I'm not very familiar with xsl, so I'm sort of stumbling my way though this.
My xsl file is building a menu. I am trying to sort the menu items by the value in menu title field in Sitecore. When I run the code, it does not sort. It just writes out each menu item four times.
Can anyone shed some light on what I am missing?
<xsl:template name="show-title">
<xsl:param name="root" />
<xsl:for-each select="$sc_currentitem/item">
<xsl:sort select="sc:fld('menu title',.)" order="ascending"/>
<xsl:choose>
<xsl:when test="sc:fld('menu title',$root)!=''">
<sc:text field="menu title" select="$root" />
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$root/#name" />
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</xsl:template>
EDIT: Below is the data that the code above is generating
Example Output:
03/05/201203/05/201203/05/201203/05/2012
03/01/201203/01/201203/01/201203/01/2012
03/08/201203/08/201203/08/201203/08/2012
03/02/201203/02/201203/02/201203/02/2012
03/07/201203/07/201203/07/201203/07/2012
I am trying to get it to generate the following:
03/01/2012
03/02/2012
03/05/2012
03/07/2012
03/08/2012
Thanks!
It looks like you are trying to read menu title field from the wrong node. You should be reading it from context node --> . <--
Try this
<xsl:template name="show-title">
<xsl:param name="root" />
<xsl:for-each select="$sc_currentitem/item">
<xsl:sort select="sc:fld('menu title',.)" order="ascending"/>
<xsl:choose>
<xsl:when test="sc:fld('menu title',$root)!=''">
<sc:text field="menu title" select="." />
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="./#name" />
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</xsl:template>
This is just a guess as you don't really supply enough information for anyone to do more than guess but....
Within your for-each you are referring to $root e.g. <xsl:value-of select="$root/#name" />
I am guessing that the $root parameter contains a list of some kind and that you should be selecting just part of this list based on some value from the current for-each context
Related
Working on the xsl and i am looking for variable inside a loop to reset on new record.
Fetching records from oracle table
<xsl:variable name="curr_temp_emp_no" select="'##'"/>
<xsl:for-each select="/data/test/loof/super_incompleted">
<xsl:variable name="curr_temp_emp_no2" select="emp_no"/>
<xsl:choose>
<xsl:when test="$curr_temp_emp_no2 != $curr_temp_emp_no">
<xsl:value-of select="emp_no"/><fo:inline> - </fo:inline><xsl:value-of select="variable_desc"/></xsl:when>
<xsl:otherwise>
<xsl:value-of select="variable_desc"/>
</xsl:otherwise>
</xsl:choose>
<xsl:variable name="curr_temp_emp_no" select="emp_no"/>
</xsl:for-each>
I am trying to compare variable "curr_temp_emp_no" if new value only it prints "emp_no - variable_desc" otherwise(if same emp_no) then print only "variable_desc".
I understood from google that Variables in XSLT are immutable, once we assign them a value, we can't change them.
Refence: Can you simulate a boolean flag in XSLT?
Can anyone please help me over here in writting this logic.
It looks like you want to compare the last two values. I could achieve this by:
<xsl:template match="/">
<xsl:call-template name="helperTemplate">
<xsl:with-param name="nodes" select="/data/test/loof/super_incompleted"/>
</xsl:call-template>
</xsl:template>
<xsl:template name="helperTemplate">
<xsl:param name="nodes"/>
<xsl:param name="oldVal" select="''"/>
<xsl:if test="$nodes">
<xsl:variable name="curr_temp_emp_no" select="$nodes[1]/emp_no"/>
<xsl:choose>
<xsl:when test="$curr_temp_emp_no != $oldVal">
<xsl:value-of select="$curr_temp_emp_no"/>
<fo:inline> - </fo:inline>
<xsl:value-of select="$nodes[1]/variable_desc"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$nodes[1]/variable_desc"/>
</xsl:otherwise>
</xsl:choose>
<xsl:call-template name="helperTemplate">
<xsl:with-param name="nodes" select="$nodes[position() > 1]"/>
<xsl:with-param name="oldVal" select="$nodes[1]/emp_no"/>
</xsl:call-template>
</xsl:if>
</xsl:template>
If you want to have the comparison on all values(if there was no previous element with that content), you can sort them first and use the same code.
