I have an XSL that is transforming one XSD into another XSD that has slightly different formatting. (Basically, the target file will be normalized). The other major difference in the target is adding a default namespace and a target namespace. I'm having trouble actually getting the namespace in. Here is a snippet of my XSL:
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsd="http://www.w3.org/2001/XMLSchema" version="1.0">
<xsl:output method="xml" version="1.0" encoding="UTF-8"/>
<xsl:variable name="Unions" select="'Yes'"/>
<xsl:variable name="myname" select="//Table/Name"/>
<xsl:variable name="namespace" select="concat('http://mynamespace/', $myname)"/>
<xsl:template match="/">
<xsl:element name="xsd:schema" namespace="http://www.w3.org/2001/XMLSchema" xmlns="$namespace"
<xsl:attribute name="targetNamespace">
<xsl:value-of select="$namespace"/>
</xsl:attribute>
<xsl:attribute name="elementFormDefault">qualified</xsl:attribute>
<xsl:attribute name="attributeFormDefault">unqualified</xsl:attribute>
...
</xsl:element>
</xsl:template>
</xsl:stylesheet>
And this is what I'm getting:
<?xml version="1.0" encoding="utf-8"?>
<xsd:schema targetNamespace="http://mynamespace/somename" elementFormDefault="qualified" attributeFormDefault="unqualified" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="">
...
</xsd:schema>
And xmlns="$namespace" is tagged on to every child node. I'm no absolute expert on XSLT. I have not had to develop it myself because BizTalk maps generate all of it for you, but this XSL was more complex than I could get BizTalk maps to handle.
Oh, and I'm limited to XSLT 1.0
Generating namespace nodes with dynamically generated values is something XSLT 1 can't really do. XSLT 2 adds xsl:namespace specifically to construct such things.
You said you are stuck at XSLT 1. Do you have EXSLT or any other extension namespace available that gives you the node-set() extension? If so you can go
<xsl:template match="/">
<xsl:variable name="x">
<xsl:element name="x" namespace="{$namespace}">
<xsl:element name="xsd:schema" namespace="http://www.w3.org/2001/XMLSchema">
....
</xsl:variable>
<xsl:copy-of select="xx:node-set($x)/*/*"/>
</xsl:template>
Creating a spurious element <x> in the desired namespace, this forces the namespace node on to its child xs:schema element which you can extract if you have a node-set extension function.
Related
we have a requirement to remove the prefix <dsr:LineItemItems>6</dsr:LineItemItems> in XML content, when we used the below code it was successfully removing the prefix "dsr" from xml elements but we need the xmlns namespaces in the output xml payload which is present in the POSLog tag.
Need all the namespaces/content present in the input first tag <POSLog> in the output xml too.
Input xml:
<?xml version="1.0" encoding="utf-8"?>
<POSLog xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:dsr="http://www.dsr.com/rsd/tlog/markup/poslog" xsi:schemaLocation="http://www.nrf-arts.org/IXRetail/namespace/ POSLog.xsd http://www.dsr.com/rsd/tlog/markup/poslog DSRPOSLog.xsd" xmlns="http://www.nrf-arts.org/IXRetail/namespace/">
<dsr:LineItemItems>6</dsr:LineItemItems>
XSL code:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:dsr="http://www.dsr.com/rsd/tlog/markup/poslog" xsi:schemaLocation="http://www.nrf-arts.org/IXRetail/namespace/ POSLog.xsd
http://www.dsr.com/rsd/tlog/markup/poslog DSRPOSLog.xsd" xmlns="http://www.nrf-arts.org/IXRetail/namespace/" >
<xsl:output method="xml" version="1.0" encoding="UTF-8" />
<xsl:template match="*">
<xsl:element name="{local-name()}" >
<xsl:apply-templates select="#*|node()"/>
</xsl:element>
</xsl:template>
<xsl:template match="#*">
<xsl:attribute name="{local-name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:template>
</xsl:stylesheet>
Output xml by the xsl code:
<?xml version="1.0" encoding="UTF-8"?>
<POSLog schemaLocation="http://www.nrf-arts.org/IXRetail/namespace/ POSLog.xsd http://www.dsr.com/rsd/tlog/markup/poslog DSRPOSLog.xsd">
<LineItemItems>6</LineItemItems>
Need the output as below with all the namespaces without change in the First Tag
<?xml version="1.0" encoding="UTF-8"?>
<POSLog xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:dsr="http://www.dsr.com/rsd/tlog/markup/poslog" xsi:schemaLocation="http://www.nrf-arts.org/IXRetail/namespace/ POSLog.xsd http://www.dsr.com/rsd/tlog/markup/poslog DSRPOSLog.xsd" xmlns="http://www.nrf-arts.org/IXRetail/namespace/">
<LineItemItems>6</LineItemItems>
Thanks,
Ravi
Add an extra template to match the document element and copy it, rather than reconstructing a new element without namespaces. And in the existing template matching elements, add an attribute to indicate the namespace in the xsl:element constructor.
