?://)(?:[\-;:&=\+\$,\w]+\.?)+(?:\/[\-;:&=\+\$,\w\.]+)+(?!\.|\)).
There are a few things to improve or change in your existing regex to allow this to work:
http[s]? can be changed to https?. They're identical. No use putting s in its own character class
[a-zA-Z]|[0-9]|[$-_#.&+]|[!*\(\),] You can shorten this entire thing and combine character classes instead of using | between them. This not only improves performance, but also allows you to combine certain ranges into existing character class tokens. Simplifying this, we get [a-zA-Z0-9$-_#.&+!*\(\),]
We can go one step further: a-zA-Z0-9_ is the same as \w. So we can replace those in the character class to get [\w$-#.&+!*\(\),]
In the original regex we have $-_. This creates a range so it actually inclues everything between $ and _ on the ASCII table. This will cause unwanted characters to be matched: $%&'()*+,-./0123456789:;<=>?#ABCDEFGHIJKLMNOPQRSTUVWXYZ[\]^_. There are a few options to fix this:
[-\w$#.&+!*\(\),] Place - at the start of the character class
[\w$#.&+!*\(\),-] Place - at the end of the character class
[\w$\-#.&+!*\(\),] Escape - such that you have \- instead
You don't need to escape ( and ) in the character class: [\w$#.&+!*(),-]
[0-9a-fA-F][0-9a-fA-F] You don't need to specify [0-9a-fA-F] twice. Just use a quantifier like so: [0-9a-fA-F]{2}
(?:%[0-9a-fA-F][0-9a-fA-F]) The non-capture group isn't actually needed here, so we can drop it (it adds another step that the regex engine needs to perform, which is unnecessary)
So the result of just simplifying your existing regex is the following:
https?://(?:[$\w#.&+!*(),-]|%[0-9a-fA-F]{2})+
Now you'll notice it doesn't match / so we need to add that to the character class. Your regex was matching this originally because it has an improper range $-_.
https?://(?:[$\w#.&+!*(),/-]|%[0-9a-fA-F]{2})+
Unfortunately, even with this change, it'll still match ). at the end. That's because your regex isn't told to stop matching after /. Even implementing this will now cause it to not match file names like index.html. So a better solution is needed. If you give me a couple of days, I'm working on a fully functional RFC-compliant regex that matches URLs. I figured, in the meantime, I would at least explain why your regex isn't working as you'd expect it to.
Thanks all for the responses. A coworker ended up helping me with it. Here is the solution:
des_links = re.findall('http[s]?://(?:[a-zA-Z]|[0-9]|[$-_#.&+]|[!*\(\),]|(?:%[0-9a-fA-F][0-9a-fA-F]))+', des)
for i in des_links:
tmps = "/".join(i.split('/')[0:-1])
print(tmps)
My Regex skills a minimum, I have been trying for a while now to get this to work:
I need to match all urls in one domain, but one (the login one).
Example:
Match: domain.com/ANYTHING-GOES-HERE
but
Not Match: domain.com/login
I don't actually need to match the domain.com part because that's always the same, what comes after it.
I have tried:
(?!\/login)\/.*
\/.*[^login]
Neither one seems to work as desired.
Update:
I should have explained that this is done in PHP. I don't have control over the actual code that runs the regex, but I do have control over how many regex I can have. So I could have one regex that matches everything, and then have one regex that matches or not matches "/login"
You're almost there:
// javascript
r = /domain\.com\/(?!login).+/
r.test("domain.com/ANYTHING-GOES-HERE") // true
r.test("domain.com/login") // false
This also rejects "domain.com/login/foobar", if you want it to be accepted, modify the regex to be
r = /domain\.com\/(?!login$).+/
I have the following statement:
Directory.GetFiles(filePath, "A*.pdf")
.Where(file => Regex.IsMatch(Path.GetFileName(file), "[Aa][i-lI-L].*"))
.Skip((pageNum - 1) * pageSize)
.Take(pageSize)
.Select(path => new FileInfo(path))
.ToArray()
My problems is that the above statement also finds the file "Adali.pdf" which it should not - but i cannot figure out why.
