Using SFINAE to calculate the size of different elements - c++

Introduction
I'm just begining to reading and studying about SFINAE. In order to improve my understanding I've started trying things by myself.
So I've been wondering about a useful but yet simple way to use the SFINAE powerful trick and I ended thinking about a set of functions that calculates how many bytes occupies a given type; as long as we're dealing with simple types the solution is trivial:
template <typename T> size_t SizeOf(const T &t)
{
return sizeof(T);
};
This naive approximation would get the size of anything: 1 for char, possibly 4 for int, hopefully 4 for char[4] and whatever for class PrettyAwesome or struct AmazingStuff including padding bytes. But, what about the dynamic memory managed by this types?
So I would check if the given type is a pointer type then, the total size would be the size of pointer plus the size of pointed memory (if any).
template <typename T> size_t SizeOf(const T &*t)
{
size_t Result = sizeof(t);
if (t)
{
Result += sizeof(T);
}
return Result;
};
Yes, at this point it seems that SFINAE isn't needed at all but, let's think about containers. The SizeOf a container must be the sum of sizeof(container_type) plus the sum of the size of each of its elements, this is where SFINAE enters:
template <typename T> size_t SizeOf(const T &t)
{
size_t Result = sizeof(t);
for (T::const_iterator i = t.begin(); i != t.end(); ++i)
{
Result += SizeOf(*i);
}
return Result;
};
In the above code, detect if tye T type has a const_iterator is needed, and it the container is a map an specialization for pairs is needed too.
Questions
Finally, the questions begins here: What have I tried and in what problems I'm stuck?
#include <type_traits>
#include <string>
#include <map>
#include <iostream>
#include <vector>
// Iterable class detector
template <typename T> class is_iterable
{
template <typename U> static char has_iterator(typename U::const_iterator *);
template <typename U> static long has_iterator(...);
public:
enum
{
value = (sizeof(has_iterator<T>(0)) == sizeof(char))
};
};
// Pair class detector
template <typename T> class is_pair
{
template <typename U> static char has_first(typename U::first_type *);
template <typename U> static long has_first(...);
template <typename U> static char has_second(typename U::second_type *);
template <typename U> static long has_second(...);
public:
enum
{
value = (sizeof(has_first<T>(0)) == sizeof(char)) && (sizeof(has_second<T>(0)) == sizeof(char))
};
};
// Pointer specialization.
template <typename T> typename std::enable_if<std::is_pointer<T>::value, size_t>::type SizeOf(const T &aValue)
{
size_t Result = sizeof(aValue);
if (aValue)
{
Result += sizeof(T);
}
return Result;
}
// Iterable class specialization.
template <typename T> typename std::enable_if<is_iterable<T>::value, size_t>::type SizeOf(const T &aValue)
{
size_t Result = sizeof(aValue);
for (T::const_iterator I = aValue.begin(); I != aValue.end(); ++I)
{
Result += SizeOf(*I);
}
return Result;
}
// Pair specialization.
template <typename T> typename std::enable_if<is_pair<T>::value, size_t>::type SizeOf(const T &aValue)
{
return SizeOf(aValue.first) + SizeOf(aValue.second);
}
// Array specialization.
template <typename T> typename std::enable_if<std::is_array<T>::value, size_t>::type SizeOf(const T &aValue)
{
size_t Result = sizeof(aValue);
for (T *I = std::begin(aValue); I != std::end(aValue); ++I)
{
SizeOf(*I);
}
return Result;
}
// Other types.
template <typename T> typename std::enable_if<std::is_pod<T>::value, size_t>::type SizeOf(const T &aValue)
{
return sizeof(aValue);
}
int main(int argc, char **argv)
{
int Int;
int *IntPtr = &Int;
int twoints[2] = {0, 0};
int *twointpointers[2] = {IntPtr};
std::string SO("StackOverflow");
std::wstring WSO(L"StackOverflow");
std::map<std::string, char> m;
std::vector<float> vf;
m[SO] = 'a';
std::cout << "1: " << SizeOf(Int) << '\n';
// std::cout << "2: " << SizeOf(IntPtr) << '\n';
// std::cout << "3: " << SizeOf(twoints) << '\n';
// std::cout << "4: " << SizeOf(twointpointers) << '\n';
std::cout << "5: " << SizeOf(SO) << '\n';
std::cout << "6: " << SizeOf(WSO) << '\n';
std::cout << "7: " << SizeOf(m) << '\n';
std::cout << "8: " << SizeOf(vf) << '\n';
return 0;
}
The above code produces this output:
1: 4
5: 45
6: 58
7: 66
8: 20
If I uncomment the lines with the 2, 3 and 4 output the compiler shows the "ambiguous call" error. I really had thought that the output 2 will use the is_pointer speciallization and the output 3 and 4 will use the is_array one. Well, I was wrong but I don't know why.
I'm not fine with the way I get the total size of a container, i think that iterating all the items and calling the SizeOf for each item is a good choice but not for all the containers, in std::basic_string doing sizeof(container) + sizeof(container::value_type) * container.size() would be faster but I cannot realize how to specializate for basic_string.
Talking about the detection classes (like the ones that detect iterable and pair), in some blogs articles and web examples about SFINAE I've seen that is a common practice to create a true_type and false_type typedefs, usually defined as char and char[2]; but I've found that some authors uses char and long as true_type and false_type. Anyone knows wich one is the best practice or the most standard one?.
Note that I'm not looking for answers like why you don't try "this library" or "this tool", my goal is practicing and understanding the SFINAE, any clue and advice is wellcome.