The following stylesheet ensures that all elements are bound to the namespace http://www.nrf-arts.org/IXRetail/namespace/ and that the namespace prefix dsr is retained:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:dsr="http://www.dsr.com/rsd/tlog/markup/poslog" xsi:schemaLocation="http://www.nrf-arts.org/IXRetail/namespace/ POSLog.xsd
http://www.dsr.com/rsd/tlog/markup/poslog DSRPOSLog.xsd" >
<xsl:output method="xml" version="1.0" encoding="UTF-8" />
<!-- copy the document element, preserving it's namespaces -->
<xsl:template match="/*">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<!--create elements using the local-name, but bound to the desired namespace -->
<xsl:template match="*">
<xsl:element name="{local-name()}" namespace="http://www.nrf-arts.org/IXRetail/namespace/" >
<xsl:apply-templates select="#*|node()"/>
</xsl:element>
</xsl:template>
<xsl:template match="#*">
<xsl:attribute name="{local-name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:template>
</xsl:stylesheet>
There are three ways of creating an element in the result tree, and they differ in how they handle namespaces:
xsl:element creates an element with no namespaces other than those used in the element name and in the names of its attributes
xsl:copy copies all the namespaces present on the source element you are copying whether or not they are actually used
a literal result element (e.g. <POSLog>) copies all the namespaces that are in scope for the element in the stylesheet, other than namespaces excluded using exclude-result-prefixes
So you want to create the outermost element of your result document using either xsl:copy or a literal result element, not using xsl:element.
The other problem you have is that you have renamed xsi:schemaLocation as schemaLocation. That happened because you used <xsl:attribute name="{local-name()}"/>. It would be better here to simply use xsl:copy-of to copy the attribute.
I know that this is simple problem. I'm still learning and getting familiarize with the XSLT coding. I have a problem in my XSLT and I don't know if I did it correctly. I need to get the value from the input file and store it in the new element tag name and that I don't need to populate the namespaces and attributes what's on the parent root element. I did a research about this and I saw many references but I can't apply it. The XSLT(v02) that I made is working fine (just copy from the references) if the root element doesn't have any namespaces and attributes. But, when I put a namespaces and attribute, no output populated.
Input file
<Root xmlns="http://abcd.com" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" releaseID="9.2" versionID="2.12.3" xsi:schemaLocation="abcd.com abcd.xsd">
<Element>
<Field>AAAAA</Field>
</Element>
<Element>
<Field>BBBBB</Field>
</Element>
<Element>
<Field>CCCCC</Field>
</Element>
xslt file
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<NewRecord>
<xsl:for-each select="Root/Element">
<NewTransaction>
<Position>
<xsl:value-of select="position()"/>
</Position>
<TransactionID>
<xsl:value-of select="Field"/>
</TransactionID>
</NewTransaction>
</xsl:for-each>
</NewRecord>
</xsl:template>
output generated
<NewRecord/>
My expected output should look like this:
<NewRecord>
<NewTransaction>
<Position>1</Position>
<TransactionID>AAAAA</TransactionID>
</NewTransaction>
<NewTransaction>
<Position>2</Position>
<TransactionID>BBBBB</TransactionID>
</NewTransaction>
<NewTransaction>
<Position>3</Position>
<TransactionID>CCCCC</TransactionID>
</NewTransaction>
I think the problem is in the <xsl:template match="/">, I'm still confused on the nodes that I need to put. Thank you for your help.
If you are really using XSLT 2.0, you only need to add:
xpath-default-namespace="http://abcd.com"
to the stylesheet tag, and leave everything else as is.
If you're using xslt 1.0, you'll have to declare the same namespace in the stylesheet, and use the prefix you map to the namespace to qualify the names of the elements:
The prefix can be whatever you want. I picked abcd to match your example, but it could be any legal identifier.
