First of all, I have very little knowledge of what shaders can do, and i am very interested in making vertex lighting. I am attempting to use a 3d colormap which would be used to calculate the vertex color at that position of the world, and also interpolate the color by using the nearby colors from the colormap.
I cant use typical OpenGL lighting because its probably too slow and theres a lot of lights i need to render. I am going to "render" the lights at the colormap first, and then i could either manually map every vertex drawn with the corresponding color from the colormap.
...Or i could somehow automate this process, so i wouldnt have to change the color values of vertexes myself, but a shader could perhaps do this for me?
Questions is... is this possible, and if it is: what i need to know to make it possible?
Edit: Note that i also need to update the lightmap efficiently, without caring about the size of the lightmap, so the update should be done only at that specific part of the lightmap i want to update.
It almost sounds like what you want to do is render the lights to your color map, then use your color map as a texture, but instead of decal mode set it to modulate mode, so it's multiplied with the existing color instead of just replacing it.
That is different in one way though: instead of just affecting the vertexes, it'll map to the individual fragments (pixels, in essence).
Edit: What I had in mind wasn't a 3D texture -- it was a cube map. Basically, create a virtual cube surrounding everything in your "world". Create a 2D texture for each face of that cube. Render your coloring to the cube map. Then, to color a vertex you (virtually) extend a ray outward from the center, through the vertex, to the cube. The pixel you hit on the cube map gives you the color of lighting for that vertex.
Updating should be relatively efficient -- you have normal 2D textures for the top, bottom, front, etc., and you update them as needed.
If you cant use the fixed function pipeline functionality the best way to do per vertex lighting should be to do all the lighting calculations per vertex in the vertex-shader, when you then pass it on the the fragment shader it will be correctly interpolated across the face.
Another way to deal with performances issues when using a lot of light sources is to use deferred rendering as it will only do lighting calculation on the geometry that is actually visible.
That is possible, but will not be effective on the current hardware.
You want to render light volumes into 3d texture. The rasterizer works on a 2D surface, so your volumes have to be split along one of the axises. The split can be done in one of the following ways:
Different draw calls for each split
Instanced draw, with layer selection based on glInstanceID (will require geometry shader)
Branch in geometry shader directly from a single draw call
In order to implement it, I would suggest reading GL-3 specification and examples. It's not going to be easy, nor it will be fast enough in the result for complex scenes.
Related
Here is a task that every GIS application can do: given some polygons, fill each polygon with a chosen color. Like this: image
What is the best way of doing this repeatedly in Opengl? That is, the polygons do not change, and I want to vary the data for coloring to produce difference renderings.
Redrawing polygons for each rendering is the most straightforward solution, but it seems to be a waste, since the geometries do not change at all.
Or is it better to create a stencil for each polygon, and stencil print the entire map? If there are too many polygons, will doing hundreds or thousands of rendering passes create a problem?
For each vertex of a polygon, map a certain color.That means when you send the data to the shaders, with each call the vertex array object sends 2 parameters: a vector which is needed in the vertex shader and a vector which will be used as the fragment color.That is the simplest way.
For example think of a triangle drawn in opengl . if you send its vertices to the vertex shader and set a color in the fragment shader everytime when a vertex enters the shader pipeline it will be positioned accordingly and on the screen set with the given color from the fragment shader.
The technique which I poorly explained ( sry I am not the best at explanations) , is used in the colored triangle example in which colors interpolate.Red maped to a corner , Green maped to another , and Blue to the last. If you set it so the red color maps to every corner you get your colored triangle.That is the basic principle.Oh and you draw the minimum count of triangles and you need one pair of shaders .
Note : a polygon is made out of N triangles and you need to map the same color to every vertex of each triangle drawn in that polygon.
I think a bigger issue will be that OpenGL doesn't support polygons or vector drawing in general, but there are libraries for this. You'll have to use an existing solution for vector drawing, or failing that, you'll have to convert from your GIS data (usually a list of points for a polygon) to triangles. This is likely the biggest obstacle.
The fact that the geometry doesn't change isn't really an issue, you would generally store geometry into one or more buffers, then create logic to only draw what is visible inside your view point area, perhaps even go as far to only generate the geometry for the visible area.
See also this question and it's answers.
Rendering Vector Graphics in OpenGL?
I want to render multiple 3D cubes from one vbo. Each cube has a uniform color.
At this time, I create a vbo where each vertex has a color information.
Is it posible to upload only one color for a one shape (list of verticies)?
I'm also want to mix GL_TRIANGLES and GL_LINES in the glDrawElements-method of the same shader. Is it posible?
//Edit : I only have OpenGL 2.1. Later I want to build this project on Android.
