Parsing the following with the php xlst processor result in this error:
`Warning: DOMDocument::load(): Namespace prefix g on id is not defined in /var/www /mistermatic/spider/resources/xslt/car/google.xsl, line: 32 in /var/www/mistermatic/ads/PublicXML/makeXML.php on line 91`
How do I correctly define the namespace inside the rss node so that I can apply it to all the children I'm gonna manipulate?
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:strip-space elements="*"/>
<xsl:output method="xml" version="1.0" encoding="UTF-8" omit-xml-declaration="no" indent="yes"/>
<xsl:template match="/">
<rss xmlns:g="http://base.google.com/ns/1.0" version="2.0">
<channel>
<title>Mistermatic</title>
<link>http://www.mistermatic.it</link>
<description>Multipubblicazione di annunci di automobili nuove ed usate</description>
<xsl:for-each select="//ad">
<item xmlns:g="http://base.google.com/ns/1.0" version="2.0">
<xsl:apply-templates select="itemId"/>
<g:availability>in stock</g:availability>
<g:google_product_category><![CDATA[Veicoli a motore > Veicoli > Auto, autocarri e furgoni]]></g:google_product_category>
</item>
</xsl:for-each>
</channel>
</rss>
</xsl:template>
<xsl:template match="itemId">
<g:id>
<xsl:text disable-output-escaping="yes"><![CDATA[</xsl:text>
<xsl:value-of select="#value"/>
<xsl:text disable-output-escaping="yes">]]></xsl:text>
</g:id>
</xsl:template>
</xsl:stylesheet>
Move the xmlns:g declaration up to the xsl:stylesheet element, making it visible throughout the stylesheet.
The problem is you are defining the namespace within your rss element, however, it is used elsewhere in your XSLT file. Try moving your namespace definition to the root of your XSLT document.
Related
i have the following xml and xslt to render it, but got no results. I checked again and again and see not path problem, and the xsl went through the compiler. so I am not sure if it's namespace problem or something else. many thx!
XML file
<?xml version="1.0" encoding="UTF-8"?>
<bibdataset xsi:schemaLocation="http://www.elsevier.com/xml/ani/ani http://www.elsevier.com/xml/ani/embase_com.xsd"
xmlns="http://www.elsevier.com/xml/ani/ani"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:ce="http://www.elsevier.com/xml/ani/common"
xmlns:ait="http://www.elsevier.com/xml/ani/ait">
<item>
<bibrecord>
<item-info>
<itemidlist><ce:doi>10.1258/0268355042555000</ce:doi>
</itemidlist>
</item-info>
<head>
<citation-title>
<titletext xml:lang="en" original="y">Effect of seasonal variations on the emergence of deep venous thrombosis of the lower extremity
</titletext>
</citation-title>
<abstracts>
<abstract xml:lang="en" original="y">
<ce:para>Objective: We aimed to determine the role of seasonal and meteorological variations in the incidence of lower extremity
</ce:para>
</abstract>
</abstracts>
</head>
</bibrecord>
</item>
</bibdataset>
XSLT file
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="http://www.elsevier.com/xml/ani/ani"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:ce="http://www.elsevier.com/xml/ani/common"
xmlns:ait="http://www.elsevier.com/xml/ani/ait">
<xsl:output indent="yes" omit-xml-declaration="no"
media-type="application/xml" encoding="UTF-8" />
<xsl:template match="/">
<searchresult>
<xsl:apply-templates
select="/bibdataset/item/bibrecord" />
</searchresult>
</xsl:template>
<xsl:template match="bibrecord">
<document>
<title><xsl:value-of select="head/citation-title/titletext" /></title>
<snippet>
<xsl:value-of select="head/abstracts/abstract/ce:para" />
</snippet>
<url>
<xsl:variable name="doilink" select="item-info/itemidlist/ce:doi"/>
<xsl:value-of
select="concat('http://dx.doi.org/', $doilink)" />
</url>
</document>
</xsl:template>
</xsl:stylesheet>
This is indeed an issue with namespaces. In your XML, you have declared a default namespace meaning the root element, and all its descendants, and in this namespace.
<bibdataset .xmlns="http://www.elsevier.com/xml/ani/ani" ...
Now, in your XSLT, you have also declared this namespace, but without a prefix.
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="http://www.elsevier.com/xml/ani/ani"
This means it only applies to the elements you are outputting, so your searchresult element gets output in this namespace
<searchresult xmlns="http://www.elsevier.com/xml/ani/ani"
However, it doesn't apply to the xpath expression in your XSLT, and so these are looking for elements in your input XML with no namespace.
