I have an inactive QMainWindow with a QTabWidget as CentralWidget which holds multiple QPlainTextEdits. Beside that I have a seperate QWidget flagged with Qt::WindowStaysOnTopHint and Qt::Tool which I want to use as a find/replace tool for the QPlainTextEdits.
Now when I use the tool widget the QMainWindow is shown as inactive like it should and the selection background of the selected text in the active QPlainTextEdit is rendered as inactive (slightly grey) but I want the selection to be rendered like the QMainWindow would be active, with the default selection color w/o loosing the focus on the tool widget.
How do I achieve that?
Try something this:
QPalette p = myInactiveWidget->palette();
for (int colorRole=0; colorRole<QPalette::NColorRoles; colorRole++) p.setColor(QPalette::Inactive, colorRole, p.color(QPalette::Active, colorRole));
myInactiveWidget->setPalette(p);
That should make (myInactiveWidget)'s inactive-color-palette the same as its active-color-palette, so that it no longer looks inactive. Or if all you care about is the color of the text-selection-block, then this would probably be sufficient:
QPalette p = myInactiveWidget->palette();
p.setColor(QPalette::Inactive, QPalette::Highlight, p.color(QPalette::Active, QPalette::Highlight));
p.setColor(QPalette::Inactive, QPalette::HighlightedText, p.color(QPalette::Active, QPalette::HighlightedText));
myInactiveWidget->setPalette(p);
Related
I have a QTreeView populated with items from a model. When a call to edit() is made on an index, a custom editor displays. The editor consists of two QLineEdit widgets.
I want the focus to switch between the two QLineEdit widgets when Tab is pressed. However, pressing Tab cycles through everything else on my program. All my QPushButton and QTabWidget objects are included in the Tab order even though they are completely different widgets than my editor.
I've tried setting the tab order using setTabOrder() to loop it between the two QLineEdit widgets, however this still doesn't isolate the editor widget from the surrounding widgets. Why is this happening?
NOTE: I'm not trying to disable tab ordering anywhere else, just isolate it to my editor for the time being.
Thanks for your time!
This can be easily implemented using QWidget::focusNextPrevChild as follows:
class EditWidget : public QWidget
{
public:
EditWidget(QWidget *pParent) : QWidget(pParent)
{
QHBoxLayout *pLayout = new QHBoxLayout(this);
setLayout(pLayout);
pLayout->addWidget(m_pEdit1 = new QLineEdit ());
pLayout->addWidget(m_pEdit2 = new QLineEdit ());
}
bool focusNextPrevChild(bool next)
{
if (m_pEdit2->hasFocus())
m_pEdit1->setFocus();
else
m_pEdit2->setFocus();
return true; // prevent further actions (i.e. consume the (tab) event)
}
protected:
QLineEdit *m_pEdit1;
QLineEdit *m_pEdit2;
};
To save space in a QTabWidget, I would like to show the close icon only for the current tab, like e.g. Firefox is doing:
Is there a simple way using a style sheet, some thing like (not working like this)
QTabBar::tab::!selected::close-button {visible: false;}
or do I have to subclass QTabWidget to get the desired behavior?
You won't need to subclass anything, you can use QTabWidget::tabBar() method to obtain a reference (i.e. QTabBar *) to the tab bar associated with your QTabWidget. (Note that this method is no longer protected, so it can be accessed without subclassing the class)
QTabBar *tabBar = tabWidget->tabBar();
You can now use tabBar reference to hide close buttons on non-current tabs. For example to hide ith button, you can do:
tabBar->tabButton(i, QTabBar::RightSide)->hide();
So a simple workflow could be as follows:
Connect QTabWidget::currentChanged(int index) signal to a slot.
In that slot hide all close buttons other than the button at index.
You can subclass QTabWidget to get access to the QTabBar widget using protected method QTabWidget::tabBar. Then you can connect to the QTabBar::currentChanged signal and hide close button for not selected tabs manually:
QTabBar::ButtonPosition closeSide =
(QTabBar::ButtonPosition)style()->styleHint(QStyle::SH_TabBar_CloseButtonPosition, 0, this);
for (int i = 0; i < toolbar->count(); ++i)
{
if (i != toolbar->currentIndex())
{
QWidget *w = toolbar->tabButton(i, closeSide);
w->hide();
}
}
hide() leaves empty space for the invisible close button. This looks funny.
Set the width to 0 instead.
I have a two state QPushButton. I want to associate an icon to each state.
