There is list
<nodes>
<node attr='1'/>
<node attr='0'/>
<node attr='1'/>
<node attr='1'/>
</nodes>
i need to apply-templates all nodes and count it:
<xsl:apply-templates select='nodes/node'>
<xsl:if test='#attr=1'>
<xsl:number/>
</xsl:if>
</xsl:apply-templates>
but a haz in result not 123, result is 134. How to fix it in xslt-1.0? There is another way to set numbers to it? position() not help, and
<xsl:apply-templates select='nodes/node[#attr=1]'>
<xsl:if test='#attr=1'>
<xsl:number/>
</xsl:if>
</xsl:apply-templates>
not help to =(((
Firstly, you have an error in your XSLT
<xsl:apply-templates select='nodes/node'>
<xsl:if test='#attr=1'> <xsl:number/>
</xsl:if>
</xsl:apply-templates>
You can't have an xsl:if within an xsl:apply-templates. You need a matching xsl:template and put the code in there...
<xsl:apply-templates select="nodes/node" />
<xsl:template match="node">
<xsl:if test='#attr=1'>
<xsl:number/>
</xsl:if>
<xsl:template>
In fact, you could do away with the xsl:if here, and just have the test in the template match
<xsl:template match="node[#attr=1]">
<xsl:number/>
<xsl:template>
But to answer your question, you probably need to use the count attribute on the xsl:number element to count only the elements you want
<xsl:number count="node[#attr=1]"/>
Here is the full XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/">
<xsl:apply-templates select="nodes/node"/>
</xsl:template>
<xsl:template match="node[#attr=1]">
<xsl:number count="node[#attr=1]"/>
</xsl:template>
<xsl:template match="node"/>
</xsl:stylesheet>
When applied to you XML, the result is 123
This says 123 - is this what you were after?
<xsl:for-each select="nodes/node[#attr='1']">
<xsl:value-of select="position()"/>
</xsl:for-each>
It is not quite clear what are you trying to achieve. I presume you need to count the number of nodes that have attribute set to 1. In that case, use the count function:
<xsl:value-of select="count(nodes/node[#attr='1'])" />
In case you need to output a position of the desired node inside the subset matching the condition, then for-each will be probably the way to go:
<xsl:for-each select="nodes/node[#attr='1']">
<xsl:value-of select="position()" />
</xsl:for-each>
Related
I have a problem getting data from a node, when I'm using xml:choose and xml:when. I only get the result NaN or the value from the main xml-file, even if.
Part of the XML-file:
<?xml version="1.0" encoding="UTF-8"?>
<Job xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" >
<Invoice>
<InvoiceLine>
<LineNo>1</LineNo>
<QtyInSecondUnit>56</QtyInSecondUnit>
<Quantity>56</Quantity>
<CustTaric>
<StatNo>34011100</StatNo>
<IssuingCountry>GB</IssuingCountry>
</CustTaric>
</InvoiceLine>
<InvoiceLine>
<LineNo>2</LineNo>
<QtyInSecondUnit>22</QtyInSecondUnit>
<Quantity>0</Quantity>
<CustTaric>
<StatNo>44152020</StatNo>
<IssuingCountry>GB</IssuingCountry>
</CustTaric>
</InvoiceLine>
</Invoice>
</Job>
Part of the XSLT-file:
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:apply-templates select="Job/Invoice"/>
</xsl:template>
<xsl:template match="Job/Invoice/InvoiceLine">
<xsl:apply-templates select="QtyInSecondUnit"/>
<xsl:apply-templates select="Quantity"/>
<xsl:apply-templates select="CustTaric/StatNo"/>
</xsl:template>
<xsl:template match="QtyInSecondUnit">
<xsl:choose>
<xsl:when test="/Job/Invoice/InvoiceLine/CustTaric/StatNo = '44152020'">
<xsl:value-of select="number(translate(Job/Invoice/InvoiceLine/NetMass,',','.')) div 25"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="."/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template match="Quantity">
<xsl:choose>
<xsl:when test="/Job/Invoice/InvoiceLine/CustTaric/StatNo = '44152020'">
<xsl:value-of select="'0'"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="."/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template match="CustTaric/StatNo">
<xsl:value-of select="."/>
</xsl:template>
Hope there is somebody how can tell me (the noob) what I'm doing wrong here?
