Copying a bitmap from another HBITMAP - c++

I'm trying to write a class to wrap bitmap functionality in my program.
One useful feature would be to copy a bitmap from another bitmap handle. I'm a bit stuck:
void operator=( MyBitmapType & bmp )
{
HDC dcMem;
HDC dcSource;
if( m_hBitmap != bmp.Handle() )
{
if( m_hBitmap )
this->DisposeOf();
// copy the bitmap header from the source bitmap
GetObject( bmp.Handle(), sizeof(BITMAP), (LPVOID)&m_bmpHeader );
// Create a compatible bitmap
dcMem = CreateCompatibleDC( NULL );
m_hBitmap = CreateCompatibleBitmap( dcMem, m_bmpHeader.bmWidth, m_bmpHeader.bmHeight );
// copy bitmap data
BitBlt( dcMem, 0, 0, bmp.Header().bmWidth, bmp.Header().bmHeight, dcSource, 0, 0, SRCCOPY );
}
}
This code is missing one thing: How can I get an HDC to the source bitmap if all I have of the source bitmap is a handle (e.g. an HBITMAP?)
You can see in the code above, I've used "dcSource" in the BitBlt() call. But I don't know how to get this dcSource from the source bitmap's handle (bmp.Handle() returns the source bitmaps handle)

You can't -- the source bitmap may not be selected into a DC at all, and even if it is you have no way to find out what DC.
To do your copy, you probably want to use something like:
dcSrc = CreateCompatibleDC(NULL);
SelectObject(dcSrc, bmp);
Then you can blit from the source to destination DC.

Worked for me:
// hBmp is a HBITMAP
HBITMAP hBmpCopy= (HBITMAP) CopyImage(hBmp, IMAGE_BITMAP, 0, 0, LR_DEFAULTSIZE);