1.You should read about POD concept in C++11. Array of POD-type elements or pointer to POD-type element are POD-types http://en.cppreference.com/w/cpp/concept/PODType
For example following code will compile well http://liveworkspace.org/code/81627f5acb546c1fb73a69c45f7cf8ec
2.Something like this can help you
template<typename T>
struct is_string
{
enum
{
value = false
};
};
template<typename Char, typename Traits, typename Alloc>
struct is_string<std::basic_string<Char, Traits, Alloc>>
{
enum
{
value = true
};
};
Functions
// Iterable class specialization.
template <typename T> typename std::enable_if<is_iterable<T>::value && !is_string<T>::value, size_t>::type SizeOf(const T &aValue)
{
size_t Result = sizeof(aValue);
for (typename T::const_iterator I = aValue.begin(); I != aValue.end(); ++I)
{
Result += SizeOf(*I);
}
return Result;
}
template <typename T> typename std::enable_if<is_string<T>::value, size_t>::type SizeOf(const T& aValue)
{
return sizeof(aValue) + sizeof(typename T::value_type) * aValue.length();
}
3.No information in standard, that sizeof(long) should never be equal to sizeof(char), but sizeof(char) cannot be equal to sizeof(char[2]), so, second variant is preferable i think.

Regarding question #3, I think that in C++11, it's much cleaner (and more clear) to use decltype instead of sizeof to obtain an integral constant such as std::true_type and std::false_type.
For example, your is_iterable:
#include <type_traits> // std::true_type, std::false_type
// Iterable class detector
template <typename T> class is_iterable {
template <typename U> static std::true_type test(typename U::const_iterator *);
template <typename U> static std::false_type test(...);
public:
// Using decltype in separate typedef because of gcc 4.6 bug:
// http://gcc.gnu.org/bugzilla/show_bug.cgi?id=6709
typedef decltype(test<T>(0)) result_type;
static const bool value = result_type::value;
};

Your "specializations" for pointers etc. are in fact not specializations. They're overloads.
The compiler first performs overload resolution, and only then checks for specializations. There's formally no such thing as an "ambiguous specialization". Your cases 2,3 and 4 fail already in overload resolution, precisely because you have no specializations.
Overload resolution is decided on argument types only. Your overloads only differ in return type. Certainly some overloads may be disabled, but you would need to disable all overloads but one. Currently, a POD array enables both your POD and array overloads.
For a container, the better solution is probably to use Container.size().
char[2] is preferred because sizeof(long) can be 1, according to the standard.
One question not asked, which I'll answer anyway, is "how should I write the array overload then"? The trick there is a reference to an array:
template<typename T, unsigned N>
constexpr size_t SizeOf(const T (&aValue)[N])
{
// return N * sizeof(T); If you want to do the work yourself
return sizeof(aValue); // But why bother?
}

