Django admin: Change selected box of related fields to autocomplete - django

We have some models that are have a user as a foreign key. But with about 25000 users in our system, it's a bit daunting to find the one we need.
Is there a solution out there that's better than the select box? Maybe an autocomplete so we can start typing the user name / address? Or just a search box? When switching the related user for these objects, it's getting harder and harder with 25000 unsorted users.
Even just setting it to sort the users by username would be helpful.

I had this problem and my conclusion was to use an autocomplete field instead. It works pretty well in most cases. The only problem is when you have a lot of entries that are mostly the same. For example, in your case, if you type Robert for the name and there's a few hundred Robert entries in the list...
UPDATE
As mentions in shuckc's answer, Django 2.0+ admin as now autocomplete built in.
For older Django or to use outside of the admin (old answer)
There are many apps that add autocomplete to the Django admin:
django-autocomplete-light
django-extensions (ForeignKeyAutocompleteAdmin)
django-autocomplete (on google code)
django-ajax-selects
django-admin-autocomplete
django-autocomplete (tyrion)
My preferred one is the last one. It's well written, it can be used with the admin and outside of the admin, it works with ManyToManyFields, ForeignKeyFields, CharFields, etc.
I did a fork of this project for my client that adds some niceties like a lookup (loupe) button like the ForeignKeyRawIdWidget.

Django 2.0 admin has autocomplete built in, just set the autocomplete_fields field on the ModelAdmin class. e.g.
class QuestionAdmin(admin.ModelAdmin):
ordering = ['date_created']
search_fields = ['question_text']
class ChoiceAdmin(admin.ModelAdmin):
autocomplete_fields = ['question']

The simplest out-of-the-box solution is to add the field to your ModelAdmin's raw_id_fields -- then you'll get a pop-up window in which you can use the built-in searching/filtering and pagination control's to find and select the object you're after.
If you really want autocomplete, the other answers give a you reasonable starting point.

You can use the ForeignKeyRawIdWidget from django.contrib.admin.widgets. It renders FK relations as an input with a small button along-side which presents a searchable pop up.

There is an app for that (django-autocomplete).

Related

Django Admin: How to change model name?

I would like to change the model name displayed in admin. The idea is to be able to register filtered versions of the model to the admin view. I know that I can add filter options when viewing the model. I am not interested in doing that.
I don't think using the approach for solving admin plural naming is an option: Django fix Admin plural. I could be wrong. If so, please tell me how this can be done.
I found this approach which seems to be the right solutions: Change 'Change model class name' in Django Admin || Change the 'Change' <h1>. However, I can't make it work. Is it just me not trying hard enough?
It is also an option to make a number of models and then register each of them. However, I will prefer to rename and register filtered versions in admin.
Any suggestions for solving this little issue?

Django app where you can send application to authorities

I am currently working to write a web app where people fill out the necessary information, and apply to their mentors.
So, at this point, mentors have a model class that is pretty much like the applicant's, so that they can correct the applicant's info without affecting the applicant's original profile.
I will appreciate any helpful comments. Specifically, I am looking for:
-A similar per-exisiting django app that does more or less so I can browse the source.
-Any special Django feature that allows this that I can not aware of.
-General info on how things like these are done in general.
Thank you.
Ad general info)
You would benefit from doing this in a single model (say ApplicationModel), with fields in pairs - field_name_applicant, field_name_mentor.
Then use a CreateView with its fields property set to only the *_applicant fields for the applicant to fill in the applications initially, and an UpdateView with its fields set to the *_mentor fields for the mentor to correct the applicant fields.
Have ApplicationModel.clean() copy all *_applicant field values to their *_mentor counterpart if the later is not set.
Now you have all your business logic in the model where it belongs; quoting a headline in the introduction of Two Scoops of Django:
Fat Models, Helper Modules, Thin Views, Stupid Templates