In XSLT 2.0 the solution would be to simply declare an "xpath-default-namespace"
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="http://www.elsevier.com/xml/ani/ani"
xpath-default-namespace="http://www.elsevier.com/xml/ani/ani" ...
In XSLT 1.0, you will have to declare the namespace with a prefix, and use this prefix in all the xpath expressions.
Try this XSLT
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="http://www.elsevier.com/xml/ani/ani"
xmlns:ani="http://www.elsevier.com/xml/ani/ani"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:ce="http://www.elsevier.com/xml/ani/common"
xmlns:ait="http://www.elsevier.com/xml/ani/ait"
exclude-result-prefixes="ani">
<xsl:output indent="yes" omit-xml-declaration="no"
media-type="application/xml" encoding="UTF-8" />
<xsl:template match="/">
<searchresult>
<xsl:apply-templates
select="/ani:bibdataset/ani:item/ani:bibrecord" />
</searchresult>
</xsl:template>
<xsl:template match="ani:bibrecord">
<document>
<title><xsl:value-of select="ani:head/ani:citation-title/ani:titletext" /></title>
<snippet>
<xsl:value-of select="ani:head/ani:abstracts/ani:abstract/ce:para" />
</snippet>
<url>
<xsl:variable name="doilink" select="ani:item-info/ani:itemidlist/ce:doi"/>
<xsl:value-of
select="concat('http://dx.doi.org/', $doilink)" />
</url>
</document>
</xsl:template>
</xsl:stylesheet>
Note that you can remove the line xmlns="http://www.elsevier.com/xml/ani/ani" but that would mean your searchresult (and other) elements would be output with no namespace, so you would need to output it as <ani:searchresult> if you wanted it in the given namespace.
My XSLT is outputiung some tags with xmlns:x="http://something" attribute... How to avoid this redundant attribute? The output XML never use, neither in a the x:tag, nor in an x:attribute.
EXAMPLE OF XML:
<root><p>Hello</p><p>world</p></root>
EXAMPLE OF XSL:
<xsl:transform version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xlink="http://www.w3.org/1999/xlink">
<xsl:output encoding="UTF-8" method="xml" version="1.0" indent="no"/>
<xsl:template match="root"><foo>
<xsl:for-each select="p">
<p><xsl:value-of select="." /></p>
</xsl:for-each></foo>
<xsl:for-each select="x">
<link xlink:href="{x}" />
</xsl:for-each></foo>
</xsl:template>
EXAMPLE OF XML OUTPUT:
<foo>
<p xmlns:xlink="http://www.w3.org/1999/xlink">Hello</p>
<p xmlns:xlink="http://www.w3.org/1999/xlink">world</p>
</foo>
The xmlns:xlink is a overhead, it is not used!
A typical case where XSLT must use namespace but the output not:
<xsl:value-of select="php:function('regFunction', . )" />
As Dimitre has already said, if you are not using the xlink namespace anywhere in your XSLT, you should just remove its namespace declaration. If, however, your XSLT is actually using it somewhere that you haven't shown us, you can prevent it from being output by using the exclude-result-prefixes attribute:
<xsl:transform version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xlink="http://www.w3.org/1999/xlink"
exclude-result-prefixes="xlink">
Just remove this namespace declaration from the xsl:stylesheet instruction -- it isn't used (and thus necessary) at all:
xmlns:xlink="http://www.w3.org/1999/xlink"
The whole transformation now becomes:
<xsl:transform version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output encoding="UTF-8" method="xml" version="1.0" indent="no"/>
<xsl:template match="root"><foo>
<xsl:for-each select="p">
<p class="a"><xsl:value-of select="." /></p>
</xsl:for-each></foo>
</xsl:template>
</xsl:transform>
and when applied on the provided XML document:
<root><p>Hello</p><p>world</p></root>
produces result that is free of namespaces:
<foo>
<p class="a">Hello</p>
<p class="a">world</p>
</foo>
I want to convert the following source xml structure to the target xml structure using xslt transformation. I am mot able to convert the following source xml to target xml using xslt. Please help us in coneverting this.
