I working my way through a C++ and Operating Systems book and I've come upon an assignment that requires creation, writing, and reading from pipes. However my program stalls on reading from the second pipe. My program is to accept input and parse out a space delimited string into tokens and classifying those tokens accordingly. My code is bellow with my problem area marked. Any help is as always very appreciated.
edit: This is supposed to have two children. One for processing the space delimited tokens and the other for determining the type of delimited tokens. As far as debugging goes I only have access to cout as a debugger. So I inserted a cout before the read and after the one before the read appeared but the one after did not.
#include <iostream>
#include <fstream>
#include <string>
#include <sys/types.h>
#include <sys/wait.h>
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
using namespace std;
//declaring the pipes
int pipeOne[2];
int pipeTwo[2];
struct inputStruct {
char str[256]; /* one extra spot for \n */
int len; /* length of str */
int flag; /* 0 for normal input, 1 to indicate “done” */
};
struct tokenStruct {
char token[256]; /* tokens can be 255 max */
int flag; /* same as inputStruct */
int tokenType; /* a code value */
};
void dataProcess(){
//new input struct to contain the the input from the parent
inputStruct input;
//the intial read from the pipe to populate the input stuct
read( pipeOne[0], (char*)&input, sizeof(inputStruct));
//set the flag
int flag = input.flag;
while (flag != 1){
int size = 0;
//get the size of the array up until the null character
while (input.str[size] != '\0'){
size++;
}
//Here's the parsing of each token
for (int i=0; i<size; i++) {
int tokenLength;
tokenStruct token;
//while the char isn't white space or null increment through it
while (input.str[i] != ' ' && input.str[i] != '\0') {
//a is the index of the string token
int a = 0;
//write the parsed string
token.token[a] = input.str[i];
a++;
i++;
}
//write to process 2
write(pipeTwo[1], (char*)&token, sizeof(tokenStruct));
}
//read again and store the results
read(pipeOne[0], (char*)&input, sizeof(inputStruct));
flag = input.flag;
}
tokenStruct token;
token.flag = flag;
//final write to the second child to tell it to commit suicide
write(pipeTwo[1], (char*)&token, sizeof(tokenStruct));
exit(0);
}
void tokenClassifer(){
tokenStruct token;
//Problem area is here on ****************************************************
//the initial read
read(pipeTwo[0], (char*)&token, sizeof(tokenStruct));
while (token.flag != 1){
int size = 0;
//get the size of the array up until the null character
while (token.token[size] != '\0'){
size++;
}
if (size == 1) {
//check for the one char things first
switch (token.token[0])
{
case '(':
token.tokenType = 0;
break;
case ')':
token.tokenType = 0;
break;
case ';':
token.tokenType = 0;
break;
case '+':
token.tokenType = 1;
break;
case '-':
token.tokenType = 1;
break;
case '/':
token.tokenType = 1;
break;
case '*':
token.tokenType = 1;
break;
default:
if (isdigit(token.token[0])) {
token.tokenType = 2;
} else {
token.tokenType = 3;
}
break;
}
} else {
bool isStr;
int i = 0;
//check for the more than one character
while (token.token[i] != '\0'){
//check if it's a string or digits
if (isdigit(token.token[0])) {
isStr=false;
} else{
//set up the bools to show it is a string
isStr=true;
break;
}
}
//if it is a string token type 3
if (isStr) {
token.tokenType = 3;
} else {
//if not then it's digits and token type 2
token.tokenType = 2;
}
}
//print out the token and token type
cout << "Token type is: " << token.tokenType << "Token value is: " << token.token << "\n";
//read the pipe again and start the process all over
read(pipeTwo[0], (char*)&token, sizeof(tokenStruct));
}
exit(0);
}
int main()
{
//create the pipes for reading and writing between processes
pipe(pipeOne);
pipe(pipeTwo);
//fork off both processes
int value = fork();
int value2 = fork();
//do the process for the first fork
if(value == 0){
//fork one
dataProcess();
} else {
wait(0);
}
//do the process for the second fork
if (value2 == 0) {
//fork two
//the token classifer function for the second fork
tokenClassifer();
} else {
cout << "Type some tokens (or just press enter to quit) \n";
//this is all of the parent functions
for (string line; getline(cin, line); )
{
inputStruct input;
if (line.empty())
{
// if the line is empty, that means the user didn't
// press anything before hitting the enter key
input.flag = 1;
write( pipeOne[1], (char*)&input, sizeof(inputStruct));
break;
} else {
//else copy the string into an array
strcpy(input.str, line.c_str());
//set the flag to zero to show everthing is ok
input.flag = 0;
}
//write the stuct to the pipe
write( pipeOne[1], (char*)&input, sizeof(inputStruct));
cout << "Type some tokens (or just press enter to quit) \n";
}
wait(0);
}
}
One problem that is evident:
//fork off both processes
int value = fork();
int value2 = fork();
This will fork 3 new processes. The initial fork will leave you with two processes, each of which go on to fork a new process.