Related

How to construct a GDI+ Bitmap object from a Device-Dependent HBITMAP

I want to use GDI+ method Image::Save() to save a DDB to a file in the following scenario:
HBITMAP hBitmap = CreateCompatibleBitmap(hDC, 200, 200) ;
...
//hBitmap is a DDB so I need to pass an HPALETTE
Gdiplus::Bitmap(hBitmap, ???HPALETTE??? ).Save(L"file.png", ...) ;
The problem is that Bitmap constructor asks for an HPALETTE when the bitmap is not a device-independent bitmap.
Where do I get the necessary HPALETTE from?
FOLLOWUP:
One of the answers suggests passing NULL as the HPALETTE parameter.
Here is a working example that does so. The result is a purely black and white image where all colors are lost.
#include <windows.h>
#include <gdiplus.h>
int main(){
using namespace Gdiplus ;
GdiplusStartupInput gdiplusStartupInput ;
ULONG_PTR gdiplusToken ;
GdiplusStartup(&gdiplusToken, &gdiplusStartupInput, NULL) ;
CLSID pngEncoder = {0x557cf406, 0x1a04, 0x11d3, {0x9a, 0x73, 0x00, 0x00, 0xf8, 0x1e, 0xf3, 0x2e} } ;
HDC dcHndl = CreateCompatibleDC(NULL) ;
HBITMAP hBitmap = CreateCompatibleBitmap(dcHndl, 200, 200) ;
SelectObject(dcHndl, hBitmap) ;
BitBlt(dcHndl, 0,0, 200,200, GetDC(NULL), 0,0, SRCCOPY|CAPTUREBLT) ;
Bitmap(hBitmap, NULL).Save(L"file.png", &pngEncoder) ;
}
First (and this is unrelated to your main question):
When creating a bitmap for screen shot, don't use a memory dc because that creates a monochrome bitmap. That's the main reason you are getting a black and white image (on my computer I just get a black image).
Don't use GetDC(0) inside another function. Every call to GetDC match have a matching ReleaseDC to avoid resource leak.
After calling BitBlt it is good practice to select hbitmap out of dc because you are basically finished drawing on dc.
The following code will work on Windows 10
int w = 800;
int h = 600;
HDC hdc = GetDC(HWND_DESKTOP);
HDC memdc = CreateCompatibleDC(hdc);
HBITMAP hbitmap = CreateCompatibleBitmap(hdc, w, h);
HBITMAP oldbmp = (HBITMAP)SelectObject(memdc, hbitmap);
BitBlt(memdc, 0, 0, w, h, hdc, 0, 0, SRCCOPY | CAPTUREBLT);
SelectObject(memdc, oldbmp);
Bitmap(hbitmap, NULL).Save(filename, &pngEncoder);
DeleteObject(hbitmap);
DeleteDC(memdc);
ReleaseDC(HWND_DESKTOP, hdc);
Back to your question regarding the documentation:
Type: HPALETTE
Handle to a GDI palette used to define the bitmap colors if hbm is not a device-independent bitmap (DIB).
In addition,
Do not pass to the Bitmap::FromHBITMAP method a GDI bitmap or a GDI palette that is currently (or was previously) selected into a device context.
The code I posted obeys only one rule, that GDI bitmap is not currently selected in to a device context (but it was previously selected).
The documentation may apply to older versions of Windows. As far as I can see MFC's CImage class does not follow all these rules. New computer displays are all 24 or 32 bit, I don't know how you would get a palette for it.
To follow the documentation to the letter, you can convert DDB to DIB section, using CreateDIBSection and GetDIBits. Use the new DIB section hbitmap_dib in Bitmap::FromHBITMAP. This will satisfy all of the conditions: hbitmap is dib, it is not (and was not) selected in to a device context.
Or, Gdiplus::Bitmap has another method Bitmap::FromBITMAPINFO. If there is no palette, you can use this code instead:
HDC hdc = GetDC(HWND_DESKTOP);
HDC memdc = CreateCompatibleDC(hdc);
HBITMAP hbitmap = CreateCompatibleBitmap(hdc, w, h);
HBITMAP oldbmp = (HBITMAP)SelectObject(memdc, hbitmap);
BitBlt(memdc, 0, 0, 800, 600, hdc, 0, 0, SRCCOPY | CAPTUREBLT);
SelectObject(memdc, oldbmp);
BITMAP bm;
GetObject(hbitmap, sizeof(bm), &bm);
int size = ((bm.bmWidth * bm.bmBitsPixel + 31) / 32) * 4 * bm.bmHeight;
BITMAPINFO info{ sizeof(info), bm.bmWidth, bm.bmHeight, 1, bm.bmBitsPixel, BI_RGB, size };
std::vector<char> bits(size);
GetDIBits(memdc, hbitmap, 0, bm.bmHeight, &bits[0], &info, DIB_RGB_COLORS);
Bitmap *bitmap = Bitmap::FromBITMAPINFO(&info, &bits[0]);
bitmap->Save(filename, &pngEncoder);
delete bitmap;
DeleteObject(hbitmap);
DeleteDC(memdc);