Source XML
<XxhrPiEmpcompOutIntCollection>
<XxhrPiEmpcompOutInt>
<employeeNumber>
200000562
</employeeNumber>
<competencyName>
Comp1
</competencyName>
<proficiencyLevel>
Prof1
</proficiencyLevel>
<compDateTo>
16-NOV-12
</compDateTo>
</XxhrPiEmpcompOutInt>
<XxhrPiEmpcompOutInt>
<employeeNumber>
200000562
</employeeNumber>
<competencyName>
Comp2
</competencyName>
<proficiencyLevel>
Prof2
</proficiencyLevel>
<compDateTo>
16-NOV-12
</compDateTo>
</XxhrPiEmpcompOutInt>
</XxhrPiEmpcompOutIntCollection>
Target xml
<EmployeeCompetencyRequest>
<EmployeeNumber>200000562</EmployeeNumber>
<Competencies>
<Competency>
<Name>Comp1</Name>
<ProficiencyLevel>Prof1</ProficiencyLevel>
<EndDate>16-NOV-12</EndDate>
</Competency>
<Competency>
<Name>Comp2</Name>
<ProficiencyLevel>Prof2</ProficiencyLevel>
<EndDate>16-NOV-12</EndDate>
</Competency>
</Competencies>
</<EmployeeCompetencyRequest>
Some hint :
<EmployeeCompetencyRequest>
template match /XxhrPiEmpcompOutIntCollection
for-each-group XxhrPiEmpcompOutInt group by employeeNumber
<EmployeeNumber> value-of current-group-key </EmployeeNumber>
<Competencies>
for-each current-group
<Competency>
value-of name
value-of proficiencyLevel
</competency>
/for-each
</Competencies>
/for-each-group
<EmployeeCompetencyRequest>
Hope you can finish it.
You can group users with for-each-group:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
version="2.0">
<xsl:output indent="yes"/>
<xsl:template match="/">
<EmployeeCompetencyRequest>
<xsl:for-each-group select="//XxhrPiEmpcompOutInt" group-by="employeeNumber">
<Name><xsl:value-of select="current-grouping-key()"/></Name>
<Competencies>
<xsl:for-each select="current-group()">
<Competency>
<Name><xsl:value-of select="competencyName"/></Name>
<ProfiencyLevel><xsl:value-of select="profiencyLevel"/></ProfiencyLevel>
<EndDate><xsl:value-of select="compDateTo"/></EndDate>
</Competency>
</xsl:for-each>
</Competencies>
</xsl:for-each-group>
</EmployeeCompetencyRequest>
</xsl:template>
Salut,
For XSLT 1.0 you must group widht xsl:key:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:key name="groups" match="/XxhrPiEmpcompOutIntCollection/XxhrPiEmpcompOutInt" use="employeeNumber" />
<xsl:template match="/">
<EmployeeCompetencyRequest>
<xsl:apply-templates select="//XxhrPiEmpcompOutInt[generate-id() = generate-id(key('groups', employeeNumber)[1])]"/>
</EmployeeCompetencyRequest>
</xsl:template>
<xsl:template match="XxhrPiEmpcompOutInt">
<Name><xsl:value-of select="employeeNumber"/></Name>
<Competencies>
<xsl:for-each select="key('groups', employeeNumber)">
<Competency>
<Name><xsl:value-of select="competencyName"/></Name>
<ProfiencyLevel><xsl:value-of select="proficiencyLevel"/></ProfiencyLevel>
<EndDate><xsl:value-of select="compDateTo"/></EndDate>
</Competency>
</xsl:for-each>
</Competencies>
</xsl:template>
</xsl:stylesheet>
I can't test it with Oracle ...
I have the following xml:
<RootNode xmlns="http://someurl/path/path/path">
<Child1>
<GrandChild1>Value</GrandChild1>
<!-- Lots more elements in here-->
</Child1>
</RootNode>
I have the following xslt:
<xsl:stylesheet version="1.0" xmlns="http://someurl/path/path/path" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xsl:output method="xml" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<NewRootNode xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<NewChild1>
<xsl:for-each select="RootNode/Child1">
<NewNodeNameHere>
<xsl:value-of select="GrandChild1"/>
</NewNodeNameHere>
<!-- lots of value-of tags in here -->
</xsl:for-each>
</NewChild1>
</NewRootNode >
</xsl:template>
</xsl:stylesheet>
The problem: this is the my result:
<?xml version="1.0" encoding="utf-8"?>
<NewRootNode xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<NewChild1 />
</NewRootNode>
I am expecting to see:
<?xml version="1.0" encoding="utf-8"?>
<NewRootNode xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<NewChild1>
<NewNodeNameHere>Value</NewNodeNameHere>
<!-- Other new elements with values from the xml file -->
</NewChild1>
</NewRootNode>
I am missing of the information inside of NewChild1 that should be there.
I think my for-each select is correct, so the only thing I can think of is that there is a problem with the namespace in the Xml and the namespace in the xslt. Can anybody see what I'm doing wrong?
The problem is caused by the namespaces.
Since the xml defines xmlns="http://someurl/path/path/path", it is not in the default namespace anymore.