Here's the line producing NaN
<xsl:value-of select="number(translate(Job/Invoice/InvoiceLine/NetMass,',','.')) div 25"/>
There are two problems (one of which is probably where you have over-simplified your XML)
The xpath expression you are using will be relative to the current node you are positioned on. There is no Job element under the current QtyInSecondUnit element
There is no NetMass element in your XML in your question
Assuming NetMass does exist in your actual XML, and is a child of the parent InvoiceLine the expression you want is this
<xsl:value-of select="number(translate(../NetMass,',','.')) div 25"/>
There is also an issue with your xsl:when (possibly)
<xsl:when test="/Job/Invoice/InvoiceLine/CustTaric/StatNo = '44152020'">
This will test for any CustTaric/StatNo anywhere in the document. Perhaps you only want to test for the one in the current InvoiceLine? If so, do this...
<xsl:when test="../CustTaric/StatNo = '44152020'">
Note, you could rewrite your XSLT to put the logic in template matches, rather than xsl:choose
Try this XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="Job/Invoice/InvoiceLine">
<xsl:apply-templates select="QtyInSecondUnit"/>
<xsl:apply-templates select="Quantity"/>
<xsl:apply-templates select="CustTaric/StatNo"/>
</xsl:template>
<xsl:template match="InvoiceLine[CustTaric/StatNo = '44152020']/QtyInSecondUnit">
<xsl:value-of select="number(translate(../NetMass,',','.')) div 25"/>
</xsl:template>
<xsl:template match="QtyInSecondUnit">
<xsl:value-of select="."/>
</xsl:template>
<xsl:template match="InvoiceLine[CustTaric/StatNo = '44152020']/Quantity">
<xsl:value-of select="'0'"/>
</xsl:template>
<xsl:template match="Quantity">
<xsl:value-of select="."/>
</xsl:template>
<xsl:template match="CustTaric/StatNo">
<xsl:value-of select="."/>
</xsl:template>
</xsl:stylesheet>
Strictly speaking, the templates that just do <xsl:value-of select="."/> can be removed, as XSLT's built-in templates will do exactly the same thing if there is no matching template in the XSLT.
With XSLT 2.0, I am trying to create a list of relations between all children of given elements, in a document such as:
<doc>
<part1>
<name>John</name>
<name>Paul</name>
<name>George</name>
<name>Ringo</name>
<place>Liverpool</place>
</part1>
<part2>
<name>Romeo</name>
<name>Romeo</name>
<name>Juliet</name>
<fam>Montague</fam>
<fam>Capulet</fam>
</part2>
</doc>
The result I would like to obtain, ideally by conflating and weighing the identical relations, would be (in whatever order) something like:
<doc>
<part1>
<rel><name>John</name><name>Paul</name></rel>
<rel><name>John</name><name>George</name></rel>
<rel><name>John</name><name>Ringo</name></rel>
<rel><name>Paul</name><name>George</name></rel>
<rel><name>Paul</name><name>Ringo</name></rel>
<rel><name>George</name><name>Ringo</name></rel>
<rel><name>John</name><place>Liverpool</place></rel>
<rel><name>Paul</name><place>Liverpool</place></rel>
<rel><name>George</name><place>Liverpool</place></rel>
<rel><name>Ringo</name><place>Liverpool</place></rel>
</part1>
<part2>
<rel weight="2"><name>Romeo</name><name>Juliet</name></rel>
<rel weight="2"><name>Romeo</name><fam>Montague</fam></rel>
<rel weight="2"><name>Romeo</name><fam>Capulet</fam></rel>
<rel><name>Juliet</name><fam>Montague</fam></rel>
<rel><name>Juliet</name><fam>Capulet</fam></rel>
<rel><fam>Montague</fam><fam>Capulet</fam></rel>
</part2>
</doc>
—but I'm not sure how to proceed. Many thanks in advance for your help.