You're asking us to reverse engineer your requirements from non-working code, which is always a challenge, but you seem to be carrying over ideas from procedural programming languages which gives us some clues as to what you imagine you want this code to do.
Basically it looks like a "group-adjacent" problem. In XSLT 2.0 you would do
<xsl:for-each-group select="/data/test/loof/super_incompleted"
group-adjacent="emp_no">
...
</xsl:for-each-group>
If you're stuck with XSLT 1.0 then the usual approach is to process the sequence of nodes with a recursive named template rather than a for-each instruction: you pass the list of nodes as a parameter to the template, together with the current employee id, and then in the template you process the first node in the list, and call yourself recursively to process the remainder of the list.
#ChristianMosz has expanded this suggestion into working code.
Thanks for your reply.
I have used the "preceding-sibling::" which solved my problem. Now the code is something like this.
<xsl:for-each select="/data/test/loof/super_incompleted">
<xsl:variable name="curr_temp_emp_no2" select="emp_no"/>
<xsl:choose>
<xsl:when test="$curr_temp_emp_no2 != preceding-sibling::super_incompleted[1]/emp_no">
<xsl:value-of select="emp_no"/><fo:inline> - </fo:inline><xsl:value-of select="variable_desc"/></xsl:when>
<xsl:otherwise>
<xsl:value-of select="variable_desc"/>
</xsl:otherwise>
</xsl:choose>
<xsl:variable name="curr_temp_emp_no" select="emp_no"/>
</xsl:for-each>
Earlier the table was like this.
1- ABC,1- DFE,1- GFH
2- DFG,2- FGH,2- SDS,2- RTY
Now table looks like this.
1- ABC,DFE,GFH
2- DFG,FGH,SDS
I'm looking for some help with an XSL selector:
What I need is a selector that will show the Title of a different list where the Document of the same row matches the Name field. If there is no entry, I will show a link to create a new one. Here is what I have:
<xsl:choose>
<xsl:when test="/dsQueryResponse
/Change_Types
/Rows
/Row
/#Document = #Name"/>
<xsl:value-of select="/dsQueryResponse
/Change_Types
/Rows
/Row
/#Document[
/dsQueryResponse
/Change_Types
/Rows
/Row
/#Document = #Name
]"/>
</xsl:when>
<xsl:otherwise>
<!-- Code to show link -->
</xsl:otherwise>
</xsl:choose>
If anyone could point out where I'm going wrong, it would be greatly appreciated!
In the absence of your source XML it's a complete guess, but I suspect that
#Document = #Name
should be
#Document = current()/#Name
on both occasions. Unless you really do want the Document and Name attributes of the same element to have the same value.
Here's how I did it:
A variable needed to be created for #FileLeafRef so it could be preserved to test against inside the for-each.
<xsl:variable name="document" select="#FileLeafRef"/>
<xsl:choose>
<!-- If there is an entry in the 'Tickets' list for this #FileLeafRef -->
<xsl:when test="/dsQueryResponse/Tickets/Rows/Row/#Document = $document">
<!-- Show it here -->
<xsl:for-each select="/dsQueryResponse/Tickets/Rows/Row">
<xsl:if test="#Document = $document">
<xsl:value-of select="#Title"/>
</xsl:if>
</xsl:for-each>
</xsl:when>
<!-- Else, show a link to add a new Ticket with the document auto-populated -->
<xsl:otherwise>
<xsl:call-template name="addNewItemLink">
<xsl:with-param name="list" select="'Tickets'"/>
<xsl:with-param name="document" select="#FileLeafRef"/>
</xsl:call-template>
</xsl:otherwise>
</xsl:choose>
I have the following xsl code in an xsl document
<A target="_blank" style="text-decoration=none">
<xsl:attribute name="href">viewdoc.aspx?doc=<xsl:value-of select="URLFilePath"/>&mode=inline</xsl:attribute>
<xsl:attribute name="prefix"><xsl:value-of select="FileName"/>: </xsl:attribute>
<IMG src="images/word_small.gif" border="0"/>
</A>
and in the code-behind I am doing this
newItemNode = xmlDocument.CreateElement("URLFilePath")
newItemNode.InnerText = correctedPath
xmlItemNode.ParentNode.AppendChild(newItemNode)
Now that works fine for word documents. However I need a way in code to check the extension of the file, and display the correct Image and xsl:attribute depending on the If statement.