Related

Multiple variable template specializations with std::enable_if

I'm trying to concisely define a variable template with these effective values:
// (template<typename T> constexpr T EXP = std::numeric_limits<T>::max_exponent / 2;)
// float and double scalar definitions:
const double huge = std::scalbn(1, EXP<double>);
const float huge = std::scalbn(1, EXP<float>);
// SIMD vector definitions:
const Vec8f huge = Vec8f(huge<float>); // vector of 8 floats
const Vec8d huge = Vec8d(huge<double>); // vector of 8 doubles
const Vec4f huge = Vec4f(huge<float>); // vector of 4 floats
// Integral types should fail to compile
The VecXX vector definitions (SIMD vectors) need to use the corresponding scalar type as shown (e.g. huge<float> for vector of floats). This is available as VecXX::value_type or through a type traits-style template class (VectorTraits<VecXX>::value_type).
Ideally I think I'd have something like:
// Primary. What should go here? I want all other types to not compile
template<typename T, typename Enabler = void>
const T huge = T{ 0 };
// Scalar specialization for floating point types:
template<typename T>
const T huge<T> = std::enable_if_t<std::is_floating_point<T>::value, T>(std::scalbn(1, EXP<T>));
// Vector specialization, uses above declaration for corresponding FP type
template<typename T>
const T huge<T> = std::enable_if_t<VectorTraits<T>::is_vector, T>(huge<VectorTraits<T>::scalar_type>);
but I can't quite figure out a working version (above fails with "redefinition of const T huge<T>"). What's the best way to do this?
Not exactly what you asked but I hope the following example can show you how to use SFINAE to specialize a template variable
template <typename T, typename = void>
constexpr T huge = T{0};
template <typename T>
constexpr T huge<T, std::enable_if_t<std::is_floating_point<T>{}>> = T{1};
template <typename T>
constexpr T huge<std::vector<T>> = T{2};
You can check it with
std::cout << huge<int> << std::endl;
std::cout << huge<long> << std::endl;
std::cout << huge<float> << std::endl;
std::cout << huge<double> << std::endl;
std::cout << huge<long double> << std::endl;
std::cout << huge<std::vector<int>> << std::endl;
Leaving #max66's answer as the accepted one for the credit, but here's the specific solution I wound up with:
struct _VectorTraits { static constexpr bool is_vector = true; };
template<class T> struct VectorTraits : _VectorTraits { static constexpr bool is_vector = false; };
template<> struct VectorTraits<Vec4f> : _VectorTraits { typedef float value_type; };
template<> struct VectorTraits<Vec8f> : _VectorTraits { typedef float value_type; };
template<> struct VectorTraits<Vec4d> : _VectorTraits { typedef double value_type; };
template<typename T> using EnableIfFP = std::enable_if_t<std::is_floating_point<T>::value>;
template<typename T> using EnableIfVec = std::enable_if_t<VectorTraits<T>::is_vector>;
template<typename T> constexpr T EXP = std::numeric_limits<T>::max_exponent / 2;
// Actual variable template, finally:
template<typename T, typename Enabler = void> const T huge = T{ 0 };
template<typename T> const T huge<T, EnableIfFP<T> > = std::scalbn(1, EXP<T>);
template<typename T> const T huge<T, EnableIfVec<T> > = T{ huge<typename VectorTraits<T>::value_type> };
This could still be improved I think:
It's verbose. T appears 4 times in each specialization's left-hand side.
Integral types (e.g. huge<uint32_t>) still compile with a nonsense 0 value. I'd rather them not compile.

Could you please explain below code ? It compiles fine. Its related to check whether given class is base of another class [duplicate]

