What's wrong with the below SAS code? The single date column cannot be read correctly.
DATA test;
INPUT mydate MMDDYY8.;
FORMAT mydate YYMMDD10.;
DATALINES;
01-22-98
03-03-97
;
PROC PRINT DATA = test;
RUN;
Edit: Thanks for the answer. Another follow-up question is, when I try to read CSV format where datetime is quoted, it always fails to read correctly. How to read CSV format with quoted datetime values correctly? DSD option doesn't help much in my case.
Try left-aligning the datalines.
Though SAS is a free format language. I.e. Any statement can start in any line, one statement can span across multiple lines, multiple statement can be on online.
However with the datalines - statement that represents data within the code, data should start from column 1 / at least in column 2. Hence if the first two columns are blank, SAS assumes that the row is blank and goes to the next row.
Hence the mistake in your code is to start the data from the right column.
Related
I am working to merge two data sets and get the following error:
Variable DOB has been defined as both character and numeric.
Here is my code. I know I need a set statement to change the character to numeric. I was thinking:
DATA Merged1;
SET Aug21 Aug22;
RUN;
set (rename=(DOB=DOBnum));
length DOB $ 10.;
DOB= put(DOBnum,f10. -L);
drop DOBnum;
Would this be placed before my Set statement to merge to Aug 21 Aug 22?
Thank you!
I tried to run the code but it would not merge, unsure if where the Set statement for DOB would go
You do not need the second SET statement. You need to add the RENAME= dataset option to the dataset where it is mentioned in the first SET statement.
So something like:
DATA BOTH;
SET Aug21 Aug22(in=in2 rename=(DOB=DOBnum));
if in2 then DOB= put(DOBnum,f10. -L);
drop DOBnum;
RUN;
To get a more detailed answer provide more details about the variables and the types of values they contain. For example if DOB means Date of Birth then it does not make much sense to use the F format. If DOB should be an actual DATE then it should be numeric and not character. And if the version that is numeric has actual date values then converting them to text using the F format is going to generate strings that will be confusing for humans.
If you're a beginner I recommend two steps so you can trace the work.
Convert dob from character to numeric
Append the two datasets together (assume you're stacking the data sets)
Use format to control how the date is displayed
*convert character to numeric SAS date;
data aug21_convert2num;
set aug21(rename=dob=dobchar);
dob = input(dob, anydtdte.);
drop dobchar;
run;
*append the two data sets;
data want;
set aug21_convert2num aug22;
format dob yymmdd10.;
run;
How to convert the default timestamp "0001-01-01-00.00.00.000000" in SAS, i have tried below code but it has returned null value. Can someone help on this please
data _NULL_;
x = "0001-01-01-00.00.00.000000";
rlstime = input(x,anydtdtm26.);
call symput('rlstime',rlstime);
run;
%put rlst: &rlstime;
As far as I remember, SAS cannot do that. Any date/timestamp before 1.1.1600 doesn't exist for SAS. Do you need it or can you just replace it with a null value? If you really need it you could transform it into another valid timestamp, split it into different columns (year, month, etc.) or just use it as a string. In your example you just write the timestamp into the log, meaning it's not necessary to transform it.
The earliest date that SAS will handle is 1st January, 1582. Additionally, a colon character should be used to delimit the time from the date, as well as the hours, minutes and seconds. Therefore, your code may be adjusted to the following:
data _NULL_;
x = "1582-01-01:00:00:00.000000";
rlstime = input(x,anydtdtm26.);
call symput('rlstime',rlstime);
run;
%put rlst: &rlstime;
I want to insert values into a new table, but I keep getting the same error: VALUES clause 1 attempts to insert more columns than specified after the INSERT table name. This is if I don't put apostrophes around my date. If I do put apostrophes then I get told that the data types do not correspond for the second value.
proc sql;
create table date_table
(cvmo char(6), next_beg_dt DATE);
quit;
proc sql;
insert into date_table
values ('201501', 2015-02-01)
values ('201502', 2015-03-01)
values ('201503', 2015-04-01)
values ('201504', 2015-05-01);
quit;
The second value has to remain as a date because it used with > and < symbols later on. I think the problem may be that 2015-02-01 just isn't a valid date format since I couldn't find it on the SAS website, but I would rather not change my whole table.
