Replace all instances of a string in XML with **** - xslt

Question

I have a XSL that needs to filter out specific data found in the XML.
Somewhere in my XML there will be a node like:
<id root="2.16.840.1.113883.3.51.1.1.6.1" extension="9494949494949" />
The XSL I have below deletes the extension node and adds a nullFlavor="MSK" to the node.
What I need to do now, is take the value from the extension node, and search the entire XML document for that value, and replace it with **.
But I'm not sure how to take the extension attribute, and find all instances of that value in the XML (they could be burried in text and inside attributes) and turn them into ** (4 *).
The example below is just an example. I cannot hard code the XSL to look at specific nodes, it needs to look through all text / attribute text in the xml (reason for this is there are 5+ different versions of XML that this will be applied to).
I need to find the Extension in the node, then replace (delete really) that value from the rest of the XML. I'm looking for a 1 solution fits all messages, so a global search->wipe of the Extension value.
Example:
<identifiedPerson classCode="IDENT">
<id root="2.16.840.1.113883.3.51.1.1.6.1" extension="9494949494949" displayable="true" />
<addr use="PHYS">
<city>KAMLOOPS</city>
<country>CA</country>
<postalCode>V1B3C1</postalCode>
<state>BC</state>
<streetAddressLine>1A</streetAddressLine>
<streetAddressLine>2A</streetAddressLine>
<streetAddressLine>9494949494949</streetAddressLine>
<streetAddressLine>4A</streetAddressLine>
</addr>
<note text="9494949494949 should be stars"/>
Should be (The below XSLT already masks the extension in the node with the matching OID).
<identifiedPerson classCode="IDENT">
<id root="2.16.840.1.113883.3.51.1.1.6.1" nullFlavor="MSK" displayable="true" />
<addr use="PHYS">
<city>KAMLOOPS</city>
<country>CA</country>
<postalCode>V1B3C1</postalCode>
<state>BC</state>
<streetAddressLine>1A</streetAddressLine>
<streetAddressLine>2A</streetAddressLine>
<streetAddressLine>****</streetAddressLine>
<streetAddressLine>4A</streetAddressLine>
</addr>
<note text="**** should be stars"/>
Any help would be appreciated.
I am able to use XSL 2.0
I have the current XSL.IT works fine. It matches any tag where the root is '2.16.840.1.113883.3.51.1.1.6.1', kills all attributes and adds a nullFlavor="MSK". However, this will not search the entire XML for that same #.
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:param name="attrToKeep" select="'root'" />
<xsl:template match="* | node()">
<xsl:copy>
<xsl:apply-templates select="node()|#*" />
</xsl:copy>
</xsl:template>
<xsl:template match="#*">
<xsl:choose>
<xsl:when test="../#root = '2.16.840.1.113883.3.51.1.1.6.1'">
<xsl:copy-of select=".[contains($attrToKeep, name())]" />
<xsl:attribute name="nullFlavor">MSK</xsl:attribute>
<!-- Need some way to use the value found in this node and hide the extension -->
</xsl:when>
<xsl:otherwise>
<xsl:copy-of select="." />
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
Any help would be appreciated.
Thanks,

Answer 1

Try using a variable to hold the value of the text to be replaced. Like this:
<xsl:variable
name="rootVar"
select="//*[#root = '2.16.840.1.113883.3.51.1.1.6.1']/#extension" />
And then you should just be able to use the replace function to replace them.
<xsl:template match="'//#*' | text()">
<xsl:sequence select="replace(., $rootVar, '****')"/>
</xsl:template>

Answer 2

The XSLT 2.0 stylesheet
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0">
<xsl:param name="replacement" select="'****'"/>
<xsl:param name="new" select="'MKS'"/>
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="identifiedPerson">
<xsl:copy>
<xsl:apply-templates select="#* , node()">
<xsl:with-param name="to-be-replaced" select="id/#extension" tunnel="yes"/>
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
<xsl:template match="identifiedPerson//text()">
<xsl:param name="to-be-replaced" tunnel="yes"/>
<xsl:sequence select="replace(., $to-be-replaced, $replacement)"/>
</xsl:template>
<xsl:template match="identifiedPerson//#*">
<xsl:param name="to-be-replaced" tunnel="yes"/>
<xsl:attribute name="{name()}" namespace="{namespace-uri()}" select="replace(., $to-be-replaced, $replacement)"/>
</xsl:template>
<xsl:template match="identifiedPerson/id">
<xsl:copy>
<xsl:apply-templates select="#*"/>
<xsl:attribute name="nullFlavor" select="$new"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="identifiedPerson/id/#extension"/>
</xsl:stylesheet>
transforms
<identifiedPerson classCode="IDENT">
<id root="2.16.840.1.113883.3.51.1.1.6.1" extension="9494949494949" displayable="true" />
<addr use="PHYS">
<city>KAMLOOPS</city>
<country>CA</country>
<postalCode>V1B3C1</postalCode>
<state>BC</state>
<streetAddressLine>1A</streetAddressLine>
<streetAddressLine>2A</streetAddressLine>
<streetAddressLine>9494949494949</streetAddressLine>
<streetAddressLine>4A</streetAddressLine>
</addr>
<note text="9494949494949 should be stars"/>
</identifiedPerson>
with Saxon 9.4 into
<?xml version="1.0" encoding="UTF-8"?><identifiedPerson classCode="IDENT">
<id root="2.16.840.1.113883.3.51.1.1.6.1" displayable="true" nullFlavor="MKS"/>
<addr use="PHYS">
<city>KAMLOOPS</city>
<country>CA</country>
<postalCode>V1B3C1</postalCode>
<state>BC</state>
<streetAddressLine>1A</streetAddressLine>
<streetAddressLine>2A</streetAddressLine>
<streetAddressLine>****</streetAddressLine>
<streetAddressLine>4A</streetAddressLine>
</addr>
<note text="**** should be stars"/>
</identifiedPerson>
So for the sample it solves that problem I think. I am not sure whether there can be more context around that sample and whether you want to change values outside of the identifiedPerson element as well or don't want to change them (which above stylesheet does). If other elements also need to be changed consider to post longer input and wanted result samples to illustrate and also explain what determines the node where the value to be replaced is found.
[edit]
Based on your comment I adapted the stylesheet, it now has a parameter to pass in a id (e.g. 2.16.840.1.113883.3.51.1.1.6.1), then it looks for an element of any name with a root attribute having that passed in id value and replaces the extension attribute value found in all attributes and all text nodes found in the document. Furthermore a nullFlavor attribute is added to the element with the id and its extension attribute is removed.
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0">
<xsl:param name="root-id" select="'2.16.840.1.113883.3.51.1.1.6.1'"/>
<xsl:variable name="to-be-replaced" select="//*[#root = $root-id]/#extension"/>
<xsl:param name="replacement" select="'****'"/>
<xsl:param name="new" select="'MKS'"/>
<xsl:template match="comment() | processing-instruction()">
<xsl:copy/>
</xsl:template>
<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates select="#* , node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="text()">
<xsl:sequence select="replace(., $to-be-replaced, $replacement)"/>
</xsl:template>
<xsl:template match="#*">
<xsl:attribute name="{name()}" namespace="{namespace-uri()}" select="replace(., $to-be-replaced, $replacement)"/>
</xsl:template>
<xsl:template match="*[#root = $root-id]">
<xsl:copy>
<xsl:apply-templates select="#*"/>
<xsl:attribute name="nullFlavor" select="$new"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[#root = $root-id]/#extension"/>
</xsl:stylesheet>