I am trying to extract some information from facebook using Regex. Here is a link with an example:
https://graph.facebook.com/210989592315921
I was interested in what would the regular expression be in order to extract just the number of likes from this string.
I have tried for example this expression:
"likes":\s[0-9]$
Thank you in advance for any advice regarding this matter,
Mark
You should follow "#Hope I helped" comment and use a json parser. You can't be sure the text is going to be formatted always the same way:
Are you always going to have a single space between : and the number ?
By the way, here is the error you are looking for, your current regex matches a single figure, not a multiple digit number, you should use something like: [0-9]+ and probably remove the $ which is not correct in your example, as you have a comma after the number.
Related
I am at the beginning of learning Regex, and I use every opportunity to understand how it's working. Currently I am trying to extract dates from a text file (which is in fact a vnt-file type from my mobile phone). It looks like following:
BEGIN:VNOTE
VERSION:1.1
BODY;ENCODING=QUOTED-PRINTABLE;CHARSET=UTF-8:18.07.=0A14.08.=0A15.09.=0A15.10.=
=0A13.11.=0A13.12.=0A12.01.=0A03.02. Grippe=0A06.03.=0A04.04.2015=0A0=
5.05.2015=0A03.06.2015=0A03.07.2015=0A02.08.2015=0A30.08.2015=0A28.09=
17.11.2017=0A
DCREATED:20171118T095601
X-IRMC-LUID:150
END:VNOTE
I want to extract all dates, so that the final list is like that:
18.07.
14.08.
15.09.
15.10.
and so on. If the date has also a year, it should also be displayed.
I almost found out how to detect the dates by the following regex:
.+(\d\d\.\d\d\.(2015|2016|2017)?).+
But it only detect very few of the dates. The result is this:
BEGIN:VNOTE
VERSION:1.1
15.10.
04.04.2015
30.08.2015
24.01.2016
DCREATED:20171118T075601
X-IRMC-LUID:150
END:VNOTE
Then I tried to add a question mark which makes the .+ not greedy, as far as I read in tutorials. Then the regex looks like:
.+?(\d\d\.\d\d\.(2015|2016|2017)?).+?
But the result is still not what I am looking for:
BEGIN:VNOTE
VERSION:1.1
21.03.20.04.18.05.18.06.18.07.14.08.15.09.15.10.
13.11.13.12.12.01.03.02.06.03.04.04.20150A0=
03.06.201503.07.201502.08.201530.08.20150A28.09=
28.10.201525.11.201528.12.201524.01.20160A
DCREATED:20171118T075601
X-IRMC-LUID:150
END:VNOTE
For someone who is familiar with regex I am pretty sure this is very easy to solve, but I don't get it. It's very confusing when you are new to regex. I tried to find a hint in some tutorials or stackoverflow posts, but all I found is this: Notepad++ how to extract only the text field which is needed?
But it doesn't work for me. I assume it might have something to do with the fact that my text file is not one single line.
I have my example on regex101 too.
I would be very thankful if maybe someone can give me a hint what else I can try.
Edit: I would like to detect the dates with the regex and as a result have a list with only the dates (maybe it is called substitute?)
Edit 2: Sorry for not mentioning it earlier: I just want to use the regex in e.g. Notepad++ or an online regex test website. Just to get the result of the dates and save the result in a new txt-file. I don't want to use the regex in an programming language. My apologies for not being precisely before.
Edit 3: The result should be a list with the dates, and each date in a new line:
I want to extract all dates, so that the final list is like that:
18.07.
14.08.
15.09.
15.10.
I suggest this pattern:
(?:.*?|\G)(\d\d\.\d\d\.(?:\d{4})?)
This makes use of the \G flag that, in this case, allows for multiple matches from the very start of the match without letting any single unmatched character in the text, thus allowing the removal of all but what's wanted.