EDIT:
Proper forking:
int value = fork();
if (value == 0) {
// do child stuff
exit(0);
} else if (value == -1) {
//fork failed
}
int value2 = fork();
if (value2 == 0) {
//do child stuff
exit(0);
} else if (value2 == -1) {
//fork failed
}
I'm actually not quite clear about how data goes through your program, so I'll leave it to you to add the waits. I'd actually change the names of value and value2, but that's just me. Also, I'm only addressing the forking issue here so there may be other problems with your code (which I kind of suspect since you have two pipes).
EDIT 2:
Another issue that I see is that you're not closing the ends of the pipes that you don't use. If you never close the write end of a pipe, your reads will block until the pipe has data (or there are no more writers to the pipe, that is, the write end is not open). This means that the write end of the pipe should be closed in all processes when you are not using it or are finished with it.
Related
I've been stuck on an issue with my program and just hoping for any help at this point :(
or guidance towards the right direction. In my code, I'm implenting a mini shell in c++ where the user can pipe 2 or more processes together, yet an issue keeps coming up whenever I execute it. Only the first and last commands actually execute so say I run:
cat b.txt | sort | tail -2
only cat b.txt and tail -2 would execute.
Here is my attempt at the whole program, also referenced to this which helped me tremendously with the setup.
#include <sys/types.h>
#include <sys/wait.h>
#include <stdio.h>
#include <string.h>
#include <iostream>
#include <sstream>
#include <stdlib.h>
#include <sys/utsname.h>
#include <unistd.h>
using namespace std;
//this variable will take in the line of input submitted by the user
char buf[1024];
//PIDs for the two child processes
pid_t pid[300];
//these will be use to check the status of each child in the parent process
int status;
int status2;
int pid_num = 1;
//initializes the pipe
int pipeA[2] = {-1,-1};
int g = 0;
void first_command(int pipeA[], char * command[], bool pipeExists){
if(pipeExists){
dup2(pipeA[1], 1);
close(pipeA[0]);
}
// this will run command[0] as the file to execute, and command as the arg
execvp(command[0], command);
printf("Can not execute FIRST command, please enter a valid command \n");
exit(127);
}
void other_command(int pipeA[], char * command0[], int index){
dup2(pipeA[0], 0);
close(pipeA[1]);
execvp(command0[0], command0);
printf("Can not execute SECOND command, please enter a valid command\n");
exit(127);
}
void main_func() {
//stay inside the loop and keep asking the user for input until the user quits the program
while (fgets(buf,1024,stdin) != NULL){
//initialize a boolean to check if user wants to pipe something, set to false by default until we check with user
bool pipeExists = false;
//initialize this arrays to NULL so anything that store in them gets cleared out.