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:abcd="http://abcd.com">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<NewRecord>
<xsl:for-each select="abcd:Root/abcd:Element">
<NewTransaction>
<Position>
<xsl:value-of select="position()"/>
</Position>
<TransactionID>
<xsl:value-of select="abcd:Field"/>
</TransactionID>
</NewTransaction>
</xsl:for-each>
</NewRecord>
</xsl:template>
</xsl:stylesheet>
I am trying to replace namespace string using xslt.
I have the source namespace string and target namespace string in another xml file in the format of "namespace source="xxx" target="xxx"". All source namespace strings in my to-be-transformed xml should be changed to the corresponding target value. Only elements need to be considered as attributes don't have namespace.
I'm using the JDK default xalan xslt processor, which supports xslt 1.0. I'd like to stick to xslt 1.0 if possible, but I can change processor and use xslt 2.0 if really needed.
For example, to-be-transformed input xml:
<root xmlns="http://ns1" xmlns:ns2="http://ns2-old" xmlns:ns3="http://ns3">
<ElementA xmlns="http://ns4-old">
<ElementB/>
<ns2:elementD/>
</ElementA>
</root>
The output xml should be ("http://ns2-old" is changed to "http://ns2-new", and "http://ns4-old" is changed to "http://ns4-new"):
<root xmlns="http://ns1" xmlns:ns2="http://ns2-new" xmlns:ns3="http://ns3">
<ElementA xmlns="http://ns4-new">
<ElementB/>
<ns2:elementD/>
</ElementA>
</root>
Here is my xsl that is not working:
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:variable name="nsmapdoc" select="document('my-map-file')"/>
<xsl:key name="nsmap" match="//namespace/#target" use="#source"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<!-- process each element -->
<xsl:template match="element()">
<xsl:for-each select="namespace::*">
<!-- for each namespace node of the element, save the string value-->
<xsl:variable name="sourceuri"><xsl:value-of select="."/>
</xsl:variable>
<!-- get the target value for this namespace-->
<xsl:variable name="targeturi">
<xsl:for-each select="$nsmapdoc">
<xsl:value-of select="key('nsmap', $sourceuri)"/>
</xsl:for-each>
</xsl:variable>
<!-- if target value exists, replace the current namespace node string value with the target value-->
<xsl:if test="$targeturi">
<xsl:value-of select="$targeturi"/>
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
I have a few questions:
For the identity template that do the copy, why doing "match="node()|#*" instead of just "match="node()"? Is attribute also a node?
I am not sure if I did correctly to get the namespace string value (like "http://ns1", "http://ns2-old") for the element.
I think I got the key correctly. However, I am not sure if I used the type correctly---looks like targeturi variable is not a string. If key does not have the entry, what will lookup the entry return? In my case, I should replace the namespace value only for the namespace that has an entry in the map.
How to write a new string value for the namespace node?
I need to process each namespace nodes for the element. Is it the right way to define a variable inside ?
please help to see what is wrong with my xsl. Any suggestion is appreciated.
I think you have two, possibly three, separate questions here.
The first question is: how to move elements from one namespace to another, using a "map" of source-to-target namespaces. Let me answer this question first. Given:
XML
<root xmlns="http://ns1" xmlns:ns2="http://ns2-old" xmlns:ns3="http://ns3">
<ElementA xmlns="http://ns4-old">
<ElementB/>
<ns2:ElementD/>
</ElementA>
</root>
map.xml
<root>
<namespace source="http://ns2-old" target="http://ns2-new"/>
<namespace source="http://ns4-old" target="http://ns4-new"/>
</root>
The following stylesheet:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>
<xsl:param name="nsmapdoc" select="document('map.xml')"/>
<xsl:template match="*">
<xsl:variable name="old-ns" select="namespace-uri()"/>
<xsl:variable name="map-entry" select="$nsmapdoc/root/namespace[#source=$old-ns]"/>
<xsl:variable name="new-ns">
<xsl:choose>
<xsl:when test="$map-entry">
<xsl:value-of select="$map-entry/#target"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$old-ns"/>
</xsl:otherwise>
</xsl:choose>
</xsl:variable>
<xsl:element name="{local-name()}" namespace="{$new-ns}">
<xsl:copy-of select="#*"/>
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
will return:
<?xml version="1.0" encoding="utf-8"?>
<root xmlns="http://ns1">
<ElementA xmlns="http://ns4-new">
<ElementB/>
<ElementD xmlns="http://ns2-new"/>
</ElementA>
</root>
Note:
ElementA and its child ElementB have been moved from namespace URI "http://ns4-old" to URI "http://ns4-new";
ElementD has been moved from namespace URI "http://ns2-old" to URI "http://ns2-new";
The prefix of ElementD has been stripped off; this is a meaningless, cosmetic change, and it should not present any problems for the receiving application;
The root element has remained in its original namespace;
Unused namespace declarations have been discarded.