django admin choices with submenus

I have a model with this field:
exercise = models.CharField(max_length=25, choices=EXERCISES_CHOICES)
but the list of exercises is VERY long, when I use it in the admin interface it occupies all the length of the page, is there a way to display in subitems?
I have a similar problem, but mine is not a list of choices - instead it is a foreign key field and the default in the Admin is also to display the entire list of available values in an option menu; as the database fills, this will probably be unusable. My plan is to create a custom Admin widget which uses a text input instead of an option menu, and use autocomplete to help fill in the value. I have not yet implemented it - I've started looking for autocomplete packages. Maybe once I decide on one, I'll come back and post an update.
P.S. It seems to me this would be a common problem and should already have been solved. Why can't I find anything out there?
---- EDIT ----
Apparently this has been solved! According to its documentation, the "django-extensions" package includes a "ForeignKeyAutocompleteAdmin" class. Hurray! See here:
http://pythonhosted.org/django-extensions/admin_extensions.html
https://pypi.python.org/pypi/django-extensions
Disclaimer: I haven't tried it yet (but I intend to!)

Can I make Django admin reflect a hierarchy of models?

Assume a Django application with a few models connected by one-to-many relationships:
class Blog(models.Model):
...
class Post(models.Model):
blog = models.ForeignKey(Blog)
...
class Comment(models.Model):
post = models.ForeignKey(Post)
...
Conceptually, they form a hierarchy, a tree-like structure. I want the Django admin to reflect that. In particular:
in a changelist of posts, every post should have a link to the changelist of corresponding comments;
similarly, a post’s edit page should link to the changelist of comments from the top-right buttons area;
when I open that list of related comments, it needs to reflect the relationship in the breadcrumbs (something like: Posts › “Hello world” › Comments) and, ideally, also in the URL (post/123/comment/).
This should of course also apply to the other levels of the hierarchy.
Number 1 is pretty easy with a custom list_display entry and using the ?post__id= query to the comments changelist. But this is little more than a hack. Generally Django assumes my three models to be independent, top-level entities.
Is there a straightforward way to accomplish this? I guess I could override a bunch of templates and AdminModel methods, but perhaps there is a better solution for what seems like a common situation?
Are you sure you are not just looking at Django Admin Inline Models ?
There is no way that an automated admin will pick up your relationships, because in an RDBS there can be any number of foreign keys / one to one / many to many relations, and Django does not have a customized hierarchical behavior built in.
You can indeed edit the breadcrumb customizing an admin template if you want.
For relations you might also be interested into django MPTT that allows to make hierarchical model instances. Also see this question: Creating efficient database queries for hierarchical models (django) in that respect.
How is this a common situation? Consider the fact a model can have a virtually unlimited number of foreign key relationships, let alone visa versa. How would the admin 'know' how to represent this data the way a user requires without customizing things?
One would suggest you are used to work with content management systems rather than webframeworks (no pun intended). It's important to notice Django isn't a cms, but a webframework you can built on top of as you see fit. In a nutshell: 'Django is rather clueless and unaware of contextual requirements'.
Although the admin is quite a beast out-of-the-box, it can be hard to customize. There have been quite some discussions whether it should even be part of core. I can only suggest, if customizing things tends to get hacky, you should probably write your own 'admin', it's not that hard.

Reusing Admin forms for user views in django?

Django is making very nice forms after creating a models.py and an admin.py.
How can I reuse these forms (with the extra nice handling of foreign keys and many-to-many fields) in my own views?
ModelForm does only generate "simple" forms. Where do I get the extra batteries?
I was actually able to replicate those green buttons in my forms by following the instructions on this page: http://www.hoboes.com/Mimsy/hacks/replicating-djangos-admin/
A stock ModelForm will do almost all of what the admin does (ForeignKeys will turn into a dropdown select, ManyToManyFields will turn into a multiple-select).
The main exception would be the little green plus buttons for adding a new entry. It would be pretty hard to make those generic, as they depend on a number of admin-specific things: knowing where to find an add page for the linked model; JS to popup a window, close it on submit, and update the parent page; etc. You can dig into the admin and figure out how it implements those extra niceties, but there is not going to be a simple way to drop them into your code.
The other nicety you might be wanting is the filter_horizontal or filter_vertical alternative UIs for a ManyToManyField. Those are implemented as ordinary form widgets, so the potential is there for reusing them in your own code, but I'm guessing it'll take some experimentation and customization to make it work properly.