//these arrays will hold the commands that the user wants to carry out.
char * command[1024] = {NULL, NULL, NULL};
char *command0[1024] = {NULL, NULL, NULL};
char *command1[] = {NULL, NULL, NULL};
char *command2[] = {NULL, NULL, NULL};
char *command3[] = {NULL, NULL, NULL};
char ** my_commands[] = {
command0,
command1,
command2,
command3,
NULL
};
//Important to delete mark the last byte as 0 in our input
buf[strlen(buf) -1] = 0;
//initialize this number to zero to start save the tokens at this index
int index = 0;
//a char * to hold the token saved by strtok
char * ptr;
ptr = strtok(buf, " \"");
//Loop through 'buf' and save tokens accordingly
while(ptr != NULL){
// if the user types exit at any moment, the program will exit gracefully and terminate
if(strcmp( ptr, "exit" ) == 0){
exit(0);
}
//if ptr is equal to | user wants to pipe something and we change pipeExists to true
if(strcmp( ptr, "|" ) == 0){
pipeExists = true;
index= 0;
ptr = strtok(NULL, " ");
}
//enter here while user doesnt want to user pipes
if(!pipeExists){
command[index] = ptr;
ptr = strtok(NULL, " ");
index++;
}
//enter here if user want to use pipes
if(pipeExists){
command0[index] = ptr;
ptr = strtok(NULL, " ");
index++;
}
g++;
printf("%s %i\n", ptr, g);
}
for (int s = 0; my_commands[s] != NULL; s++) {
cout << command0[s] << " \n" << endl;
}
//if pipes exists then initialize it
if(pipeExists){
pipe(pipeA);
}
//create first child
if ((pid[0] = fork()) == 0) {
//pass in the pipe, commands and pipe to function to execute
first_command(pipeA, command, pipeExists);
}
else if(pid[0] < 0){
//error with child
cerr<<"error forking first child"<<endl;
}
// if pipe exists create a second process to execute the second part of the command
if(pipeExists){
for(int f = 0; my_commands[f] != NULL; f++) {
//create second child
if ((pid[f] = fork()) == 0) {
other_command(pipeA, command0, index);
}
else if(pid[f] < 0){
//error with second child
cerr<<"error forking child "<< pid_num << endl;
}
}
pid_num++;
}
//if the pipe was created then we close its ends
if(pipeExists){
for(int z = 0; z < pid_num; z++) {
close(pipeA[z]);
}
}
//wait for the first child that ALWAYS executes
if ( (pid[0] = waitpid(pid[0], &status, 0)) < 0)
cerr<<"error waiting for first child"<<endl;
//wait for the second child but only if user wanted to created to use piping
if(pipeExists){
for(int j = 1; j < pid_num; j++) {
if ( (pid[j] = waitpid(pid[j], &status2, 0)) < 0){
printf("Status: %d", pid[j]);
cerr<<"error waiting for child " << j <<endl;
}
}
}
pid_num = 1;
}//endwhile
}
After running my program for the first time around it runs correctly but the loop does not continue.
I have tried adding more forks into my function but it seems to not work.
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <sys/types.h>
#include <sys/wait.h>
using namespace std;
int main(){
int pipefd[2];
int rs;
pid_t cpid;
char* args1[256];
char* args2[256];
char cmd1[256];
char cmd2[256];
char path1[10];
char path2[10];
//starts while loop
while(true){
//creates pipe
rs = pipe(pipefd);
if (rs < 0){
perror("pipe");
exit(1);
}
//gets comands from user
cout << "Command 1";
cin.getline(cmd1,256);
cout << "command 2";
cin.getline(cmd2,256);
//checks id with commands are quit
if (strcmp(cmd1,"quit") == 0)
break;
if (strcmp(cmd2,"quit") == 0)
break;
char *token;
token = strtok(cmd1," ");
int i=0;
//splits char arrays up
while(token != NULL){
args1[i] = token;
token = strtok(NULL, " ");
i++;
}
args1[i] = NULL;
token = strtok(cmd2," ");
i = 0;
while(token != NULL){
args2[i] = token;
token = strtok(NULL, " ");
i++;
}
args2[i] = NULL;
strcpy(path1,args1[0]);//copis the command to the path file
strcpy(path2,args2[0]);
//forks and creates child process
rs = fork();
if (rs == 0){//child process
close(pipefd[1]);//close write end of pipe
close(0);//close standard input
dup(pipefd[0]);//duplicate read end of pipe into standard
input
close(pipefd[0]);//close read end of pipe
rs = execvp(path2,args2);//runs program 2
if (rs < 0){
perror("execl");
exit(1);
}
}
else{//PARENT PROCESS
close(pipefd[0]);//close read end of pipe
close(1);//close standard input
dup(pipefd[1]);//duplicate write end of pipe into standard
input
close(pipefd[1]);//clsoe write end of pipe
rs = execvp(path1,args1);//runs command 1
if (rs < 0){
perror("execl");
exit(1);
}
}
}
return 0;
}
After going through the loop the first time the user should be asked for enter in two more commands or be able to quit out of the function
rs = execvp(path1,args1);//runs command 1
This line in the "parent process" replaces the current program. There is no while loop after this succeeds anymore, only program 1.