You still haven't explained the logic that needs to be applied here, so this is based largely on a guess:
XSLT 2.0
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="/">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="doc/*">
<!-- first pass-->
<xsl:variable name="unique-items">
<xsl:for-each-group select="*" group-by="concat(name(), '|', .)">
<item name="{name()}" count="{count(current-group())}" value="{.}"/>
</xsl:for-each-group>
</xsl:variable>
<!-- output -->
<xsl:copy>
<xsl:for-each select="$unique-items/item">
<xsl:variable name="left" select="."/>
<xsl:for-each select="following-sibling::item">
<xsl:variable name="weight" select="$left/#count * #count" />
<rel>
<xsl:if test="$weight gt 1">
<xsl:attribute name="weight" select="$weight"/>
</xsl:if>
<xsl:apply-templates select="$left | ." />
</rel>
</xsl:for-each>
</xsl:for-each>
</xsl:copy>
</xsl:template>
<xsl:template match="item">
<xsl:element name="{#name}">
<xsl:value-of select="#value"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
The idea here is to remove duplicates in the first pass, then enumerate all combinations in the second (final) pass. The weight is computed by multiplying the number of occurrences of each member of a combination pair and shown only when it exceeds 1.
At least the combinatoric part of your problem could be solved with the following XSLT script. It does not solve the elimination of duplicates, but that could possibly be done in a second transformation.
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<!-- standard copy template -->
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*" />
</xsl:copy>
</xsl:template>
<xsl:template match="doc/*">
<xsl:copy>
<xsl:variable name="l" select="./*"/>
<xsl:for-each select="$l">
<xsl:variable name="a" select="."/>
<xsl:variable name="posa" select="position()"/>
<xsl:variable name="namea" select="name()"/>
<xsl:for-each select="$l">
<xsl:if test="position() > $posa and (. != $a or name() != $namea)">
<rel>
<xsl:copy-of select="$a"/>
<xsl:copy-of select="."/>
</rel>
</xsl:if>
</xsl:for-each>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
When applied to the first part of your example, this produces:
<part1>
<rel><name>John</name><name>Paul</name></rel>
<rel><name>John</name><name>George</name></rel>
<rel><name>John</name><name>Ringo</name></rel>
<rel><name>John</name><place>Liverpool</place></rel>
<rel><name>Paul</name><name>George</name></rel>
<rel><name>Paul</name><name>Ringo</name></rel>
<rel><name>Paul</name><place>Liverpool</place></rel>
<rel><name>George</name><name>Ringo</name></rel>
<rel><name>George</name><place>Liverpool</place></rel>
<rel><name>Ringo</name><place>Liverpool</place></rel>
</part1>
Which seems about correct. If have no idea if the duplicate elimination (or weighting, as you call it) could be done in the same transformation.
Silly, simple question. When I output text, it still get the tabs based on my formatted/indented XSL structure. How do I instruct the transformer to ignore the spacing in the stylesheet while still keeping it neatly formatted?
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:apply-templates select="Foo/Bar"></xsl:apply-templates>
</xsl:template>
<xsl:template match="Bar">
<xsl:for-each select="AAA"><xsl:for-each select="BBB"><xsl:value-of select="Label"/>|<xsl:value-of select="Value"/><xsl:text>
</xsl:text></xsl:for-each></xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Produces output line by line with no tabs:
SomeLabel|SomeValue
SomeLabel|SomeValue
SomeLabel|SomeValue
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:apply-templates select="Foo/Bar"></xsl:apply-templates>
</xsl:template>
<xsl:template match="Bar">
<xsl:for-each select="AAA">
<xsl:for-each select="BBB">
<xsl:value-of select="Label"/>|<xsl:value-of select="Value"/>
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Produces output with tabs:
SomeLabel|SomeValue
SomeLabel|SomeValue
SomeLabel|SomeValue
Update:
Adding this does not fix it:
<xsl:output method="text" indent="no"/>
<xsl:strip-space elements="*"></xsl:strip-space>
This is contrived, but you can imagine the XML looks like this:
<Foo>
<Bar>
<AAA>
<BBB>
<Label>SomeLabel1</Label>
<Value>SomeValue1</Value>
</BBB>
<BBB>
<Label>SomeLabel2</Label>
<Value>SomeValue2</Value>
</BBB>
<BBB>
<Label>SomeLabel3</Label>
<Value>SomeValue3</Value>
</BBB>
</AAA>
</Bar>
</Foo>
What you could try is wrapping all your current text nodes in xsl:text. For example, try this
<xsl:for-each select="BBB">
<xsl:value-of select="Label"/>
<xsl:text>|</xsl:text>
<xsl:value-of select="Value"/>
<xsl:text>|</xsl:text>
</xsl:for-each>
Alternatively, you could make use of the concat function.
