I want to control the precision for a double during a comparison, and then come back to default precision, with C++.
I intend to use setPrecision() to set precision. What is then syntax, if any, to set precision back to default?
I am doing something like this
std::setPrecision(math.log10(m_FTOL));
I do some stuff, and I would like to come back to default double comparison right afterwards.
I modified like this, and I still have some errors
std::streamsize prec = std::ios_base::precision();
std::setprecision(cmath::log10(m_FTOL));
with cmath false at compilation, and std::ios_base also false at compilation. Could you help?
You can get the precision before you change it, with std::ios_base::precision and then use that to change it back later.
You can see this in action with:
#include <ios>
#include <iostream>
#include <iomanip>
int main (void) {
double d = 3.141592653589;
std::streamsize ss = std::cout.precision();
std::cout << "Initial precision = " << ss << '\n';
std::cout << "Value = " << d << '\n';
std::cout.precision (10);
std::cout << "Longer value = " << d << '\n';
std::cout.precision (ss);
std::cout << "Original value = " << d << '\n';
std::cout << "Longer and original value = "
<< std::setprecision(10) << d << ' '
<< std::setprecision(ss) << d << '\n';
std::cout << "Original value = " << d << '\n';
return 0;
}
which outputs:
Initial precision = 6
Value = 3.14159
Longer value = 3.141592654
Original value = 3.14159
Longer and original value = 3.141592654 3.14159
Original value = 3.14159
The code above shows two ways of setting the precision, first by calling std::cout.precision (N) and second by using a stream manipulator std::setprecision(N).
But you need to keep in mind that the precision is for outputting values via streams, it does not directly affect comparisons of the values themselves with code like:
if (val1== val2) ...
In other words, even though the output may be 3.14159, the value itself is still the full 3.141592653590 (subject to normal floating point limitations, of course).
If you want to do that, you'll need to check if it's close enough rather than equal, with code such as:
if ((fabs (val1 - val2) < 0.0001) ...
Use C++20 std::format and {:.2} instead of std::setprecision
Finally, this will be the superior choice once you can use it:
#include <format>
#include <string>
int main() {
std::cout << std::format("{:.3} {:.4}\n", 3.1415, 3.1415);
}
Expected output:
3.14 3.145
This will therefore completely overcome the madness of modifying std::cout state.
The existing fmt library implements it for before it gets official support: https://github.com/fmtlib/fmt Install on Ubuntu 22.04:
sudo apt install libfmt-dev
Modify source to replace:
<format> with <fmt/core.h>
std::format to fmt::format
main.cpp
#include <iostream>
#include <fmt/core.h>
int main() {
std::cout << fmt::format("{:.3} {:.4}\n", 3.1415, 3.1415);
}
and compile and run with:
g++ -std=c++11 -o main.out main.cpp -lfmt
./main.out
Output:
3.14 3.142
See also:
How do I print a double value with full precision using cout?
std::string formatting like sprintf
Pre C++20/fmt::: Save the entire state with std::ios::copyfmt
You might also want to restore the entire previous state with std::ios::copyfmt in these situations, as explained at: Restore the state of std::cout after manipulating it
main.cpp
#include <iomanip>
#include <iostream>
int main() {
constexpr float pi = 3.14159265359;
constexpr float e = 2.71828182846;
// Sanity check default print.
std::cout << "default" << std::endl;
std::cout << pi << std::endl;
std::cout << e << std::endl;
std::cout << std::endl;
// Change precision format to scientific,
// and restore default afterwards.
std::cout << "modified" << std::endl;
std::ios cout_state(nullptr);
cout_state.copyfmt(std::cout);
std::cout << std::setprecision(2);
std::cout << std::scientific;
std::cout << pi << std::endl;
std::cout << e << std::endl;
std::cout.copyfmt(cout_state);
std::cout << std::endl;
// Check that cout state was restored.
std::cout << "restored" << std::endl;
std::cout << pi << std::endl;
std::cout << e << std::endl;
std::cout << std::endl;
}
GitHub upstream.
Compile and run:
g++ -ggdb3 -O0 -std=c++11 -Wall -Wextra -pedantic -o main.out main.cpp
./main.out
Output:
default
3.14159
2.71828
modified
3.14e+00
2.72e+00
restored
3.14159
2.71828
Tested on Ubuntu 19.04, GCC 8.3.0.
You need to keep track of your current precison and then reset back to the same once done with your operations with required modified precison. For this you can use std::ios_base::precision:
streamsize precision ( ) const;
streamsize precision ( streamsize prec );
The first syntax returns the value of the current floating-point precision field for the stream.