ReleaseDC(HWND_DESKTOP, hdc);
As CreateCompatibleBitmap remarks sate if you are dealing with color bitmaps we can also assume that hDC is a nonmemory device context (because memory device context will only create monochrome bitmaps) and the color palette used by this bitmap is the same color palette used by this device context. You can query it using GetCurrentObject method. However remarks to Bitmap.Bitmap(HBITMAP, HPALETTE) constructor state:
Do not pass to the GDI+ Bitmap::Bitmap constructor a GDI bitmap or a GDI palette that is currently (or was previously) selected into a device context.
So you can not used current device context palette directly and need to create a copy of it instead.
/// <returns>
/// Handle to palette currently selected into device context without granting ownership.
/// </returns>
_Check_return_ ::HPALETTE
Fetch_CurrentPalette(_In_ ::HDC const h_dc)
{
assert(h_dc);
::HGDIOBJ const h_palette_object{::GetCurrentObject(h_dc, OBJ_PAL)}; // not owned
assert(h_palette_object);
assert(OBJ_PAL == ::GetObjectType(h_palette_object));
// Perform unchecked conversion of generic GDI object descriptor to GDI palette descriptor.
::HPALETTE h_current_palette{}; // not owned
{
static_assert(sizeof(h_palette_object) == sizeof(h_current_palette), "wat");
::memcpy
(
::std::addressof(h_current_palette)
, ::std::addressof(h_palette_object)
, sizeof(h_current_palette)
);
}
return(h_current_palette);
}
/// <returns>
/// Handle to palette copy with granting ownership.
/// </returns>
_Check_return_ ::HPALETTE
Make_PaletteCopy(_In_ ::HPALETTE const h_palette)
{
assert(h_palette);
::UINT const first_entry_index{};
::UINT entries_count{};
::LPPALETTEENTRY p_entries{};
// Figure out how many entries palette contains.
entries_count = ::GetPaletteEntries(h_palette, first_entry_index, entries_count, p_entries);
assert(1 < entries_count);
assert(entries_count <= ::std::numeric_limits< decltype(LOGPALETTE::palNumEntries) >::max());
// This buffer will hold palette description which contains first PALETTEENTRY as last field.
// followed by the rest of PALETTEENTRY items.
::std::unique_ptr< ::std::uint8_t[] > const p_buffer
{
new ::std::uint8_t[sizeof(::LOGPALETTE) + (sizeof(::PALETTEENTRY) * (entries_count - 1u))]
};
// Perform unchecked conversion of buffer pointer to palette description pointer.
::LOGPALETTE * p_description{};
{
::std::uint8_t * const p_buffer_bytes{p_buffer.get()};
static_assert(sizeof(p_buffer_bytes) == sizeof(p_description), "wat");
::memcpy
(
::std::addressof(p_description)
, ::std::addressof(p_buffer_bytes)
, sizeof(p_description)
);
}
// Copy palette entries into buffer.
p_entries = static_cast< ::LPPALETTEENTRY >(p_description->palPalEntry);
::UINT const copied_entries_count
{
::GetPaletteEntries(h_palette, first_entry_index, entries_count, p_entries)
};
assert(copied_entries_count == entries_count);
// Create palette copy.
p_description->palVersion = 0x300; // magic
p_description->palNumEntries = static_cast< ::WORD >(copied_entries_count);
::HPALETTE const h_copied_palette{::CreatePalette(p_description)}; // owned
assert(h_copied_palette);
return(h_copied_palette);
}
::HPALETTE const hPal{Make_PaletteCopy(Fetch_CurrentPalette(hDC))}; // owned
assert(hPal);
::HBITMAP const hBitmap{::CreateCompatibleBitmap(hDC, 200, 200)}; // owned
assert(hBitmap);
{
::Gdiplus::Bitmap bmp{hBitmap, hPal};
assert(::Gdiplus::Status::Ok == bmp.GetLastStatus());
// Do something...
}
// Delete palette and bitmap after GDI+ bitmap object went out of scope.
if(FALSE == ::DeleteObject(hPal))
{
assert(false);
}
if(FALSE == ::DeleteObject(hBitmap))
{
assert(false);
}
You can pass NULL. Sample code below.
int main()
{
GdiplusStartupInput gdiplusStartupInput;
ULONG_PTR gdiplusToken;
GdiplusStartup(&gdiplusToken, &gdiplusStartupInput, NULL);
GUID encoder = {};
GetGdiplusEncoderClsid(L"image/png", &encoder); // https://stackoverflow.com/a/5346026/104458
HDC hdc = GetDC(NULL);
HBITMAP hBitmap = CreateCompatibleBitmap(hdc, 200, 200);
Bitmap bmp(hBitmap, NULL);
bmp.Save(L"File.png", &encoder);
return 0;
}