I want to get into more template meta-programming. I know that SFINAE stands for "substitution failure is not an error." But can someone show me a good use for SFINAE?
I like using SFINAE to check boolean conditions.
template<int I> void div(char(*)[I % 2 == 0] = 0) {
/* this is taken when I is even */
}
template<int I> void div(char(*)[I % 2 == 1] = 0) {
/* this is taken when I is odd */
}
It can be quite useful. For example, i used it to check whether an initializer list collected using operator comma is no longer than a fixed size
template<int N>
struct Vector {
template<int M>
Vector(MyInitList<M> const& i, char(*)[M <= N] = 0) { /* ... */ }
}
The list is only accepted when M is smaller than N, which means that the initializer list has not too many elements.
The syntax char(*)[C] means: Pointer to an array with element type char and size C. If C is false (0 here), then we get the invalid type char(*)[0], pointer to a zero sized array: SFINAE makes it so that the template will be ignored then.
Expressed with boost::enable_if, that looks like this
template<int N>
struct Vector {
template<int M>
Vector(MyInitList<M> const& i,
typename enable_if_c<(M <= N)>::type* = 0) { /* ... */ }
}
In practice, i often find the ability to check conditions a useful ability.
Heres one example (from here):
template<typename T>
class IsClassT {
private:
typedef char One;
typedef struct { char a[2]; } Two;
template<typename C> static One test(int C::*);
// Will be chosen if T is anything except a class.
template<typename C> static Two test(...);
public:
enum { Yes = sizeof(IsClassT<T>::test<T>(0)) == 1 };
enum { No = !Yes };
};
When IsClassT<int>::Yes is evaluated, 0 cannot be converted to int int::* because int is not a class, so it can't have a member pointer. If SFINAE didn't exist, then you would get a compiler error, something like '0 cannot be converted to member pointer for non-class type int'. Instead, it just uses the ... form which returns Two, and thus evaluates to false, int is not a class type.
In C++11 SFINAE tests have become much prettier. Here are a few examples of common uses:
Pick a function overload depending on traits
template<typename T>
std::enable_if_t<std::is_integral<T>::value> f(T t){
//integral version
}
template<typename T>
std::enable_if_t<std::is_floating_point<T>::value> f(T t){
//floating point version
}
Using a so called type sink idiom you can do pretty arbitrary tests on a type like checking if it has a member and if that member is of a certain type
//this goes in some header so you can use it everywhere
template<typename T>
struct TypeSink{
using Type = void;
};
template<typename T>
using TypeSinkT = typename TypeSink<T>::Type;
//use case
template<typename T, typename=void>
struct HasBarOfTypeInt : std::false_type{};
template<typename T>
struct HasBarOfTypeInt<T, TypeSinkT<decltype(std::declval<T&>().*(&T::bar))>> :
std::is_same<typename std::decay<decltype(std::declval<T&>().*(&T::bar))>::type,int>{};
struct S{
int bar;
};
struct K{
};
template<typename T, typename = TypeSinkT<decltype(&T::bar)>>
void print(T){
std::cout << "has bar" << std::endl;
}
void print(...){
std::cout << "no bar" << std::endl;
}
int main(){
print(S{});
print(K{});
std::cout << "bar is int: " << HasBarOfTypeInt<S>::value << std::endl;
}
Here is a live example: http://ideone.com/dHhyHE
I also recently wrote a whole section on SFINAE and tag dispatch in my blog (shameless plug but relevant) http://metaporky.blogspot.de/2014/08/part-7-static-dispatch-function.html
Note as of C++14 there is a std::void_t which is essentially the same as my TypeSink here.
Boost's enable_if library offers a nice clean interface for using SFINAE. One of my favorite usage examples is in the Boost.Iterator library. SFINAE is used to enable iterator type conversions.
Here's another (late) SFINAE example, based on Greg Rogers's answer:
template<typename T>
class IsClassT {
template<typename C> static bool test(int C::*) {return true;}
template<typename C> static bool test(...) {return false;}
public:
static bool value;
};
template<typename T>
bool IsClassT<T>::value=IsClassT<T>::test<T>(0);
In this way, you can check the value's value to see whether T is a class or not:
int main(void) {
std::cout << IsClassT<std::string>::value << std::endl; // true
std::cout << IsClassT<int>::value << std::endl; // false
return 0;
}
Examples provided by other answers seems to me more complicated than needed.
Here is the slightly easier to understand example from cppreference :
#include <iostream>
// this overload is always in the set of overloads
// ellipsis parameter has the lowest ranking for overload resolution
void test(...)
{
std::cout << "Catch-all overload called\n";
}
// this overload is added to the set of overloads if
// C is a reference-to-class type and F is a pointer to member function of C
template <class C, class F>
auto test(C c, F f) -> decltype((void)(c.*f)(), void())
{
std::cout << "Reference overload called\n";
}
// this overload is added to the set of overloads if
// C is a pointer-to-class type and F is a pointer to member function of C
template <class C, class F>
auto test(C c, F f) -> decltype((void)((c->*f)()), void())
{
std::cout << "Pointer overload called\n";
}
struct X { void f() {} };
int main(){
X x;
test( x, &X::f);
test(&x, &X::f);
test(42, 1337);
}
Output:
Reference overload called
Pointer overload called
Catch-all overload called
As you can see, in the third call of test, substitution fails without errors.
C++17 will probably provide a generic means to query for features. See N4502 for details, but as a self-contained example consider the following.