//Edit 2:
I want to render a large count of cubes (up to 150.000). One cube has 24 verticies of geometry and color and 34 indices. Now my idea is to create some vbo's (maybe 50) and share out the cubes to the vbo's. I hope that this minimizes the overhead.
Drawing lots of cubes
Yes, if you want to draw a bunch of cubes, you can specify the color for each cube once.
Create a VBO containing the vertexes for one cube.
// cube = 36 vertexes with glDrawArrays(GL_TRIANGLES)
vbo1 = [v1] [v2] [v3] ... [v36]
Create another VBO with the view matrix and color for each cube, and use an attribute divisor of 1. (You can use the same vbo, but I would use a separate one.)
vbo2 = [cube 1 mat, color] [cube 2 mat, color] ... [cube N mat, color]
Call glDrawElementsInstanced() or glDrawArraysInstanced(). This will draw the cube over and over again.
Alternatively, you can use glUniform() for each cube, but this will limit the number of cubes you can draw. The above method will let you draw thousands, easily.
Mixing GL_TRIANGLES and GL_LINES
You will have to call glDraw????() once for each type of primitive. You can use the same shader for both times, if you like.
Regarding your questions :
Is it possible to upload only one color for one shape ?
Yes , you can use a uniform instead of a vertex attribute(ofc this means changes in more places). However, you will need to set the uniform for each shape, and have a different drawcall for each differently colored shape .
Is it possible to mix GL_TRIANGLES and GL_LINES in the glDrawElements ?
Yes and no. Yes , but you will need a new drawcall (which is obvious). You cannot do on the same drawcall some shapes with GL_TRIANGLES and some shapes with GL_LINES.
In pseudocode this will look like this :
draw shapes 1,2,10 from the vbo using color red and GL_TRIANGLES
draw shapes 3,4,6 from the vbo using color blue and GL_LINES
draw shapes 7,8,9 from the vb using color blue and GL_TRIANGLES
With OpenGL 2.1, I don't think there's a reasonable way of specifying the color only once per cube, and still draw everything in a single draw call.
The most direct approach is that, instead of having the color attribute in a VBO, you specify it directly before the draw call. Assuming that you're using generic vertex attributes, where you would currently have:
glEnableVertexAttribArray(colorLoc);
glVertexAttripPointer(colorLoc, ...);
you do this:
glDisableVertexAttribArray(colorLoc);
glVertexAttrib3f(colorLoc, r, g, b);
where glDisableVertexAttribArray() is only needed if the array was previously enabled for the location.
The big disadvantage is that you can only draw cubes with the same color in one draw call. In the extreme case, that's one draw call per cube. Of course if you have multiple cubes with the same color, you could still batch those into a single draw call.
You wonder whether this is more efficient than having a color for each vertex in the VBO? Impossible to say in general. You'll always get the same answer in cases like this: Try both, and benchmark. I'm skeptical that you will find it beneficial. In my experience, it's fairly rare for fetching vertex data to be a major performance bottleneck. So cutting out one attribute will likely no give you much of a gain. On the other hand, making many small draw calls absolutely can (and often will) hurt performance.
There is one option you can use that is sort of a hybrid. I'm not necessarily recommending it, but just in the interest of brainstorming. If you use a fairly limited number of colors, you can use a single scalar attribute in the VBO that encodes a "color index". Then in the vertex shader, you can use a texture lookup to translate the "color index" to the actual color.
The really good options are beyond OpenGL 2.1. #DietrichEpp nicely explained instanced rendering, which is an elegant solution for cases like this.
And no, you can not have lines and triangles in the same draw call. Even the most flexible draw calls in OpenGL 4.x, like glDrawElementsIndirect(), still take only one primitive type.
I'd like to do a cartoony 3D character, where the facial features are flat-drawn and animated in 2D. Sort of like the Bubble Guppies characters.
I'm struggling with finding a good method to do it. I'm using Libgdx, but I think the potential methodologies could apply to any game engine.
Here are ideas I thought of, but each has drawbacks. Is there a way this is commonly done? I was just playing a low-budget Wii game with my kids (a Nickelodeon dancing game) that uses this type of animation for the faces.
Ideas:
UV animation - Is there a way to set up a game model (FBX format) so that certain UV's are stored in various skins? Then the UV's could jump around to various places in a sprite map.
Projected face - This idea is convoluted. Use a projection of a texture onto the model with a vertex shader uniform that shifts the UV's of the projected texture around. So basically, you'd need a projection matrix that's set up to move the face projection around with the model. But you'd need enough padding around the face frame sprites to keep the rest of the model clear of other parts of the sprite map. And this results in a complicated fragment shader that would not be great for mobile.