<xsl:for-each select="BBB">
<xsl:value-of select="concat(Label, '|')"/>
<xsl:value-of select="concat(Value, '|')"/>
</xsl:for-each>
You could even combine the two statements into one if you wanted
<xsl:for-each select="BBB">
<xsl:value-of select="concat(Label, '|', Value, '|')"/>
</xsl:for-each>
EDIT: If you prefer not to enter the separator | so many times, you make use of template matching to output the fileds. First, replace the value-of with apply-templates like so
<xsl:for-each select="BBB">
<xsl:apply-templates select="Label"/>
<xsl:apply-templates select="Value"/>
<xsl:text>
</xsl:text>
</xsl:for-each>
Then you would have one specific template to match Label, where you wouldn't need to output the separator, and another more generic template matching any child of BBB
<xsl:template match="BBB/Label" priority="1">
<xsl:value-of select="." />
</xsl:template>
<xsl:template match="BBB/*">
<xsl:text>|</xsl:text><xsl:value-of select="." />
</xsl:template>
(The priority here is needed to ensure Label is matched by the first template, and not the general one). Of course, you could also not do apply-templates on Label in this case, and just do xsl:value-of for that one.
Furthermore, if the fields were being output in the order they appear in the XML, you could simplify the for-each to just this
<xsl:for-each select="BBB">
<xsl:apply-templates />
<xsl:text>
</xsl:text>
</xsl:for-each>
Hope find a guru's help to figure out the next problem.
I have two xml files. Firts one here (text.xml):
<text>
<ref>Author1, Title1, Date1</ref>
<ref>Author75, Title75, Date2</ref>
<ref>Author2, Title2, Date2</ref>
<ref>Author3, Title3, Date3</ref>
<text>
And the second one like this (list.xml):
<list>
<bibl xml:id="1"><author>Author1</author><date>Date1</date></bibl>
<bibl xml:id="2"><author>Author2</author><date>Date2</date></bibl>
<bibl xml:id="3"><author>Author3</author><date>Date3</date></bibl>
</list>
I want to query text.xml and check against list.xml to add #xml:id (from list.xml) to <ref> (from text.xml) wich contain same Author and Date. If not, then just copy original <ref>.
So I want to obtain:
<ref xml:id="1">Author1, Title1, Date1</ref>
<ref>Author75, Title75, Date2</ref>
<ref xml:id="2>Author2, Title2, Date2</ref>
etc.
My XSLT identify well all correpondence:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="ref">
<xsl:variable name="ref" select="."/>
<xsl:for-each select="document('list.xml')//bibl">
<xsl:variable name="bibl" select="."/>
<xsl:variable name="author" select="author"/>
<xsl:variable name="date" select="date"/>
<xsl:choose>
<xsl:when test="contains($ref, $author) and contains($ref, $date)">
<ref>
<xsl:attribute name="xml:id">
<xsl:value-of select="$bibl/#xml:id"/>
</xsl:attribute>
<xsl:value-of select="$ref"/>
</ref>
</xsl:when>
<xsl:otherwise>
<xsl:copy-of select="$ref"/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
But, then there aren't correpondence it's not just copy right <ref>, but copy all <ref> the number of time I have <bibl> nodes in the second file.
So problem is in <xsl:otherwise><xsl:copy-of select="$ref"/></xsl:otherwise>.
Any ideas how I can obtain only this distinct value I need? I know it's must be very simple actually and I try key, generate-id, for-each-group, distinct-values, but can't figure it out.
The problem is that you are creating a ref element for each iteration of the for-each loop whether there is a match or not.
