rendering a ReportLab pdf built from SimpleDocTemplate - django

I've a got a django app that currently generates pdfs using a canvas that the user can download. I create a StringIO buffer, do some stuff and then send call response.write.
# Set up response
response = HttpResponse(mimetype='application/pdf')
response['Content-Disposition'] = 'attachment; filename=menu-%s.pdf' % str(menu_id)
# buffer
buff = StringIO()
# Create the pdf object
p = canvas.Canvas(buff)
# Add some elements... then
p.showPage()
p.save()
# Get the pdf from the buffer and return the response
pdf = buff.getvalue()
buff.close()
response.write(pdf)
I now want to build my pdf using platypus and SimpleDocTemplate and have written this
# Set up response
response = HttpResponse(mimetype='application/pdf')
pdf_name = "menu-%s.pdf" % str(menu_id)
response['Content-Disposition'] = 'attachment; filename=%s' % pdf_name
menu_pdf = SimpleDocTemplate(pdf_name, rightMargin=72,
leftMargin=72, topMargin=72, bottomMargin=18)
# container for pdf elements
elements = []
styles=getSampleStyleSheet()
styles.add(ParagraphStyle(name='centered', alignment=TA_CENTER))
# Add the content as before then...
menu_pdf.build(elements)
response.write(menu_pdf)
return response
But this doesn't work, it creates a bad pdf that cannot be opened. I presume the line
response.write(menu_pdf)
is incorrect.
How do I render the pdf?

Your error is actually a pretty simple one. It's just a matter of trying to write the wrong thing. In your code, menu_pdf is not a PDF, but a SimpleDocTemplate, and the PDF has been stored in pdf_name, although here I suspect pdf_name is a path name rather than a file object. To fix it, change your code to use a memory file like you did in your original code:
# Set up response
response = HttpResponse(mimetype='application/pdf')
pdf_name = "menu-%s.pdf" % str(menu_id)
response['Content-Disposition'] = 'attachment; filename=%s' % pdf_name
buff = StringIO()
menu_pdf = SimpleDocTemplate(buff, rightMargin=72,
leftMargin=72, topMargin=72, bottomMargin=18)
# container for pdf elements
elements = []
styles=getSampleStyleSheet()
styles.add(ParagraphStyle(name='centered', alignment=TA_CENTER))
# Add the content as before then...
menu_pdf.build(elements)
response.write(buff.getvalue())
buff.close()
return response
I'm not sure if using file objects rather than paths with Platypus is mentioned in the documentation, but if you dig into the code you'll see that it is possible.

For people who are working with python3 and django 1.7+ some changes to the answer need to be done.
from django.shortcuts import HttpResponse
import io
from reportlab.platypus import SimpleDocTemplate, BaseDocTemplate
def view(request):
buffer = io.BytesIO()
doc = # ... create your SimpleDocTemplate / BaseDocTemplate
# create the usual story
story = []
# ...
doc.build(story)
response = HttpResponse(content_type='application/pdf')
response['Content-Disposition'] = 'attachment; filename=your_name.pdf'
response.write(buffer.getvalue())
buffer.close()
return response

Related

the filename of pdf file doesnt work correctly with wkhtmltopdf

I have a button download in my Django project, where I can export the report for a certain date in a pdf format. Everything works fine on my laptop with Linux, but when I set the project in the local server of our company, the name of the file is showing without a date.
Here is my code:
template_name = 'pdf.html'
template = get_template(template_name)
html = template.render({"data": data, "date":date, "index":index})
if 'DYNO' in os.environ:
print('loading wkhtmltopdf path on heroku')
WKHTMLTOPDF_CMD = subprocess.Popen(
['which', os.environ.get('WKHTMLTOPDF_BINARY', 'wkhtmltopdf-pack')],
stdout=subprocess.PIPE).communicate()[0].strip()
else:
print('loading wkhtmltopdf path on localhost')
WKHTMLTOPDF_CMD = ('/usr/local/bin/wkhtmltopdf/bin/wkhtmltopdf')
config = pdfkit.configuration(wkhtmltopdf=WKHTMLTOPDF_CMD)
options = {
'margin-bottom': '10mm',
'footer-center': '[page]'
}
pdf = pdfkit.from_string(html, False, configuration=config, options=options)
response = HttpResponse(pdf, content_type='application/pdf')
response['Content-Disposition'] = 'attachment; filename="otchet-{}.pdf"'.format(date)
return response
when I download locally, the name of the file is - otchet-2021-06-30.pdf
but on server, it looks like - otchet%20.pdf
I have no idea, how to fix it...
Just a thought. Use an f string.
response['Content-Disposition'] = f'attachment; filename="otchet-{date}.pdf"'