If you want to remove the extra matches as well, add |.* at the end:
(?:.*?|\G)(\d\d\.\d\d\.(?:\d{4})?)|.*
regex101 demo
In N++, make sure the options underlined are selected, and that the cursor is at the beginning. In the picture below, I replaced then undid the replacement, only to show that matches were identified (16 replacements).
You can try using the following pattern:
\d{2}\.\d{2}\.(?:\d{4})?
This will match day.month dates of the form 18.07., but it also allows such a date to be followed by a four digit year, e.g. 18.07.2017. While it would be nice to make the pattern more restrictive, to avoid false fire matches, I do not see anything obvious which can be added to the above pattern. Follow the demo link below to see the pattern in action.
Demo
I am looking to extract some text from a raw credit card feed for a workflow. I have gotten almost where I want to but am struggling with the final piece of information I'm trying to extract.
An example of the raw feed is:
LEO'SFINEFOOD&WINEHARTWELLJune350.0735.00ICGROUP,INC.MELBOURNEJune5UNITEDSTATESDOLLARAUD50.07includesconversioncommissionofAUD1.469.96WOOLWORTHS3335CHADSTOCHADSTONE
I am looking to extract this from the above:
(ICGROUP,INC.MELBOURNE)June5UNITEDSTATESDOLLARAUD(50.07)includesconversioncommissionof
with the brackets representing the two groups I am after. The consistent parts across all instances of what I'm trying to extract is:
DIGITS (TEXT) DATE TEXT AMOUNT includesconversioncommissionof
I have been able to use the regex:
([A-Z][a-z]\d)[A-Z]AUD(\d\,?\d+?.\d*)includesconversioncommissionofAUD
to get me the date and the amount. I am struggling to find a way to get as per the example above the words ICGROUP,INC.MELBOURNE
I have tried putting \d\d(.*) before the above regex but that doesn't work for some reason.
Would appreciate if anyone is able to help with what I'm after!
The closest I think we can get (PCRE) is something like:
/
[\d,.]+ # a currency value to bookend
(.+?) # capture everything in-between
[A-Z][a-z]+\d+ # a month followed by a day, e.g. "June5"
.+? # everything in-between
([\d,.]+) # capture a currency value
includesconversioncommissionof # our magic token to bookend
/x
The technique here is to pit greedy expressions against non-greedy expressions in a very deliberate way. Let me know if you have any questions about it. I would be extremely hesitant to put this in production—or even trust its output as an ad-hoc pass—without rigorous testing!
I'm using the pattern [\d,.] for currency, but you can replace that with something more sophisticated, especially if you expect weird formats and currency symbols. The biggest potential pitfall here is if the ICGROUP,INC.MELBOURNE token might start with a number. Then you'll definitely need a more sophisticated currency pattern!
Here's what I've got (in php).
$string = "LEO'SFINEFOOD&WINEHARTWELLJune350.0735.00ICGROUP,INC.MELBOURNEJune5UNITEDSTATESDOLLARAUD50.07includesconversioncommissionofAUD1.469.96WOOLWORTHS3335CHADSTOCHADSTONE";
$cleaned = preg_replace("/^(LEO'SFINEFOOD&WINEHARTWELL)([A-Za-z]{3,9})(\.|\d)*/", "", $string);
echo $cleaned;
what it returns is: ICGROUP,INC.MELBOURNEJune5UNITEDSTATESDOLLARAUD50.07includesconversioncommissionofAUD1.469.96WOOLWORTHS3335CHADSTOCHADSTONE
Which you can then use and run your own little regex on.
Explanation:
The \w{3,9} is used to remove the month which may be 3-9 characters long. Then the (\.|\d)* is to remove the digits and dots. I'm thinking that we could parse the month/date better using your regex to extract that June 5 part but from your example given, it shouldn't be necessary.
However, it would be much more helpful if you could provide at least 3 examples, optimally 5, so we can get a good feel of the pattern. Otherwise this is the best I can do with what you've given.
