I’m using Umbraco 4.7.0
My goal is to get the image path from a hard coded media node id of 4191. If I create a new macro with the code:
<xsl:copy-of select="umbraco.library:GetMedia(4191, false())"/>
I get the output:
/media/17675/my image.jpg50033618497jpg
I was expecting some well formed xml, however, it appears I’m missing all the tags. I therefore cannot reference the path for the image directly.
Am I missing something really simple here?
EDIT
I discovered how to get the raw xml output from my copy-of statement. I needed to wrap it in a <textarea> tag:
<textarea>
<xsl:copy-of select="umbraco.library:GetMedia(4191, false())"/>
</textarea>
This should do it:
<xsl:copy-of select="umbraco.library:GetMedia(4191, 0)/umbracoFile"/>
See also http://our.umbraco.org/wiki/reference/umbracolibrary/getmedia
Related
I have several html files starting with a title and the author name, but I don't want them in the table of content. I used remove toc from toc in wkhtmltopdf to hard code the value of the h1/h2 to remove but I would like the xlst toc file to be independent of the name of the document and the author.
So I gave these specific titles a class attribute. The problem lies in the xlst filter, I didn't find a way to test or extract the class attribute.
Here is a part of the html file :
<h1 class="title">Me</h1>
<h2 class="author">My Title</h2>
Here is the xslt toc file part :
<xsl:template match="outline:item">
<li>
<xsl:if test="(#title!='') and (#title!='My little TOC')and (#class!='author')and (#class!='title')">
I'm a total newbie to xslt and don't know what outline:item really is, but it seems that it doesn't get the original class attribute. How could I get the job done ?
One simple solution is to use div tags instead of headings. In your CSS, make sure you specify display: block;.
if you run the
--dump-outline toc.xml
flag when you generate the pdf and look at the xml file you will see the xml nodes and attributes.
You can then test for either the title, page number, link and backlink the document. You can use these attributes for your if statment.
For example:
<xsl:if test="((#page!=1) and (#page!=2) and (#page!=5))">
blah blah blah
</xsl:if>
Note the brackets around the full test.
You can even then nest the if statements further if needed:
<xsl:if test="((#page!=1) and (#page!=2) and (#page!=5))">
<xsl:if test="(#title!='A title')">
more code
</xsl:if>
</xsl:if>
I've an XML of below format.
<book:para>
<book:page num="228"/>
<book:page num="229"/>
Other data
</book:para>
Here I want to apply-templates to immediate page nodes before the text. I'm currently using the below XSLT for doing this task. This matches only one direct page before text.
<xsl:apply-templates select="./node()[1][self::book:page]" mode="first"/>
Please let me know how can I do it for more than one page.
Thanks
I'm trying to write some XSLT which basically should go through the following algorithm:
if child of current node is of type Accordion
if child of Accordion node is of type AccordionItem
take the AccordionItem's title and content and display in <div> tags
end if
end if
It seems pretty straight forward, but the code I currently have doesn't appear to be working as it should. I must be missing something, but I can't figure out exactly what. Here's my XSLT code so far:
<xsl:for-each select="$currentPage/ancestor-or-self::Home//AccordionItem[#isDoc]">
<div id="accordion">
<h3><a href='#'><xsl:value-of select="accordionItemTitle"/></a></h3>
<div><xsl:value-of select="accordionItemContent" disable-output-escaping="yes" />
</div>
</div>
</xsl:for-each>
Can anyone offer any suggestions as to why this wouldn't be working correctly? Thanks in advanced!
It seems that your XPath isn't quite behaving as you've defined in your algorithm and is navigating to the node of type Home, is that intended?
If not, try modifying the XPath to the following:
<xsl:for-each select="$currentPage/Accordion/AccordionItem[#isDoc]">
Lets say I have the following code snippet below, how do I also apply the disable-output-escaping to the {name} in the title attribute?
<a title="{name}"><xsl:value-of select="name" disable-output-escaping="yes" /></a>
This has really got me stumped.
Thanks guys.
This cannot be done with XSLT. The spec says:
It is an error for output escaping to
be disabled for a text node that is
used for something other than a text
node in the result tree.
Thus it makes no difference if you use Attribute Value Templates or xsl:attribute with xsl:value-of, because you're generating an attribute node, not a text node. It's a limitation in the language.
You can't as is. The {name} shortcut doesn't allow additional parameters. Use the <xsl:attribute> tag instead.
How can print a page using xslt.
i need a link, or a button which when clicked invokes the print page printer dialog box.
I suspect you need to specify a bit more about what you are trying to do.
XSLT is simply a way to turn one block of text into another. The input is generally an xml buffer and the output is some text rendering of that buffer.
It is possible that you are trying to generate a script using XSLT and that you want that script to be able to open a print dialog when it is run by something e.g. you generate javascript, that then runs on a browser.
Can you describe in more detail what you want to achieve?
The following in an html page gives you a print link:
Print
XSLT is a language for transforming XML documents. That means you can add/modify content. Assuming your output is HTML, you can do this:
<xsl:template match="top">
<html>
<head>
</head>
<body>
<input name="print" type="button" value="Print"
onclick="javascript:window.print()">
<xsl:apply-templates />
</body>
</html>
</xsl:template>
But of course, where exactly the button has to go depends on your needs. I'd additionally, add a media=print specific CSS at the top so that the document comes out neat!