I am having trouble using regex in fitnesse. I want to get a regex for a sequence of 10 digits. I tried the following-
=~/\d{10}/
and
=~/[0-9]{10}/
But these are not working. For a sample input say "1234", the above regex is passing as green.
What would be the regex to test a sequence of 10 digits in fitnesse?
Try adding start/end anchors, e.g.
=~/^\d{10}$/
or perhaps word anchors if the 10 digit number is embedded in other text:
=~/\b\d{10}\b/
your regex match sequence of only 10 digits, but not 4
you must write \d{1,10}
Related
I am trying to match all characters between "xAA" and "xFF" but only if theres at least 4 characters between those. Is there a simple way to do this with RegEx?
For example, xAA-12345-xFF should be matched but xAA-1-xFF should be ignored.
My RegEx currently looks like this:
"(?<=\xAA).*(?=\xFF)"
this does match everything between those characters, but i can't find a way on how to only match if at least 4 characters between them, can someone help me?
Quick and dirty hack could be:
"xAA....*xFF"
This requires three (...) characters followed by 0 or more (.*).
Do this:
xAA\S{4,}xFF
\S{4,} matches at least 4 non whitespace characters.
Demo
(?<=xAA-)[0-9]{4,}(?=\-xFF)
retracts 12345 from xAA-12345-xFF in case there are only digits
(?<=xAA-)[0-9a-zA-Z]{4,}(?=\-xFF) if letters or digits are possible
regex101.com
Is there a regular expression for? :
String of length 8
First two chracters fixed 'UE' or 'ue'
remaining 6 characters must be digits [0-9]
Eg: https://regex101.com/r/PufypE/1
The expression i tried
\^(UE|ue){2}[0-9]{6}\
but its not working (no match found!)
You want:
\b(UE|ue)[0-9]{6}\b
You don't need the {2} next to the (UE|ue) since you are specifying those exactly. The \b is a word boundary so this will match a list like you put in the comment: UE123456,ue654321 This is a good site to play with a regex on for this kind of stuff: http://regex101.com
Regex should be:
^[Uu][Ee][0-9]{6}$
(UE|ue){2} in your regex would match 2 occurrences of UE or ue
Say i give a pattern 123* or 1234* , i would like to match any 10 digit number that starts with that pattern. It should have exactly 10 digits.
Example:
Pattern : 123 should match 1234567890 but not 12345678
I tried this regex : (^(123)(\d{0,10}))(?(1)\d{10}).. obviously it didn't work. I tried to group the pattern and remaining digits as two different groups. It matches 10 digits after the captured group (https://regex101.com/). How do i check the captured group is exactly 10 digits? Or is there any good knacks here. Please guide me.
Sounds like a case for the positive lookahead:
(?=123)\d{10}
This will match any sequence of exactly 10 digits but only if prefixed with 123. Test it here.
Similarly for prefix 1234:
(?=1234)\d{10}
Of course, if you know the prefix length upfront, you can use 123\d{7}, but then you'll have to change range limits with each prefix change (for example: 1234\d{6}).
Additionally, to ensure only isolated groups of 10 digits are captured, you might want to anchor the above expression with a (zero-length) word boundary \b:
\b(?=123)\d{10}\b
or, if your sequence can appear inside of the word, you might want to use negative lookbehind and lookahead on \d (as suggested in comments by #Wiktor):
(?<!\d)(?=123)\d{10}(?!\d)
I would keep it simple:
import re
text = "1234567890"
match = re.search("^123\d{7}$|^1111\d{6}$", text)
if match:
print ("matched")
Just throw your 2 patterns in as such and it should be good to go! Note that 123* would catch 1234* so I'm using 1111\d{6} as an example
I am trying to implement a regex for phone numbers, based on our business logic.
What the customer wants is that the phone must contain between 8 and 15 characters of numbers, and also can contain any spaces and dots anywhere which doesn't add to the count of numbers. So, theoretically this should be valid:
3 .... 44444444
Because it contains 9 numbers.
I can't really go further on
~[0-9\.\ ]{8,15}$
but obviously it counts dots and spaces to the limit too.
Is it even possible to implement it via regex?
A Regex attempt:
^(?:[ .]*\d){8,15}[ .]*$
This will match 8 to 15 digits, with any number of space or dot happening anywhere in between.
The non-captured group, (?:[ .]*\d), matches any digit preceded by any number of dot or space, {8,15} ensures the range on numbers
[ .]*$ matches any number of dot or space at the end
Demo
As far as I know, regular expressions cannot validate this. However you could maybe globally remove all whitespace and dots and then try to match a regex that is ^[[:digit:]]{8,15}$
I'm looking to build a regex that matches the following group of numbers:
10xxxxxxx
1116xxxxx
143xxxxxx
146xxxxxx
149xxxxxx
159xxxxxx
16xxxxxxx
(note the length is always 9)
where x is any digit. My best attempt yielded this:
/^1[01456][1369]*[6]*[0-9]$/
However, I can't get the length of the string to always be 9. Any ideas?
Edit: Maybe I wasn't clear enough, it needs to match those 7 cases, and ONLY those, inclusively and exclusively.
How about:
^1(?:[06]\d{2}|116|4[369]\d|59\d)\d{5}$
use this pattern
^1[01456](16|3\d|6\d|9\d|\d\d)\d{5}$
Is this what you want?
^(?=[0-9]{9}$)(?:10|1116|143|146|149|159|16)
Demo
This starts by looking at the beginning of the string for exactly 9 digits using a positive lookahead anchored to the end of the string. Then we look for any of your 7 specific groups of numbers that the string can start with.
You can use this regex:
/^1[01456][1369][0-9]{6}$/
Since 3 digits are already matched by first 3 patterns 1, [01456] and [1369] so last one must match exact 6 characters to enforce it a 9 digit input.