This part is the constant part, put it in a header.
// See http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2015/n4502.pdf.
template <typename...>
using void_t = void;
// Primary template handles all types not supporting the operation.
template <typename, template <typename> class, typename = void_t<>>
struct detect : std::false_type {};
// Specialization recognizes/validates only types supporting the archetype.
template <typename T, template <typename> class Op>
struct detect<T, Op, void_t<Op<T>>> : std::true_type {};
The following example, taken from N4502, shows the usage:
// Archetypal expression for assignment operation.
template <typename T>
using assign_t = decltype(std::declval<T&>() = std::declval<T const &>())
// Trait corresponding to that archetype.
template <typename T>
using is_assignable = detect<T, assign_t>;
Compared to the other implementations, this one is fairly simple: a reduced set of tools (void_t and detect) suffices. Besides, it was reported (see N4502) that it is measurably more efficient (compile-time and compiler memory consumption) than previous approaches.
Here is a live example, which includes portability tweaks for GCC pre 5.1.
Here is one good article of SFINAE: An introduction to C++'s SFINAE concept: compile-time introspection of a class member.
Summary it as following:
/*
The compiler will try this overload since it's less generic than the variadic.
T will be replace by int which gives us void f(const int& t, int::iterator* b = nullptr);
int doesn't have an iterator sub-type, but the compiler doesn't throw a bunch of errors.
It simply tries the next overload.
*/
template <typename T> void f(const T& t, typename T::iterator* it = nullptr) { }
// The sink-hole.
void f(...) { }
f(1); // Calls void f(...) { }
template<bool B, class T = void> // Default template version.
struct enable_if {}; // This struct doesn't define "type" and the substitution will fail if you try to access it.
template<class T> // A specialisation used if the expression is true.
struct enable_if<true, T> { typedef T type; }; // This struct do have a "type" and won't fail on access.
template <class T> typename enable_if<hasSerialize<T>::value, std::string>::type serialize(const T& obj)
{
return obj.serialize();
}
template <class T> typename enable_if<!hasSerialize<T>::value, std::string>::type serialize(const T& obj)
{
return to_string(obj);
}
declval is an utility that gives you a "fake reference" to an object of a type that couldn't be easily construct. declval is really handy for our SFINAE constructions.
struct Default {
int foo() const {return 1;}
};
struct NonDefault {
NonDefault(const NonDefault&) {}
int foo() const {return 1;}
};
int main()
{
decltype(Default().foo()) n1 = 1; // int n1
// decltype(NonDefault().foo()) n2 = n1; // error: no default constructor
decltype(std::declval<NonDefault>().foo()) n2 = n1; // int n2
std::cout << "n2 = " << n2 << '\n';
}
The following code uses SFINAE to let compiler select an overload based on whether a type has certain method or not:
#include <iostream>
template<typename T>
void do_something(const T& value, decltype(value.get_int()) = 0) {
std::cout << "Int: " << value.get_int() << std::endl;
}
template<typename T>
void do_something(const T& value, decltype(value.get_float()) = 0) {
std::cout << "Float: " << value.get_float() << std::endl;
}
struct FloatItem {
float get_float() const {
return 1.0f;
}
};
struct IntItem {
int get_int() const {
return -1;
}
};
struct UniversalItem : public IntItem, public FloatItem {};
int main() {
do_something(FloatItem{});
do_something(IntItem{});
// the following fails because template substitution
// leads to ambiguity
// do_something(UniversalItem{});
return 0;
}
Output:
Float: 1
Int: -1
Here, I am using template function overloading (not directly SFINAE) to determine whether a pointer is a function or member class pointer: (Is possible to fix the iostream cout/cerr member function pointers being printed as 1 or true?)
https://godbolt.org/z/c2NmzR
#include<iostream>
template<typename Return, typename... Args>
constexpr bool is_function_pointer(Return(*pointer)(Args...)) {
return true;
}
template<typename Return, typename ClassType, typename... Args>
constexpr bool is_function_pointer(Return(ClassType::*pointer)(Args...)) {
return true;
}
template<typename... Args>
constexpr bool is_function_pointer(Args...) {
return false;
}
struct test_debugger { void var() {} };
void fun_void_void(){};
void fun_void_double(double d){};
double fun_double_double(double d){return d;}
int main(void) {
int* var;
std::cout << std::boolalpha;
std::cout << "0. " << is_function_pointer(var) << std::endl;
std::cout << "1. " << is_function_pointer(fun_void_void) << std::endl;
std::cout << "2. " << is_function_pointer(fun_void_double) << std::endl;
std::cout << "3. " << is_function_pointer(fun_double_double) << std::endl;
std::cout << "4. " << is_function_pointer(&test_debugger::var) << std::endl;
return 0;
}
Prints
0. false
1. true
2. true
3. true
4. true
As the code is, it could (depending on the compiler "good" will) generate a run time call to a function which will return true or false. If you would like to force the is_function_pointer(var) to evaluate at compile type (no function calls performed at run time), you can use the constexpr variable trick:
constexpr bool ispointer = is_function_pointer(var);
std::cout << "ispointer " << ispointer << std::endl;
By the C++ standard, all constexpr variables are guaranteed to be evaluated at compile time (Computing length of a C string at compile time. Is this really a constexpr?).