Think of it this way. When user inputs m pairs of commands to your program, how many processes do you expect to be spawned? You expect a total of 2m processes each corresponding to a command but you only fork m times each corresponding to an iterations of the while loop in your current code.
You should instead fork a different process for program 1 as well, similar to how you did it for program 2.
I am trying to pipe data from one child process to another. When I run this, it hangs. If I don't make it wait for the first child process, it goes back to the top of the loop prompting for commands without giving the expected output, and when I prompt it to quit, it dumps all of the output I was expecting. I had it working with just one child process, but then the second execvp killed the parent process, and I didn't get back to the top of the loop prompting for more commands.
#include <iostream>
#include <unistd.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <string.h>
#include <sys/wait.h>
using namespace std;
int main(int argc, const char * argv[]) {
bool quit=0;
char quitArray[] = "quit";
int pipeReturnValue, fork1ReturnValue, fork2ReturnValue, pipefd[2], checkForQuit;
//Enter a loop where each iteration prompts for two single-line inputs
while (!quit) {
//Get command 1
char command1[128];
printf("Enter command 1: ");
fgets(command1,128,stdin);
command1[strlen(command1) -1] = 0;
//Exit if user enters quit
checkForQuit = strncmp(command1, quitArray, 4);
if (checkForQuit == 0) {
exit(0);
}
//Get command 2
char command2[128];
printf("Enter command 2: ");
fgets(command2,128,stdin);
command2[strlen(command2) -1] = 0;
//Exit if user enters quit
checkForQuit = strncmp(command2, quitArray, 4);
if (checkForQuit == 0) {
exit(0);
}
//Open pipe
pipeReturnValue = pipe(pipefd);
if (pipeReturnValue < 0) {
perror("Pipe failed");
exit(1);
}
//Fork 1
fork1ReturnValue = fork();
if(fork1ReturnValue < 0) {
perror("Fork failed");
exit(1);
}
else if (fork1ReturnValue == 0) {
//Fork 2
fork2ReturnValue = fork();
if (fork2ReturnValue < 0) {
perror("Fork 2 failed");
}
else if (fork2ReturnValue == 0) {
//close read end of pipe
close(pipefd[0]);
//parse command 1 arguments
//store tokens in array
char *arguments[6] = {};
arguments[0] = strtok(command1, " ");
int tokenCounter = 0;
while (arguments[tokenCounter] != NULL) {
tokenCounter++;
arguments[tokenCounter] = strtok(NULL, " ");
}
//dup stdo to pipe
dup2(pipefd[1], 1);
//execute arguments
execvp(arguments[0], arguments);
}
else {
wait(&fork2ReturnValue);
//close write end of pipe
close(pipefd[1]);
//parse command 2 arguments
//store tokens in array
char *arguments[6] = {};
arguments[0] = strtok(command2, " ");
int tokenCounter = 0;
while (arguments[tokenCounter] != NULL) {
tokenCounter++;
arguments[tokenCounter] = strtok(NULL, " ");
}
//dup stdin to pipe
dup2(pipefd[0], 0);
//exec
execvp(arguments[0], arguments);
}
}
else {
wait(&fork1ReturnValue);
}
}
return 0;
}
I finally figured it out. I needed to open the pipe after the first fork rather than before.