The second syntax also sets it to a new value.
setprecision() can be used only for output operations and cannot be used for comparisons
To compare floats say a and b , you have to do it explicitly like this:
if( abs(a-b) < 1e-6) {
}
else {
}
You can use cout << setprecision(-1)
Related
I want to control the precision for a double during a comparison, and then come back to default precision, with C++.
I intend to use setPrecision() to set precision. What is then syntax, if any, to set precision back to default?
I am doing something like this
std::setPrecision(math.log10(m_FTOL));
I do some stuff, and I would like to come back to default double comparison right afterwards.
I modified like this, and I still have some errors
std::streamsize prec = std::ios_base::precision();
std::setprecision(cmath::log10(m_FTOL));
with cmath false at compilation, and std::ios_base also false at compilation. Could you help?
You can get the precision before you change it, with std::ios_base::precision and then use that to change it back later.
You can see this in action with:
#include <ios>
#include <iostream>
#include <iomanip>
int main (void) {
double d = 3.141592653589;
std::streamsize ss = std::cout.precision();
std::cout << "Initial precision = " << ss << '\n';
std::cout << "Value = " << d << '\n';
std::cout.precision (10);
std::cout << "Longer value = " << d << '\n';
std::cout.precision (ss);
std::cout << "Original value = " << d << '\n';
std::cout << "Longer and original value = "
<< std::setprecision(10) << d << ' '
<< std::setprecision(ss) << d << '\n';
std::cout << "Original value = " << d << '\n';
return 0;
}
which outputs:
Initial precision = 6
Value = 3.14159
Longer value = 3.141592654
Original value = 3.14159
Longer and original value = 3.141592654 3.14159
Original value = 3.14159
The code above shows two ways of setting the precision, first by calling std::cout.precision (N) and second by using a stream manipulator std::setprecision(N).
But you need to keep in mind that the precision is for outputting values via streams, it does not directly affect comparisons of the values themselves with code like:
if (val1== val2) ...
In other words, even though the output may be 3.14159, the value itself is still the full 3.141592653590 (subject to normal floating point limitations, of course).
If you want to do that, you'll need to check if it's close enough rather than equal, with code such as:
if ((fabs (val1 - val2) < 0.0001) ...
Use C++20 std::format and {:.2} instead of std::setprecision
Finally, this will be the superior choice once you can use it:
#include <format>
#include <string>
int main() {
std::cout << std::format("{:.3} {:.4}\n", 3.1415, 3.1415);
}
Expected output:
3.14 3.145
This will therefore completely overcome the madness of modifying std::cout state.
The existing fmt library implements it for before it gets official support: https://github.com/fmtlib/fmt Install on Ubuntu 22.04:
sudo apt install libfmt-dev
Modify source to replace:
<format> with <fmt/core.h>
std::format to fmt::format
main.cpp
#include <iostream>
#include <fmt/core.h>
int main() {
std::cout << fmt::format("{:.3} {:.4}\n", 3.1415, 3.1415);
}
and compile and run with:
g++ -std=c++11 -o main.out main.cpp -lfmt
./main.out
Output:
3.14 3.142
See also:
How do I print a double value with full precision using cout?
std::string formatting like sprintf
Pre C++20/fmt::: Save the entire state with std::ios::copyfmt
You might also want to restore the entire previous state with std::ios::copyfmt in these situations, as explained at: Restore the state of std::cout after manipulating it
main.cpp
#include <iomanip>
#include <iostream>
int main() {
constexpr float pi = 3.14159265359;
constexpr float e = 2.71828182846;
// Sanity check default print.
std::cout << "default" << std::endl;
std::cout << pi << std::endl;
std::cout << e << std::endl;
std::cout << std::endl;
// Change precision format to scientific,
// and restore default afterwards.
std::cout << "modified" << std::endl;
std::ios cout_state(nullptr);
cout_state.copyfmt(std::cout);
std::cout << std::setprecision(2);
std::cout << std::scientific;
std::cout << pi << std::endl;
std::cout << e << std::endl;
std::cout.copyfmt(cout_state);
std::cout << std::endl;
// Check that cout state was restored.
std::cout << "restored" << std::endl;
std::cout << pi << std::endl;
std::cout << e << std::endl;
std::cout << std::endl;
}
GitHub upstream.