So the If statement will be like this:-
If correctedPath.ToLower.Contains(".doc") Then
//display the word icon and attributes
Else
//display the excel icon and attributes
End If
Can you please give me some tips and help on how I can achieve this?
Thanks
Just using contains() may generally produce the wrong results (see the test XML document).
What is necessary is a ends-with() function, which is standard in XPath 2.0 and can be implemented in XSLT 1.0 as in the following transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:template match="URLFilePath">
<xsl:variable name="visDoc">
<xsl:call-template name="ends-with">
<xsl:with-param name="pEnding" select="'.doc'"/>
</xsl:call-template>
</xsl:variable>
<xsl:variable name="visXls">
<xsl:call-template name="ends-with">
<xsl:with-param name="pEnding" select="'.xls'"/>
</xsl:call-template>
</xsl:variable>
<xsl:choose>
<xsl:when test="$visDoc=1">word_small.gif</xsl:when>
<xsl:when test="$visXls=1">xls_small.gif</xsl:when>
<xsl:otherwise>unknown_small.gif</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template name="ends-with">
<xsl:param name="pEnding"/>
<xsl:value-of select=
"number(substring(.,
string-length() -string-length($pEnding) +1
)
=
$pEnding
)
"/>
</xsl:template>
</xsl:stylesheet>
When this transformation is applied on the following test XML document:
<files>
<URLFilePath>myFile.doc</URLFilePath>
<URLFilePath>myFile.xls</URLFilePath>
<URLFilePath>myFile.xls.doc</URLFilePath>
<URLFilePath>myFile.doc.xls</URLFilePath>
</files>
the correct result is produced:
word_small.gif
xls_small.gif
word_small.gif
xls_small.gif
Do note that just using contains() produces incorrect results.
I managed to come up with a solution! Sorry for the late reply but had to work on something else
Here is the code:-
<A target="_blank" style="text-decoration=none">
<xsl:choose>
<xsl:when test="contains(., '.doc')">
<xsl:attribute name="href">viewdoc.aspx?doc=<xsl:value-of select="URLFilePath"/>&mode=inline
</xsl:attribute>
<xsl:attribute name="prefix">
<xsl:value-of select="FileName"/>:
</xsl:attribute>
<IMG src="images/word_small.gif" border="0"/>
</xsl:when>
<xsl:when test="contains(., '.xls')">
<xsl:attribute name="href">viewxls.aspx?doc=<xsl:value-of select="URLFilePath"/>&mode=inline
</xsl:attribute>
<xsl:attribute name="prefix">
<xsl:value-of select="FileName"/>:
</xsl:attribute>
<IMG src="images/excel_small.gif" border="0"/>
</xsl:when>
</xsl:choose>
</A>
Thanks for all your help guys, really very much appreciated!
A late reply but I hit to two answers that deal with matching end of string with XSLT 1.0 and are very elegant:
https://stackoverflow.com/a/3081205/520567
https://stackoverflow.com/a/3081866/520567
go give them +1
This can be done purely in your XSLT document if you require. For displaying the image, you could use a xsl:choose statement, that tests the URLFilePath element
<xsl:choose>
<xsl:when test="contains(., '.doc')">
<IMG src="images/word_small.gif" border="0"/>
</xsl:when>
<xsl:when test="contains(., '.xls')">
<IMG src="images/excel_small.gif" border="0"/>
</xsl:when>
</xsl:choose>
If you wanted to do this check in the code behind, you could always add extra attributes to your URLFilePath element.