MFC: How to copy bitmap using OLE clipboard

Now I have a CImage img, and I wanted to copy the bitmap to the OLE clipboard.
What I did is the following
HBITMAP hImage = img.Detach();
CBitmap *pBitmap = CBitmap::FromHandle(hImage);
BITMAP bm;
pBitmap->GetObject(sizeof(bm), &bm);
HBITMAP hImage = Detach();
// the bitmap src
CBitmap *pBitmap = CBitmap::FromHandle(hImage);
BITMAP bm;
pBitmap->GetObject(sizeof(bm), &bm);
// the copy (dest)
CBitmap bitmap;
bitmap.CreateBitmapIndirect(&bm);
// create mem dc and select src and dest bitmaps
CDC dcMemSrc, dcMemDest;
dcMemSrc.CreateCompatibleDC(NULL);
CBitmap* pOldBitmapSrc = dcMemSrc.SelectObject(pBitmap);
dcMemDest.CreateCompatibleDC(NULL);
CBitmap* pOldBitmapDest = dcMemDest.SelectObject(&bitmap);
// bit-blt
dcMemDest.BitBlt(0, 0, bm.bmWidth, bm.bmHeight, &dcMemSrc,
0, 0, SRCCOPY);
HBITMAP hBitmap = (HBITMAP)bitmap.Detach();
// restore mem dc
dcMemDest.SelectObject(pOldBitmapDest);
dcMemSrc.SelectObject(pOldBitmapSrc);
// Place the copy on the clipboard.
AfxOleInit();
CoInitialize(NULL);
COleDataSource* pods = new COleDataSource;
pods->CacheGlobalData(CF_BITMAP, hBitmap);
pods->SetClipboard();
CoUninitialize();
I tested the program, it just doesn't work, I tried to CTRL+V to the Windows Paint program, but it complained the data cannot be pasted in it. If I use the Legacy Clipboard(just replace the last 6 lines with ::OpenClipboard(hWnd), ::EmptyClipboard(), ::SetClipboardData(CF_BITMAP, hBitmap), ::CloseClipboard() ), it works fine. I have no experience working with COM and OLE, can anyone help? Many thanks.

GDI+ DC in memory always monochrome

Working in mingw, having a terrible time creating a color DC in memory. For instance, in the following code snippet, as written, "foo_scratch.bmp" is a monochrome version of the
image (from an EMR_STRETCHDIBITS record). If instead aDC is omitted and srcDC uses the CreateDC directly, then that file has a color image.
Gdiplus::Bitmap *pbmp = NULL;
BITMAPINFO *pbitmapinfo = (BITMAPINFO *)((char *)lpEMFR + pEmr->offBmiSrc);
void *pBitsInMem = (char *)lpEMFR + pEmr->offBitsSrc;
HBITMAP hbmsrc;
HDC aDC = CreateDC("DISPLAY", "", NULL, NULL);
HDC srcDC = CreateCompatibleDC(aDC);
hbmsrc = CreateDIBitmap(
srcDC,
&(pbitmapinfo->bmiHeader),
CBM_INIT,
pBitsInMem,
pbitmapinfo,
DIB_RGB_COLORS);
if(hbmsrc){
CLSID pngClsid;
GetEncoderClsid(L"image/bmp", &pngClsid);
pbmp = Gdiplus::Bitmap::FromHBITMAP(hbmsrc,NULL);
pbmp->Save(L"C:\\Temp\\foo_scratch.bmp",&pngClsid, NULL);
This all comes to a head later when two images (hbmdst, hbmsrc) need to be put together with a bitblt operation. At present the best I have managed is monochrome. At worst the image is solid black. In this snippet the ROP has been hard coded to SRCCOPY, and I still have not succeeded in just copying the image from one HBITMAP to another. Very frustrating!
HDC dstDC = CreateCompatibleDC(aDC);
HBITMAP hbmdOld = (HBITMAP) SelectObject(dstDC, hbmdst);
HBITMAP hbmsOld = (HBITMAP) SelectObject(srcDC, hbmsrc);
GetObject(hbmsrc, sizeof(bm), &bm);
BitBlt(dstDC, 0, 0, bm.bmWidth, bm.bmHeight, srcDC, 0, 0, SRCCOPY);
SelectObject(srcDC, hbmsOld);
SelectObject(dstDC, hbmdOld);
(void) DeleteDC(dstDC);
pbmp = Gdiplus::Bitmap::FromHBITMAP(hbmdst,NULL);
pbmp->Save(L"C:\\Temp\\scratch.bmp",&pngClsid, NULL);
What am I doing wrong?
Thanks
Figured it out - wherever a bitmap is created have to use the DC directly associated with the display (or other device), not the "compatible" DC derived from the first DC.