Compile and run:
g++ -ggdb3 -O0 -std=c++11 -Wall -Wextra -pedantic -o main.out main.cpp
./main.out
Output:
default
3.14159
2.71828
modified
3.14e+00
2.72e+00
restored
3.14159
2.71828
Tested on Ubuntu 19.04, GCC 8.3.0.
You need to keep track of your current precison and then reset back to the same once done with your operations with required modified precison. For this you can use std::ios_base::precision:
streamsize precision ( ) const;
streamsize precision ( streamsize prec );
The first syntax returns the value of the current floating-point precision field for the stream.
The second syntax also sets it to a new value.
setprecision() can be used only for output operations and cannot be used for comparisons
To compare floats say a and b , you have to do it explicitly like this:
if( abs(a-b) < 1e-6) {
}
else {
}
You can use cout << setprecision(-1)
Using the following bit of code compiled against boost 1.62:
#include <boost/rational.hpp>
#include <iostream>
int main() {
auto val = boost::rational<int64_t>(499999, 2);
std::cout << val << std::endl;
std::cout << boost::rational_cast<double>(val) << std::endl;
}
I get the following output:
499999/2
250000
I would expect rational_cast to output 249999.5
Can anyone explain what I am doing wrong?
Modify the default formatting for floating-point input/output:
std::cout << std::fixed << boost::rational_cast<double>(v) << std::endl; add std::fixed to it.
Here is my code, just a basic test program to print a number with floating point, with printf it works great (I guess because the format is passed explicitly) but with std::cout I'm unable to get it right and std::setprecision doesn't seem to help, can you please give me a hand?
#include <iostream>
#include <iomanip>
int main ()
{
std::cout << double(1999999900) / 10000 << std::endl;
std::cout << std::setprecision(5) << double(1999999900) / 10000 << std::endl;
printf("%f\n", double(1999999900) / 10000);
return 0;
}
Here is the output, how can I get 199999.99 from the std::cout print also?
[root# test00]# g++ -std=c++11 test1.cpp -o test1; ./test1
200000
2e+05
199999.990000
Use
std::cout << std::setprecision(5) << std::fixed << double(1999999900) / 10000 << std::endl;
I have a problem where I need to print some double value using basic C++ output system (such as iostream or sstream) and this value somehow gets truncated a lot.
For example:
double a = 283752.24234;
std::cout << 283752.24234 << std::endl;
std::cout << a << std::endl;
Both of the outputs will be 283752
Why is this happening and what can I do to get complete output of any double value?
Why is this happening ...
That's because the default precision is 6 and thus only the foremost 6 digits are rendered 283752.
... and what can I do to get complete output of any double value?
First option is to use a bigger precision value using the std::setprecision() I/O manipulator:
#include <iostream>
#include <iomanip>
int main(){
double a = 283752.24234;
std::cout << std::setprecision(12) << 283752.24234 << std::endl;
std::cout << std::setprecision(12) << a << std::endl;
}
See Live Demo
Second option is to use the std::fixed I/O manipulator to show the values after the decimal point:
#include <iostream>
#include <iomanip>
int main(){
double a = 283752.24234;
std::cout << std::fixed << 283752.24234 << std::endl;
std::cout << std::fixed << a << std::endl;
}
See Live Demo
Output:
283752.242340
283752.242340
I am having trouble converting a string to a double. I am given a string with lat/long coordinates in the format of 33.9425/N 118.4081/W
I first call my function trimLastChar(std::string& input) twice, which will remove the the North, South, East, West characters and then the forward slash. This function correctly returns 33.9425 and 118.4081 respectfully as a std::string.
I am using the following code to convert my std::string to a double...however the problem is, the conversion losses precision -- I suspect it gets rounded?.
// Location In String is what trimLastChar returns
std::stringstream stream(locationInString);
std::cout << "DEBUG: before: " << locationInString << " ";
// output is a double* output = new double passed by reference to my function
stream >> output;
std::cout << output << std::endl;
The output in this case would produce:
33.9425
118.408
As you notice, the correct value should be 118.4081 but the 1 is missing...
Any ideas how to fix? Or more important, why is this happening?
The precision wasn't lost on input. It's being lost on output.
#include <iostream>
using std::cout;
using std::endl;
int main()
{
double v = 118.4081;
cout << v << endl;
cout.precision(10);
cout << v << endl;
}
outputs:
$ g++ -Wall x.cpp && ./a.out
118.408
118.4081
$
You probably have more digits than the output shows. By default, only a small number of digits is shown, you need to use std::setprecision to see more digits. Try
std::cout << std::setprecision(10) << output << std::endl;