The above statement should only select files starting with a, and where the second letter is in the range i-l.
Because it matches Adali taking 3rd and 4th characters (al):
Adali
--
Try using ^ in your regex which allows looking for start of the string (regex cheatsheet):
Regex.IsMatch(..., "^[Aa][i-lI-L].*")
Also I doubt you need asterisk at all.
PS: As a sidenote let me notice that this question doesn't seem to be written that good. You should try debugging this code yourself and particularly you should try checking your regex against your cases without LINQ. I'm sure there is nothing to do here with LINQ (the tag you have in your question), but the issue is about regular expressions (which you didn't mention in tags at all).
You are not anchoring the string. This makes the regex match the al in Adali.pdf.
Change the regex to ^[Aa][i-lI-L].* You can do just ^[Aa][i-lI-L] if you don't need anything besides matching.
You should to do this
var f = Directory.GetFiles(tb_Path.Text, "A*.pdf").Where(file => Regex.IsMatch(Path.GetFileName(file), "[Aa][i-lI-L].pdf")).ToArray();
When you call ".*" Adali accept in Regex
I would like some help matching the following urls.
/settings => /settings.php
/657_46hallo => /657_46hallo.php
/users/create => /users.php/create
/contact/create/user => /contact.php/create/user
/view/info.php => /view.php/info.php
/view/readme - now.txt => /view.php/readme - now.txt
/ => [NO MATCH]
/filename.php => /unknown.php
/filename.php/users/create => /unknown.php
if the first part after the domain name is a filename ending with ".php"
(see last 2 examples) It should redirect to /unknown.php
I think I need 2 regular expressions
1st should be almost something like: ^/([a-zA-Z0-9_]+)(/)?(.*)?$
2nd to catch the direct filename "/filename.php" or "/filename.php/create/user"
so I can redirect to unknown.php
The 1st regular expression that I got almost works for the first part.
==============================================
request url: http://domain.com/user/create
regex: ^/([a-zA-Z0-9_]+)(/)?(.*)?$
replace http://domain.com/$1.php$2$3
makes: http://domain.com/user.php/create
Problem is it also matches http://domain.com/user.php/create
If someone could help me with both regular expressions that would be great.
If you want to match those .php cases you can try this:
^\/([a-zA-Z0-9_]+)(\/)?(.*)?$
See here on Regexr
If you want to avoid those cases try this:
^/([a-zA-Z0-9_]+)(?!\.php)(?:(/)(.*)|)$
See here on Regexr
The (?!\.php) is a negative look ahead that ensures that there is no .php at this place.
When all you have is a hammer...
While this probably could be solved with a regexp, it is probably the wrong tool for the job, unless you have constraints that MANDATE the use of regexps.
Split the string using '/' as the delimiter, see whether the first component ends with '.php'; if so, reject it, otherwise append '.php' to the first component and join the components back using '/'.
I have the following strings in my application.
/admin/stylesheets/11
/admin/javascripts/11
/contactus
what I want to do is to write a regular expression to capture anything other than string starting with 'admin'
basically my regex should capture only
/contactus
by excluding both
/admin/stylesheets/11
/admin/javascripts/11
to capture all i wrote
/.+/
and i wrote /(admin).+/ which captures everything starts with 'admin'. how can i do the reverse. I mean get everything not starting with 'admin'
thanks in advance
cheers
sameera
EDIT - Thanks all for the answers
I'm using ruby/ Rails3 and trying to map a route in my routes.rb file
My original routes file is as followss
match '/:all' => 'page#index', :constraints => { :all => /.+/ }
and i want the RegEx to replace /.+/
thanks
If the language/regular expression implementation you are using supports look-ahead assertions, you can do this:
^/(?!admin/).+/
Otherwise, if you only can use basic syntax, you will need to do something like this:
^/([^a].*|a($|[^d].*|d($|[^m].*|m($|[^i].*|i($|[^n].*)))))