#include <iostream>
#include <unistd.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <string.h>
#include <sys/wait.h>
using namespace std;
int main(int argc, const char * argv[]) {
bool quit=0;
char command1[128],
command2[128],
quitArray[] = "quit";
int pipeReturnValue,
fork1ReturnValue,
fork2ReturnValue,
checkForQuit,
pipefd[2];
//Loop where each iteration prompts for two single-line inputs
while (!quit) {
//Get command 1
printf("Enter command 1: ");
fgets(command1,128,stdin);
command1[strlen(command1) -1] = 0;
//Exit if user enters quit
checkForQuit = strncmp(command1, quitArray, 4);
if (checkForQuit == 0) {
quit = 1;
exit(0);
}
//Get command 2 and trim trailing new line character
printf("Enter command 2: ");
fgets(command2,128,stdin);
command2[strlen(command2) -1] = 0;
//Exit if user enters quit
checkForQuit = strncmp(command2, quitArray, 4);
if (checkForQuit == 0) {
quit = 1;
exit(0);
}
//Fork to create 1st child process, return error if fork fails
fork1ReturnValue = fork();
if(fork1ReturnValue < 0) {
perror("Fork 1 failed");
exit(1);
}
//Open pipe, return error if fork fails
pipeReturnValue = pipe(pipefd);
if (pipeReturnValue < 0) {
perror("Pipe failed");
exit(1);
}
//First child process
else if (fork1ReturnValue == 0) {
//Fork to create 2nd child process, return error if fork fails
fork2ReturnValue = fork();
if (fork2ReturnValue < 0) {
perror("Fork 2 failed");
}
//Second child process
else if (fork2ReturnValue == 0) {
//close read end of pipe
close(pipefd[0]);
//Parse command 1 arguments, store tokens in an array
char *arguments[6] = {};
arguments[0] = strtok(command1, " ");
int tokenCounter = 0;
while (arguments[tokenCounter] != NULL) {
tokenCounter++;
arguments[tokenCounter] = strtok(NULL, " ");
}
//Dup standard output to write side of pipe
dup2(pipefd[1], 1);
//Execute arguments from command 1
execvp(arguments[0], arguments);
}
//First child code continued
else {
//Wait for child 2 to to terminate
wait(&fork2ReturnValue);
//Close write end of pipe
close(pipefd[1]);
//Parse command 2 arguments, store tokens in array
char *arguments[6] = {};
arguments[0] = strtok(command2, " ");
int tokenCounter = 0;
while (arguments[tokenCounter] != NULL) {
tokenCounter++;
arguments[tokenCounter] = strtok(NULL, " ");
}
//dup standard input to read side of pipe
dup2(pipefd[0], 0);
//Execute arguments from command 2
execvp(arguments[0], arguments);
}
}
//Parent process continued
else {
//Wait for child 1 to terminate
wait(&fork1ReturnValue);
}
//return to top of loop
}
return 0;
}
I have been working on this project for a while. The purpose is to make a functioning shell that can do pretty much all the shell commands (except cd). It does almost everything I want it to do, except for a couple things. The first is that when I put an '&' to signify background processing, it does it, but then doesn't print another myshell> line. I can still input something, but the myshell> never shows up, no matter where I put another cout<<"myshell> ";.
Another issue is if I press enter, making myString empty, many times, it crashes the program with a seg fault. Also after I do the '&' background processing and press enter to get the myshell> to come back up, it prints one myshell> but then seg faults on the next hit of enter. I'm sorry if I didn't explain this well, but it is really driving me crazy. Please let me know if you have any suggestions.
#include <stdio.h>
#include <iostream>
#include <unistd.h>
#include <cstdlib>
#include <cstring>
#include <sys/types.h>
#include <cstdio>
#include <sys/wait.h>
#include <stdio.h>
/*Function that parses the command the user inputs.
It takes myArgv and myString as inputs.
It returns the value of exitcond, which is used to see if the user wants to exit or not.
Also, this is where myString is tokenized using strok()*/
int parseCommand(char *myArgv[10], char myString[255])
{
int exitcond=0;
if((strcmp(myArgv[0], "exit") == 0)||(strcmp(myArgv[0], "quit")==0))
{
exitcond = 1;
return exitcond;
}
int i;
char *token;
token = strtok(myString," ");
i=0;
while (token != NULL)
{
myArgv[i] = token;
token = strtok(NULL," ");
i++;
}
/*
* Set the last entry our new argv to a null char
* (see man execvp to understand why).
*/
myArgv[i] = '\0';
return exitcond;
}
/*Function that gets the command from the user and sees if they want
background processing or not (presence of '&').