Note also that we are not using a key to lookup the new namespace: using a key across documents is quite awkward in XSLT 1.0 and I have chosen to do without.
The second question is how to copy the unused namespace declarations. There are several possible answers to choose from:
It's not necessary to copy them, since that are not used for anything;
It's not possible to copy them;
It is possible to copy them by copying some element from the source document; however copying an element also copies its namespace - so this can be done only if there is a known element that is supposed to stay in its original namespace. For example, if you know beforehand that the root element is not supposed to be moved to another namespace, you can add another template to the stylesheet:
to get this result:
<?xml version="1.0" encoding="utf-8"?>
<root xmlns="http://ns1" xmlns:ns2="http://ns2-old" xmlns:ns3="http://ns3">
<ElementA xmlns="http://ns4-new">
<ElementB/>
<ElementD xmlns="http://ns2-new"/>
</ElementA>
</root>
I'm trying to create a standard-use XSLT that will perform a given task based upon a user-provided XPATH expression as an XSLT parameter.
That is, I need something like this:
<xsl:template match="$paramContainingXPATH">
<!-- perform the task on the node(s) in the given xpath -->
</xsl:template>
For example, suppose I have some XML:
<xml>
<nodeA>whatever</nodeA>
<nodeB>whatever</nodeB>
<nodeC>whatever</nodeC>
<nodeD>whatever</nodeD>
<nodeE>whatever</nodeE>
</xml>
The XSLT needs to transform just a node or nodes matching a provided XPATH expression. So, if the xslt parameter is "/xml/nodeC", it processes nodeC. If the xslt parameter is "*[local-name() = 'nodeC' or local-name() = 'nodeE']", it processes nodeC and nodeE.
This should work for absolutely any XML message. That is, the XSLT cannot have any direct knowledge of the content of the XML. So, it could be a raw XML, or a SOAP Envelope.
I was guessing I might need to grab all the nodes matching the xpath, and then looping over them calling a named template, and using the standard identity template for all other nodes.
All advice is appreciated.
If you really need that feature with XSLT 1.0 or 2.0 then I think you should consider writing one stylesheet that takes that string parameter with the XPath expression and then simply generates the code of a second stylesheet where the XPath expression is used as a match pattern and the other needed templates like the identity template are included statically. Dynamic XPath evaluation is only available in XSLT 3.0 or in earlier versions as a proprietary extension mechanism.
You cannot match a template using a parameter - but you can traverse the tree and compare the path of each node with the given path. Here's a simple example:
XSLT 1.0
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:param name="path" select="'/world/America/USA/California'"/>
<xsl:template match="/">
<root>
<xsl:apply-templates select="*"/>
</root>
</xsl:template>
<xsl:template match="*">
<xsl:variable name="path-to-me">
<xsl:for-each select="ancestor-or-self::node()">
<xsl:value-of select="name()" />
<xsl:if test="position()!=last()">
<xsl:text>/</xsl:text>
</xsl:if>
</xsl:for-each>
</xsl:variable>
<xsl:if test="$path=$path-to-me">
<xsl:call-template name="action"/>
</xsl:if>
<xsl:apply-templates select="*"/>
</xsl:template>
<xsl:template name="action">
<return>
<xsl:value-of select="." />
</return>
</xsl:template>
</xsl:stylesheet>
Applied to a slightly more ambitious test input of:
<world>
<Europe>
<Germany>1</Germany>
<France>2</France>
<Italy>3</Italy>
</Europe>
<America>
<USA>
<NewYork>4</NewYork>
<California>5</California>
</USA>
<Canada>6</Canada>
</America>
</world>
the result will be:
<?xml version="1.0" encoding="UTF-8"?>
<root>
<return>5</return>
</root>
This could be made more efficient by passing the accumulated path as a parameter of the recursive template, so that each node needs only to add its own name to the chain.
Note:
The given path must be absolute;
Predicates (including positional predicates) and attributes are not implemented in this. They probably could be, with a bit more effort;
Namespaces are ignored (I don't see how you could pass an XPath as a parameter and include namespaces anyway).
If your processor supports an evaluate() extension function, you could forgo the calculated text path and test for intersection instead.