How to convert HICON to HBITMAP in VC++?

How to convert HICON to HBITMAP in VC++?
I know this is an FAQ but all the solutions I've found on Google don't work. What I need is a function which takes a parameter HICON and returns HBITMAP.
Greatest if possible to make conversion to 32-bit bitmap even the icon is 24-bit, 16-bit or 8-bit.
This is the code, I don't know where it goes wrong:
HBITMAP icon_to_bitmap(HICON Icon_Handle) {
HDC Screen_Handle = GetDC(NULL);
HDC Device_Handle = CreateCompatibleDC(Screen_Handle);
HBITMAP Bitmap_Handle =
CreateCompatibleBitmap(Device_Handle,GetSystemMetrics(SM_CXICON),
GetSystemMetrics(SM_CYICON));
HBITMAP Old_Bitmap = (HBITMAP)SelectObject(Device_Handle,Bitmap_Handle);
DrawIcon(Device_Handle, 0,0, Icon_Handle);
SelectObject(Device_Handle,Old_Bitmap);
DeleteDC(Device_Handle);
ReleaseDC(NULL,Screen_Handle);
return Bitmap_Handle;
}
this code do it:
HICON hIcon = (HICON)LoadImage(instance, MAKEINTRESOURCEW(IDI_ICON), IMAGE_ICON, width, height, 0);
ICONINFO iconinfo;
GetIconInfo(hIcon, &iconinfo);
HBITMAP hBitmap = iconinfo.hbmColor;
and this is the code in the *.rc file:
IDI_ICON ICON "example.ico"
and this is the code in the *.h file:
#define IDI_ICON 4000
HDC hDC = GetDC(NULL);
HDC hMemDC = CreateCompatibleDC(hDC);
HBITMAP hMemBmp = CreateCompatibleBitmap(hDC, x, y);
HBITMAP hResultBmp = NULL;
HGDIOBJ hOrgBMP = SelectObject(hMemDC, hMemBmp);
DrawIconEx(hMemDC, 0, 0, hIcon, x, y, 0, NULL, DI_NORMAL);
hResultBmp = hMemBmp;
hMemBmp = NULL;
SelectObject(hMemDC, hOrgBMP);
DeleteDC(hMemDC);
ReleaseDC(NULL, hDC);
DestroyIcon(hIcon);
return hResultBmp;
I don't have code readily available to share, but I think this is pretty easy. You have to create the HBITMAP, create a device context, select the bitmap into the DC (this will make the bitmap the drawing area for this DC). Finally call the DrawIcon() function to draw your icon on this DC. After that detach the bitmap from the DC and destroy the DC. Your bitmap now should be ready to go.
Update after looking at your code:
I believe the problem is in the createCompatibleBitmap call. You are asking for a bitmap compatible with the memory DC, but memory DCs start with a 1 bit/pixel bitmap selected into them. Try asking for a bitmap compatible with the screen DC instead.
Update 2: you may want to look at this question as it seems related to your problem.
I found this(similar code works for me - 32x32 icons with or without alpha data):
used CopyImage (msdn link)
HICON hICON = /*your code here*/
HBITMAP hBITMAPcopy;
ICONINFOEX IconInfo;
BITMAP BM_32_bit_color;
BITMAP BM_1_bit_mask;
// 1. From HICON to HBITMAP for color and mask separately
//.cbSize required
//memset((void*)&IconInfo, 0, sizeof(ICONINFOEX));
IconInfo.cbSize = sizeof(ICONINFOEX);
GetIconInfoEx( hICON , &IconInfo);
//HBITMAP IconInfo.hbmColor is 32bit per pxl, however alpha bytes can be zeroed or can be not.
//HBITMAP IconInfo.hbmMask is 1bit per pxl
// 2. From HBITMAP to BITMAP for color
// (HBITMAP without raw data -> HBITMAP with raw data)
// LR_CREATEDIBSECTION - DIB section will be created,
// so .bmBits pointer will not be null
hBITMAPcopy = (HBITMAP)CopyImage(IconInfo.hbmColor, IMAGE_BITMAP, 0, 0, LR_CREATEDIBSECTION);
// (HBITMAP to BITMAP)
GetObject(hBITMAPcopy, sizeof(BITMAP), &BM_32_bit_color);
//Now: BM_32_bit_color.bmBits pointing to BGRA data.(.bmWidth * .bmHeight * (.bmBitsPixel/8))
// 3. From HBITMAP to BITMAP for mask
hBITMAPcopy = (HBITMAP)CopyImage(IconInfo.hbmMask, IMAGE_BITMAP, 0, 0, LR_CREATEDIBSECTION);
GetObject(hBITMAPcopy, sizeof(BITMAP), &BM_1_bit_mask);
//Now: BM_1_bit_mask.bmBits pointing to mask data (.bmWidth * .bmHeight Bits!)
BM_32_bit_color bitmap may be have Alpha *channel*(each 4th byte) already set! So - check for it before u add mask bit to color data.