Generate multiple PDFs and zip them for download, all in a single view

I am using xhtml2pdf to generate PDFs in my Django View. The idea is to loop over all the instances that are there in the query, then for each instance create a PDF, then add all the generated PDFs to one zip File for download. The xtml2pdf logic is working okay but the looping logic is what gives me headache.
So this is my function so far:
def bulk_cover_letter(request, ward_id, school_cat_id, cheque_number):
school_type = SchoolType.objects.get(id=school_cat_id)
schools_in_school_type = Applicant.objects.filter(
school_type=school_type, ward_id=ward_id, award_status='awarded'
).order_by().values_list('school_name', flat=True).distinct()
for school in schools_in_school_type:
beneficiaries = Applicant.objects.filter(school_type=school_type, ward_id=ward_id, award_status='awarded', school_name=school)
total_amount_to_beneficiaries = Applicant.objects.filter(school_type=school_type, ward_id=ward_id, award_status='awarded', school_name=school).aggregate(total=Sum('school_type__amount_allocated'))
context = {
'school_name' : school,
'beneficiaries' : beneficiaries,
'total_amount_to_beneficiaries' : total_amount_to_beneficiaries,
'title' : school + ' Disbursement Details',
'cheque_number': cheque_number
}
response = HttpResponse('<title>Cover Letter</title>', content_type='application/pdf')
filename = "%s.pdf" %(cheque_number)
content = "inline; filename=%s" %(filename)
response['Content-Disposition'] = content
template = get_template('cover_letter.html')
html = template.render(context)
result = io.BytesIO()
pdf = pisa.CreatePDF(
html, dest=response, link_callback=link_callback)
if not pdf.error:
# At this point I can generate a single PDF.
# But no idea on what to do next.
# The zipping logic should follow here after looping all the instances - (schools)
From that Point I have no idea on what to do next. Any help will be highly appreciated.
Try this:
Utils.py
def render_to_pdf(template_src, context_dict={}):
template = get_template(template_src)
html = template.render(context_dict)
buffer = BytesIO()
p = pisa.pisaDocument(BytesIO(html.encode("ISO-8859-1")), buffer)
pdf = buffer.getvalue()
buffer.close()
if not p.err:
return pdf#HttpResponse(result.getvalue(), content_type='application/pdf')
return None
def generate_zip(files):
mem_zip = BytesIO()
with zipfile.ZipFile(mem_zip, mode="w",compression=zipfile.ZIP_DEFLATED) as zf:
for f in files:
zf.writestr(f[0], f[1])
return mem_zip.getvalue()
Views.py
def generate_attendance_pdf(modeladmin, request, queryset):
template_path = 'student/pdf_template.html'
files = []
for q in queryset:
context = {
'firstname': q.firstname,
'lastname': q.lastname,
'p_firstname': q.bceID.firstname
}
pdf = render_to_pdf(template_path, context)
files.append((q.firstname + ".pdf", pdf))
full_zip_in_memory = generate_zip(files)
response = HttpResponse(full_zip_in_memory, content_type='application/force-download')
response['Content-Disposition'] = 'attachment; filename="{}"'.format('attendnace.zip')
return response
Obviously, you have to modify the context/names to what you need.
Credit to -> Neil Grogan https://www.neilgrogan.com/py-bin-zip/
If you need to generate several PDF files and send them as a response in a zip file then you can store the reports in memory and set it as dest when you call pisa.CreatePDF. Then have a list of reports in memory, zip them, and send as a Django response specifying another content type.
For example:
reports = tempfile.TemporaryDirectory()
report_files = {}
for school in schools_in_school_type:
# ... same code that renerates `html`
mem_fp = BytesIO()
pisa.CreatePDF(html, dest=mem_fp)
report_files[filename] = mem_fp
mem_zip = BytesIO()
with zipfile.ZipFile(mem_zip, mode="w") as zf:
for filename, content in report_files.items():
zf.write(filename, content)
response = HttpResponse(mem_zip, content_type='application/force-download')
response['Content-Disposition'] = 'attachment; filename="{}"'.format('cover_letters.zip')
This still generates an error of [Errno 2] No such file or directory: 'cheque_number.pdf'.