What you need to do in this case is create the ref element outside of the for-each and then only create the id attribute for the matching element inside the loop
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="ref">
<xsl:variable name="ref" select="."/>
<ref>
<xsl:apply-templates select="#* "/>
<xsl:for-each select="document('list.xml')//bibl">
<xsl:variable name="bibl" select="."/>
<xsl:variable name="author" select="author"/>
<xsl:variable name="date" select="date"/>
<xsl:choose>
<xsl:when test="contains($ref, $author) and contains($ref, $date)">
<xsl:attribute name="xml:id">
<xsl:value-of select="$bibl/#xml:id"/>
</xsl:attribute>
</xsl:when>
</xsl:choose>
</xsl:for-each>
<xsl:apply-templates select="node()"/>
</ref>
</xsl:template>
</xsl:stylesheet>
When applied to your sample XML, the following is output
<text>
<ref xml:id="1">Author1, Title1, Date1</ref>
<ref>Author75, Title75, Date2</ref>
<ref xml:id="2">Author2, Title2, Date2</ref>
<ref xml:id="3">Author3, Title3, Date3</ref>
</text>
However, your current method is not very efficient, as for each ref element you are iterating over all bibl elements. Another approach would be to extract the author and date from the ref elements, and then look up the bibl element directly
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="ref">
<xsl:variable name="author" select="normalize-space(substring-before(., ','))"/>
<xsl:variable name="date" select="normalize-space(substring-after(substring-after(., ','), ','))"/>
<ref>
<xsl:apply-templates select="#* "/>
<xsl:apply-templates select="document('list.xml')//bibl[author=$author][date=$date]"/>
<xsl:apply-templates select="node()"/>
</ref>
</xsl:template>
<xsl:template match="bibl">
<xsl:attribute name="xml:id">
<xsl:value-of select="#xml:id"/>
</xsl:attribute>
</xsl:template>
</xsl:stylesheet>
This should also give the same results.
EDIT:
humm...too much focus on xsl syntax, i should have seen that earlier...
you have an implicated outer loop over each ref and an inner loop over each bibl. You generate one element for every bibl for every ref regardless of match or no match.
So, instead of the xsl:otherwise you need a check after the for-each loop to see if there was no match and do the copy-of if neccessary.
Not sure how to do the check, though..maybe using position() and count() of the generated <ref>s, sorry...don't have any more time to think about this right now.
not really an explanation, but a workaround:
<xsl:otherwise>
<ref>
<xsl:value-of select="$ref"/>
</ref>
</xsl:otherwise>
My guess is that the problem lies in $ref, which is not a xpath expression at that moment (if i remember xsl-t correctly)
I have a pretty flat XML structure that I need to reorder into categorised sections and, for the life of me, I can't figure out how to do it in XSLT (not that I'm by any means an expert.)
Basically, the original XML looks kinda like:
<things>
<thing>
<value>one</value>
<type>a</type>
</thing>
<thing>
<value>two</value>
<type>b</type>
</thing>
<thing>
<value>thee</value>
<type>b</type>
</thing>
<thing>
<value>four</value>
<type>a</type>
</thing>
<thing>
<value>five</value>
<type>d</type>
</thing>
</things>
And I need to output something like:
<data>
<a-things>
<a>one</a>
<a>four</a>
</a-things>
<b-things>
<b>two</b>
<b>three</b>
</b-things>
<d-things>
<d>five</d>
</d-things>
</data>
Note that I can't output <c-things> if there aren't any <c> elements, but I do know ahead of time what the complete list of types is, and it's fairly short so handcoding templates for each type is definitely possible. It feels like I could probably hack something together using <xsl:if> and <xsl:for-each> but it also feels like there must be a more ... 'templatey' way to do it. Can anyone help?
Cheers.
As you are using Saxon, use the native XSLT 2.0 grouping.
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" />
<xsl:template match="things">
<data>
<xsl:for-each-group select="thing" group-by="type">
<xsl:element name="{concat(current-grouping-key(),'-things')}">
<xsl:for-each select="current-group()">
<xsl:element name="{current-grouping-key()}">
<xsl:value-of select="value" />
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:for-each-group>
</data>
</xsl:template>
</xsl:stylesheet>
In XSLT 1.0 you can group with keys. This approach is called Muenchian Grouping.