You can define that namespace with an name like xmlns:ns="http://someurl/path/path/path" in the xsl, and then use that name in the XPath expression.
The following works for me:
<xsl:stylesheet version="1.0" xmlns:ns="http://someurl/path/path/path" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xsl:output method="xml" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<NewRootNode xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<NewChild1>
<xsl:for-each select="ns:RootNode/ns:Child1">
<NewNodeNameHere>
<xsl:value-of select="ns:GrandChild1"/>
</NewNodeNameHere>
<!-- lots of value-of tags in here -->
</xsl:for-each>
</NewChild1>
</NewRootNode >
</xsl:template>
</xsl:stylesheet>
The stylesheet namespace should be http://www.w3.org/1999/XSL/Transform instead of http://someurl/path/path/path.
Also, since the input XML uses a namespace all your XPath expressions should be namespace-qualified:
<xsl:template match="/" xmlns:ns1="http://someurl/path/path/path">
<NewRootNode xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<NewChild1>
<xsl:for-each select="ns1:RootNode/ns1:Child1">
<NewNodeNameHere>
<xsl:value-of select="ns1:GrandChild1"/>
</NewNodeNameHere>
<!-- lots of value-of tags in here -->
</xsl:for-each>
</NewChild1>
</NewRootNode>
</xsl:template>
I need to copy a subnode from a XML to a certain node of a new XML in a Biztalk Map using XSLT.
Consider the following input XML:
<?xml version="1.0" encoding="UTF-8"?>
<ns0:root xmlns:ns0="http://not/useful/data/">
<ns0:notuseful>
<ns0:foo></ns0:foo>
<ns0:foo2></ns0:foo2>
<ns0:blabla></ns0:blabla>
</ns0:notuseful>
<ns0:data>
<ns1:usefulDataList xmlns:ns1="http://useful/data/">
<ns1:usefulData>
<ns1:usefulChild1></ns1:usefulChild1>
<ns1:usefulChild2></ns1:usefulChild2>
<ns1:usefulChild3></ns1:usefulChild3>
<ns1:usefulChild4></ns1:usefulChild4>
<ns1:usefulChild5></ns1:usefulChild5>
</ns1:usefulData>
</ns1:usefulDataList>
</ns0:data>
<ns0:root>
What I need is to extract the node called "usefulDataList", so I need to copy it in a new XML like this one:
<?xml version="1.0" encoding="UTF-8"?>
<ns2:root2 xmln:ns2="http://new/xml">
<ns2:blabla>
<ns2:stuff />
</ns2:blabla>
<ns2:data>
<ns2:usefulDataList>
<ns2:usefulData>
<ns2:usefulChild1></ns2:usefulChild1>
<ns2:usefulChild2></ns2:usefulChild2>
<ns2:usefulChild3></ns2:usefulChild3>
<ns2:usefulChild4></ns2:usefulChild4>
<ns2:usefulChild5></ns2:usefulChild5>
</ns2:usefulData>
</ns2:usefulDataList>
</ns2:data>
</ns2:root2>
This should be done inside a Biztalk Functoid, as you see namespaces from source and target are diferent.
I'm an absolute beginner with XSLT, and I've been doing some tests, but I've something wrong with my XSLT expressions:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ns2="http://new/xml">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" />
<xsl:template name="testTemplate" match="//*[local-name() = 'usefulDataList ']">
<xsl:element name="ns0:usefulDataList " namespace="">
<xsl:apply-templates mode="copy-no-ns" select="usefulDataList"/>
</xsl:element>
</xsl:template>
<xsl:template mode="copy-no-ns" match="*">
<xsl:element name="{name(.)}" namespace="{namespace-uri(.)}">
<xsl:copy-of select="#*"/>
<xsl:apply-templates mode="copy-no-ns"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
I'd appreciate any tip, with XSLT or Biztalk mapper. I don't like linking a huge amount of fields one by one if I can solve it with a XSLT expression.
Greetings.
Beware you had a space in *[local-name() = 'usefulDataList ']" so that would never match. this works:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ns2="http://new/xml">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" />
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<ns2:root>
<ns2:blabla>
<ns2:stuff />
</ns2:blabla>
<ns2:data>
<xsl:apply-templates mode="copy-no-ns" select="//*[local-name() = 'usefulDataList']"/>
</ns2:data>
</ns2:root>
</xsl:template>
<xsl:template mode="copy-no-ns" match="*">
<xsl:element name="ns2:{local-name(.)}">
<xsl:copy-of select="#*"/>
<xsl:apply-templates mode="copy-no-ns"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>