Display different xsl:attribute depending on the ending of a string - xslt

Question

I have the following xsl code in an xsl document
<A target="_blank" style="text-decoration=none">
<xsl:attribute name="href">viewdoc.aspx?doc=<xsl:value-of select="URLFilePath"/>&mode=inline</xsl:attribute>
<xsl:attribute name="prefix"><xsl:value-of select="FileName"/>: </xsl:attribute>
<IMG src="images/word_small.gif" border="0"/>
</A>
and in the code-behind I am doing this
newItemNode = xmlDocument.CreateElement("URLFilePath")
newItemNode.InnerText = correctedPath
xmlItemNode.ParentNode.AppendChild(newItemNode)
Now that works fine for word documents. However I need a way in code to check the extension of the file, and display the correct Image and xsl:attribute depending on the If statement.
So the If statement will be like this:-
If correctedPath.ToLower.Contains(".doc") Then
//display the word icon and attributes
Else
//display the excel icon and attributes
End If
Can you please give me some tips and help on how I can achieve this?
Thanks

Answer 1

Just using contains() may generally produce the wrong results (see the test XML document).
What is necessary is a ends-with() function, which is standard in XPath 2.0 and can be implemented in XSLT 1.0 as in the following transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:template match="URLFilePath">
<xsl:variable name="visDoc">
<xsl:call-template name="ends-with">
<xsl:with-param name="pEnding" select="'.doc'"/>
</xsl:call-template>
</xsl:variable>
<xsl:variable name="visXls">
<xsl:call-template name="ends-with">
<xsl:with-param name="pEnding" select="'.xls'"/>
</xsl:call-template>
</xsl:variable>
<xsl:choose>
<xsl:when test="$visDoc=1">word_small.gif</xsl:when>
<xsl:when test="$visXls=1">xls_small.gif</xsl:when>
<xsl:otherwise>unknown_small.gif</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template name="ends-with">
<xsl:param name="pEnding"/>
<xsl:value-of select=
"number(substring(.,
string-length() -string-length($pEnding) +1
)
=
$pEnding
)
"/>
</xsl:template>
</xsl:stylesheet>
When this transformation is applied on the following test XML document:
<files>
<URLFilePath>myFile.doc</URLFilePath>
<URLFilePath>myFile.xls</URLFilePath>
<URLFilePath>myFile.xls.doc</URLFilePath>
<URLFilePath>myFile.doc.xls</URLFilePath>
</files>
the correct result is produced:
word_small.gif
xls_small.gif
word_small.gif
xls_small.gif
Do note that just using contains() produces incorrect results.

Answer 2

I managed to come up with a solution! Sorry for the late reply but had to work on something else
Here is the code:-
<A target="_blank" style="text-decoration=none">
<xsl:choose>
<xsl:when test="contains(., '.doc')">
<xsl:attribute name="href">viewdoc.aspx?doc=<xsl:value-of select="URLFilePath"/>&mode=inline
</xsl:attribute>
<xsl:attribute name="prefix">
<xsl:value-of select="FileName"/>:
</xsl:attribute>
<IMG src="images/word_small.gif" border="0"/>
</xsl:when>
<xsl:when test="contains(., '.xls')">
<xsl:attribute name="href">viewxls.aspx?doc=<xsl:value-of select="URLFilePath"/>&mode=inline
</xsl:attribute>
<xsl:attribute name="prefix">
<xsl:value-of select="FileName"/>:
</xsl:attribute>
<IMG src="images/excel_small.gif" border="0"/>
</xsl:when>
</xsl:choose>
</A>
Thanks for all your help guys, really very much appreciated!

Answer 3

A late reply but I hit to two answers that deal with matching end of string with XSLT 1.0 and are very elegant:
https://stackoverflow.com/a/3081205/520567
https://stackoverflow.com/a/3081866/520567
go give them +1

Answer 4

This can be done purely in your XSLT document if you require. For displaying the image, you could use a xsl:choose statement, that tests the URLFilePath element
<xsl:choose>
<xsl:when test="contains(., '.doc')">
<IMG src="images/word_small.gif" border="0"/>
</xsl:when>
<xsl:when test="contains(., '.xls')">
<IMG src="images/excel_small.gif" border="0"/>
</xsl:when>
</xsl:choose>
If you wanted to do this check in the code behind, you could always add extra attributes to your URLFilePath element.
imageAttr = xmlDocument.CreateAttr("image")
If correctedPath.ToLower.Contains(".doc") Then
imageAttr.value = "images/word_small.gif"
Else
imageAttr.value = "images/excel_small.gif"
End If
newItemNode.AppendChild(imageAttr)
And then, in your xls, you can simply use this attribute to set the source attribute of the image
<IMG border="0">
<xsl:attribute name="src"><xsl:value-of select='#image' /></xsl:attribute>
</IMG>