How to provide a common interface for creation of static and dynamic size vectors?

I have a lot of code that currently works with dynamic size vectors (such as std::vector, Eigen::VectorXd, ...) and I would like it to work also with static size vectors (such as std::array, Eigen::Vector3d, ...). My code is templatized with respect to TVector in such a way that it assumes that TVector has just size and operator[]. But the big problem is construction.
There are no common grounds when it comes to construction of both static and dynamic vectors. I have decided to replace all calls to the constructor of TVector by the following hypothetical function:
template <typename TVector>
TVector createVector(std::size_t sizeAtInitialization)
{
if (TVector has constructor taking an integral type)
return TVector(sizeAtInitialization);
else
return TVector(); // sizeAtInitialization ignored
}
Such that a generic call to createVector<TVector> will become createVector<std::vector<double>>(3) or createVector<std::array<double, 3>>(3).
std::is_default_constructible will not help me here, since both vector types are default constructible.
However, I am not sure that such a thing is even possible.
I have studied the static if here and member function detection here. It all seems extremely complicated and since the static_if uses lambdas which must return to an intermediate result, which must already be constructed, I am not sure it leads anywhere.
You can use std::is_constructible together with a bit of sfinae and std::enable_if
using namespace std;
template <class T>
using IntegerConstructible =
typename enable_if<is_constructible<T, int>::value, T>::type;
template <class T>
using NotIntegerConstructible =
typename enable_if<!is_constructible<T, int>::value, T>::type;
template<class T>
auto createVector(int size)
-> IntegerConstructible<T> {
return {size};
}
template<class T>
auto createVector(int size)
-> NotIntegerConstructible<T>{
return {};
}
int main(){
auto x = createVector<std::vector<int>>(3);
auto y = createVector<std::array<int,3>>(3);
return 0;
}
IntegerConstructible and NotIntegerConstructible are alias templates which are defined as long as the template argument can (or can't) be constructed. When defined
IntegerConstructible<T> = T.
So only one of the two createVector functions has a valid return type, the other one cannot be called. This allows the compiler to choose the right overload.
I love SFINAE (+1 for Tim) but I think that tag-dispatcing is clearer for this type of problem
#include <array>
#include <vector>
#include <iostream>
#include <type_traits>
template <typename T>
T cVH (int size, std::true_type const &)
{ std::cout << "with size" << std::endl; return { size }; }
template <typename T>
T cVH (int, std::false_type const &)
{ std::cout << "without size" << std::endl; return { }; }
template <typename T>
T createVector (int size)
{ return cVH<T>(size, typename std::is_constructible<T, int>::type{}); }
int main()
{
auto x = createVector<std::vector<int>>(3); // print "with size"
auto y = createVector<std::array<int,3>>(3); // print "without size"
}
--- EDIT ---
If there isn't a type-traits that can select the right value for all your tyes, you can create one yourself as (struct withSize) follows
#include <array>
#include <vector>
#include <iostream>
#include <type_traits>
template <typename>
struct withSize;
template <typename T>
struct withSize<std::vector<T>>
{ using type = std::true_type; };
template <typename T, std::size_t N>
struct withSize<std::array<T, N>>
{ using type = std::false_type; };
// others specializations of withSize for Eigen::Vector3d, Eigen::Matrix, etc.
template <typename T>
T cVH (int size, std::true_type const &)
{ std::cout << "with size" << std::endl; return { size }; }
template <typename T>
T cVH (int, std::false_type const &)
{ std::cout << "without size" << std::endl; return { }; }
template <typename T>
T createVector (int size)
{ return cVH<T>(size, typename withSize<T>::type{}); }
int main()
{
auto x = createVector<std::vector<int>>(3); // print "with size"
auto y = createVector<std::array<int,3>>(3); // print "without size"
}

How can a C++ template be specialized for all 32-bit POD types?