Return Zip file with HttpResponse using StringIO, Django, Python

I'm trying to return a zip file with HttpResponse, using StringIO() because i'm not storing in DB or Harddrive.
My issue is that my response is returning 200 when i request the file, but the OS never ask me if i want to save the file, or the file is never saved. i think that the browser is reciving the file because i have seen on the Network Activity (inspect panel) and it says than a 6.4 MB file type zip is returned.
I'm taking a .step file (text file) from a DB's url, extracting the content, zipping and returning, that's all.
this my code:
def function(request, url_file = None):
#retrieving info
name_file = url_file.split('/')[-1]
file_content = urllib2.urlopen(url_file).read()
stream_content = StringIO(file_content)
upload_name = name_file.split('.')[0]
# Create a new stream and write to it
write_stream = StringIO()
zip_file = ZipFile(write_stream, "w")
try:
zip_file.writestr(name_file, stream_content.getvalue().encode('utf-8'))
except:
zip_file.writestr(name_file, stream_content.getvalue().encode('utf-8', 'ignore'))
zip_file.close()
response = HttpResponse(write_stream.getvalue(), mimetype="application/x-zip-compressed")
response['Content-Disposition'] = 'attachment; filename=%s.zip' % upload_name
response['Content-Language'] = 'en'
response['Content-Length'] = write_stream.tell()
return response

How to serve a django-webodt file to users?

I'm trying to allow users to export some of their database data. I am using django-webodt to create a .odt file from their data. I then am trying to allow them to download it. The file is created just fine, but when it downloads it seems to download a blank file. I think there is some difference between where the server is looking for the file and where it actually is. I was wondering how to get this to work properly? I'm relatively new to django so any help would be appreciated. The code I have is below:
def downloadBook(request, val):
template = webodt.ODFTemplate('conversion.odt')
context = dict(ideas=Book.objects.getIdeaSet(int(val)))
document = template.render(Context(context))
file_name = os.path.basename(document.name)
path_to_file = os.path.dirname(document.name)
response = HttpResponse(mimetype='application/force-download')
response['Content-Disposition'] = 'attachment; filename=%s' % smart_str(file_name)
response['X-Sendfile'] = smart_str(path_to_file)
return response
I did the following and it works:
from django.template import Context
from webodt import ODFTemplate
template = ODFTemplate('template_file.odt')
context = { 'some_dict': '' }
document = template.render(Context(context))
response = HttpResponse(document.read(), mimetype='application/vnd.oasis.opendocument.text')
response['Content-Disposition'] = "attachment; filename=fancy-filename-as-you-like.odt"
document.close() # delete the document on /tmp
return response

returning zip for download from view in django

I try to download a zip file in my Django application.
How should I return it from the view?
I tried the code below, but I get some kind of alert in the browser with the content of the file inside my zip.
What am I doing wrong?
def download_logs(request):
date = datetime.datetime.now().__str__().replace(" ", "_").split(".")[0]
os.system("df -h . > /tmp/disk_space")
response = HttpResponse(mimetype='application/zip')
response['Content-Disposition'] = 'filename=logs_%s.zip' % date
files = []
files.append("/tmp/disk_space")
buffer = StringIO()
zip = zipfile.ZipFile(buffer, "w", zipfile.ZIP_DEFLATED)
for name in files:
file = open(name, "r")
zip.writestr(name, file.read())
file.close()
zip.close()
buffer.flush()
ret_zip = buffer.getvalue()
buffer.close()
response.write(ret_zip)
return response
You should tell the browser to treat the response as a file attachment.
From the docs, you should do something like:
>> response = HttpResponse(my_data, mimetype='application/vnd.ms-excel')
>>> response['Content-Disposition'] = 'attachment; filename=foo.xls'
Here is a link to actual working code for building a ZipFile in memory and returning it to the user as a file to download: django-rosetta's view.py