The xsl:key defines an index containing thing elements, grouped by the string value of their type element. Function key() returns all nodes from the key with the specified value.
The outer xsl:for-each selects the thing elements that are the first returned by key() for their value.
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" />
<xsl:key name="thing" match="thing" use="type" />
<xsl:template match="things">
<data>
<xsl:for-each select="thing[generate-id(.)=generate-id(key('thing',type)[1])]">
<xsl:element name="{concat(type,'-things')}">
<xsl:for-each select="key('thing',type)">
<xsl:element name="{type}">
<xsl:value-of select="value" />
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:for-each>
</data>
</xsl:template>
</xsl:stylesheet>
The generic solution is to use an XSL key:
<xsl:key name="kThingByType" match="thing" use="type" />
<xsl:template match="things">
<xsl:copy>
<xsl:apply-templates select="thing" mode="group">
<xsl:sort select="type" />
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
<xsl:template match="thing" mode="group">
<xsl:variable name="wholeGroup" select="key('kThingByType', type)" />
<xsl:if test="generate-id() = generate-id($wholeGroup[1])">
<xsl:element name="{type}-thing">
<xsl:copy-of select="$wholeGroup/value" />
</xsl:element>
</xsl:if>
</xsl:template>
The above yields:
<things>
<a-thing>
<value>one</value>
<value>four</value>
</a-thing>
<b-thing>
<value>two</value>
<value>thee</value>
</b-thing>
<d-thing>
<value>five</value>
</d-thing>
</things>
In XSLT 2, you can do this very elegantly. Say you have a template for formatting each thing before it is wrapped in an <a> element:
<xsl:template match="thing" mode="format-thing">
<xsl:value-of select="value/text()"/>
</xsl:template>
Then you can apply that to each thing of some $type to build the <a-things> elements via a function:
<xsl:function name="my:things-group" as="element()">
<xsl:param name="type" as="xs:string"/>
<xsl:param name="things" as="element(thing)*"/>
<xsl:element name="{ concat($type, '-things') }">
<xsl:for-each select="$things[type/text() eq $type]">
<xsl:element name="{ $type }">
<xsl:apply-templates select="." mode="format-thing"/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:function>
Then you can call that function for each unique type (a, b, d in your sample input) to build the entire output and you're done:
<xsl:template match="/">
<data>
<xsl:sequence select="
for $type in distinct-values(things/thing/type/text())
return my:things-group($type, /things/thing)
"/>
</data>
</xsl:template>
Of course, asking the question made it obvious...
My solution does use an <xsl:if>, but I can't see how it couldn't now I think about it. My solution looks basically like:
<xsl:if test="/things/thing/type = 'a'">
<a-things>
<xsl:apply-templates select="/things/thing[type='a']" mode="a" />
</a-things>
</if>
<xsl:template match="/things/thing[type='a']" mode="a">
<a><xsl:value-of select="value"/>
</xsl:template>
And repeat for the other types. I've coded it up, and it seems to work just fine.
<a-things>
<xsl:for-each select="thing[type = 'a']">
<a><xsl:value-of select="./value" /></a>
</xsl:for-each>
</a-things>
If you want to get really snazzy, replace the <a-things> and the predicate with parameters and use attribute value templates:
<xsl:param name="type" />
<xsl:element name="{$type}-things">
<xsl:for-each select="thing[type = $type]">
<xsl:element name="{$type}"><xsl:value-of select="./value" /></xsl:element>
</xsl:for-each>
</xsl:element>
And using grouping, you can do it without the if:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="things">
<data>
<xsl:for-each select="thing[not(type=preceding-sibling::thing/type)]">
<xsl:variable name="type"><xsl:value-of select="type" /></xsl:variable>
<xsl:element name="concat($type, '-things')">
<xsl:for-each select="../thing[type=$type]">
<xsl:element name="$type">
<xsl:value-of select="value" />
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:for-each>
</data>
</xsl:template>
</xsl:stylesheet>