Edit:
Here's an example using EXSLT dyn:evaluate() and set:intersection():
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:dyn="http://exslt.org/dynamic"
xmlns:set="http://exslt.org/sets"
extension-element-prefixes="dyn set">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:param name="path" select="'/world/America/USA/California'"/>
<xsl:variable name="path-set" select="dyn:evaluate($path)" />
<xsl:template match="/">
<root>
<xsl:apply-templates select="*"/>
</root>
</xsl:template>
<xsl:template match="*">
<xsl:if test="set:intersection(. , $path-set)">
<xsl:call-template name="action"/>
</xsl:if>
<xsl:apply-templates select="*"/>
</xsl:template>
<xsl:template name="action">
<return>
<xsl:value-of select="." />
</return>
</xsl:template>
</xsl:stylesheet>
Note that this will also work with with paths like:
/world/America/USA/*[2]
//California
and many others that the text comparison method could not accommodate.
I'm sending the element name as a param to the XSLT
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
<xsl:output method="xml"/>
<xsl:param name="user"/>
<xsl:template match="/">
<xsl:call-template name="generic" />
</xsl:template>
<xsl:template name="generic">
<count><xsl:value-of select="count(.//*[local-name()=$user])"/></count>
</xsl:template>
</xsl:stylesheet>
I hope this could help!
Consider the following XSLT script:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" encoding="iso-8859-1"/>
<xsl:variable name="stringmap">
<map>
<entry><key>red</key><value>rot</value></entry>
<entry><key>green</key><value>gruen</value></entry>
<entry><key>blue</key><value>blau</value></entry>
</map>
</xsl:variable>
<xsl:template match="/">
<!-- IMPLEMENT ME -->
</xsl:template>
</xsl:stylesheet>
I'd like this script to print redgreenblue.
Is there any way to treat the XML markup which is stored in the stringmap variable as a document of its own which I can run XPath queries on? I'm basically looking for something like
<xsl:for-each select="document($stringmap)/map/entry">
<xsl:value-of select="key"/>
</xsl:for-each>
(except that the document() function expects an URI).
Motivation: I have various long <xsl:choose> elements which map a given string to another string. I'd like to replace all those with a single template which takes a 'map' argument (which is a simple XML document). My hope is that I can then replace the <xsl:choose> with a simple statement like <xsl:value-of select="$stringmap/map/entry/value[../key='$givenkey']"/>
I'm using XSLT 1.0 using xsltproc.
You're almost right, using document('') will allow you to process node sets inside the current stylesheet:
<xsl:for-each select="document('')/xsl:stylesheet/xsl:variable[#name='stringmap']/map/entry">
<xsl:value-of select="key"/>
</xsl:for-each>
It's not necessary to define the map node set as a variable in this case:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet xmlns:data="some.uri" version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<data:map>
<entry><key>red</key><value>rot</value></entry>
<entry><key>green</key><value>gruen</value></entry>
<entry><key>blue</key><value>blau</value></entry>
</data:map>
<xsl:template match="/">
<xsl:for-each select="document('')/xsl:stylesheet/data:map/entry">
<xsl:value-of select="key"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
If you do not use xsl:variable as a wrapper, you must remember that a top level elements must have a non null namespace URI.
In XSLT 2.0 it would've been possible to just iterate over the content in a variable:
<xsl:variable name="map">
<entry><key>red</key><value>rot</value></entry>
<entry><key>green</key><value>gruen</value></entry>
<entry><key>blue</key><value>blau</value></entry>
</xsl:variable>
<xsl:template match="/">
<xsl:for-each select="$map/entry">
<xsl:value-of select="key"/>
</xsl:for-each>
</xsl:template>
A posting by M. David Peterson just taught me how to make this work:
It's not necessary to have an <xsl:variable> for this case. Instead, I can embed the data document directly into the XSL stylesheet (putting it into a namespace for sanity) and then select elements from that. Here's the result:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:map="uri:map">
<xsl:output method="text" encoding="iso-8859-1"/>
<map:colors>
<entry><key>red</key><value>rot</value></entry>
<entry><key>green</key><value>gruen</value></entry>
<entry><key>blue</key><value>blau</value></entry>
</map:colors>
<xsl:template match="/">
<xsl:for-each select="document('')/*/map:colors/entry">
<xsl:value-of select="key"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
This generates the expected output redgreenblue.
The trick is to use document('') to get a handle to the XSLT document itself, then * to get into the toplevel xsl:stylesheet element and from there I can access the color map.