Drawing On GDI+ Graphics Object a Bitmap using StretchDIBits for Scaling

I am drawing bitmap images on graphics object using DrawImage method But the Images are in large number so it is taking too much time for Drawing. I have read in this forum that using StretchDIBits takes less time for Drawing.
I am scaling the image by calling Drawimage but i want any other efficent method.
I have a Vector of Bitmap* & i want to draw each Bitmap on graphics.
HDC orghDC = graphics.GetHDC();
CDC *dc = CDC::FromHandle(orghDC);
m_vImgFrames is image vector containg Bitmap*. I have taken HBITMAP from Bitmap*.
HBITMAP hBitmap;
m_vImgFrames[0]->GetHBITMAP(Color(255,0,0),&hBitmap);
Using this HBITMAP i want to draw on orghDC & finally on graphics. So I want to know how StretchDIBits can be used for scaling the Bitmap and finally draw on Graphics Object.
I am new to this forum.Any ideas or code can be helpful
Instead of using StretchDIBits, why not use the GDI+ API directly to scale the bitmap?:
CRect rc( 0, 0, 20, 30 );
graphics.DrawImage( (Image*)m_vImgFrames[0],
rc.left, rc.top, rc.Width(), rc.Height() );
To use StretchDIBits with Gdiplus::Bitmap you could do the following:
// get HBITMAP
HBITMAP hBitmap;
m_vImgFrames[0]->GetHBITMAP( Gdiplus::Color(), &hBitmap );
// get bits and additional info
BITMAP bmp = {};
::GetObject( hBitmap, sizeof(bmp), &bmp );
// prepare BITMAPINFO
BITMAPINFO bminfo = {};
bminfo.bmiHeader.biSize = sizeof( BITMAPINFO );
bminfo.bmiHeader.biWidth = bmp.bmWidth;
bminfo.bmiHeader.biHeight = bmp.bmHeight;
bminfo.bmiHeader.biBitCount = bmp.bmBitsPixel;
bminfo.bmiHeader.biCompression = BI_RGB;
bminfo.bmiHeader.biPlanes = bmp.bmPlanes;
bminfo.bmiHeader.biSizeImage = bmp.bmWidthBytes*bmp.bmHeight*4; // 4 stands for 32bpp
// select stretch mode
::SetStretchBltMode( HALFTONE );
// draw
::StretchDIBits( hDC, 0, 0, new_cx, new_cy, 0, 0,
m_vImgFrames[0]->GetWidth(), m_vImgFrames[0]->GetHeight(),
bmp.bmBits, &bminfo, DIB_RGB_COLORS, SRCCOPY );
But this doesn't looks much faster on my machine than simple Graphics::DrawImage.