Is there anyway in which I can get the value of a querystring variable and work with it with xsl. I tried with <xsl:param name="qsVariableName">, but had no success, it doesnt break but it gives me an empty value when I try to input it like this.
www.example.com?qsVariableName=true
<xsl:param name="qsVariableName" />
<xsl:value-of select="$qsVariableName"></xsl:value-of>
Querystring parameters from either the source XML file or the XSLT are not automatically mapped to set <xsl:param> in your stylesheet.
The <xsl:param> need to be explicitly set when the transform is invoked. Depending upon the environment and how your are invoking it there is different syntax for setting the parameters.
In Java, you would set the parameter with something like this:
javax.xml.transform.Transformer trans =
transFact.newTransformer(xsltSource);
trans.setParameter("qsVariableName", "true");
In XSLT 2.0 you could use the document-uri() function to obtain the URL of the source XML file and then parse that value to obtain a sequence of the querystring parameter(s) and value(s).
tokenize(substring-after(document-uri(/), '?'), '&')
For instance, with the code above if you were transforming an XML file with the url: http://example.com/file.xml?qsVariableName=true it would return "qsVariableName=true".
Related
I need to pass a node as a parameter to an XSL stylesheet. The issue is that the parameter gets sent as a string. I have seen the several SO questions regarding this topic, and I know that the solution (in XSLT 1.0) is to use an external node-set() function to transform the string to a node set.
My issue is that I am using eXist DB I cannot seem to be able to get its XSLT processor to locate any such function. I have tried the EXSLT node-set() from the namespace http://exslt.org/common as well as both the Saxon and Xalan version (I think eXist used to use Xalan but now it might be Saxon).
Are these extensions even allowed in the XSLT processor used by eXist? If not, is there something else I can do?
To reference or transform documents from the database, you should pass the path as a parameter to the transformation, and then refer to it using a parameter and variable
(: xquery :)
let $path-to-document := "/db/test/testa.xml"
let $stylesheet :=
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:param name="source" required="no"/>
<xsl:variable name="error"><error>doc not available</error></xsl:variable>
<xsl:variable name="theDoc" select="if (doc-available($source)) then doc($source) else $error"/>
<xsl:template match="/">
<result><xsl:value-of select="$source"/> - <xsl:value-of select="node-name($theDoc/*)"/></result>
</xsl:template>
</xsl:stylesheet>
return transform:transform(<dummy/>,$stylesheet, <parameters><param name="source" value="xmldb:exist://{$path-to-document}"/></parameters>)
As per Martin Honnen's comments I don't think it is possible to pass an XML node via the <parameters> structure of the transform:transform() function in eXist. The function seems to strip away any XML tags passed to it as a value.
As a workaround I will wrap both my input XML and my parameter XML into a root element and pass that as input to the transform function.
I am using xslt 1.0.
I want to import A.xsl into B.xsl.
I am unable to use relative paths in href attribute of xsl:import. for ex. path is c:/test/testdata/xsl/file/A.xsl
I tired following code
<xsl:variable name="filePath" select="concat(Systemprop:getProperty('docRootPath'),'/xsl/file/A.xsl')" />
and
<xsl:import href="{concat(Systemprop:getProperty('docRootPath'),'/xsl/file/A.xsl')}">
where docrootPath = c:/test/testdata
but its is giving error : Element type "xsl:variable" must be followed by either attribute specifications, ">" or "/>".
but its giving me :Had IO Exception with stylesheet file. Please suggest .
See the spec, http://www.w3.org/TR/xslt#section-Combining-Stylesheets, it defines the syntax for include and import as
<!-- Category: top-level-element -->
<xsl:include
href = uri-reference />
<xsl:import
href = uri-reference />
So the href attribute value needs to be a URI reference, neither an expression nor an attribute value template is allowed there. So putting in an XPath expression like concat(...) is not possible, is not supported.
A relative URI reference can be used of course, but you would need to make sure a base URI is defined properly, for instance doing <xsl:import xml:base="file:///C:/test/testdata/" href="file.xml"/>. That is however also only a static value to be defined during stylesheet authoring.
This is a very basic XSL question and I am just getting started with the topic in the context of Umbraco:
I've defined a macro with a XSLT file. The macro has a parameter of type 'ContentPicker'. What I want to do with the macro, is to render the picked content in a certain way. The relevant bit of my XSLT file is this:
<xsl:param name="source" select="/macro/BlogPostSource"/>
<xsl:template match="/">
<div>
<xsl:value-of select="$source/blogPostIntroduction"/>
</div>
I define a parameter, which is set to the parameter of the macro (this works). Now I simply want to render the property blogPostIntroduction which is a generic property on the picked content. This doesn't work. If I use
<xsl:value-of select="$source"/>
the ID of the content is rendered.
Question A: How do I select fields of the selected content?
Question B: Is my idea correct in general or am I missing a better way to do what I need, rather than using macros and XSLT?
I am using Saxon to perform a transformation of an XML document in my .NET application. I am passing in a parameter to my xslt document but I have no idea how to use it in my template.
Here is what I have done so far:
var zipcode = _db.AXCustomers.FirstOrDefault(x => x.ACCOUNTNUM == accNo).ZIPCODE;
transformer.SetParameter(new QName("CustomerZipCode"), new XdmAtomicValue(zipcode));
Then in my xslt document I am specifying the parameter like so:
<xsl:template match="/">
<xsl:param name="CustomerZipCode" />
But when I try to use the parameter, nothing appears. I am using it like so:
<xsl:value-of select="substring-before($CustomerZipCode, ' ')"/>
But nothing is output even though my zipcode does contain a value
You are using xsl:param inside a xsl:template element, it means that the param is for the template. The parameter you are passing from the .net code is a transformer parameter and related xsl:param must be placed at the top level of the stylesheet, into the xsl:stylesheet element.
I'm trying to get the value of iWantToGetThis.jpg and put it into an <img> during my XSL transformation. This is how my xml is structures:
<article>
<info>
<mediaobject>
<imageobject>
<imagedata fileref='iWantToGetThis.jpg'>
Here's what I've come up with for the XSL:
<xsl:template name="user.header.content">
<xsl:stylesheet xmlns:d='http://docbook.org/ns/docbook'>
<img><xsl:attribute name="src">../icons/<xsl:value-of select='ancestor-or-self::d:article/info/mediaobject/imageobject/imagedata/#fileref' /></xsl:attribute></img>
</xsl:stylesheet>
</xsl:template>
The image is being added to the output, but the src attribute is set to "../icons/", so I'm assuming it's not finding the fileref attribute in the XML. This looks perfectly valid to me, so I'm not sure what I'm missing.
I am not sure how you can get anything back at all, because that does not look like a valid XSLT document (I would expect the error "Keyword xsl:stylesheet may not contain img.").
However, it may be you are just showing a fragment of the code. If this is the case, your issue may be that you have only specified the namespace for the article element, when you really need to specify it for all elements in your xpath. Try this
<xsl:value-of
select="ancestor-or-self::d:article/d:info/d:mediaobject/d:imageobject/d:imagedata/#fileref"/>
Another possible problem may be because you are using the 'ancestor-or-self' xpath axis to find the attribute. This would only work if your current context was already on the article element, or one of its descendants.
As a side note, you can simplify the code by making use of Attribute Value Templates here
<img src="../icons/{ancestor-or-self::d:article/d:info/d:mediaobject/d:imageobject/d:imagedata/#fileref}" />