I've developed a simple template function for swapping the byte order of a single field:
template <typename T> inline void SwapEndian(T& ptr) {
char *bytes = reinterpret_cast<char*>(&ptr);
int a = sizeof(T) / 2;
while (a--) {
char tmp = bytes[a];
int b = sizeof(T) - 1 - a;
bytes[a] = bytes[b];
bytes[b] = tmp;
}
}
I'll often use it where T = int or float. Both of these types are represented by 4 bytes on the target platforms, and can be processed by the same specialization of the template.
Because this function sometimes is responsible for processing large buffers of raw data, I've created an optimized specialization:
template<> inline void SwapEndian(float& ptr) {
#if defined(__GNUC__)
*reinterpret_cast<unsigned*>(&ptr) = __builtin_bswap32(*reinterpret_cast<unsigned*>(&ptr));
#elif defined(_MSC_VER)
*reinterpret_cast<unsigned*>(&ptr) = __byteswap_ulong(*reinterpret_cast<unsigned*>(&ptr));
#endif
}
This specialization also works with 32-bit integers, signed or unsigned, so I have a big smelly pile of duplicates with only the type name different.
How do I route all instantiations of 4 byte POD types through this one template? (PS. I'm open to solving this in a different way, but in that case I'd like to know definitively whether or not it's possible to build these kind of meta-specialized templates.)
EDIT: Thanks everyone, after reading the answers and realizing that arithmetic is a better restriction than pod, I was inspired to write something. All the answers were useful but I could only accept one, so I accepted the one that appears to be structurally the same.
template<bool, bool> struct SwapEndian_ { template<typename T> static inline void _(T&); };
template<> template<typename T> inline void SwapEndian_<true, true>::_(T& ptr) {
// ... stuff here ...
}
// ... more stuff here ...
template<typename T> inline void SwapEndian(T& ptr) {
static_assert(is_arithmetic<T>::value, "Endian swap not supported for non-arithmetic types.");
SwapEndian_<sizeof(T) & (8 | 4), sizeof(T) & (8 | 2)>::template _<T>(ptr);
}
When in doubt, tag dispatch.
This implementation has 2 traits -- is_pod and get_sizeof_t. The base override dispatches to SwapEndians with those two traits tagged. There is also a is_pod override, and an override (which I'd advise =deleteing) for non-pod types.
Extension to new traits and types is relatively easy.
template<size_t n>
using sizeof_t = std::integral_constant<size_t, n>;
template<class T>
using get_sizeof_t = sizeof_t<sizeof(T)>;
template <class T>
void SwapEndian(T& t, std::true_type /*is pod*/, sizeof_t<4>) {
std::cout << "4 bytes!\n";
// code to handle 32 bit pods
}
template <class T, size_t n>
void SwapEndian(T& t, std::true_type /*is pod*/, sizeof_t<n>) {
std::cout << "pod\n";
// code to handle generic case
}
template <class T, size_t n>
void SwapEndian(T& t, std::false_type /*is pod*/, sizeof_t<n>) {
std::cout << "not pod\n";
// probably want to =delete this overload actually
}
template<class T>
void SwapEndian(T& t) {
SwapEndian(t, std::is_pod<T>{}, get_sizeof_t<T>{});
}
I am not sure if this is a good idea, but the above should do it.
Uses some C++14 features. Assumes CHAR_BIT is 8.
You should only rarely specialize template functions. Instead overload. Tag dispatching gives you the power of overload resolution to dispatch what code to run at compile time.
live example
I'm using a separate SwapEndian and SwapEndianImpl so that we can use template deduction and partial specialization.
template<bool> struct SwapEndianImpl
{
template<typename t> static inline void Func(t& n);
};
template<> template<typename t> void SwapEndianImpl<false>::Func(t& n)
{
std::cout << "not 32bit pod" << std::endl;
}
template<> template<typename t> void SwapEndianImpl<true>::Func(t& n)
{
std::cout << "32bit pod" << std::endl;
}
template<typename t> inline void SwapEndian(t& n)
{
SwapEndianImpl<std::is_pod<t>::value && sizeof(t) == (32 / CHAR_BIT)>::template Func<t>(n);
}
I believe that this is a better way to go than SFINAE if you specialize to more than two conditions.
You might limit your swap on arithmetic types (not using all POD types) and use specialized template classes for flexibility:
#include <climits>
#include <iostream>
#include <type_traits>
namespace Detail {
template <
typename T,
unsigned N = sizeof(T) * CHAR_BIT,
bool Swap = std::is_arithmetic<T>::value>
struct SwapEndian
{
static void apply(T&) {
std::cout << "Not Swapping\n";
}
};
template <typename T>
struct SwapEndian<T, 16, true>
{
static void apply(T&) {
std::cout << "Swapping\n";
}
};
template <typename T>
struct SwapEndian<T, 32, true>
{
static void apply(T&) {
std::cout << "Swapping\n";
}
};
template <typename T>
struct SwapEndian<T, 64, true>
{
static void apply(T&) {
std::cout << "Swapping\n";
}
};
}
template <typename T>
void SwapEndian(T& value) {
Detail::SwapEndian<T>::apply(value);
}
struct Structure
{
char s[4];
};
static_assert(std::is_pod<Structure>::value, "Should be POD");
int main() {
char c;
short s;
int i;
long long l;
float f;
double d;
void* p;
Structure structure;
SwapEndian(c);
SwapEndian(s);
SwapEndian(i);
SwapEndian(l);
SwapEndian(f);
SwapEndian(d);
SwapEndian(p);
SwapEndian(structure);
}