It takes inputs of choose and myString. choose is the variable for
whether background processing is necessary or not, while myString is
an empty character array.
It outputs the value of the choose variable for lter use.*/
int getCommand(int choose, char myString[255])
{
int i;
choose=0;
fgets(myString, 256, stdin);
if (myString[0]=='\0')
{
choose=0;
return choose;
}
for (i=0; myString[i]; i++)
{
if (myString[i]== '&')
{
choose=1;
myString[i]=' ';
}
if (myString[i] == '\n')
{
myString[i] = '\0';
}
}
return choose;
}
/*Main function where all the calling of other functions and processes
is done. This is where the user enters and exits the shell also. All
usage of fork, pid, waitpid and execvp is done here.*/
int main()
{
using namespace std;
int exitCondition=0, i=0, status;
char myString[255];
char *token, *myArgv[10];
pid_t pid, waiting;
int bg=0;
while (!exitCondition)
{
/* print a prompt and allow the user to enter a stream of characters */
cout << "myshell> ";
bg=0;
int choose=0;
bg=getCommand(choose,myString);
exitCondition=parseCommand(myArgv,myString);
if(exitCondition==1)
{
cout<<"Thank you for using my shell.\n";
}
else {
/* while (myString[0]=='\0')
{
cout<<"myshell> ";
bg=getCommand(choose,myString);
}*/
/* The user has a command, so spawn it in a child process */
pid = fork();
if (pid == -1)
{
/* to understand why this is here, see man 2 fork */
cout << "A problem arose, the shell failed to spawn a child process" << endl;
return(1);
}
else if (pid == 0)
{
// Child process
execvp(myArgv[0],myArgv);
cout << "Bad command or file name, please try again!\n" << endl;
return 0;
} else {
/* This makes sure that the spawned process is run in the foreground,
because the user did not choose background */
if(bg==0)
{
waitpid(pid,NULL,0);
}
}
}
}
return 0;
}
Okay, you had three bugs, one of which caused the segfault. Of the others, one would put a garbage argument in the array passed to execvp and the other would leak zombie processes for background jobs.
I've corrected the code and annotated it with where the bugs were along with the fixes [please pardon the gratuitous style cleanup]:
#include <cstdio>
#include <iostream>
#include <sys/types.h>
#include <sys/wait.h>
#include <stdio.h>
#include <string.h>
#include <unistd.h>
#define AVCOUNT 100
#define STRBUFLEN 2000
/*Function that parses the command the user inputs.
It takes myArgv and myString as inputs.
It returns the value of exitcond, which is used to see if the user wants to
exit or not.
Also, this is where myString is tokenized using strok()*/
int
parseCommand(char **myArgv, char *myString)
{
char *token;
char *bp;
int exitcond = 0;
int i;
// NOTE/BUG: original check for exit/quit was here -- at this point
// myArgv is undefined (hence the segfault)
// NOTE/BUG: your original loop -- at the end i was one beyond where it
// should have been so that when myArgv gets passed to execvp it would
// have an undefined value at the end
#if 0
token = strtok(myString, " ");
i = 0;
while (token != NULL) {
myArgv[i] = token;
token = strtok(NULL, " ");
i++;
}
#endif
// NOTE/BUGFIX: here is the corrected loop
i = 0;
bp = myString;
while (1) {
token = strtok(bp, " ");
bp = NULL;
if (token == NULL)
break;
myArgv[i++] = token;
}
/*
* Set the last entry our new argv to a null pointer
* (see man execvp to understand why).
*/
// NOTE/BUG: with your code, i was one too high here
myArgv[i] = NULL;
// NOTE/BUGFIX: moved exit/quit check to here now that myArgv is valid
token = myArgv[0];
if (token != NULL) {
if ((strcmp(token, "exit") == 0) || (strcmp(token, "quit") == 0))
exitcond = 1;
}
return exitcond;
}
/*Function that gets the command from the user and sees if they want
background processing or not (presence of '&').
It takes inputs of choose and myString. choose is the variable for
whether background processing is necessary or not, while myString is
an empty character array.