imageAttr = xmlDocument.CreateAttr("image")
If correctedPath.ToLower.Contains(".doc") Then
imageAttr.value = "images/word_small.gif"
Else
imageAttr.value = "images/excel_small.gif"
End If
newItemNode.AppendChild(imageAttr)
And then, in your xls, you can simply use this attribute to set the source attribute of the image
<IMG border="0">
<xsl:attribute name="src"><xsl:value-of select='#image' /></xsl:attribute>
</IMG>
So,
I have an XSLT template which expects a node set as a parameter and uses this as display text. However, sometimes this node is empty in the XML and I want to pass default display text instead of the display text not showing up instead:
Works:
<xsl:call-template name="myTemplate">
<xsl:with-param name="parm1" select="//element">
</xsl:call-template>
Doesn't work:
<xsl:variable name="dispText">
<xsl:choose>
<xsl:when test="string-length(//element) = 0">
<xsl:value-of select="'Default Text'" />
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="//element" />
</xsl:otherwise>
</xsl:choose>
</xsl:variable>
<xsl:call-template name="myTemplate">
<xsl:with-param name="parm1" select="$dispText">
</xsl:call-template>
Any ideas as to how I could accomplish this? I've tried all sorts of things with no luck :(
It seems like all I need to do is create a new node with the display text I want, but I don't know if that is even possible?
Thanks
Implement the default handling in the template, because that's where it belongs. The calling side should be consistent and not have side-effects on the template behavior (i.e. you should not be able to "forget" passing in the default value).
<xsl:template name="myTemplate">
<xsl:param name="parm1" /><!-- node set expected! -->
<!-- actual value or default -->
<xsl:variable name="value1">
<xsl:choose>
<xsl:when test="not($parm1 = '')">
<xsl:value-of select="$parm1" />
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$default1" />
</xsl:otherwise>
</xsl:choose>
</xsl:variable>
<!-- work with $value1 from this point on -->
</xsl:template>
I'm guessing //element is a nodeset and using string-length() on it might not be valid. Try converting it to a string() first?
I am making a newslist, and have until now sorted the news after their date. Newest first.
But I would like to give the administrator of the site a more flexible solution. This means that in the backend, the admin can choose from a dropdown-list, in wich way he/she want's the list to be sorted. By date(newest first and oldest first), or by title (A-Z and Z-A). This means 4 possible ways right.
Right now I have the following XSLT:
<xsl:variable name="alleNyheder" select="$currentPage//node" />
<xsl:variable name="sort">
<news>
<xsl:for-each select="$alleNyheder[#template='1092']">
<news>
<id>
<xsl:value-of select="./#id"></xsl:value-of>
</id>
<date>
<xsl:choose>
<xsl:when test="./data[#alias='date'] != ''">
<xsl:value-of select="./data[#alias='date']"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="./#createDate"/>
</xsl:otherwise>
</xsl:choose>
</date>
</news>
</xsl:for-each>
</news>
</xsl:variable>
<xsl:for-each select="msxml:node-set($sort)/news/news">
<xsl:sort data-type="text" select="date" order="descending" />
---- My newsitems ----
</xsl:for-each>
So in the moment I sort my list after the "date"-value in my variable $sort.
If I change the "date"-field in $sort, to titles instead of date's I can actually sort my list after the titles of the news. But unfortunately it should be sorted in an ascending order, instead of a descending order. And I can't figure out how to change the order-value dynamically like I do in the select-value.
If it helps anyone, I am working on Umbraco CMS.
Thanks
-Kim
<xsl:choose>
<xsl:when test="$sortfield = 'date' and $sortorder = 'D'>
<xsl:for-each select="msxml:node-set($sort)/news/news">
<xsl:sort data-type="text" select="date" order="descending" />
<!-- ... -->
</xsl:for-each>
</xsl:when>
<xsl:when test="$sortfield = 'date' and $sortorder = 'A'>
<xsl:for-each select="msxml:node-set($sort)/news/news">
<xsl:sort data-type="text" select="date" order="ascending" />
<!-- ... -->
</xsl:for-each>
</xsl:when>
<!-- ... -->
</xsl:choose>
On a different note, you really should look into <xsl:apply-templates> and avoid <xsl:for-each>. Your code gets cleaner and a lot more idiomatic this way. I am also sure that the entire temporary node-set() business is completely avoidable.