Detecting a function in C++ at compile time

Is there a way, presumably using templates, macros or a combination of the two, that I can generically apply a function to different classes of objects but have them respond in different ways if they do not have a specific function?
I specifically want to apply a function which will output the size of the object (i.e. the number of objects in a collection) if the object has that function but will output a simple replacement (such as "N/A") if the object doesn't. I.e.
NO_OF_ELEMENTS( mySTLMap ) -----> [ calls mySTLMap.size() to give ] ------> 10
NO_OF_ELEMENTS( myNoSizeObj ) --> [ applies compile time logic to give ] -> "N/A"
I expect that this might be something similar to a static assertion although I'd clearly want to compile a different code path rather than fail at build stage.
From what I understand, you want to have a generic test to see if a class has a certain member function. This can be accomplished in C++ using SFINAE. In C++11 it's pretty simple, since you can use decltype:
template <typename T>
struct has_size {
private:
template <typename U>
static decltype(std::declval<U>().size(), void(), std::true_type()) test(int);
template <typename>
static std::false_type test(...);
public:
typedef decltype(test<T>(0)) type;
enum { value = type::value };
};
If you use C++03 it is a bit harder due to the lack of decltype, so you have to abuse sizeof instead:
template <typename T>
struct has_size {
private:
struct yes { int x; };
struct no {yes x[4]; };
template <typename U>
static typename boost::enable_if_c<sizeof(static_cast<U*>(0)->size(), void(), int()) == sizeof(int), yes>::type test(int);
template <typename>
static no test(...);
public:
enum { value = sizeof(test<T>(0)) == sizeof(yes) };
};
Of course this uses Boost.Enable_If, which might be an unwanted (and unnecessary) dependency. However writing enable_if yourself is dead simple:
template<bool Cond, typename T> enable_if;
template<typename T> enable_if<true, T> { typedef T type; };
In both cases the method signature test<U>(int) is only visible, if U has a size method, since otherwise evaluating either the decltype or the sizeof (depending on which version you use) will fail, which will then remove the method from consideration (due to SFINAE. The lengthy expressions std::declval<U>().size(), void(), std::true_type() is an abuse of C++ comma operator, which will return the last expression from the comma-separated list, so this makes sure the type is known as std::true_type for the C++11 variant (and the sizeof evaluates int for the C++03 variant). The void() in the middle is only there to make sure there are no strange overloads of the comma operator interfering with the evaluation.
Of course this will return true if T has a size method which is callable without arguments, but gives no guarantees about the return value. I assume wou probably want to detect only those methods which don't return void. This can be easily accomplished with a slight modification of the test(int) method:
// C++11
template <typename U>
static typename std::enable_if<!is_void<decltype(std::declval<U>().size())>::value, std::true_type>::type test(int);
//C++03
template <typename U>
static typename std::enable_if<boost::enable_if_c<sizeof(static_cast<U*>(0)->size()) != sizeof(void()), yes>::type test(int);
There was a discussion about the abilities of constexpr some times ago. It's time to use it I think :)
It is easy to design a trait with constexpr and decltype:
template <typename T>
constexpr decltype(std::declval<T>().size(), true) has_size(int) { return true; }
template <typename T>
constexpr bool has_size(...) { return false; }
So easy in fact that the trait loses most of its value:
#include <iostream>
#include <vector>
template <typename T>
auto print_size(T const& t) -> decltype(t.size(), void()) {
std::cout << t.size() << "\n";
}
void print_size(...) { std::cout << "N/A\n"; }
int main() {
print_size(std::vector<int>{1, 2, 3});
print_size(1);
}
In action:
3
N/A
This can be done using a technique called SFINAE. In your specific case you could implement that using Boost.Concept Check. You'd have to write your own concept for checking for a size-method. Alternatively you could use an existing concept such as Container, which, among others, requires a size-method.
You can do something like
template< typename T>
int getSize(const T& t)
{
return -1;
}
template< typename T>
int getSize( const std::vector<T>& t)
{
return t.size();
}
template< typename T , typename U>
int getSize( const std::map<T,U>& t)
{
return t.size();
}
//Implement this interface for
//other objects
class ISupportsGetSize
{
public:
virtual int size() const= 0;
};
int getSize( const ISupportsGetSize & t )
{
return t.size();
}
int main()
{
int s = getSize( 4 );
std::vector<int> v;
s = getSize( v );
return 0;
}
basically the most generic implementation is always return -1 or "NA" but for vector and maps it will return the size. As the most general one always matches there is never a build time failure
Here you go. Replace std::cout with the output of your liking.
template <typename T>
class has_size
{
template <typename C> static char test( typeof(&C::size) ) ;
template <typename C> static long test(...);
public:
enum { value = sizeof(test<T>(0)) == sizeof(char) };
};
template<bool T>
struct outputter
{
template< typename C >
static void output( const C& object )
{
std::cout << object.size();
}
};
template<>
struct outputter<false>
{
template< typename C >
static void output( const C& )
{
std::cout << "N/A";
}
};
template<typename T>
void NO_OF_ELEMENTS( const T &object )
{
outputter< has_size<T>::value >::output( object );
}
You could try something like:
#include <iostream>
#include <vector>
template<typename T>
struct has_size
{
typedef char one;
typedef struct { char a[2]; } two;
template<typename Sig>
struct select
{
};
template<typename U>
static one check (U*, select<char (&)[((&U::size)!=0)]>* const = 0);
static two check (...);
static bool const value = sizeof (one) == sizeof (check (static_cast<T*> (0)));
};
struct A{ };
int main ( )
{
std::cout << has_size<int>::value << "\n";
std::cout << has_size<A>::value << "\n";
std::cout << has_size<std::vector<int>>::value << "\n";
}
but you have to be careful, this does neither work when size is overloaded, nor when it is a template. When you can use C++11, you can replace the above sizeof trick by decltype magic