Move flat 3D decal with model - Separately show a 3D decal that's lined up with the model and batched as a separate mesh in the game. The decal could just be a quad where you change the UV attributes of the vertices on each frame of animation. However, this method won't wrap around the curvature of a face. Maybe it could be broken down to separate decals for each eye and the mouth, but still wouldn't look great, and require creating a separate file to go with each model to define where the decals go.
Separate bone for each frame of animation - Model a duplicate face in the mesh for every frame of animation, and give each a unique bone. Animate the face by toggling bone scales between zero and one. This idea quickly breaks down if there are more than a few frames of animation.
Update part of skin each frame - Copy the skin into an FBO. Draw the latest frame of animation into the part of the FBO color texture that contains the face. Downsides to this method are that you'd need a separate copy of the texture in memory for every instance of the model, and the FBO would have to either do a buffer restore every frame (costly) or you'd have to redraw the entire skin into the FBO each frame (also costly).
I have other ideas that are considerably more difficult than these. It feels like there must be an easier way.
Edit:
One more idea... Uniform UV offset and vertex colors - This method would use vertex colors since they are easily supported in all game engines and modeling packages, but in many cases are unused. In the texture, create a strip of the frames of animation. Set up the face UV's for the first frame. Color all vertices with Alpha 0 except the face vertices, which can be colored Alpha 1. Then pass a UV face offset uniform to the vertex shader, and multiply it by a step function on the vertex colors before adding it to the UVs. This avoids the downsides of all the above methods: everything could be wrapped into one texture shared by all instances of the model, and there would be no two-pass pixels on the model except possibly where the face is. The downside here is a heftier model (four extra attributes per vertex, although perhaps the color could be baked down to a single byte).
Your shader could receive 2 textures, one for the body, and one for the face. The face one being transparent so you could overlay it on top of the body one. Then you just need to send a different face texture based on the animation.
I am struggling with the same problem with implementing a 2d animation to a background billboard in my 3d scene.
I believe that Using Decals is the simplest solution, and implementing the animation is as easy as updating the decal’s TextureRegion according to an Animation object:
TextureRegion frame = animation.getKeyFrame(currentFrameTime, true);
decal.setTextureRegion (frame);
I guess the real problem in your case is positioning the decal inside the scene.
One solution could be using your 3D modeling software for modeling a "phantom" mesh that will store the position of the decal.
The "phantom" mesh will not be rendered with all the other 3d elements, instead it will be used to determine the position of the decals vertices. The only thing you’ll need to do is copy the “phantom” position vertices and paste them to the decal.
I hadn’t got to implement this solution yet, but theoretically it could be relatively easily done.
Hope this idea will help you, and I will appreciate you sharing other solutions/code to this problem if you find any.
I am working on a painting app using the LibGDX framework, though this should be primarily OpenGL related.
Basically, I am looking for a way to prevent the sprites I use to draw from overlapping each other when they aren't fully opaque, as this creates a lot of unpleasant effects. Drawing the sprites at 1.0 alpha onto a texture and then drawing that texture back at the desired alpha gives the effect I want, but that method would involve constantly recreating the texture as the user is drawing, which is far too intensive to be viable.
From what I can see, the best option for me, in basic terms, is to sort of subtract one of these sprites from the other in the fragment shader. I am quite certain this route would work, but I cannot figure out how to get to the point where I can actually compare them in the fragment shader. Both will always use the same single texture, but they will be positioned in different spots. Is it at all possible to actually compare them like that, or is there a suitable alternative?
It's not actually possible to compare 2 textures that are applied to different geometry (sprites) in the fragment or vertex shader that way, because they will be rendered on different iterations of the shaders, at different points in time.
You could have two or more texture units to sample and subtract multiple textures, but they would have to be applied to the same vertices (sprites), which I think is not what you want.
A better approach would be to compute the proximity of the sprites before they are rendered. You could then either change their positions, or pass the proxmity as a uniform value into the shaders, which could then be used to change the alpha of the fragment pixels for the sprites.
I'm wondering how I could create a gradient wuth multiple stops and a direction if I'm making polygons. Right now I'm creating gradients by changing the color of the verticies but this is limiting. Is there another way to do this?
Thanks
One option you may have is to render a simple polygon with a gradient to a texture, which you then use to texture your actual polygon.
Then you can rotate the source polygon and anything textured with its image will have its gradient rotate as well, without the actual geometry changing.
The most flexible way is probably to create a texture with the gradient you want, and then apply that to your geometry.
If you're using a shader, you can pass your vertex world positions into your vertex shader and they'll interpolate to your fragment shader, so for every fragment, you'll get where it is in world-space (of course you can use any space). Then it's just a matter of choosing whatever transfer function to change that value to a color. You can make any kind of elaborate algorithm using b-splines or whatever in your fragment shader.