How do I Handle multiple XSLT copy statements on same match? - xslt

Question

Are there any XSLT statements that will execute in consideration of other XSLT statements within the same stylesheet?
For example, if I have two copy statements matched to the same node (but only desire one copied node that contains the modifications declared in BOTH copy statements) is there a statement that will do this?
Assume that I cannot put all the transformations in one copy node, but instead have to use two or more.
---Clearer example---
//XML
<toy></toy>
//XSLT
<xsl:template match="toy">
<xsl:copy>
<xsl:attribute name="label">SOME TOY</xsl:attribute>
</xsl:copy>
</xsl:template>
<xsl:template match="toy">
<xsl:copy>
<xsl:apply-templates select="#*" />
<xsl:element name="range">
<xsl:element name="min">200001</xsl:element>
<xsl:element name="max">999999</xsl:element>
</xsl:element>
</xsl:copy>
</xsl:template>
My desired result would be a new toy node that is copied to a new file that has both things applied to it, so something like:
<toy label='SOME TOY'>
<range>
<min>200001</min>
<max>999999</max>
</range>
</toy>
Not two different copies
Is this possible? Is there some way I can redo the first template so that will make this one outcome?

Answer 1

There is rule in XSLT specification, which forbid this - Conflict Resolution for Template Rules.
If node fits several templates - only one template will be executed - in relation to the template import precedence, priority or document order, etc.
But you can separate it with named templates:
<xsl:template match="toy">
<xsl:call-template name="toyAttribute" />
<xsl:call-template name="toyElements" />
</xsl:template>
<xsl:template name="toyAttribute">
<xsl:copy>
<xsl:attribute name="label">SOME TOY</xsl:attribute>
</xsl:copy>
</xsl:template>
<xsl:template name="toyElements">
<xsl:copy>
<xsl:apply-templates select="#*" />
<xsl:element name="range">
<xsl:element name="min">200001</xsl:element>
<xsl:element name="max">999999</xsl:element>
</xsl:element>
</xsl:copy>
</xsl:template>
Update:
If you asking about only updating <toy> node with attribute and elements you don't need separate templates:
<!--toy template -->
<xsl:template match="/toys/toy">
<!--copy toy node with namespaces -->
<xsl:copy>
<!-- copy toy node attributes -->
<xsl:apply-templates select="#*" />
<!-- add new attribute or xsl:call-template name="toyAttribute"-->
<xsl:attribute name="label">SOME TOY</xsl:attribute>
<!-- copy toy node child elements -->
<xsl:apply-templates select="node()" />
<!-- add new elements - or xsl:call-template name="toyElements"-->
<xsl:element name="range">
<xsl:element name="min">200001</xsl:element>
<xsl:element name="max">999999</xsl:element>
</xsl:element>
</xsl:copy>
</xsl:template>
<!--Copy node content -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
which for XML:
<?xml version="1.0" encoding="UTF-8"?>
<toys>
<toy name="a">
<toy-part/>
</toy>
<toy name="b">
<toy-part/>
</toy>
</toys>
will give following result:
<?xml version="1.0" encoding="utf-8"?><toys>
<toy name="a" label="SOME TOY">
<toy-part/>
<range>
<min>200001</min>
<max>999999</max>
</range>
</toy>
<toy name="b" label="SOME TOY">
<toy-part/>
<range>
<min>200001</min>
<max>999999</max>
</range>
</toy>
</toys>