C++ and writing enum values into Windows registry - c++

Question

I am writing a function as follows:
bool abc::GetLoggingStatus() {
//true or false is returned
int value;
if (regKey->HasValue("LoggingStatus")) {
regKey->QueryValue("LoggingStatus", &value);
if (value == 1)
return true; //no logging possible
else
return false;
}
regKey->SetValue("LoggingStatus", 1);
return true;
}
Logging level is defined as:
typedef enum {
Entry,
Exit,
Debug,
Warning,
Notification,
Error
} TYPE;
What I need if I select 1 the levels for logging must be shown namely debug,error ... In regedit and if 0 nothing should be shown and logging be disabled.

Answer 1

You can't create dropdown menus in regedit, but what you can do is create a new entry called LoggingLevel. This entry is ignored if LoggingStatus is 0. LoggingLevel is a string defining the level.
If you want to convert this string back to an enum, the easiest way is to create a map from string to your Enum type:
std::map<std::string, TYPE> typeMap;
typeMap["Warning"] = Warning;
...
In your code you query the logging level:
char* level;
regKey->QueryValue("LoggingLevel", level);
TYPE theLevel = typeMap[level];
Of course you need to do appropriate error checking.
edit
You should add two function to get the log settings, shouldLog() and getLevel().
The log function would then look like:
void log(Logger* logger, TYPE type, string sClassName, string sMethodName, string sMessage = "") {
if (!logger || !abc::shouldLog()) {
return;
}
TYPE curLevel = abc::getLevel();
bool shouldLog = false;
if (type == Warning && (curLevel == All || curLevel == Warning) ...) {
shouldLog = true;
}
if (shouldLog) {logger->WriteEntry(sClassName, sMethodName); }
}
If you want to avoid complicated if-structures, you could also try and map the enums to a value and compare that. For example Warning = 1 and ALL = 0. Then you can check if curLevel < type to see if the logger should log.