It is like Play|Pause buttons in music players.
To do so, I would like to get the current icon name in order to know what the next icon to set will be.
I could subclass QPushButton but is it worth it?
Instead of setting an icon based on the QPushButton's state, set one QIcon that has two states, Qt will select the correct icon if you use it with a checkable QPushButton.
QIcon icon = QIcon();
// 'Off' state corresponds to unchecked state of QPushButton
icon.addPixmap( QPixmap( ":/img/play.png" ), QIcon::Normal, QIcon::Off );
// 'On' state corresponds to checked state of QPushButton
icon.addPixmap( QPixmap( ":/img/pause.png" ), QIcon::Normal, QIcon::On );
QPushButton * button = new QPushButton();
button->setIcon( icon );
button->setCheckable( true );
Use QPushButton::icon() and QIcon::name() to get the icon name.
I want to make a QCheckBox named "Show Captions" disable another QCheckBox named "Show captions if no title" when the first is checked, but my problem is that how I can make it disabled immediately when the user checks the first checkbox.
SetupSlideShow::SetupSlideShow(QWidget* parent)
: QScrollArea(parent), d(new SetupSlideShowPriv)
{
QWidget* panel = new QWidget(viewport());
setWidget(panel);
setWidgetResizable(true);
QVBoxLayout* layout = new QVBoxLayout(panel);
d->showComment = new QCheckBox(i18n("Show captions"), panel);
d->showComment->setWhatsThis( i18n("Show the image caption at the bottom of the screen."));
d->showTitle = new QGroupBox(i18n("Show title"), panel);
d->showTitle->setWhatsThis( i18n("Show the image title at the bottom of the screen."));
d->showTitle->setCheckable(true);
d->showCapIfNoTitle = new QCheckBox(i18n("Show captions if no title"), panel);
d->showCapIfNoTitle->setWhatsThis( i18n("Show the image caption at the bottom of the screen if no titles existed."));
QVBoxLayout *vbox = new QVBoxLayout;
vbox->addWidget(d->showCapIfNoTitle);
d->showTitle->setLayout(vbox);
layout->addWidget(d->showLabels);
layout->addWidget(d->showComment);
layout->addWidget(d->showTitle);
}
Doesn't this work?
connect(d->showComment, SIGNAL(toggled(bool)), d->showCapIfNoTitle, SLOT(setDisabled(bool)));
The call to paintEvent() isn't really doing anything for you regarding immediacy. Nothing will be repainted until control returns to the event loop (after your constructor exits). It is more typical to call update() but even this is unnecessary when changing the properties of built in widgets.
To link the check boxes, define a slot for the stateChanged() signal of showComment, connect the signal to your slot in your constructor above (by calling connect(), and in that slot, call d->showCapIfNoTitle->setCheckState(d->showComment->checkState()).
I have a tab widget where every tab is a QTableView. I would like to be able to pass an updated model (QModelIndex) into each tab whenever the contents of that tab need to change.
The alternative (and nastier way) is for me to delete all the tabs, and then recreate them.
I know I can get the widget in the tab by doing something like:
tabWidget->widget(i);
This will return a widget, which is really a QTableView, but I want to update the model that is in that widget without having to delete and recreate the tab.
Thank you!
P.S. This is my current attempt...
for (int i = 0; i < tableView.size(); i++)
{
tabWidget->setCurrentWidget(tableView.at(i));
QTableView* updatedTable = (QTableView*)tabWidget->currentWidget();
updatedTable->setModel(dataModel);
tableView.replace(i, updatedTable);
}
It's not clear why you can't keep the QTableView widget and just change the model, as in your code. Doesn't the view refresh without this tableView.replace thing?
There doesn't appear to be a direct API for replacing the widget you put in with addTab() without going through a tab removal step. But instead of inserting the QTableView directly, you could instead call addTab() on a dummy widget that has a layout in it with a single item. A QStackedLayout, for instance:
QWidget* dummy = new QWidget;
QStackedLayout stackedLayout = new QStackedLayout;
stackedLayout->addWidget(tableView);
dummy->setLayout(stackedLayout);
tabWidget->addTab(dummy);
Then later, when you want to replace the tableView with a new one:
QWidget* dummy = tabWidget->currentWidget();
QStackedLayout newStackedLayout = new QStackedLayout;
newStackedLayout->addWidget(newTableView);
delete dummy->layout();
dummy->setLayout(newStackedLayout);
I still wonder what this is buying you that reusing the old table view couldn't do.