I am pretty new to the concept of regex and so I am hoping an expert user can help me craft the right expression to find all the matches in a string. I have a string that represents a lot of support information in it for vulnerabilities data. In that string are a series of CVE references in the format: CVE-2015-4000. Can anyone provide me a sample regex on finding all occurrences of that ? obviously, the numeric part of that changes throughout the string...
Generally you should always include your previous efforts in your question, what exactly you expect to match, etc. But since I am aware of the format and this is an easy one...
CVE-\d{4}-\d{4,7}
This matches first CVE- then a 4-digit number for the year identifier and then a 4 to 7 digit number to identify the vulnerability as per the new standard.
See this in action here.
If you need an exact match without any syntax or logic violations, you can try this:
^(CVE-(1999|2\d{3})-(0\d{2}[1-9]|[1-9]\d{3,}))$
You can run this against the test data supplied by MITRE here to test your code or test it online here.
I will add my two cents to the accepted answer. Incase we want to detect case insensitive "CVE" we can following regex
r'(?i)\bcve\-\d{4}-\d{4,7}'
I am trying to use PSQL, specifically AWS Redshift to parse a line. Sample data follows
{"c.1.mcc":"250","appId":"sx-calllog","b.level":59,"c.1.mnc":"01"}
{"appId":"sx-voice-call","b.level":76,"foreground":9}
I am trying the following regex in order to to extract the appId field, but my query is returning empty fields.
'appId\":\"[\w*]\",'
Query
SELECT app_params,
regexp_substr(app_params, 'appId\":\"[\w*]\",')
FROM sample;
You can do that as follows:
(\"appId\":\"[^"]*\")(?:,)
Demo: http://regex101.com/r/xP0hW3
The first extracted group is what you want.
Your regex was not matching because \w does not match -
Adding this here despite this being an old question since it may help someone viewing this down the road...
If your lines of data are valid json, you can use Redshift's JSON_EXTRACT_PATH_TEXT function to extract the value a given key. Emphasis on the json being valid, as it will fail if even one line cannot be parsed and Redshift will throw a JSON parsing error.
Example using given data:
select json_extract_path_text('{"c.1.mcc":"250","appId":"sx-calllog","b.level":59,"c.1.mnc":"01"}','appId');
returns sx-calllog
This is especially useful since Redshift does not support lookahead/lookbehind (it is POSIX regex) & extract groups.
You can try using some lookahead and look behinds to isolate just the text inside the quotes for the appid. (?<=appId\":\")(?=.*\",)[^\"]*. I tested this out a bit using your examples you provided here.
To explain the regex a bit more: (?<=appId\":\")(?=.*\",)[^\"]*
(?<=appId\":\"): positive look behind for appid":". Since you don't want the appid text itself being returned (just the value), you can preface the regex with a look behind to say "find me the following regex, but only when it is following the look behind text.
(?=.*\",): positive look ahead for the ending ",. You don't want quotes to be returned in your match, but as with number 1 you want your regex to be bounded a bit and a look ahead does that.
[^\"]*: The actual matching portion. You want to find the string of chars that are NOT ". This will match the entire value and stop matching right before the closing ".
EDIT: Changed the 3rd step a little bit, removed the , from that last piece, it is not needed and would break the match if the value were to actually contain a ,.
In a .txt file i have multiple lines. Every line contains timing data like this:
time [4.1s] [4100ms]
time [5.53s] [5530ms]
All lines have different words/chars before and after the times.
I want to do a Find- and replace action (In Notepad++) to get the following, simple, format:
4.1
5.53
How do I do it? What is the regular expression to use?
Any help is greatly appreciated!
Find:
.*\[([\d.]+)s\].*
Replace with:
\1
Assuming that you only want the first number in brackets and that has a decimal point as per your example:
\d*[.]\d+
This returns 4.1 and 5.53 as requested when applied to your example.
If the first number might not have a decimal point, then you want to consider:
\d*[.]?\d+s
but append s in your replace to account for the s.
Update
Update based on your latest information. I don't know if Notepad++ supports positive lookbehind (?<=), but if it does you could do this:
(?<=time \[)\d*[.]\d+