Doctrine findBy with OR condition - doctrine-orm

Question

Is it possible to use OR statement in Doctrine findBy() method?
I know that given array is interpreted as case1 AND case2...
Like this
$this->repos['notif']->findBy(array('status' => 1, 'status' => 2, 'status' => 3);
Stands for
SELECT * FROM `notif` WHERE status=1 AND status=2 AND status=3;
Now I need something to stand for:
SELECT * FROM `notif` WHERE status=1 OR status=2 OR status=3;
Is there a way to get all cases?

Answer 1

You can write:
$this->repos['notif']->findBy(array('status' => array(1, 2, 3)));
and that should work too.

Answer 2

I know that this is old question. Anyways, it's possible to use Criteria for the complex queries (in Doctrine 2 at least):
$criteria = new \Doctrine\Common\Collections\Criteria();
$criteria
->orWhere($criteria->expr()->contains('domains', 'a'))
->orWhere($criteria->expr()->contains('domains', 'b'));
$groups = $em
->getRepository('Group')
->matching($criteria);

Answer 3

As far as I know this is not a supported feature by Doctrine to use IN() queries with findby. You could do two things:
Implement a findByStatus(array $statusTypes) method in your (custom) 'notif' repository class. If you like this approach I can give you a example.
Convert your findBy to the following:
$qb = $this->repos['notif']->createQueryBuilder('n');
$data = $qb->where($qb->expr()->in('status', array(1,2,3)))->getQuery()->getResult();
That should work either :)

Answer 4

If you are using MongoDB and need more complex queries, like "less than" linked together with OR, but cannot use a query builder, this also works with this syntax:
->findBy(array(
'$or' => array(
array('foo' => array('$lt' => 1234)),
array('$and' => array(
array('bar' => 45678),
array('baz' => array('$lt' => 89013))
))
)
));
Or as a solution for your question:
->findBy(array(
'$or' => array(
array('status' => 1),
array('status' => 2),
array('status' => 3),
)
));