It outputs the value of the choose variable for lter use.*/
int
getCommand(int choose, char *myString)
{
int i;
choose = 0;
fgets(myString, STRBUFLEN, stdin);
if (myString[0] == '\0') {
choose = 0;
return choose;
}
for (i = 0; myString[i]; i++) {
if (myString[i] == '&') {
choose = 1;
myString[i] = ' ';
}
if (myString[i] == '\n') {
myString[i] = '\0';
break;
}
}
return choose;
}
/*Main function where all the calling of other functions and processes
is done. This is where the user enters and exits the shell also. All
usage of fork, pid, waitpid and execvp is done here.*/
int
main()
{
using namespace std;
int exitCondition = 0;
int status;
char myString[STRBUFLEN];
char *myArgv[AVCOUNT];
pid_t pid;
int bg = 0;
while (!exitCondition) {
// NOTE/BUGFIX: without this, any background process that completed
// would become a zombie because it was never waited for [again]
// reap any finished background jobs
while (1) {
pid = waitpid(0,&status,WNOHANG);
if (pid < 0)
break;
}
/* print a prompt and allow the user to enter a stream of characters */
cout << "myshell> ";
bg = 0;
int choose = 0;
bg = getCommand(choose, myString);
exitCondition = parseCommand(myArgv, myString);
if (exitCondition == 1) {
cout << "Thank you for using my shell.\n";
break;
}
/* while (myString[0]=='\0') { cout<<"myshell> "; bg=getCommand(choose,myString); } */
/* The user has a command, so spawn it in a child process */
pid = fork();
if (pid == -1) {
/* to understand why this is here, see man 2 fork */
cout << "A problem arose, the shell failed to spawn a child process" << endl;
return 1;
}
if (pid == 0) {
// Child process
execvp(myArgv[0], myArgv);
cout << "Bad command or file name, please try again!\n" << endl;
return 1;
}
/* This makes sure that the spawned process is run in the
foreground, because the user did not choose background */
if (bg == 0)
waitpid(pid, &status, 0);
}
return 0;
}
I want to print an array of characters, these characters are underscores first.
Then the user can write characters on these underscores.I used gotoxy() but it doesn't work properly.
That is what i wrote:
int main(void)
{
char arr[20];
int i;
char ch;
clrscr();
for(i=0;i<=20;i++)
{
textattr(0x07);
cprintf("_");
}
do
{
for(i=0;i<=20;i++)
{
//gotoxy(i,0);
//ch = getche();
if( isprint(ch) == 1)
{
arr[i] = ch;
gotoxy(i,0);
//printf("%c",ch);
}
}
} while(i == 20);
getch();
return 0;
}
The first thing is this: You probably don't want to have all those calls to gotoxy, textattr and cprintf in your main function, since that is not what the main function is supposed to do.
It is much more likely that the main function's purpose is "to read some text from the user, presented nicely in an input field". So you should make this a function:
static int
nice_input_field(char *buf, size_t bufsize, int x, int y) {
int i, ch;
gotoxy(x, y);
for (i = 0; i < bufsize - 1; i++) {
cprintf("_");
}
i = 0;
gotoxy(x, y);
while ((ch = readkey()) != EOF) {
switch (ch) {
case '...': /* ... */
break;
case '\b': /* backspace */
cprintf("_");
i--;
gotoxy(x + i, y);
break;
case '\t': /* tabulator */
case '\n': /* enter, return */
buf[i] = '\0';
return 0; /* ok */
default: /* some hopefully printable character */
if (i == bufsize - 1) {
cprintf("\a"); /* beep */
} else {
buf[i++] = ch;
gotoxy(x + i, y);
cprintf("%c", buf[i]);
}
}
}
/* TODO: null-terminate the buffer */
return 0;
}
Printing an array of characters is fairly easy:
char* str = your_array;
while(*str) {
putc(*str++);
}
From memory that should print a string out to the screen.
Your code is very DOS-specific. There is not a good general solution to the problem of reading immediate input in a portable way. It does get asked quite often, so I think the C FAQ broke down and included an answer which you might want to seek out.
That said, I think your bug is that gotoxy(1, 1) is the upper corner of the screen, not 0,0. So you want gotoxy(i, 1)