Date literals (constants) are quoted strings with the letter d immediately after the close quote. The string needs to be in a format that is valid for the DATE informat.
'01FEB2015'd
"01-feb-2015"d
'1feb15'd
If you really want to insert a series of dates then just use a data step with a DO loop. Also make sure to attach one of the many date formats to your date values so that they will print as human understandable text.
data data_table ;
length cvmo $6 next_beg_dt 8;
format next_beg_dt yymmdd10.;
do _n_=1 to 4;
cvmo=put(intnx('month','01JAN2015'd,_n_-1,'b'),yymmn6.);
next_beg_dt=intnx('month','01JAN2015'd,_n_,'b');
output;
end;
run;
#tom suggest you in comments how to use date and gives very good answer how to it efficently, which is less error prone than typing values. I am just putting the same into the insert statement.
proc sql;
create table date_table
(cvmo char(6), next_beg_dt DATE);
quit;
proc sql;
insert into date_table
values ('201501', "01FEB2015"D)
;
I have a column that contains date values. So when imported as numeric, it shows 20668, 20669...etc. if I format it as yymmddn8, it shows 20160802 etc. However, what I really want is a numeric variable that shows 20160802. I have tried to create other to get day, month, year and then concatenate them. Unfortunately, the issue is if month and day is 1 digit, it would only show 201682. what would be the quickest way to achieve my goal. I guess a can turn the day and month variable to text and add 0 if day or month is less than 10. But this is not elegant and efficient. Please help.
Thanks
You can just wrap an input around that format:
data test;
date = 20668;
full_date = input(put(date,yymmddn8.),best12.);
run;
The put is converting the date to character in the format as you want it to appear, and the input with the best12. format is converting it back to numeric in that format.
It sounds like you just need to attach a format to your variable.
format date yymmddn8. ;
Try running this program to see a few of the different formats that are available for displaying dates.
data _null_;
do date = 20668, 20669 ;
put (6*date) (=10. =date9. =yymmddn8. =mmddyy10. =ddmmyy10. =yymmdd10.) ;
end;
run;
I want to convert a String to Date in SAS, I tried:
data _null_;
monyy = '05May2013';
date = input(substr(strip(monyy),1,9),yymmdd.);;
put date=date9.;
run;
But it did not work. Can this be done?
Formats like
date9.
or
mmddyy10.
are not valid for input command while converting text to a sas date. You can use
Date = input( cdate , ANYDTDTE11.);
or
Date = input( cdate , ANYDTDTE10.);
for conversion.
You don't need substr or strip.
input(monyy,date9.);
As stated above, the simple answer is:
date = input(monyy,date9.);
with the addition of:
put date=yymmdd.;
The reason why this works, and what you did doesn't, is because of a common misunderstanding in SAS. DATE9. is an INFORMAT. In an INPUT statement, it provides the SAS interpreter with a set of translation commands it can send to the compiler to turn your text into the right numbers, which will then look like a date once the right FORMAT is applied. FORMATs are just visible representations of numbers (or characters). So by using YYMMDD., you confused the INPUT function by handing it a FORMAT instead of an INFORMAT, and probably got a helpful error that said:
Invalid argument to INPUT function at line... etc...
Which told you absolutely nothing about what to do next.
In summary, to represent your character date as a YYMMDD. In SAS you need to:
change the INFORMAT - date = input(monyy,date9.);
apply the FORMAT - put date=YYMMDD10.;
Try
data _null_;
monyy = '05May2013';
date = input(substr(strip(monyy),1,9),date9.);
put date=date9.;
run;
input(char_val, date9.);
You can consider to convert it to word format using
input(char_val, worddate.)
You can get a lot in this page http://v8doc.sas.com/sashtml/lrcon/zenid-63.htm
This code helps:
data final; set final;
first_date = INPUT(compress(char_date),date9.); format first_date date9.;
run;
I personally have tried it on SAS
input(char_val,current_date_format);
You can specify any date format at display time, like set char_val=date9.;